Available online Journal of Scientific and Engineering Research, 2016, 3(6): Research Article
|
|
|
- Juniper Daniels
- 6 years ago
- Views:
Transcription
1 Av Ju St E R, 2016, 3(6): R At ISSN: CODEN(USA): JSERBR Cutvt R Au Su H Lv I y t Mt Btt M Zu H Ut, Su, W Hy Dtt Ay Futy Autu, Uvt Tw, J. Tw N. 9 P, 25136,Wt Sut, I, E-: 65@y. Att I 2013 ut 71,279,709 M y (DGM) uvt t 44,528,434 M ut. Dt t Mty Ht, w xty 100 I, u utt ( ) u t ty t u uttu, ut y y t utt. Dy (F) t, w t, ut t, w t, t tu, v u t. I- I ut 30-60% t u v y t w w u t y utt. T v t t ut 137 t -1 y -1, tuty t t utt, y y t t -tt, wt utvt t y w tt (F) u. T tv t utvty t w F, wt tt >7 M -1 wt tt t t vt v wt tt >30-1. T ut w tt t t t ty t ut v wt t t tt, w t ut w: 1) T u t tt t I 29 vty t t ttt, t u t; 2) Put t t DGM u M vt wt ut wt ttt, y 7,417.9 M; 3) t v, vt wt PGR ttt, w t ut tw It t ty (vt tt + t 10 M -1 + t u [(10 x 10) x 25 x 10x10)] tt u 4 + yu 10 y + PGR) SRI t u t ut tt t y t t -tt z F. Kyw -tt,, Itut R t tt t w', w u u t wt, t tt w tu t t. T t, y y ut (F) ut [1]. A t WHO (2000), y 3 t utt, w -I ut 30-60% u v y t w w u t y utt [1]. T v t t ut 137 t - 1 y -1 [2], tuty t v t utt, y y t t tt. Mt -tt t wy utvt tt ut (F), t t tuy y ut v t t z t t, t vt t tt t. H v v F 2+ t t w, tt tt t xt, t vt wt tt y t t -tt. I ut v y Ju St E R 131
2 Ut MZH t Ju St E R, 2016, 3(6): t t y t t -tt, ut y ttt wt wt ut ut t ux, u t ty t ut t w Su-S t, ty t t [3-4]. T tt tt u t t ut w Dy wt v 2,691 [5], w u y t uty F 2+ A 3+ [6-8], ut u tt wt v. T v utvty y M -1 w t ut w t 4.75 M -1 [2]. T ut t y xt w t t t tt vy wy vy w t vy, y: N tt (0.11% w), v P ( vy w), wt t t t (K w, N w, M vy w, C vy w), w A u, F [9]. Lv u ut t ut F 3+ t F 2+, t t t t tt t t w tty t [8,10], w u t t t wt vt, y t vt w tv t utt t [7, 11-14]. T ut - vt y, utvty vt w wt wt utvt ty t -tt. It t utvt u u t -tt t t wy t y t vtt tt t tuy utvt u u t. T xt ttt t t utvty wt w t t F, wt tt >7 M -1, t t t wt tt >30-1 ; t t t ty t wt ut ux t t t t t. T ut t tuy vy tt t ut, ty vt t t u y w, t utt ty. Mt Mt T xt w ut Fuy t Auut 2014, t w wt t t Sutt Kt Bu, Dtt Dy. T xt u tw-t t Cty Rz D wt t t. T t t w t vty (V) w: V 1 = I 24; V 2 = SBY; V 3 = I 26; V 4 = I 27; V 5 = I 28; V 6 = I 29; V 7 = I 30; V 8 = Cu; V 9 = M; V 10 = A D. T t w t wt ut (Z), y: Z 0 = Ct; Z 1 = Sytt PGR (Aux); Z 2 = Ntu PGR (ut wt). T t ty u t xt, y: (1). tt vt F A; (2). At w 10 M -1 ; (3). S u [(10 x 10 ) x 25 x (10x10 )]; (4). O t t 10 y [8, 13, 15-16]. Ovt t ut t xt u t ut u t t, t u t, u, t, t ty, t wt 1000 ; y (DGM) -1. Lv (F) u wt AA V 240 wt t t SNI t Itt Lty Kt R X P. R, t t ut D, wt tt ut, t tuy 2 x 24 u. R wt wt 7 y, t t t t w u 10 M -1 u t. At tt, t t y tt, wt t t xt t wt z 6.0 x 3.0 t, tt 60 xt t. T t wt ut 2 w t t SRI t. Gt y tu wt tt v, t y v wt tt t. T t ut t ut 10 y y t t t. T t t t t U tz, SP-36 KC t y t (250 NPK P) 170 U, 36 P 2 O 5 60 K 2 O). A ut v U t t 6 w t t w t t tv. W t 2 w t 6 w t t. Wt tt, t Ju St E R 132
3 Ut MZH t Ju St E R, 2016, 3(6): wt w tt. Hvt t t yw 80% t tt ut. Rut Du T xt ut w tt t w vt t wt ut vt tt tt wt wt ut ut ytt tu (ut wt) v t u t t, u t, u, t (T 1), t u t, u -1, wt 1000 ; DGM -1 (T 2), v (F) (T 3). T 1: Pt t, t u, u t v vt utvt y t t -tt Ty R Vty PGR I 24 SBY I 26 I 27 I 28 I 29 I 30 Cu M A D Pt Ht () Ct u (5) u v Cut Wt x w t Σ T () Ct w J (5) Cut Wt u 81.2 t 78.8 v 75.0 x P () Ct t (5) Cut Wt u P Lt () Ct (5) Cut Wt M w y t tt t v ttt w ty t t 5% v y Tuy tt. T wt, w t tty t vt t t F. But t vt t w u w, w T 1 2. T t tt t wt t t y t ut ty vt, tu u vt wt Ju St E R 133
![Ut MZH t Ju St E R, 2016, 3(6):131-138 ut t t t t t v vt tt t tt tw ty y vt [17], t t t vt wt t ty t t vt ty vty. T t wt wt t t vt I 29 (t) 114.69 tu t wt ut ttt (82.27 ).](/docs-images/77/76666257/images/4-0.jpg "At t t t t w tt t ttt t wt ut y t vt t, vt u I 24, SBY, I 27 I 29, M ut t vt, ttt PGR t t I 28 A D. H w t t t y t t, w w t t t tyt t wt ut t t t t ut tyt [17].")
4 Ut MZH t Ju St E R, 2016, 3(6): ut t t t t t v vt tt t tt tw ty y vt [17], t t t vt wt t ty t t vt ty vty. T t wt wt t t vt I 29 (t) tu t wt ut ttt (82.27 ). At t t t t w tt t ttt t wt ut y t vt t, vt u I 24, SBY, I 27 I 29, M ut t vt, ttt PGR t t I 28 A D. H w t t t y t t, w w t t t tyt t wt ut t t t t ut tyt [17]. T u t vt I 24 I 26 I 30 Cu, M A D tt wt PGR, ut t t vt t wt ut ttt t t. T t t u t t ttt wt PGR I 24 ytt, 95 t, w t wt u ttt I 29 wt ut wt, w 75 t. T u t uy u t t u t yt [(10 x 10 ) x 25 x (10x10 )] u u (Fu 2B). Itt wt t t, u u t t wt vt u t t tt y t t utt, wt t. I vt ( ), t u t tt ut 20 t, ty t t ttt t wt ut t t u t 4x t t vt utvt (Fu 1A). D t u t, uy u t u t t t yt utvt. Dt t t y y vu ttut t t u utv t u u t [18-20]. A B Fu 1: Gwt t u wt v () u t (A), u (4 ) wt [(10x10) x 25 x (10x10)] u t (B) T t u u I 24 wt ytt t wt ut ttt, 50.4, w t wt t u I PGR 29 wtut ttt (t) wt T t t t utv t [20]. T u u t xt 2-3 t, t t u v t y vt. Nt vt utvt y y u ut [21]. T t u t t t wy utvt, t utvt vt u t 4-6 u (w t) t t ut 21 y, w t ty u ut 12 y u 4 (Fu 1B), wt t t t t t w ty tt tt t y t tt t u Ju St E R 134
5 Ut MZH t Ju St E R, 2016, 3(6): Su vt u v, wt t ut tt t t tt - zt vt t tt tyt u t t tu. R t t xt w t ttt PGR ut wt, w I 27, t t wt t ut t ytt t wt ut ttt t t vty, t t t I W t tt vt A D wt ytt t wt ut ttt, (T 2). T u ty I 24 wt t ytt t wt ut ttt (47.8 ), w t t u I 30 wt PGR ttt ut wt 20.1 ut. T ut vt ( tu) w tt t u t t, ty w t u T 2: Nu t, u, 1000 wt, DGM -1 v vt utvt y t t -tt. Ty R Vty PGR I 24 SBY I 26 I 27 I 28 I 29 I 30 Cu M A D St () Ct B (5) B A K B G P -1 () Ct (5) A K G Wt () Ct (5) A K Dy G M Put (DGM M -1 ) Ct 6,767 6,881 5,912 5,418 4,891 6,346 4,404 3,068 5,552 5,606 (5) 5,974 4,375 4,535 3,903 4,170 4,314 2,024 4,444 3,455 4,216 A K 5,262 3,884 3,887 2,751 1,920 3,953 2,850 3,406 7,418 3,266 M w y t tt t v ttt w ty t t 5% v y Tuy tt. St t vt SBY wt ut wt ttt t wt ut tt 12.2, ty t t I 24 28, w t t vt w t ty t (T 2). Ju St E R 135
6 Ut MZH t Ju St E R, 2016, 3(6): I t t ttt w, v t w v v tt ut t t ttt t wt ut u ytt ut wt, t t; t t, t, t u -1, t wt T uy u t ty t u u (w) x wt w u u 10 M -1, ut t t t t utvt. Pt PGR vy utt, w ut -1. Cw u t t wt ut ux t u, w y tut w, t, v, tt [22-24]. M vt (t) w t u t ty t wt I 26 (t) , w t u -1 wt t vt SBY-tt wt ut wt, w (T 3). R t w w v ut t F, u t vt u tt vt tt t t ut t. I t, ty u u t wt t u t vty utt. At t tu t t (4 t ) t u t y vttv wt tt, t t tt tt t y t [9]. T ty, t u vttv wt tv u t t vy yu. T tv vttv wt, v y t u t wt ut tt t v, t. T 3: Lv (F) vt utvt wt -tt SRI t. Ty R Vty PGR I SBY I I I I I Cu M A D I Ctt R G ( -1 ) Ct (5) Cut Wt M w y t tt t v ttt w ty t t 5% v y Tuy tt. I v vt w utvt y t t -tt w tt vy 18.8 t I v wt t vt A D y ttt wt ut wt ( ), w t v t I 28 ( ) w t ty t t I 27 wt wt ttt u ut ( ), w vt M t ( ), I 29 wt t ttt ( ) t ( ). I v I 28 ( ) w tt wt ut wt y 62% wt t ( ), w t vt A D ( ) w w tt wt ut wt y 19% wt t (23.6-1). I v vt utvt z y F (T 3) u, w wt t v t t y ut (Iz Ayu, 2012). T w tt, uy u vt utvt t wt v v vy w. Cutvt vt (T 3) t-tt vt F [15], t vt t t w. I t, ut utu y y t v ty, t : tt vt F A 3+ t 10 M -1 + S u [(10 x 10 ) x 25 x (10x10) ] + O t t w 10 y [8, 13, 15-16]. Cu T ut w tt t t t ty t ut v wt t t -tt, w w t ut: Ju St E R 136
7 Ut MZH t Ju St E R, 2016, 3(6): T u t tt t I 29 t t ttt, t u t. 2. Put t t DGM u y M vt wt ut wt ttt, M T tt, vt wt PGR ttt w t ut tw It t ty (vt tt + t 10 M -1 + u [10 x 10) x 25 x 10x10)] + yu 10 y + PGR) wt t SRI t u t ut t tt t y t t -tt z F. Awt T t S-Lt H Eut Mty Nt Eut t t tu D Kt W X , t Ltt At Itt R Cttv Gt Nt Pty F Y T t M. S K, t Stu IV V t tut u u Nt E Pyt ty ut t w. R [1]. Ayu P t, uy t. K, 22 Nv Jt. H 13. (I I). [2]. BPS I D A. B Put Sttt. Jt, I. (I I). [3]. H, W.G Itut t Pt Pyy. T Uvty Wt Ot. J Wy S, INC. [4]. Y, J., S. P., Z. Z., Z. W., R.M. V Q. Zu L. Lu G y tt y tt t / y. C S. 42: [5]. BPS Kut Dy. B Dy BPS, Sut Bt, I. (I I). [6]. Ut, M.Z.H P vt t uu. J. A. I. 38 (3): (I I). [7]. Ut, M.Z.H Et NC-t t NO 3-, NH 4+ NO 2- t v vt. J. T S. 15 (3): : /t [8]. Su., I. W., M.Z.H. Ut P vt t F 2+ w u u. J.At A. 13 (1): (I I). [9]. Ut, MZH., Su., W Hy Et t v t t ty ut F 2+. J T S. 18 (3): : / t [10]. Swt, K.L I txty wt t t utt. J.Pt Nut. 27: [11]. M, J. F R txt uu t. Pt y. 41(4): [12]. R, Z M utt, ut t. F ut, Bt. [13]. Ut, M.Z.H., W. Hy., R. Mu, Su P vt t t w D Kut P St. J. A. I. 37(2): (I I). [14]. N, A., I. Lu, M. Gu, M.A. Cz, K. Aw, D. W Pu t ut t u tuu t. J. A. I. 40 (2): (I I). [15]. Ut, M.Z.H., I. W., Su R utv z wt F 2+ w tu wt ut ty. J T S. 17 (3): : /t Ju St E R 137
8 Ut MZH t Ju St E R, 2016, 3(6): [16]. Hy, W., K., I. Suy., A. Sy., T.B. Pty T vt w ut u t. J.A. I. 40(2): (I I) [17]. Lt, A.P., B. Au, A. Ju, H. Aw Y tty tty t w t ty. J. A I. 38: [18]. Pu, T., S Iy, M. Mu, E.Wt Ct yt utu t tuu t. J. A. I 41(3): (I I). [19]. Putwt, M.D., Suyt, I A Pt ut t utu u uu P w. J. A. I 41(3): (I I). [20]. Ut, MZH., Su., W Hy A A Cutu t y F u v wt tt t. Itt x Pt u t. Uvty Buu, Buu, Ot [21]. Ayu Dt vt uu. Put Pt T P, B Pt P Pt. tt:// (I I). [22]. C-U, S., B. S, A. Pu, C. K A t u y u ut u t t tu t utu t t (Oyz tv L. u ). I Vt C.Dv.B. Pt 45: [23]. Ku, L., R. S, S.M. B, K. Ut, V. Sy Et ttt v t utu (Oyz tv L.) J. Ex.B. A. S.2: [24]. Gu, C., Puw, B.S., Dw, I.S Syuu M Pt t tzt t utu 6 F. J. A. I 44 (2): Ju St E R 138
Simulation of Natural Convection in a Complicated Enclosure with Two Wavy Vertical Walls
A Mtt S, V. 6, 2012,. 57, 2833-2842 Sut Ntu Cvt Ct Eu wt Tw Wvy Vt W P S Dtt Mtt, Futy S K K Uvty, K K 40002, T Ct E Mtt CHE, S Ayutty R., B 10400, T y 129@t. Sut Wtyu 1 Dtt Mtt, Futy S K K Uvty, K K 40002,
/99 $10.00 (c) 1999 IEEE
P t Hw Itt C Syt S 999 P t Hw Itt C Syt S - 999 A Nw Atv C At At Cu M Syt Y ZHANG Ittut Py P S, Uvty Tuu, I 0-87, J Att I t, w tv t t u yt x wt y tty, t wt tv w (LBSB) t. T w t t x t tty t uy ; tt, t x
Differentiation of allergenic fungal spores by image analysis, with application to aerobiological counts
15: 211 223, 1999. 1999 Kuw Puss. Pt t ts. 211 tt u ss y yss, wt t t uts.. By 1, S. s 2,EuR.Tvy 2 St 3 1 tt Ss, R 407 Bu (05), Uvsty Syy, SW, 2006, ust; 2 st ty, v 4 Bu u (6), sttut Rsty, Uvsty Syy, SW,
SHORT WAY SYMMETRY/SYMMETRICAL SYNTHETIC TREAD TELEVISION VERTICAL VITREOUS VOLUME. 1 BID SET No. Revisions / Submissions Date CAR
//0 :: T U 0 : /" = '-0" 0 0 0 View ame T W T U T UT 0 0 T T U 0 U T T TT TY V TT TY T. 00' - 0" T U T T U T T U U ( ) '-" T V V U T W T T U V T U U ( ) T T 0 T U XT W T WW Y TT T U U ( ) U WW00 T U W
R a. Aeolian Church. A O g C. Air, Storm, Wind. P a h. Affinity: Clan Law. r q V a b a. R 5 Z t 6. c g M b. Atroxic Church. d / X.
A M W A A A A R A O C A () A 6 A A G A A A A A A-C Au A A P 0 V A T < Au J Az01 Az02 A Au A A A A R 5 Z 6 M B G B B B P T Bu B B B B S B / X B A Cu A, S, W A: S Hu Ru A: C L A, S, F, S A, u F C, R C F
Fuzzy Reasoning and Optimization Based on a Generalized Bayesian Network
Fuy R O B G By Nw H-Y K D M Du M Hu Cu Uvy 48 Hu Cu R Hu 300 Tw. @w.u.u.w A By w v wy u w w uy. Hwv u uy u By w y u v w uu By w w w u vu vv y. T uy v By w w uy v v uy. B By w uy. T uy v uy. T w w w- uy.
BLUE LINE TROLLEY STATION IMPROVEMENTS
TUT GT DD T T TUT HU GT WTH HG GHT G TZ # - + V Y 0/00 HZ GT WTH HG - + = U& PV-50 #555- P JUT X GHT G & DD. HG GHT D P UT UT Y TW P GT WTH HG GHT G & P DT P UT # - + U& P-50 #500-0 UT Y W/HVY DUTY TT
Econometric modelling and forecasting of intraday electricity prices
E y y Xv:1812.09081v1 [q-.st] 21 D 2018 M Nw Uvy Duu-E F Z Uvy Duu-E D 24, 2018 A I w w y ID 3 -P G Iy Cuu Ey M u. A uv u uy qu-uy u y. W u qu u-- vy - uy. T w u. F u v w G Iy Cuu Ey M y ID 3 -P vu. T
2 u Du, k Hu Dv Hu, y H. u Cu j u qu u. Nv. v uy. Cu Hu F A H. qu Cu.. Cu j 1980, u V, v Nu My O k. v u u. A G C. My u v k, 2.5 H v v u / u v u v k y
H HE 1016 M EEING OF HE ODIE CLU 1,016 Cu 7:30.. D 11, 2007 y W L Uvy. C : Pu A y: Ov 25 x u. Hk, u k MA k D u y Hu, u G, u C C, MN C, Nk Dv Hu, MN, u K A u vu v. W y A Pku G, G u. N EW UINE: D, Cu, 22
Asynchronous Training in Wireless Sensor Networks
u t... t. tt. tt. u.. tt tt -t t t - t, t u u t t. t tut t t t t t tt t u t ut. t u, t tt t u t t t t, t tt t t t, t t t t t. t t tt u t t t., t- t ut t t, tt t t tt. 1 tut t t tu ut- tt - t t t tu tt-t
CONSTRUCTION DOCUMENTS
//0 :: 0 0 OV Y T TY O YTO: TY O YTO W # : U.. O OVTO 00 WT V V, OO OTUTO OUT U 0, 0 UTO U U \\d\ayton rojects\ayton nternational irport\.00 Y ustoms acility\\rchitecture\ rocessing enovation_entral.rvt
Trade Patterns, Production networks, and Trade and employment in the Asia-US region
Trade Patterns, Production networks, and Trade and employment in the Asia-U region atoshi Inomata Institute of Developing Economies ETRO Development of cross-national production linkages, 1985-2005 1985
A L A BA M A L A W R E V IE W
A L A BA M A L A W R E V IE W Volume 52 Fall 2000 Number 1 B E F O R E D I S A B I L I T Y C I V I L R I G HT S : C I V I L W A R P E N S I O N S A N D TH E P O L I T I C S O F D I S A B I L I T Y I N
Section 2.4 Linear Equations
Section 2.4 Linear Equations Key Terms: Linear equation Homogeneous linear equation Nonhomogeneous (inhomogeneous) linear equation Integrating factor General solution Variation of parameters A first-order
Map A-2. Riparian Reserves, Late-Successional Reserves, and Adaptive Management Area Land Management Allocations.
Appix A: Mp Mp A-. G pjt p. Mp A-. ipi v, Lt-Sui v, Aptiv Mgt A L Mgt Ati. Mp A-. t P gt ti witi t pjt (t giy Digt A u Wi Ivti A i t pjt buy). Mp A-. Attiv B Lggig yt,, u f uit i t pjt. Mp A-. Attiv B
A TYP A-602 A-304 A-602 A-302 GRADE BEAM SEE 95% COMPACTED STRUCTURAL FILL A '-0"
W W/TITI -0 X U I I X TITI TY S W TYS TIS X W S SU XISTI -0-0 -0-0 -0-0 ' - " ' - " ' - " ' - " ' - " ' - /" ' - /" ' - " -STUTU I -0 ' - ' - " " ' - " " 0' - " ' - U I S STUT W'S TY UTI W S STUT W'S TY
On Hamiltonian Tetrahedralizations Of Convex Polyhedra
O Ht Ttrrzts O Cvx Pyr Frs C 1 Q-Hu D 2 C A W 3 1 Dprtt Cputr S T Uvrsty H K, H K, C. E: @s.u. 2 R & TV Trsss Ctr, Hu, C. E: q@163.t 3 Dprtt Cputr S, Mr Uvrsty Nwu St. J s, Nwu, C A1B 35. E: w@r.s.u. Astrt
T H E S C I E N C E B E H I N D T H E A R T
A t t R u r s - L x C t I. xtr turs t Lx Ct Rurs. Rr qurtr s s r t surt strutur. Ts Att Rurs rv ut us, s srt t tr t rtt rt yur t w yu ru. T uqu Lx st ut rv ss ts ss t t y rt t tys t r ts w wr rtts. Atrx
T T - PTV - PTV :\er\en utler.p\ektop\ VT \9- T\_ T.rvt T PT P ode aterial. Pattern / olor imenion omment PT T T ode aterial. Pattern / olor imenion omment W T ode aterial. Pattern / olor imenion omment
N C GM L P, u u y Du J W P: u,, uy u y j S, P k v, L C k u, u GM L O v L v y, u k y v v QV v u, v- v ju, v, u v u S L v: S u E x y v O, L O C u y y, k
Qu V vu P O B x 1361, Bu QLD 4575 C k N 96 N EWSLEE NOV/ DECE MBE 2015 E N u uu L O C 21 Nv, 2 QV v Py Cu Lv Su, 23 2 5 N v, 4 2015 u G M v y y : y quu u C, u k y Bu k v, u u vy v y y C k! u,, uu G M u
Mouse-Human Experimental Epigenetic Analysis Unmasks Dietary Targets and Genetic Liability for Diabetic Phenotypes
C M Ru Mu-Hu Ex E Ay U Dy T G Ly D Py M L. Muu,,, Mu M. S,,, Aw E. J,,, X L,, H K, P M, Yuyu L, V Ruz,, Ax D, M Hu, C L, M MCy,,, E Näu, Ju R. Z, G. W W,, Aw P. F,, * D M, J H Uvy S M, N W S, B, MD, USA
FilfidatiPm 51mazi6umn1I40171mhz4nnin15miTtiuvintfr, b 1,1411.1
'h ldflu D w ) l blv JLfffTU f8fltflud dbw uuu vultj @@ @ DJ b bub LD ftujf:ttvtt t:9u zfty f/d:thlvtuuzytvvu (Ttulu) lfdt zuhzttuvtf b uvj:ulludlutluwul'ut'jj/fll ltttvtulvlztvfvt tt tluu bb b(ttd ulfu
T h e C S E T I P r o j e c t
T h e P r o j e c t T H E P R O J E C T T A B L E O F C O N T E N T S A r t i c l e P a g e C o m p r e h e n s i v e A s s es s m e n t o f t h e U F O / E T I P h e n o m e n o n M a y 1 9 9 1 1 E T
Contents FREE!
Fw h Hu G, h Cp h w bu Vy Tu u P. Th p h pk wh h pp h. Th u y D 1 D 1 h h Cp. Th. Th hu K E xp h Th Hu I Ch F, bh K P pp h u. Du h p, K G u h xp Ch F. P u D 11, 8, 6, 4, 3. Th bk w K pp. Wh P p pp h p,
duct end blocks filters lamps filters duct end blocks filters lamps filters metric
S Iu N 33 t t ut ut t t ut t ut t t t ut t ut ut t t t ut t ut ut t ut t t t ut ut t t t ut t ut ut t t t ut t ut ut t t t ut t ut t t t ut t t t t ut ut t t t ut t ut t ut t t t t ut ut t t ut t t t t
Solutions to Homework 3
Solutions to Homework 3 Section 3.4, Repeated Roots; Reduction of Order Q 1). Find the general solution to 2y + y = 0. Answer: The charactertic equation : r 2 2r + 1 = 0, solving it we get r = 1 as a repeated
Mathematical Models of Systems
Mathematical Models of Systems Transfer Function and Transfer functions of Complex Systems M. Bakošová and M. Fikar Department of Information Engineering and Process Control Institute of Information Engineering,
THIS PAGE DECLASSIFIED IAW E
THS PAGE DECLASSFED AW E0 2958 BL K THS PAGE DECLASSFED AW E0 2958 THS PAGE DECLASSFED AW E0 2958 B L K THS PAGE DECLASSFED AW E0 2958 THS PAGE DECLASSFED AW EO 2958 THS PAGE DECLASSFED AW EO 2958 THS
r R N S Hobbs P J Phelan B E A Edmeaes K D Boyce 2016 Membership ams A P Cowan D D J Robinson B J Hyam J S Foster A NAME MEMBERSHIP NUMBER
ug bb K S bb h B E E ch Smth K t Sth E ugh m Cw b C w h T B ug bb K C t tch S bb h B E ch Smth K t Sth E ugh m Cw b S B C w Shh T ug bb K C tch S bb h ch Smth K t u Sth E m Cw b h S B C w O Shh T ug bb
Three Phase Asymmetrical Load Flow for Four-Wire Distribution Networks
T Aytl Lo Flow o Fou-W Dtuto Ntwo M. Mo *, A. M. Dy. M. A Dtt o Eltl E, A Uvty o Toloy Hz Av., T 59, I * El: o8@yoo.o Att-- Mjoty o tuto two ul u to ul lo, yty to l two l ut. T tt o tuto yt ult y o ovt
The first order quasi-linear PDEs
Chapter 2 The first order quasi-linear PDEs The first order quasi-linear PDEs have the following general form: F (x, u, Du) = 0, (2.1) where x = (x 1, x 2,, x 3 ) R n, u = u(x), Du is the gradient of u.
Fall 2001, AM33 Solution to hw7
Fall 21, AM33 Solution to hw7 1. Section 3.4, problem 41 We are solving the ODE t 2 y +3ty +1.25y = Byproblem38x =logt turns this DE into a constant coefficient DE. x =logt t = e x dt dx = ex = t By the
Exam 2, Solution 4. Jordan Paschke
Exam 2, Solution 4 Jordan Paschke Problem 4. Suppose that y 1 (t) = t and y 2 (t) = t 3 are solutions to the equation 3t 3 y t 2 y 6ty + 6y = 0, t > 0. ( ) Find the general solution of the above equation.
Lecture 6c: Green s Relations
Lecture 6c: Green s Relations We now discuss a very useful tool in the study of monoids/semigroups called Green s relations Our presentation draws from [1, 2] As a first step we define three relations
P a g e 3 6 of R e p o r t P B 4 / 0 9
P a g e 3 6 of R e p o r t P B 4 / 0 9 p r o t e c t h um a n h e a l t h a n d p r o p e r t y fr om t h e d a n g e rs i n h e r e n t i n m i n i n g o p e r a t i o n s s u c h a s a q u a r r y. J
Computer Graphics. Viewing & Projections
Vw & Ovrvw rr : rss r t -vw trsrt: st st, rr w.r.t. r rqurs r rr (rt syst) rt: 2 trsrt st, rt trsrt t 2D rqurs t r y rt rts ss Rr P usuy st try trsrt t wr rts t rs t surs trsrt t r rts u rt w.r.t. vw vu
A review of stability and dynamical behaviors of differential equations:
A review of stability and dynamical behaviors of differential equations: scalar ODE: u t = f(u), system of ODEs: u t = f(u, v), v t = g(u, v), reaction-diffusion equation: u t = D u + f(u), x Ω, with boundary
A BRIEF INTRODUCTION INTO SOLVING DIFFERENTIAL EQUATIONS
MATTHIAS GERDTS A BRIEF INTRODUCTION INTO SOLVING DIFFERENTIAL EQUATIONS Universität der Bundeswehr München Addresse des Autors: Matthias Gerdts Institut für Mathematik und Rechneranwendung Universität
Help parents get their kids settled in with this fun, easy-to-supervise coloring activity. A Fun Family Portrait... 3
K u R C d C! m m m k m u y g H p u R Cd C g d g b u d yu g p m d fu g f pg m g w Tk yu C g p D Ng kd pg u bk! T y g b fm dy m d md g g p By pvdg ud d ug yu u f D Ng Cg v, yu b pg up g u d g v bf W v pvdd
Review. To solve ay + by + cy = 0 we consider the characteristic equation. aλ 2 + bλ + c = 0.
Review To solve ay + by + cy = 0 we consider the characteristic equation aλ 2 + bλ + c = 0. If λ is a solution of the characteristic equation then e λt is a solution of the differential equation. if there
MASSALINA CONDO MARINA
p p p p p G.. HWY. p p.. HWY... HWY. : HG, 00 T. TY, 0 Y 0 T o. B WG T T 0 okia 0 icrosoft orporatio - VY - T - T - GG - HBT - TT - T - TT T - TWT T 0 - T TT T - T TT T T T - TTY T - - T VT - K T ( H ),±
The variational iteration method for solving linear and nonlinear ODEs and scientific models with variable coefficients
Cent. Eur. J. Eng. 4 24 64-7 DOI:.2478/s353-3-4-6 Central European Journal of Engineering The variational iteration method for solving linear and nonlinear ODEs and scientific models with variable coefficients
Distributed Set Reachability
Dstt St Rty S Gj Mt T Mx-P Isttt Its, Usty U Gy SIGMOD 2016, S Fs, USA Dstt St Rty Dstt St Rty (DSR) s zt ty xt t sts stt stt Dstt St Rty 2 Dstt St Rty Dstt St Rty (DSR) s zt ty xt t sts stt stt Dstt St
Housing Market Monitor
M O O D Y È S A N A L Y T I C S H o u s i n g M a r k e t M o n i t o r I N C O R P O R A T I N G D A T A A S O F N O V E M B E R İ Ī Ĭ Ĭ E x e c u t i v e S u m m a r y E x e c u t i v e S u m m a r y
The Equivalent Differential Equation of the Gas-Kinetic BGK Scheme
The Equivalent Differential Equation of the Gas-Kinetic BGK Scheme Wei Gao Quanhua Sun Kun Xu Abstract The equivalent partial differential equation is derived for the gas-kinetic BGK scheme (GKS) [Xu J.
Lecture Notes in Mathematics. A First Course in Quasi-Linear Partial Differential Equations for Physical Sciences and Engineering Solution Manual
Lecture Notes in Mathematics A First Course in Quasi-Linear Partial Differential Equations for Physical Sciences and Engineering Solution Manual Marcel B. Finan Arkansas Tech University c All Rights Reserved
7. Find the Fourier transform of f (t)=2 cos(2π t)[u (t) u(t 1)]. 8. (a) Show that a periodic signal with exponential Fourier series f (t)= δ (ω nω 0
![7. Find the Fourier transform of f (t)=2 cos(2π t)[u (t) u(t 1)]. 8. (a) Show that a periodic signal with exponential Fourier series f (t)= δ (ω nω 0](/thumbs/96/126850209.jpg "7. Find the Fourier transform of f (t)=2 cos(2π t)[u (t) u(t 1)]. 8. (a) Show that a periodic signal with exponential Fourier series f (t)= δ (ω nω 0")
Fourier Transform Problems 1. Find the Fourier transform of the following signals: a) f 1 (t )=e 3 t sin(10 t)u (t) b) f 1 (t )=e 4 t cos(10 t)u (t) 2. Find the Fourier transform of the following signals:
Ex. Utility. Ex. Transformers. Ex. 8" Fire Hydrant. Ex. 12" DIP Waterline. Ex. 12" DIP. Waterline 2" BLOWOFF (TYP) Ex. TBM 'BOX CUT' El
Drawing: :\U\B\DT\\\UBH_\-UTTD ayout Tab:UT lotted by: B n this date: Thu, arch - :am :, D: x x TB ' ut lev ' ' T D VD VB DTH UB UTT T x Tel T D V ( td H ( BD H- x Blowo Valve UVT ' T T Top nv in nv out
Observability. Dynamic Systems. Lecture 2 Observability. Observability, continuous time: Observability, discrete time: = h (2) (x, u, u)
Observability Dynamic Systems Lecture 2 Observability Continuous time model: Discrete time model: ẋ(t) = f (x(t), u(t)), y(t) = h(x(t), u(t)) x(t + 1) = f (x(t), u(t)), y(t) = h(x(t)) Reglerteknik, ISY,
A Step by Step Guide Chris Dew: Clinical Indicators Programme Manager Health and Social Care Information Centre
Mug Quy ug C Quy I, M Db A S by S Gu C Dw: C I Pg Mg H S C If C 1 Ev Cx Sy w g: A w y f g, vg, ug f, ub u Nw uu b bw NHS Eg, Pub H Eg, H S C If C (HSCIC), D f H (DH) Gv A gu vu g Nw guy fu f uy b T Quy
A B C D E F G H I J K
3 5 6 7 8 9 0 3 4 5 6 7 8 9 Cu D. R P P P 3 P 4 P 5 P 6 P 7 M ASHP 33 P C PAP P C PAP AP S AP S P C PAP P C PAP ASHP 3 AP C AB AP C BC AP C AB AP C AB AP C AB AP C AB M ASHP N405, 9 C S I 9 C S I 9 C S
FH6 GENERAL CW CW CHEMISTRY # BMC10-4 1BMC BMC10-5 1BMC10-22 FUTURE. 48 x 22 CART 1BMC10-6 2NHT-14,16,18 36 X x 22.
0 //0 :0: TR -00 A 0-W -00 00-W -00 A 00-W R0- W- & W- U RTAY TA- RAT WT AA TRATR R AT ' R0- B U 0-00 R0- B- B0- B0- R0- R0- R0- R0- B0- R0-0 B0- B0- A. B0- B0- UTR TAT 0-00 R0-,, T R-,,0 0-0 A R- R0-,
Honors Differential Equations
MIT OpenCourseWare http://ocw.mit.edu 18.034 Honors Differential Equations Spring 2009 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms. LECTURE 13. INHOMOGENEOUS
Weak Singular Optimal Controls Subject to State-Control Equality Constraints
Int. Journal of Math. Analysis, Vol. 6, 212, no. 36, 1797-1812 Weak Singular Optimal Controls Subject to State-Control Equality Constraints Javier F Rosenblueth IIMAS UNAM, Universidad Nacional Autónoma
I N A C O M P L E X W O R L D
IS L A M I C E C O N O M I C S I N A C O M P L E X W O R L D E x p l o r a t i o n s i n A g-b eanste d S i m u l a t i o n S a m i A l-s u w a i l e m 1 4 2 9 H 2 0 0 8 I s l a m i c D e v e l o p m e
Marine Harvest Herald
Hv H T u 6-2013. u! u v v u up uu. F u - p u u u u u u pu uu x. W xu u u, u u k, O uu u u v v, u p. T, v u u u, u, k. p, u u u. v v,, G, pp u. W v p pv u x p v u v p. T v x u p u vu. u u v u u k upp, p
68X LOUIE B NUNN PKWYLOUIE B NUNN PKWY NC
B v Lk Wf gmt A Ix p 86 12'W 86 1'W 85 56'W 85 54'W 85 52'W 85 5'W 37 'N 68X Ggw LOI B NNN KWYLOI B NNN KWY N 36 58'N WAN p 1 36 56'N utt' v vt A S p 4 B v Lk Bg Stt Ntu v BAN 36 52'N 36 5'N p 2 Spg B
SYSTEMTEORI - KALMAN FILTER VS LQ CONTROL
SYSTEMTEORI - KALMAN FILTER VS LQ CONTROL 1. Optimal regulator with noisy measurement Consider the following system: ẋ = Ax + Bu + w, x(0) = x 0 where w(t) is white noise with Ew(t) = 0, and x 0 is a stochastic
Flatness Properties of Acts over Commutative, Cancellative Monoids
Wilfrid Laurier University Scholars Commons @ Laurier Mathematics Faculty Publications Mathematics 6-1999 Flatness Properties of Acts over Commutative, Cancellative Monoids Sydney Bulman-Fleming Wilfrid
Winnie flies again. Winnie s Song. hat. A big tall hat Ten long toes A black magic wand A long red nose. nose. She s Winnie Winnie the Witch.
Wnn f gn ht Wnn Song A g t ht Tn ong to A k g wnd A ong d no. no Sh Wnn Wnn th Wth. y t d to A ong k t Bg gn y H go wth Wnn Whn h f. wnd ootk H Wu Wu th t. Ptu Dtony oo hopt oon okt hng gd ho y ktod nh
Problem Set 1. This week. Please read all of Chapter 1 in the Strauss text.
Math 425, Spring 2015 Jerry L. Kazdan Problem Set 1 Due: Thurs. Jan. 22 in class. [Late papers will be accepted until 1:00 PM Friday.] This is rust remover. It is essentially Homework Set 0 with a few
TH THE 997 M EETING OF THE BRODIE CLUB th The 997 meeting of The Brodie Club was held on Nov. 15, R amsay Wright Zoological Laboratories at the Univer
H HE 997 M EENG OF HE RODE CLU 997 m d Cu w d Nv 15, R my W Z L U 2005 Rm 432 C m: K Am S y: Ov w 19 mm d v u R my d P Add d M R, u Ed Add J my Hu, u Dvd Hu J Sdm, u J Yu mu 995 m w ppvd w m R Pwy d d
Jim Lambers MAT 285 Spring Semester Practice Exam 2 Solution. y(t) = 5 2 e t 1 2 e 3t.
. Solve the initial value problem which factors into Jim Lambers MAT 85 Spring Semester 06-7 Practice Exam Solution y + 4y + 3y = 0, y(0) =, y (0) =. λ + 4λ + 3 = 0, (λ + )(λ + 3) = 0. Therefore, the roots
P a g e 5 1 of R e p o r t P B 4 / 0 9
P a g e 5 1 of R e p o r t P B 4 / 0 9 J A R T a l s o c o n c l u d e d t h a t a l t h o u g h t h e i n t e n t o f N e l s o n s r e h a b i l i t a t i o n p l a n i s t o e n h a n c e c o n n e
Dierential Geometry Curves and surfaces Local properties Geometric foundations (critical for visual modeling and computing) Quantitative analysis Algo
Dierential Geometry Curves and surfaces Local properties Geometric foundations (critical for visual modeling and computing) Quantitative analysis Algorithm development Shape control and interrogation Curves
and the ANAVETS Unit Portage Ave, Winnipeg, Manitoba, Canada May 23 to May E L IBSF
t NVET Uit 283 IR FO RE VET ER N N N I MY NVY & R 3584 Pt, Wii, Mitb, IN O RPORTE E IL L I GU VET IF N ENG R H LI E My 23 t My 28-2015 R LE YOUR ONE TOP HOP FOR QULITY POOL UE & ILLIR EORIE GMEROOM 204-783-2666
The Hilltopper-20 a compact 20M CW transceiver. Offered by the 4-State QRP Group
T H-2 m 2M CW v Off 4-S QRP Gu T H-2 Tv KSWL v O 28 u: u v: 4 43 MHz Tu: Hz /2 Hz Tm uu: W m Rv u : x 6 ma Sz: 43 x 39 x 7, 8 z u- k- O--f CW, m m A/B, 8-3 m Ajum: BO m, -m u C u u: Au M SMT P 2: P- D:
MAT292 - Calculus III - Fall Solution for Term Test 2 - November 6, 2014 DO NOT WRITE ON THE QR CODE AT THE TOP OF THE PAGES.
MAT9 - Calculus III - Fall 4 Solution for Term Test - November 6, 4 Time allotted: 9 minutes. Aids permitted: None. Full Name: Last First Student ID: Email: @mail.utoronto.ca Instructions DO NOT WRITE
BUILDER SERIES BALL KNOBSETS
BU B NBT FTU NTT P N Y HN GUNT YWY 5 PN -YB, WT PTY YNG NTUTN YNG () T YNG () FT 1 3 8" T 1 3 4" TH 2 1 1 4" U N JUTB T TH 2 3 8" 2 3 4" BT UTTN PTN FNH # QTY. G B NB N T FNT/B NTY PH B (U3) 36-4410 30
93 Analytical solution of differential equations
1 93 Analytical solution of differential equations 1. Nonlinear differential equation The only kind of nonlinear differential equations that we solve analytically is the so-called separable differential
Handout 30. Optical Processes in Solids and the Dielectric Constant
Haut Otal Sl a th Dlt Ctat I th ltu yu wll la: La ut Ka-Kg lat Dlt tat l Itba a Itaba tbut t th lt tat l C 47 Sg 9 Faha Raa Cll Uty Chag Dl, Dl Mt, a lazat Dty A hag l t a gat a a t hag aat by ta: Q Q
fur \ \,,^N/ D7,,)d.s) 7. The champion and Runner up of the previous year shall be allowed to play directly in final Zone.
OUL O GR SODRY DUTO, ODS,RT,SMTUR,USWR.l ntuctin f cnuct f Kbi ( y/gil)tunent f 2L-Lg t. 2.. 4.. 6. Mtche hll be lye e K ule f ene f tie t tie Dutin f ech tch hll be - +0 (Rece)+ = M The ticint f ech Te
06/12/ rws/jMc- modif SuFY10 (MPF) - Textbook Section IX 1
IV. Continuous-Time Signals & LTI Systems [p. 3] Analog signal definition [p. 4] Periodic signal [p. 5] One-sided signal [p. 6] Finite length signal [p. 7] Impulse function [p. 9] Sampling property [p.11]
Lecture 10: Linear Matrix Inequalities Dr.-Ing. Sudchai Boonto
Dr-Ing Sudchai Boonto Department of Control System and Instrumentation Engineering King Mongkuts Unniversity of Technology Thonburi Thailand Linear Matrix Inequalities A linear matrix inequality (LMI)
Lecture two. January 17, 2019
Lecture two January 17, 2019 We will learn how to solve rst-order linear equations in this lecture. Example 1. 1) Find all solutions satisfy the equation u x (x, y) = 0. 2) Find the solution if we know
Hyperbolic Partial Differential Equations
Hyperbolic Partial Differential Equation Evolution equation aociated with irreverible phyical procee like diffuion heat conduction lead to parabolic partial differential equation. When the equation i a
Second-Order Linear ODEs
Second-Order Linear ODEs A second order ODE is called linear if it can be written as y + p(t)y + q(t)y = r(t). (0.1) It is called homogeneous if r(t) = 0, and nonhomogeneous otherwise. We shall assume
Lecture Notes for Math 251: ODE and PDE. Lecture 13: 3.4 Repeated Roots and Reduction Of Order
Lecture Notes for Math 251: ODE and PDE. Lecture 13: 3.4 Repeated Roots and Reduction Of Order Shawn D. Ryan Spring 2012 1 Repeated Roots of the Characteristic Equation and Reduction of Order Last Time:
MATH107 Vectors and Matrices
School of Mathematics, KSU 20/11/16 Vector valued functions Let D be a set of real numbers D R. A vector-valued functions r with domain D is a correspondence that assigns to each number t in D exactly
Using Hybrid Functions to solve a Coupled System of Fredholm Integro-Differential Equations of the Second Kind
Advances in Dynamical Systems and Applications ISSN 973-532, Volume 9, Number, pp 5 (24) http://campusmstedu/adsa Using Hybrid Functions to solve a Coupled System of Fredholm Integro-Differential Euations
Linear Homogeneous ODEs of the Second Order with Constant Coefficients. Reduction of Order
Linear Homogeneous ODEs of the Second Order with Constant Coefficients. Reduction of Order October 2 6, 2017 Second Order ODEs (cont.) Consider where a, b, and c are real numbers ay +by +cy = 0, (1) Let
MAPPING AND ITS APPLICATIONS. J. Jeyachristy Priskillal 1, P. Thangavelu 2
International Journal of Pure and Applied Mathematics Volume 11 No. 1 017, 177-1 ISSN: 1311-00 (printed version); ISSN: 1314-3395 (on-line version) url: http://www.ijpam.eu doi: 10.173/ijpam.v11i1.14 PAijpam.eu
Sheet Title: Building Renderings M. AS SHOWN Status: A.R.H.P.B. SUBMITTAL August 9, :07 pm
1 2 3 4 5 6 7 8 9 1 11 12 13 14 15 16 17 18 19 orthstar expressly reserves its common law copyright and other property rights for all ideas, provisions and plans represented or indicated by these drawings,
2. Time-Domain Analysis of Continuous- Time Signals and Systems
2. Time-Domain Analysis of Continuous- Time Signals and Systems 2.1. Continuous-Time Impulse Function (1.4.2) 2.2. Convolution Integral (2.2) 2.3. Continuous-Time Impulse Response (2.2) 2.4. Classification
Lecture 2. Classification of Differential Equations and Method of Integrating Factors
Math 245 - Mathematics of Physics and Engineering I Lecture 2. Classification of Differential Equations and Method of Integrating Factors January 11, 2012 Konstantin Zuev (USC) Math 245, Lecture 2 January
6.241 Dynamic Systems and Control
6.241 Dynamic Systems and Control Lecture 24: H2 Synthesis Emilio Frazzoli Aeronautics and Astronautics Massachusetts Institute of Technology May 4, 2011 E. Frazzoli (MIT) Lecture 24: H 2 Synthesis May
University lthcare scholarship,
y s Dv c H p s C c c Sv by S RMH M P yu s A! s Su c c? pusu cuu? b u c A yu b sy H sp, Dv sc S RMH Appy f s: f yu : cku, c b s v Fm y Rc, c Lu R sucu, fmy xu S s m sb c ys P sus - f s: ccmc S y c u c s
Partial Differential Equations, Winter 2015
Partial Differential Equations, Winter 215 Homework #2 Due: Thursday, February 12th, 215 1. (Chapter 2.1) Solve u xx + u xt 2u tt =, u(x, ) = φ(x), u t (x, ) = ψ(x). Hint: Factor the operator as we did
Title. Author(s) 井上, 貴翔. Citation 研究論集, 11: 199( 左 )-212( 左 ) Issue Date Doc URL. Type. File Information
T D F / mm F Au() 井上 貴翔 C 研究論集 11: 199( 左 )-212( 左 ) u D 2011-12-26 D URL :///2115/47879 T bu () F m 11_RONSHU_11_NOUE u u Hkk U C S A D F / mm F K u Summ A b w qu m u U S J u u m O u E u w 1908 u T u
MATH 4B Differential Equations, Fall 2016 Final Exam Study Guide
MATH 4B Differential Equations, Fall 2016 Final Exam Study Guide GENERAL INFORMATION AND FINAL EXAM RULES The exam will have a duration of 3 hours. No extra time will be given. Failing to submit your solutions
Chapter 3: Second Order Equations
Exam 2 Review This review sheet contains this cover page (a checklist of topics from Chapters 3). Following by all the review material posted pertaining to chapter 3 (all combined into one file). Chapter
Cataraqui Source Protection Area Stream Gauge Locations
Cqu u P m Gu s Ts Ez K Ts u s sp E s ms P Ps s m m C Y u u I s Ts x C C u R 4 N p Ds Qu H Em us ms p G Cqu C, s Ks F I s s Gqu u Gqu s N D U ( I T Gqu C s C, 5 Rs p, Rs 15, 7 N m s m Gus - Ps P f P 1,
144 Chapter 3. Second Order Linear Equations
144 Chapter 3. Second Order Linear Equations PROBLEMS In each of Problems 1 through 8 find the general solution of the given differential equation. 1. y + 2y 3y = 0 2. y + 3y + 2y = 0 3. 6y y y = 0 4.
< < or a. * or c w u. "* \, w * r? ««m * * Z * < -4 * if # * « * W * <r? # *» */>* - 2r 2 * j j. # w O <» x <» V X * M <2 * * * *
- W # a a 2T. mj 5 a a s " V l UJ a > M tf U > n &. at M- ~ a f ^ 3 T N - H f Ml fn -> M - M. a w ma a Z a ~ - «2-5 - J «a -J -J Uk. D tm -5. U U # f # -J «vfl \ \ Q f\ \ y; - z «w W ^ z ~ ~ / 5 - - ^
i t 1 v d B & N 1 K 1 P M 1 R & H 1 S o et al., o 1 9 T i w a s b W ( 1 F 9 w s t t p d o c o p T s a s t b ro
Pgm PII: S0042-6989(96)00205-2 VR, V 37, N 6, 705 720,1997 01997 E S L Pd G B 0042-698997$1700+ 000 P M L I B L P S M S E C S W A U O S R E R O 1 f 1 A 1 f fm J 1 A bqu g vy bd z gu u vd mvg z d,, -dg
3 The Life Cycle, Tax Policy,
3 The Life Cycle, Tax Policy, and the Current Account C 1 + I 1 + C 2 + I 2 = Y 1 T 1 + Y 2 T 2. (1) G 1 + G 2 = T 1 + T 2, (2) C 1 + I 1 + C 2 + I 2 = Y 1 G 1 + Y 2 G 2, Foundations of International Macroeconomics
LEVEL 2 ASSESSMENT TASK. WRITING Can write a Personal Response
W f f N Su W S 4 6 Vu A Sybu d f S 4 6 P, Vd d D Im d S 5 6 Vu D Sybu. LEVEL 2 ASSESSMENT TASK ASSESSMENT CONDITIONS Tm d: u 50 mu E d/ Bu d MAY NOT b ud U m f vbuy Gmm d d f m dmb TASK: W k: H D C/A By
n r t d n :4 T P bl D n, l d t z d th tr t. r pd l
n r t d n 20 20 :4 T P bl D n, l d t z d http:.h th tr t. r pd l 2 0 x pt n f t v t, f f d, b th n nd th P r n h h, th r h v n t b n p d f r nt r. Th t v v d pr n, h v r, p n th pl v t r, d b p t r b R
THE SCHOOL DISTRICT OF OSCEOLA COUNTY, FLORIDA
THE HOOL DITIT OF OEOLA OUTY FLOIDA D. DEBA AE UEITEDET 8 B Bu K F 3-9 HOE: (0) 80-00 FAX: (0) 80-00 www.. HOOL BOAD MEMBE J D K 0-93- K D K 0-80-009 T D 3 K 0-3-035 T D K 0-80-009 M T: :00.M. ALL TO ODE
MATH 308 Differential Equations
MATH 308 Differential Equations Summer, 2014, SET 6 JoungDong Kim Set 6: Section 3.3, 3.4, 3.5, 3.6 Section 3.3 Complex Roots of the Characteristic Equation Recall that a second order ODE with constant