Cargo securing in Sweden

Size: px
Start display at page:

Download "Cargo securing in Sweden"

Transcription

1 State of play on national saf fe loading & cargo securing standards in Europe and wor rk of the UN group of experts on the ILO/IMO/U UNECE standard Slagelse, Denmark 6-7 Septem mber 2012 Sven Sökjer-Petersen Managing Director MariTerm AB (c) International Road Transport Union (IRU) 2011

2 Cargo securing in Sweden Agenda: Short presentation of MariTerm AB Overview of current regulations Scientific background to basic cargo securing parameters Comparison of standards and guidelines for cargo securing Use of Quick Lashing Guides Practical tests Vehicle body structures

3 MariTerm AB MariTerm AB: An engineering company Working within the field of transport mainly, with cargo securing for land and sea transports 7 employees Independent privately owned Established in 1978

4 MariTerm AB MariTerm is a Swedish company with office in Höganäs in Sweden.

5 MariTerm AB Cargo securing instructions

6 MariTerm AB Re esearch projects MariTerm AB

7 Overv view of Current Re egulations

8 Current regulations

9 Current regulations VDI 2700

10 Current re egulations Securing of wooden box weighing 10 tons

11 Current re egulations Securing according to North American Cargo Securement Standard

12 Current re egulations Securing according to European Standard (2003)

13 IMO/ILO/UN ECE Guidelines for acking of Cargo Transport Units 1997 (under revision) Current re egulations Model Course EU Best Practice Guidelines on Cargo Securing Cargo Securing Standard EN

14 Scientific ba ackground to basic cargo securing param meters

15 Differences in basic parameters in IMO and CEN 2003 IMO/ILO/UN ECE 1. Static friction factor at top over lashings 2. Total vertical pre-tension from top over lashing: 2 S TF S TF 0.5 g 0.5 S TF S TF µ S EN (2003) 1. Dynamic friction factor (70% of static friction factor) for all types of securing arrangement 2. Total vertical pre-tension for 0.7 µ S top over lashings= 1.5 S TF 3. Sideways acceleration: 0.5 g for sliding and tipping 4. Internal friction between rows are taken into consideration in tipping equation = VDI 2700 (2002) g for sliding 0.7 g for tipping 3. Sideways acceleration: 0.5 g for sliding ( ) = 0.7 g for tipping 4. No instructions for how to consider internal friction between rows in tipping equation.

16 Effect of the differences IMO/ILO/UN ECE EN (2003) 8 top over lashings (One lashing / section) 32 top over lashings 32 top over lashings (Four lashings / section)

17 1. Static or dynamic friction at top- -over lashings

18 Static or dynamic fric ction in combination with top ov ver lashing Tests carried out at Holmen Paper in Norrköping

19 Accelerations obser rved at breaking test Horizontal acc. 4 Vertical acc T i me [ s e c. ]

20 Results of br reaking tests Weight of paper reel: 600 kg Static coefficient of friction: 0.54 Try no. Measured retardation Required pretension with [m/s 2 ] dynamic friction Peak value Mean value [kg] 1 7,3 6, ,7 6, ,3 6, , ,8 7, ,3 7, CONCLUSION: Required pretension with static friction Actual pretension [kg] [kg] [mm] Sliding didn t occurred until the sum of the pre-tension on both sides had been reduced to 250 kg. Thus, static friction should be used in combination with top over lashings, when dimensioning cargo securing arrangements. Sliding

21 2. Pre-tensio on in top-over over lashi ings

22 Total pressure from a top-over over lashing

23

24 Schematic arrangem ment for testing the pre-tensioning ability of ratchets

25 Pre-tension of a ratche et marked S TF = 400 dan Tests carried out in Laholm in Sweden Point on the gearwheel Force on the tensioning side [dan] Force on the other side [dan] Relation between forces [%] Total vertical pressure [dan]

26 3. Transverse e acceleration 0.5, 0.6 or 0.7 g for tipping

27 Side acceleration 0.5 or 0.7 g for tipping Tests carried out at Holmen Paper in Norrköping

28 Accelerations obse erved at turning test Tur ning te s t no Sideways acc. 6 Vertical acc T i me [ s e c ]

29 Required pre-tension n in top over lashing IMO side acceleration 0.5 g 130 kg friction between piles EN side acceleration 0.7 g 1414 kg tensioner on one side 2.27 m 2.0 m

30 Results of tu urning tests Turning tests with the tensioner on the high side Try no. Pretension before test [kg] Pretension after test [kg] Peak side acceleration High side Low side High side Low side [m/s ] Tipping of vehicle, no tipping of reels Tipping of vehicle, no tipping of reels Tipping of vehicle, no tipping of reels Tipping of vehicle, no tipping of reels Turning tests with the tensioner on the low side Try no. Pretension before test [kg] Pretension after test [kg] Peak side acceleration Comment Comment High side Low side High side Low side [m/s ] Tipping of vehicle, no tipping of reels CONCLUSION: A cargo securing arrangement with top-over lashings, designed in accordance with IMO/ILO/UN ECE Guidelines, provide sufficient safety against tipping, whatever side the tensioning device is applied at and even during extreme vehicle operation.

31 4. Internal fric ction between row ws

32 Internal friction between rows Round turn lashings to prevent tipping Rubber to avoid slidin ng

33 Tipping angles for reels Unsecured Round turn lashed Top over lashed Tests carried out at SCA in Sundsvall /19

34 Comparison of standards and gui idelines

35 Cargo Securing Guidelines and standards for cargo securing European Best Practice Guidelines on Cargo Securing for Road Transport IMO/ILO/UN ECE Guidelines for packing of cargo transport units (CTU s) with IMO Model Course 3.18 Standard EN (2003) (Supers seded) Load restraint assemblies on road vehicles Safety Part 1: Calculation of lashing forces Revised Standard EN (2010 0) Load restraining on road vehicles Safety Part 1: Calculation of securing forces

36 Cargo securing Cargo securing guidelines IMO/ILO/UN ECE 2001 EN EN Supersededd by version 2010

37 Differences in parameters in Cargo securing the guidelines and standards Item IMO/ILO/UN ECEE EN :2003 EN :2010 Acceleration coefficients (road transport) - Forward - Sliding sideways - Tipping sideways + Direct lashings + Frictional lashings c x = 1.0 c y = 0.5 c y = 0.5 (F T =LC) c y = 0.5 (F T =S TF ) c x = 0.8 c y = 0.5 c y = 0.7 (F T =LC) c y = 0.7 (F T =S TF ) c x = 0.8 c y = 0.5 c y = 0.6 (F T =LC)* c y = 0.5 (F T =S TF ) or c y = 0.6 (F T =LC/2) Safety factor in calculations of frictional (top over) lashings - Forward - Sideways and backward f s = 1.0 f s = 1.0 f s = 1.0 f s = 1.0 f s = 1.25 f s = 1.1 * For loop lashing F T =LC/2

38 Cargo se ecuring Differences in parameters in the guidelines and standards Item IMO/ILO/UN ECEE EN :2003 EN :2010 Friction factor established by friction test - Frictional lashings Static friction µ s - Direct lashings Dynamic friction µ d = µ s 0.70 Dynamic friction µ d = µ s 0.70 Dynamic friction µ d = µ s 0.70 µ =µ s µ f µ 0.75 < f µ < 1.0 Internal friction Included Not included Included Coefficient of transmission (k-factor) k = 2 k =1.5 k = 2

39 Cargo se ecuring Differences in parameters in the guidelines and standards Item IMO/ILO/UN ECE EN :2003 EN :2010 Some differences in table of friction factors, e.g: - sawn wood against fabric base laminate/plywood - sawn wood against steel sheet - steel crate against fabric base laminate/plywood µ = 0.50 (dry) µ = 0.40 (dry) Not included µ = 0.50 (dry) µ = 0.40 (dry) Not included µ = 0.45 (dry or wet) µ = 0.30 (dry or wet) µ = 0.45 (dry or wet) Verification of the efficiency of securing arrangement by Calculations Static inclining test Calculations Calculations Static inclining test Dynamic driving test (road transport) Lashing protocol Included Not included Included

40 Cargo securin ng example 1 Required number of top-over lashings to prevent sideways sliding Curtain sided trailer, aluminium floor and strong headboard Wooden boxes H Length = 13.6 m Height = 2.55 m Breadth = 2.48 m Web lashings LC = dan = 1.6 tonnes = 16 kn S TF = 400 dan = 0.4 tonnes = 4 kn B Quantity = 8 pieces H B L = m Weight = kg/box Total cargo weight: 24.0 tonnes L Friction between floor and cargo µ = µ static = 0.4

41 Cargo securin ng example 1 Required number of top-over lashings to prevent sideways sliding IMO/ILO/UN ECE EN :2003 EN :2010 EU Best Practice Guidelines - Cargo Securing (p.108) Equation (6) n where ( c y c k µ d z µ d ) m g sinα F T Equation (10) n where ( c y c z µ ) m g 2µ sin α F T f s n = 0.9 m = 3 tons g = 9.81 m/s 2 c y = 0.5 c z = 1.0 µ d = µ s 0.7 = 0.28 (section 6.1) k = 1.5 F T = 0.4 ton 4 kn α = 84.3º Answer n = 3..9 (table 2) (table 2) (section 6.2) m = 3 tons g = 9.81 m/s 2 c y = 0.5 (table 2) c z = 1.0 (table 2) µ = 0.4 (table B.1) α = 84.3º F T = 0.4 ton 4 kn f s = 1.1 n = 1.02

42 Cargo securin ng example 1 Required number of top-over lashings to prevent sideways sliding IMO/ILO/UN ECE EN :203 EN : top over lashings (One lashing / section) Static friction µ s = 0.4 Lashing force F T = S TF K-factor k = 2 Safety factor f s = top over lashings (Four lashings / section) Reasons for the difference: Dynamic friction µ d = 0.7 µ s = 0.28 Lashing force F T = S TF K-factor k = 1.5 Safety factor f s = top over lashings (with supporting beam) Friction factor µ = 0.4 Lashing force F T = S TF K-factor k = 2 Safety factor f s = 1.1

43 Cargo securing example 1 Required number of top-over over lashings to prevent sideways sliding IMO/ILO/UN ECE EN : EN :2010 Rev EN top over lashings 32 top over lashings 9 top 16 topover overlashings lashings (One lashing / section) (Four lashings / section) (with beam) (Two supporting lashing / section). Reasons for the difference: Static friction µs = 0.4 Lashing force FT = STF K-factor k = 2 Safety factor fs = 1.0 Dynamic friction µd = 0.7 µs= 0.28 Lashing force FT = STF K-factor k = 1.5 Safety factor fs = 1.0 Friction factor µ = 0.4 Lashing force FT = STF K-factor k = 2 Safety factor fs = 1.1

44 Cargo securin ng example 2 Required number of top-over lashings to prevent sideways tipping Curtain sided trailer with strong headboard Steel crates H Blocking Side bottom blocking Length = 13.6 m Height = 2.55 m Breadth = 2.48 m Web lashings LC = dan = 1.6 tonnes = 16 kn S TF = 400 dan = 0.4 tonnes = 4 kn B Quantity = 99 pcs in 11 sections Cargo section dimensions: H B L = m Weight = kg/section Total cargo weight: 22.0 tonnes H/B = (2.4/2.4) =1 Number of rows = 3

45 Cargo securin ng example 2 Required number of top-over lashings to prevent sideways tipping IMO/ILO/UN ECE EU Best Practice Guidelines - Cargo Securing (p.108) n = 0.9/section where EN :2003 Equation (11) nf T 1 2 m = 2 tons/section g = 9.81 m/s 2 c y = 0.7 c z = 1.0 h = 2.4 w = 2.4 k = 1.5 m g( c ( k 1) w sinαα (2 k) h cosα F T = 0.4 ton 4 kn α = 90º h c Answer w) (table 2) (table 2) n = 5.4/section y z (section 6.2) EN :2010 Equation (16) m g ( c y d c z b) n f s w FT (sin α ( N 1)) where m = 2 tons/section g = 9.81 m/s 2 c y = 0.5 or 0.6 (table 2) c z = 1.0 (table 2) d = 1.2 b = 0.4 w = 0.8 F T = S TF or LC/2 4 kn or 8kN N = 3 f s = 1.1 α = 90º n = 0.9/section

46 Cargo securing example 2 Required number of top-over over lashings to prevent sideways tipping IMO/ILO/UN ECE EN : EN : top over lashings 66 top over lashings 11 top over lashings (One lashing / section) (Six lashings / section) (One lashing / section) Reasons for the difference: Acceleration factor cy = 0.5 Lashing force FT = STF K-factor k = 2 Safety factor fs = 1.0 Internal friction considered Acceleration factor cy = 0.7 Lashing force FT = STF K-factor k = 1.5 Safety factor fs = 1.0 No instructions for internal friction Acceleration factor cy = 0.5 or cy = 0.6 Lashing force FT = STF or FT = 0.5 LC K-factor k = 2 Safety factor fs = 1.1 Internal friction considered

47 Cargo securin ng example 3 Required number of top-over lashings to prevent sideways sliding and tipping Curtain sided trailer with strong headboard Paper reels H 2 H 1 Length = 13.6 m Height = 2.55 m Breadth = 2.48 m Web lashings LC = dan = 1.6 tonnes = 16 kn S TF = 400 dan = 0.4 tonnes = 4 kn B 1 One layer B 2 Two layers Quantity = 36 reels in 12 sections H B = m / reel Weight = 650 kg / reel Total cargo weight: 23.4 tonnes H 1 /B 1 = (1.3/2.2) 0.6 H 2 /B 2 = (2.6/2.2) 1.2 Number of rows = 2 Static friction between floor and reel and between reels, µ static = 0.5 Friction factor = 0.46 ( )

48 Cargo securin ng example 3 Required number of top-over lashings to prevent sideways sliding IMO/ILO/UN ECE EU Best Practice Guidelines - Cargo Securing (p.108) No sliding Equation (6) n where m 1 = 1.3 tons m 2 = 2.6 tons EN :2003 ( c y c k µ d g = 9.81 m/s 2 c y = 0.5 g = 1.0 g c z z µ sinα F µ d = µ s 0.7 = 0.35 (section 6.1) k = 1.5 F T = 0.4 ton 4 kn α 1 = 85.6º α 2 = 87.8º Answer (one layer) n 1 = 0.91/section n 2 = 1.82/section d ) m g T (two layers) (table 2) (table 2) (section 6.2) n where EN :2010 Equation (10) ( c y cz µ ) m g 2µ sin α F m 1 = 1.3 tons (one layer) m 2 = 2.6 tons T f s (two layers) g = 9.81 m/s 2 c y = 0.5 g (table 2) c z = 1.0 g (table 2) µ = 0.46 (Annex B) α 1 = 85.6º α 2 = 87.8º F T = 0.4 ton 4 kn f s = 1.1 n 1 = 0.16/section n 2 = 0.31/section

49 Cargo securin ng example 3 Required number of top-over lashings to prevent sideways tipping one layer IMO/ILO/UN ECE EN :2003 EN :2010 EU Best Practice Guidelines - Cargo Securing (p.108) Equation (11) nf T where 1 2 m = 1.3 tons/section g = 9.81 m/s 2 c y c z = 0.7 g = 1.0 g h = 1.3 w = 1.1 k = 1.5 m g ( c ( k 1) w sin α (2 k) h cosα F T = 0.4 ton 4 kn α = 85.6º y h c Answer z w) (table 2) (table 2) (section 6.2) Equation (16) m g ( c y d c z b) n w FT (sin α ( N 1)) where m = 1.3 tons/section g = 9.81 m/s 2 c y = 0.5 g or 0.6g (table 2) c y = 1.0 g (table 2) d = 0.65 b = 0.55 w = 1.1 F T = S TF or LC/2 4 kn or 8 kn N = 2 f s = 1.1 α = 85.6º f s No tipping No tipping No tipping

50 Cargo securin ng example 3 Required number of top-over lashings to prevent sideways tipping two layers IMO/ILO/UN ECE EN :2003 EN :2010 EU Best Practice Guidelines - Cargo Securing (p.108) Equation (11) 1 m g( cy h cz w) nf T 2 ( k 1) w sinαα (2 k) h cosα Equation (16) m g ( c y d c z b) n w F (sin α ( N 1)) T f s where m = 2.6 tons/section g = 9.81 m/s 2 c y c z = 0.7 g = 1.0 g h = 2.6 w = 1.1 k = 1.5 F T = 0.4 ton 4 kn α = 87.8º Answer (table 2) (table 2) (section 6.2) where m = 2.6 tons/section g = 9.81 m/s 2 c y = 0.5 g or 0.6g (table 2) c z = 1.0 g (table 2) d = 1.3 b = 0.55 w = 1.1 F T = S TF or LC/2 4 kn or 8 kn N = 2 f s = 1.1 α = 87.8º n 2 = 0.5/section n 2 = 4.6/section n 2 = 0.7/section

51 Cargo securing example 3 Required number of top-over over lashings to prevent sideways sliding and tipping IMO/ILO/UN ECE 9 top over lashings (One lashing / 4 tonnes of cargo to prevent tipping and wandering) EN : EN : top over lashings 10 top over lashings (five lashings/section when loaded in two layers to prevent sliding and tipping, and one lashing/section when loaded in one layer to prevent sliding) (five lashings / six sections loaded in two layers to prevent tipping, and one lashing / 1-2 sections of cargo loaded in one layer to prevent sliding) Reasons for the difference: Static friction µs = 0.5 Acceleration factor cy = 0.5 Lashing force FT = STF K-factor k = 2 Safety factor fs = 1.0 Internal friction considered Dynamic friction µd = 0.7 µs= 0.35 Acceleration factor cy = 0.5 (sliding) and cy = 0.7 (tipping) Lashing force FT = STF K-factor k = 1.5 Safety factor fs = 1.0 No instructions for internal friction Friction factor µ = 0.46 Acceleration factor cy = 0.5 or cy = 0.6 Lashing force FT = STF or FT = 0.5 LC K-factor k = 2 Safety factor fs= 1.1 Internal friction considered

52 Cargo securin ng example 4 Required number of top-over lashings to prevent sideways sliding and tipping Truck with plyfa floor Heat exchanger with steel feet H h l Length = 8. m Height = 2.55 m Breadth = 2.48 m Breadth between lashing points = 2.36 m Web lashings LC = dan = 1.6 tonnes = 16 kn S TF = 400 dan = 0.4 tonnes = 4 kn b B L The heat exchanger is blocked in forward direction. H B L = m Centre of gravity: h b l = m Weight = 2000 kg = 2 tonnes h/b= (1.35/0.45) = 3.0 Number of rows = 1 Static friction µ static = 0.4 and friction factor µ = 0.45

53 Cargo securin ng example 4 Required number of top-over lashings to prevent sideways sliding IMO/ILO/UN ECE EU Best Practice Guidelines - Cargo Securing (p.108) Equation (6) where n m = 2 tons EN :2003 ( c y c k µ d g = 9.81 m/s 2 c y = 0.5 g c z = 1.0 g z µ sinα F µ d = µ s 0.7 = 0.28 (section 6.1) k = 1.5 F T = 0.4 ton 4 kn α = 70º d ) m g T (table 2) (table 2) (section 6.2) n where EN :2010 Equation (10) ( c y cz µ ) m g 2µ sin α F m = 2 tons g = 9.81 m/s 2 c y = 0.5 g (table 2) c z = 1.0 g (table 2) µ = 0.45 (Annex B) α = 70º F T = 0.4 ton 4 kn f s = 1.1 T f s n = 0.6 Answer n = 2.7 n = 0.3

54 Required number of top-over lashings to prevent sideways tipping IMO/ILO/UN ECE EU Best Practice Guidelines - Cargo Securing (p.108) Cargo securin ng example 4 where m = 2 tons EN :2003 Equation (11) modified for centre of gravity off centre m g ( cy d cz b) nf T ( k 1) w sin α (2 k) h cosα g = 9.81 m/s 2 c y c z = 0.7 g = 1.0 g d = 1.35 b = 0.45 h = 2.0 w = 0.9 k = 1.5 F T = 0.4 ton = 4 kn α = 70º Answer (table 2) (table 2) (section 6.2) EN :2010 Equation (16) m g ( c y d c z b) n where w F (sin α ( N 1)) m = 2 tons/section g = 9.81 m/s 2 c y = 0.5 g or 0.6g (table 2) c z = 1.0 g (table 2) n = 1.25 n = 30.0 n = 1.9 T d = 1.35 b = 0.45 w = 0.9 F T = S TF or LC/2 = 4 kn or 6.5kN N = 2 f s = 1.1 α = 70º f s

55 Cargo securin ng example 4 Required number of top-over lashings to prevent sideways sliding and tipping IMO/ILO/UN ECE EN :2003 EN : top over lashings 30 top ove er lashings 2 top over lashings Static friction µ s = 0.4 Acceleration factor c y = 0.5 Lashing force F T = S TF K-factor k = 2 Safety factor f s = 1.0 Reasons for the difference: Dynamic friction µ d = 0.7 µ s = 0.28 Acceleration factor c y = 0.5 (sliding) and c y = 0.7 (tipping) Lashing force F T = S TF K-factor 1.5 Safety factor f s = 1.0 Friction factor µ = 0.45 Acceleration factor c y = 0.5 or c y = 0.6 Lashing force F T = S TF or F T = 0.5 LC K-factor k = 2 Safety factor f s = 1.1

56 Cargo securing according to IMO Weight of box 2 ton

57 Cargo securing according to EN 2003 Weight of box 2 ton

58 Cargo securing according to EN 2010 Weight of box 2 ton

59 Cargo securing acco ording to EN Photo of the month for January 2009 Weight of beams 24 ton

60 Cargo secu uring level SAFE IS ENOUGH! SAFE AND RATIONAL! IMO/ILO/UN ECE EN EN

61 Number of Top-Over lashings to prevent sliding Sideways IMO/ILO/ IMO/ILO IMO/ILO/ µ UN ECE UN ECEE UN ECE ,05 100% 204% 110% 100% 0,10 100% 212% 110% 100% 0,15 100% 223% 110% 100% 0,20 100% 237% 110% 100% 0,25 100% 256% 110% 100% Cargo securing Comparison between the different guidelines for road transport 0,30 100% 286% 110% 100% 0,35 100% 335% 110% 100% 0,40 100% 434% 110% 100% 0,45 100% 730% 110% 100% 0,50 100% 0,55 100% 0,60 No sliding 100% 0,65 100% 0,70 100% 0,75 100% Forward Backwards 200% 99% 100% 204% 110% 204% 97% 100% 212% 110% 208% 96% 100% 223% 110% 212% 94% 100% 237% 110% 217% 92% 100% 256% 110% 223% 89% 100% 286% 110% 229% 87% 100% 335% 110% 237% 83% 100% 434% 110% 246% 80% 100% 730% 110% 256% 75% 270% 69% 286% 63% No sliding 307% 54% 335% 42% 375% 25%

62 Level of carg go securing Applicable for top-over lashings EN (2003 3) VDI 2700 part 2 German national standard EN (2010 0) IMO Model Cours se 3.18 Swedish rules No cargo secur ring

63 Level of carg go securing Applicable for top-over lashings EN (2003 3) VDI 2700 part 2: :2002 German national standard EN (2010 0) IMO Model Cours se 3.18 Swedish rules No cargo secur ring

64 Quick Lashing Guides

65 MariTerm AB in House Training Volvo CE in Arvika

66 MariTerm AB Carg go securing training Cargo securing training in Pusan for IMO (International Maritime Organisation)

67 Cargo securing Quick Lashing Guides

68 Cargo securing ins spections in Sweden Cargo securing is inspected against the Quick Lashing Guide

69 Cargo securing Quick Lashing Guides

70 Practical al tests

71 Practica al tests Dynamic driving tests carried out by DEKRA

72 Practical inclination tests

73 Theory behin nd the tests Basic design requirement: Practical inclination test: S = m (a h - µ a v ) S = m (sin α - µ cos α) The support S shall be equal in basic design and test and thus: m (a h -µ a v ) = m (sin α -µ cos α)

74 Practical incl lination tests Inclination α [ ] α Practical tests Practical tests can be worked out for determining the coefficient of friction for different types of combined materials, in purpose of controlling the function of the lashing arrangement. Sideways Functionality of lashing arrangement ,2 0,3 0,4 0,5 0,6 0,7 0,8 0,9 Current coefficient of friction, µ Road, the Baltic Sea 2 The North Sea 3 Unrestricted area Forwards and backwards 4 The Baltic Sea 5 The North Sea 6 Unrestricted area 7 Forwards road transport 8 Backwards road transport

75 Practical incl lination tests Practical tests in longitudinal and transverse direction with a truck crane loaded onto a container flat rack for road and sea transport

76 Practical incl lination tests Practical tests with chemicals in bags

77 Practical incl lination tests Practical tests lengthways and sideways with a Volvo XC 90

78 Vehicle e body struct tures

79 Cargo Transport Units Different types of vehicle body structures Open type Cover stake type Box type Curtainsider Box type with side doors

80 Curtain nsiders Cargo shifting in curtainsiders

81 Curtain nsiders Marking according to EN 12642

82 Curtainsiders

83 Curtainsiders

84 Curtainsiders

85 Thanks for yo our attention! riterm.se

INF.7. Economic Commission for Europe Inland Transport Committee. Working Party on the Transport of Dangerous Goods 23 July 2012

INF.7. Economic Commission for Europe Inland Transport Committee. Working Party on the Transport of Dangerous Goods 23 July 2012 Economic Commission for Europe Inland Transport Committee Working Party on the Transport of Dangerous Goods 23 July 2012 Joint Meeting of the RID Committee of Experts and the Working Party on the Transport

More information

CARGO STOWAGE AND SECURING

CARGO STOWAGE AND SECURING Resolutions from the 17th Session of the Assembly of IMO, November 1991, as amended CODE OF SAFE PRACTICE FOR CARGO STOWAGE AND SECURING CARGO STOWAGE AND SECURING ANNEX 13. Til bruk i maritime fagskoler

More information

# x = v f + v & % ( t x = v

# x = v f + v & % ( t x = v Name: Physics Chapter 4 Study Guide ----------------------------------------------------------------------------------------------------- Useful Information: F = ma µ = F fric a = v f " v i t # x = v f

More information

Seminar Container Securing on Container Vessels Part 1. May 11, 2012 Portoroz

Seminar Container Securing on Container Vessels Part 1. May 11, 2012 Portoroz Seminar Container Securing on Container Vessels Part 1 University of Ljubljana May 11, 2012 Portoroz Why pay keen attention to container securing? Forces acting on container stack Wind load (only for wind

More information

Friction (static & Kinetic) Review

Friction (static & Kinetic) Review Friction (static & Kinetic) Review 1. Sand is often placed on an icy road because the sand A) decreases the coefficient of friction between the tires of a car and the road B) increases the coefficient

More information

Dynamics-Friction. 1. Which vector diagram best represents a cart slowing down as it travels to the right on a horizontal surface?

Dynamics-Friction. 1. Which vector diagram best represents a cart slowing down as it travels to the right on a horizontal surface? 1. Which vector diagram best represents a cart slowing down as it travels to the right on a horizontal surface? Base your answers to questions 2 and 3 on the information A student and the waxed skis she

More information

4.0 m s 2. 2 A submarine descends vertically at constant velocity. The three forces acting on the submarine are viscous drag, upthrust and weight.

4.0 m s 2. 2 A submarine descends vertically at constant velocity. The three forces acting on the submarine are viscous drag, upthrust and weight. 1 1 wooden block of mass 0.60 kg is on a rough horizontal surface. force of 12 N is applied to the block and it accelerates at 4.0 m s 2. wooden block 4.0 m s 2 12 N hat is the magnitude of the frictional

More information

MEI Mechanics 1. Applying Newton s second law along a line

MEI Mechanics 1. Applying Newton s second law along a line MEI Mechanics 1 Applying Newton s second law along a line Chapter assessment 1. (a) The following two questions are about the motion of a car of mass 1500 kg, travelling along a straight, horizontal road.

More information

Physics 6A TR Section Winter 2012 Midterm

Physics 6A TR Section Winter 2012 Midterm Physics 6A TR Section Winter 2012 Midterm The test consists of 19 multiple choice questions. Enter the answer to the multiple choice questions in the pink scantron sheet. Use a pencil, not a pen. There

More information

5. Two forces are applied to a 2.0-kilogram block on a frictionless horizontal surface, as shown in the diagram below.

5. Two forces are applied to a 2.0-kilogram block on a frictionless horizontal surface, as shown in the diagram below. 1. The greatest increase in the inertia of an object would be produced by increasing the A) mass of the object from 1.0 kg to 2.0 kg B) net force applied to the object from 1.0 N to 2.0 N C) time that

More information

ASSOCIATE DEGREE IN ENGINEERING EXAMINATIONS SEMESTER /13

ASSOCIATE DEGREE IN ENGINEERING EXAMINATIONS SEMESTER /13 ASSOCIATE DEGREE IN ENGINEERING EXAMINATIONS SEMESTER 2 2012/13 COURSE NAME: ENGINEERING MECHANICS - STATICS CODE: ENG 2008 GROUP: AD ENG II DATE: May 2013 TIME: DURATION: 2 HOURS INSTRUCTIONS: 1. This

More information

4. The diagram below shows a 4.0-kilogram object accelerating at 10. meters per second 2 on a rough horizontal surface.

4. The diagram below shows a 4.0-kilogram object accelerating at 10. meters per second 2 on a rough horizontal surface. 1. An 8.0-newton wooden block slides across a horizontal wooden floor at constant velocity. What is the magnitude of the force of kinetic friction between the block and the floor? A) 2.4 N B) 3.4 N C)

More information

University Physics (Prof. David Flory) Chapt_06 Saturday, October 06, 2007 Page 1

University Physics (Prof. David Flory) Chapt_06 Saturday, October 06, 2007 Page 1 University Physics (Prof. David Flory) Chapt_06 Saturday, October 06, 2007 Page 1 Name: Date: 1. A crate resting on a rough horizontal floor is to be moved horizontally. The coefficient of static friction

More information

Consider the case of a 100 N. mass on a horizontal surface as shown below:

Consider the case of a 100 N. mass on a horizontal surface as shown below: 1.9.1 Introduction The study of friction is called: The force of friction is defined as: The force of friction acting between two surfaces has three properties: i) ii) iii) Consider the case of a 100 N.

More information

LECTURE 11 FRICTION AND DRAG

LECTURE 11 FRICTION AND DRAG LECTURE 11 FRICTION AND DRAG 5.5 Friction Static friction Kinetic friction 5.6 Drag Terminal speed Penguins travel on ice for miles by sliding on ice, made possible by small frictional force between their

More information

Newton s Laws Student Success Sheets (SSS)

Newton s Laws Student Success Sheets (SSS) --- Newton s Laws unit student success sheets--- Page 1 Newton s Laws Student Success Sheets (SSS) HS-PS2-1 HS-PS2-2 NGSS Civic Memorial High School - Physics Concept # What we will be learning Mandatory

More information

Forces. 3. The graph given shows the weight of three objects on planet X as a function of their mass. A. 0 N. B. between 0 N and 12 N C.

Forces. 3. The graph given shows the weight of three objects on planet X as a function of their mass. A. 0 N. B. between 0 N and 12 N C. Name: Date: 1. When a 12-newton horizontal force is applied to a box on a horizontal tabletop, the box remains at rest. The force of static friction acting on the box is 3. The graph given shows the weight

More information

B x. B cos B. B sin B 0 N 64 N 64 N (47 N) 79 N

B x. B cos B. B sin B 0 N 64 N 64 N (47 N) 79 N 85. What is the net force acting on the ring in Figure 5-18? Figure 5-18 R 2 A 2 B 2 R A 2 B 2 (5. N) 2 (4. N) 2 64.3 N tan A B tan 1 A B tan 1 5. 4. 51.34 from B The net force is 64.3 N at 51.34 86. What

More information

Review: Advanced Applications of Newton's Laws

Review: Advanced Applications of Newton's Laws Review: Advanced Applications of Newton's Laws 1. The free-body diagram of a wagon being pulled along a horizontal surface is best represented by a. A d. D b. B e. E c. C 2. The free-body diagram of a

More information

LECTURE 9 FRICTION & SPRINGS. Instructor: Kazumi Tolich

LECTURE 9 FRICTION & SPRINGS. Instructor: Kazumi Tolich LECTURE 9 FRICTION & SPRINGS Instructor: Kazumi Tolich Lecture 9 2 Reading chapter 6-1 to 6-2 Friction n Static friction n Kinetic friction Springs Static friction 3 Static friction is the frictional force

More information

LECTURE 12 FRICTION & SPRINGS. Instructor: Kazumi Tolich

LECTURE 12 FRICTION & SPRINGS. Instructor: Kazumi Tolich LECTURE 12 FRICTION & SPRINGS Instructor: Kazumi Tolich Lecture 12 2 Reading chapter 6-1 to 6-2 Friction n Static friction n Kinetic friction Springs Origin of friction 3 The origin of friction is electromagnetic

More information

Here is what you will be able to do when you complete each objective: 1. State the general laws of static and kinetic friction.

Here is what you will be able to do when you complete each objective: 1. State the general laws of static and kinetic friction. Friction I Learning Outcome When you complete this module you will be able to: Describe and solve problems involving friction. Learning Objectives Here is what you will be able to do when you complete

More information

Today we applied our knowledge of vectors to different kinds of problems.

Today we applied our knowledge of vectors to different kinds of problems. DAY 18 Summary of Primary Topics Covered Center of Mass and More Vector Examples Today we applied our knowledge of vectors to different kinds of problems. Working these problems is a matter of taking concepts

More information

Advanced/Advanced Subsidiary. You must have: Mathematical Formulae and Statistical Tables (Blue)

Advanced/Advanced Subsidiary. You must have: Mathematical Formulae and Statistical Tables (Blue) Write your name here Surname Other names Pearson Edexcel International Advanced Level Centre Number Mechanics M1 Advanced/Advanced Subsidiary Candidate Number Monday 25 January 2016 Afternoon Time: 1 hour

More information

Every object remains in a state of rest or move with constant velocity in a straight line unless forces acts on it to change that state

Every object remains in a state of rest or move with constant velocity in a straight line unless forces acts on it to change that state " NEWONʼS LAW OF MOION NEWONʼS FIRS LAW Newtonʼs First Law of Motion states that: Every object remains in a state of rest or move with constant velocity in a straight line unless forces acts on it to change

More information

Advanced/Advanced Subsidiary. You must have: Mathematical Formulae and Statistical Tables (Blue)

Advanced/Advanced Subsidiary. You must have: Mathematical Formulae and Statistical Tables (Blue) Write your name here Surname Other names Pearson Edexcel International Advanced Level Centre Number Mechanics M1 Advanced/Advanced Subsidiary Candidate Number Monday 25 January 2016 Afternoon Time: 1 hour

More information

2. Mass, Force and Acceleration

2. Mass, Force and Acceleration . Mass, Force and Acceleration [This material relates predominantly to modules ELP034, ELP035].1 ewton s first law of motion. ewton s second law of motion.3 ewton s third law of motion.4 Friction.5 Circular

More information

3. A piece of candy is accelerated at 3.0 m/s 2 in the direction shown by a, over a frictionless horizontal surface. The acceleration is caused by 3

3. A piece of candy is accelerated at 3.0 m/s 2 in the direction shown by a, over a frictionless horizontal surface. The acceleration is caused by 3 3. A piece of candy is accelerated at 3.0 m/s 2 in the direction shown by a, over a frictionless horizontal surface. The acceleration is caused by 3 forces, 2 of which are shown. F 1 has a magnitude of

More information

WS-CH-4 Motion and Force Show all your work and equations used. Isaac Newton ( )

WS-CH-4 Motion and Force Show all your work and equations used. Isaac Newton ( ) AP PHYSICS 1 WS-CH-4 Motion and Force Show all your work and equations used. Isaac Newton (1643-1727) Isaac Newton was the greatest English mathematician of his generation. He laid the foundation for differential

More information

Quiz #8. Vector. 2) Given A( 1, 4, 3), and B( 3, 4, 1), calculate A B

Quiz #8. Vector. 2) Given A( 1, 4, 3), and B( 3, 4, 1), calculate A B Quiz #8 Vector 1) Given A(1, 2), and B( 3, 4), calculate A B 2) Given A( 1, 4, 3), and B( 3, 4, 1), calculate A B 3) Given the following magnitude of forces in Figure 1: α = 20, θ = 60, β = 30, F 1 = 1N,

More information

I. AXN/RXN W.S. In the example below, the action-reaction pair is shown by the arrows (vectors), and the action-reaction described in words.

I. AXN/RXN W.S. In the example below, the action-reaction pair is shown by the arrows (vectors), and the action-reaction described in words. I. AXN/RXN W.S. In the example below, the action-reaction pair is shown by the arrows (vectors), and the action-reaction described in words. 1. For the remaining situations, discuss with your neighbor

More information

The box is pushed by a force of magnitude 100 N which acts at an angle of 30 with the floor, as shown in the diagram above.

The box is pushed by a force of magnitude 100 N which acts at an angle of 30 with the floor, as shown in the diagram above. 1. A small box is pushed along a floor. The floor is modelled as a rough horizontal plane and the 1 box is modelled as a particle. The coefficient of friction between the box and the floor is. 2 The box

More information

Dynamics Review Checklist

Dynamics Review Checklist Dynamics Review Checklist Newton s Laws 2.1.1 Explain Newton s 1 st Law (the Law of Inertia) and the relationship between mass and inertia. Which of the following has the greatest amount of inertia? (a)

More information

2D - STRIP ANCHOR LIFTING SYSTEM

2D - STRIP ANCHOR LIFTING SYSTEM 2D - STRIP ANCHOR LIFTING SYSTEM WWW.TERWA.COM Terwa reserves the right to make changes to the documentation at any time Page 1 OVERVIEW LIFTING CLUTCHES AND TRANSPORT ANCHOR SA-B SA-ST SA-TTU UNIVERSAL

More information

2. A 10 kg box is being pushed by a 100 N force 30 above the horizontal. The acceleration of the box is 5 m/s 2. What is the value of µ k?

2. A 10 kg box is being pushed by a 100 N force 30 above the horizontal. The acceleration of the box is 5 m/s 2. What is the value of µ k? Physics Whiteboard Forces with Friction 1. A 70 kg block is being pushed across a tabletop with a constant force of 350 N exerted in the direction of travel. If the coefficient of kinetic friction (µ k

More information

Dynamics Review Checklist

Dynamics Review Checklist Dynamics Review Checklist Newton s Laws 2.1.1 Explain Newton s 1 st Law (the Law of Inertia) and the relationship between mass and inertia. Which of the following has the greatest amount of inertia? (a)

More information

Chapter 4. Table of Contents. Section 1 Changes in Motion. Section 2 Newton's First Law. Section 3 Newton's Second and Third Laws

Chapter 4. Table of Contents. Section 1 Changes in Motion. Section 2 Newton's First Law. Section 3 Newton's Second and Third Laws Forces and the Laws of Motion Table of Contents Section 1 Changes in Motion Section 2 Newton's First Law Section 3 Newton's Second and Third Laws Section 4 Everyday Forces Section 1 Changes in Motion Objectives

More information

Newton s 3 rd Law. Book page 48-49

Newton s 3 rd Law. Book page 48-49 Newton s 3 rd Law Book page 48-49 14/9/2016 cgrahamphysics.com 2016 Newton s 2 nd Law problem Newton s second law does not always work: - does not work when applied to atoms and molecules - does not work

More information

Statics Chapter II Fall 2018 Exercises Corresponding to Sections 2.1, 2.2, and 2.3

Statics Chapter II Fall 2018 Exercises Corresponding to Sections 2.1, 2.2, and 2.3 Statics Chapter II Fall 2018 Exercises Corresponding to Sections 2.1, 2.2, and 2.3 2 3 Determine the magnitude of the resultant force FR = F1 + F2 and its direction, measured counterclockwise from the

More information

*************************************************************************

************************************************************************* Your Name: TEST #2 Print clearly. On the Scantron, fill out your student ID, leaving the first column empty and starting in the second column. Also write your name, class time (11:30 or 12:30), and Test

More information

Name Period Date. Record all givens, draw a picture, arrow all vectors, write the formula, substitute and solve. units

Name Period Date. Record all givens, draw a picture, arrow all vectors, write the formula, substitute and solve. units Example Problems 5.2 Friction E1. A monkey is dragging a box full of books from his office to his car. The combined weight of the box and books is 134 N. If the coefficient of static friction between the

More information

Application nr. 7 (Connections) Strength of bolted connections to EN (Eurocode 3, Part 1.8)

Application nr. 7 (Connections) Strength of bolted connections to EN (Eurocode 3, Part 1.8) Application nr. 7 (Connections) Strength of bolted connections to EN 1993-1-8 (Eurocode 3, Part 1.8) PART 1: Bolted shear connection (Category A bearing type, to EN1993-1-8) Structural element Tension

More information

3. The diagram shows two bowling balls, A and B, each having a mass of 7.00 kilograms, placed 2.00 meters apart.

3. The diagram shows two bowling balls, A and B, each having a mass of 7.00 kilograms, placed 2.00 meters apart. 1. Which statement describes the gravitational force and the electrostatic force between two charged particles? A) The gravitational force may be either attractive or repulsive, whereas the electrostatic

More information

Last-night s Midterm Test. Last-night s Midterm Test. PHY131H1F - Class 10 Today, Chapter 6: Equilibrium Mass, Weight, Gravity

Last-night s Midterm Test. Last-night s Midterm Test. PHY131H1F - Class 10 Today, Chapter 6: Equilibrium Mass, Weight, Gravity PHY131H1F - Class 10 Today, Chapter 6: Equilibrium Mass, Weight, Gravity Clicker Question 1 Which of the following objects described below is in dynamic equilibrium? A. A 100 kg barbell is held at rest

More information

There are two main types of friction:

There are two main types of friction: Section 4.15: Friction Friction is needed to move. Without friction, a car would sit in one spot spinning its tires, and a person would not be able to step forward. However, the motion of an object along

More information

2016 ENGINEERING MECHANICS

2016 ENGINEERING MECHANICS Set No 1 I B. Tech I Semester Regular Examinations, Dec 2016 ENGINEERING MECHANICS (Com. to AE, AME, BOT, CHEM, CE, EEE, ME, MTE, MM, PCE, PE) Time: 3 hours Max. Marks: 70 Question Paper Consists of Part-A

More information

Newton s Laws Pre-Test

Newton s Laws Pre-Test Newton s Laws Pre-Test 1.) Consider the following two statements and then select the option below that is correct. (i) It is possible for an object move in the absence of forces acting on the object. (ii)

More information

Physics 12. Unit 5 Circular Motion and Gravitation Part 1

Physics 12. Unit 5 Circular Motion and Gravitation Part 1 Physics 12 Unit 5 Circular Motion and Gravitation Part 1 1. Nonlinear motions According to the Newton s first law, an object remains its tendency of motion as long as there is no external force acting

More information

Review of Lectures 1, 2 and 3

Review of Lectures 1, 2 and 3 Physics 22000 General Physics Lecture 5 Applying Newton s Laws Fall 2016 Semester Prof. Matthew Jones 1 Review of Lectures 1, 2 and 3 Algebraic description of linear motion with constant acceleration:

More information

Physics 101. Hour Exam I Spring Last Name: First Name Network-ID Discussion Section: Discussion TA Name:

Physics 101. Hour Exam I Spring Last Name: First Name Network-ID Discussion Section: Discussion TA Name: Last Name: First Name Network-ID Discussion Section: Discussion TA Name: Instructions Turn off your cell phone and put it away. Calculators may not be shared. Please keep your calculator on your own desk.

More information

Practice Problems from Chapters 11-13, for Midterm 2. Physics 11a Fall 2010

Practice Problems from Chapters 11-13, for Midterm 2. Physics 11a Fall 2010 Practice Problems from Chapters 11-13, for Midterm 2. Physics 11a Fall 2010 Chapter 11 1. The Ferris wheel shown below is turning at constant speed. Draw and label free-body diagrams showing the forces

More information

Sample Final Exam 02 Physics 106 (Answers on last page)

Sample Final Exam 02 Physics 106 (Answers on last page) Sample Final Exam 02 Physics 106 (Answers on last page) Name (Print): 4 Digit ID: Section: Instructions: 1. There are 30 multiple choice questions on the test. There is no penalty for guessing, so you

More information

Name Period Date. Record all givens, draw a picture, arrow all vectors, write the formula, substitute and solve. units

Name Period Date. Record all givens, draw a picture, arrow all vectors, write the formula, substitute and solve. units Example Problems 5.1 Force and Acceleration E1. A monkey pushes his pet lemur in a wagon with a net force of 38 N. If the mass of the lemur and wagon combined is 57 kg, calculate the acceleration of the

More information

Coplanar Concurrent Forces 7) Find magnitude and direction of the resultant force of the force system as shown in

Coplanar Concurrent Forces 7) Find magnitude and direction of the resultant force of the force system as shown in ALPHA COLLEGE OF ENGINEERING & TECHNOLOGY SUBJECT: Engineering Mechanics(3300008) Introduction 1) Define the terms. (WINTER 2013) [1] Kinematics [2] Freebody diagram [3] Equilibrunt [4] Couple [5] Limiting

More information

Lecture III. Introduction to Mechanics, Heat, and Sound /FIC 318

Lecture III. Introduction to Mechanics, Heat, and Sound /FIC 318 Introduction to Mechanics, Heat, and Sound /FIC 318 Lecture III Motion in two dimensions projectile motion The Laws of Motion Forces, Newton s first law Inertia, Newton s second law Newton s third law

More information

Physics 8 Monday, October 12, 2015

Physics 8 Monday, October 12, 2015 Physics 8 Monday, October 12, 2015 HW5 will be due Friday. (HW5 is just Ch9 and Ch10 problems.) You re reading Chapter 12 ( torque ) this week, even though in class we re just finishing Ch10 / starting

More information

Dynamics Review Checklist

Dynamics Review Checklist Dynamics Review Checklist Newton s Laws 2.1.1 Explain Newton s 1 st Law (the Law of Inertia) and the relationship between mass and inertia. Which of the following has the greatest amount of inertia? (a)

More information

AP Physics 1 Multiple Choice Questions - Chapter 4

AP Physics 1 Multiple Choice Questions - Chapter 4 1 Which of ewton's Three Laws of Motion is best expressed by the equation F=ma? a ewton's First Law b ewton's Second Law c ewton's Third Law d one of the above 4.1 2 A person is running on a track. Which

More information

Physics 218 Exam II. Spring 2017 (all sections) March 20 th, 2017

Physics 218 Exam II. Spring 2017 (all sections) March 20 th, 2017 Physics 218 Exam II Spring 2017 (all sections) March 20 th, 2017 Rules of the exam: Please fill out the information and read the instructions below, but do not open the exam until told to do so. 1. You

More information

International Conference KNOWLEDGE-BASED ORGANIZATION Vol. XXIII No CARGO SECURING DURING TRANSPORTATION USING EXTREME VALUES

International Conference KNOWLEDGE-BASED ORGANIZATION Vol. XXIII No CARGO SECURING DURING TRANSPORTATION USING EXTREME VALUES International Conference KNOWLEDGE-BASED ORGANIZATION Vol. XXIII No 3 017 CARGO SECURING DURING TRANSPORTATION USING EXTREME VALUES Martin VLKOVSKÝ*, Luděk RAK*, Balázs TAKSÁS** * University of Defence,

More information

1. A sphere with a radius of 1.7 cm has a volume of: A) m 3 B) m 3 C) m 3 D) 0.11 m 3 E) 21 m 3

1. A sphere with a radius of 1.7 cm has a volume of: A) m 3 B) m 3 C) m 3 D) 0.11 m 3 E) 21 m 3 1. A sphere with a radius of 1.7 cm has a volume of: A) 2.1 10 5 m 3 B) 9.1 10 4 m 3 C) 3.6 10 3 m 3 D) 0.11 m 3 E) 21 m 3 2. A 25-N crate slides down a frictionless incline that is 25 above the horizontal.

More information

DESIGN, DEVELOPMENT, AND COMMISSIONING OF A 120 kn DEADWEIGHT FORCE STANDARD MACHINE

DESIGN, DEVELOPMENT, AND COMMISSIONING OF A 120 kn DEADWEIGHT FORCE STANDARD MACHINE DESIGN, DEVELOPMENT, AND COMMISSIONING OF A 120 kn DEADWEIGHT FORCE STANDARD MACHINE Andy Knott National Physical Laboratory, United Kingdom ABSTRACT This paper describes the development of a 120 kn deadweight

More information

Circular motion minutes. 62 marks. theonlinephysicstutor.com. facebook.com/theonlinephysicstutor Page 1 of 22. Name: Class: Date: Time: Marks:

Circular motion minutes. 62 marks. theonlinephysicstutor.com. facebook.com/theonlinephysicstutor Page 1 of 22. Name: Class: Date: Time: Marks: Circular motion 2 Name: Class: Date: Time: 67 minutes Marks: 62 marks Comments: Page 1 of 22 1 A lead ball of mass 0.25 kg is swung round on the end of a string so that the ball moves in a horizontal circle

More information

Name. ME 270 Fall 2005 Final Exam PROBLEM NO. 1. Given: A distributed load is applied to the top link which is, in turn, supported by link AC.

Name. ME 270 Fall 2005 Final Exam PROBLEM NO. 1. Given: A distributed load is applied to the top link which is, in turn, supported by link AC. Name ME 270 Fall 2005 Final Exam PROBLEM NO. 1 Given: A distributed load is applied to the top link which is, in turn, supported by link AC. Find: a) Draw a free body diagram of link BCDE and one of link

More information

SEE the list given for chapter 04 where Newton s laws were introduced.

SEE the list given for chapter 04 where Newton s laws were introduced. PH2213 : Examples from Chapter 5 : Applying Newton s Laws Key Concepts Newton s Laws (basically Σ F = m a ) allow us to relate the forces acting on an object (left-hand side) to the motion of the object,

More information

What factors affect friction?

What factors affect friction? Friction What factors affect friction? What factors affect friction? Survey says: Surface texture Surface material Surface area Speed of slide Mass Weight Angle of surface Normal Force What really affects

More information

Exam 2--PHYS 101--F17

Exam 2--PHYS 101--F17 Name: Exam 2--PHYS 0--F7 Multiple Choice Identify the choice that best completes the statement or answers the question.. A ball is thrown in the air at an angle of 30 to the ground, with an initial speed

More information

66 Chapter 6: FORCE AND MOTION II

66 Chapter 6: FORCE AND MOTION II Chapter 6: FORCE AND MOTION II 1 A brick slides on a horizontal surface Which of the following will increase the magnitude of the frictional force on it? A Putting a second brick on top B Decreasing the

More information

Physics 8 Wednesday, October 19, Troublesome questions for HW4 (5 or more people got 0 or 1 points on them): 1, 14, 15, 16, 17, 18, 19. Yikes!

Physics 8 Wednesday, October 19, Troublesome questions for HW4 (5 or more people got 0 or 1 points on them): 1, 14, 15, 16, 17, 18, 19. Yikes! Physics 8 Wednesday, October 19, 2011 Troublesome questions for HW4 (5 or more people got 0 or 1 points on them): 1, 14, 15, 16, 17, 18, 19. Yikes! Troublesome HW4 questions 1. Two objects of inertias

More information

Outline: Types of Friction Dry Friction Static vs. Kinetic Angles Applications of Friction. ENGR 1205 Appendix B

Outline: Types of Friction Dry Friction Static vs. Kinetic Angles Applications of Friction. ENGR 1205 Appendix B Outline: Types of Friction Dry Friction Static vs. Kinetic Angles Applications of Friction ENGR 1205 Appendix B 1 Contacting surfaces typically support normal and tangential forces Friction is a tangential

More information

Time: 1 hour 30 minutes

Time: 1 hour 30 minutes Paper Reference(s) 6677/01 Edexcel GCE Mechanics Gold Level G1 Time: 1 hour 30 minutes Materials required for examination Mathematical Formulae (Green) Items included with question papers Nil Candidates

More information

Dynamics Review Outline

Dynamics Review Outline Dynamics Review Outline 2.1.1-C Newton s Laws of Motion 2.1 Contact Forces First Law (Inertia) objects tend to remain in their current state of motion (at rest of moving at a constant velocity) until acted

More information

Announcements. Equilibrium of a Rigid Body

Announcements. Equilibrium of a Rigid Body Announcements Equilibrium of a Rigid Body Today s Objectives Identify support reactions Draw a free body diagram Class Activities Applications Support reactions Free body diagrams Examples Engr221 Chapter

More information

Ted Ankara College Foundation High School International Baccalaureate Physics Extended Essay May 2015

Ted Ankara College Foundation High School International Baccalaureate Physics Extended Essay May 2015 Comparison Between the Order of Coefficients of Rolling and Sliding Friction Ted Ankara College Foundation High School International Baccalaureate Physics Extended Essay May 2015 Candidate Name: Candidate

More information

Name: M1 - Dynamics. Date: Time: Total marks available: Total marks achieved:

Name: M1 - Dynamics. Date: Time: Total marks available: Total marks achieved: Name: M1 - Dynamics Date: Time: Total marks available: Total marks achieved: Questions Q1. A railway truck P, of mass m kg, is moving along a straight horizontal track with speed 15 ms 1. Truck P collides

More information

Engineering Unit 1: Engineering Principles

Engineering Unit 1: Engineering Principles Write your name here Surname Other names Pearson BTEC Level 3 Extended Certificate, Foundation Diploma, Diploma, Extended Diploma Centre Number Learner Registration Number Engineering Unit 1: Engineering

More information

AP Physics First Nine Weeks Review

AP Physics First Nine Weeks Review AP Physics First Nine Weeks Review 1. If F1 is the magnitude of the force exerted by the Earth on a satellite in orbit about the Earth and F2 is the magnitude of the force exerted by the satellite on the

More information

Honors Physics Final Exam Review. Symbol Units Units (if applicable)

Honors Physics Final Exam Review. Symbol Units Units (if applicable) Honors Physics Final Exam Review Name: Date: Write the symbol and the SI units for each of the following: Symbol Units Units (if applicable) 1) Time 2) Distance 3) Speed 4) Displacement 5) Velocity 6)

More information

HATZIC SECONDARY SCHOOL

HATZIC SECONDARY SCHOOL HATZIC SECONDARY SCHOOL PROVINCIAL EXAMINATION ASSIGNMENT STATIC EQUILIBRIUM MULTIPLE CHOICE / 33 OPEN ENDED / 80 TOTAL / 113 NAME: 1. State the condition for translational equilibrium. A. ΣF = 0 B. ΣF

More information

VISUAL PHYSICS ONLINE DYNAMICS TYPES OF FORCES FRICTION

VISUAL PHYSICS ONLINE DYNAMICS TYPES OF FORCES FRICTION VISUAL PHYSICS ONLINE DYNAMICS TYPES OF FORCES FRICTION Friction force: the force acting on the object which acts in a direction parallel to the surface. A simple model for friction F f is that it is proportional

More information

LAWS OF MOTION Newtons laws of motion. (i) First law: Law of inertia. Every body continues to be in its state of rest or of uniform motion in a

LAWS OF MOTION Newtons laws of motion. (i) First law: Law of inertia. Every body continues to be in its state of rest or of uniform motion in a LAWS OF MOTION Newtons laws of motion. (i) First law: Law of inertia. Every body continues to be in its state of rest or of uniform motion in a straight line unless compelled to change that state by an

More information

Forces and Newton s Laws Notes

Forces and Newton s Laws Notes Forces and Newton s Laws Notes Force An action exerted on an object which can change the motion of the object. The SI unit for force is the Newton (N) o N = (kg m)/s 2 o Pound is also a measure of force

More information

Physics 211 Week 10. Statics: Walking the Plank (Solution)

Physics 211 Week 10. Statics: Walking the Plank (Solution) Statics: Walking the Plank (Solution) A uniform horizontal beam 8 m long is attached by a frictionless pivot to a wall. A cable making an angle of 37 o, attached to the beam 5 m from the pivot point, supports

More information

FORCE & MOTION Instructional Module 6

FORCE & MOTION Instructional Module 6 FORCE & MOTION Instructional Module 6 Dr. Alok K. Verma Lean Institute - ODU 1 Description of Module Study of different types of forces like Friction force, Weight force, Tension force and Gravity. This

More information

Concepts Scaling; Surface Area; Volume; Air Friction; Terminal Velocity; Force of Gravity

Concepts Scaling; Surface Area; Volume; Air Friction; Terminal Velocity; Force of Gravity Laboratory #6 Atomic Structure Part A: Styrofoam Rain Drops Concepts Scaling; Surface Area; Volume; Air Friction; Terminal Velocity; Force of Gravity Introduction Why is it that if you or I were to fall

More information

Guidelines on the Calibration of Automatic Instruments for Weighing Road Vehicles in Motion and Measuring Axle Loads AWICal WIM Guide May 2018

Guidelines on the Calibration of Automatic Instruments for Weighing Road Vehicles in Motion and Measuring Axle Loads AWICal WIM Guide May 2018 Guidelines on the Calibration of Automatic Instruments for Weighing Road Vehicles in Motion and Measuring Axle Loads AWICal WIM Guide May 2018 Guidelines on the Calibration of Automatic Instruments for

More information

Friction, Inclined Planes, Forces Practice

Friction, Inclined Planes, Forces Practice Name: Date: 1. The diagram below shows a 4.0-kilogram object accelerating at 10. meters per second 2 on a rough horizontal surface. 4. n 8.0-newton block is accelerating down a frictionless ramp inclined

More information

1. An object is fired with an initial velocity of 23 m/s [R30 U]. What are the initial components of its velocity?

1. An object is fired with an initial velocity of 23 m/s [R30 U]. What are the initial components of its velocity? Physics 304 Unit 1 - Total Review 1. An object is fired with an initial velocity of 3 m/s [R30U]. What are the initial components of its velocity?. An object rolls off the top of a horizontal table. a)

More information

Physics 2514 Lecture 13

Physics 2514 Lecture 13 Physics 2514 Lecture 13 P. Gutierrez Department of Physics & Astronomy University of Oklahoma Physics 2514 p. 1/18 Goals We will discuss some examples that involve equilibrium. We then move on to a discussion

More information

AP/Honors Physics Take-Home Exam 1

AP/Honors Physics Take-Home Exam 1 AP/Honors Physics Take-Home Exam 1 Section 1: Multiple Choice (Both Honors & AP) Instructions: Read each question carefully and select the best answer from the choices given. Show all work on separate

More information

6. Which graph best represents the motion of an object that is not in equilibrium as it travels along a straight line? A) B)

6. Which graph best represents the motion of an object that is not in equilibrium as it travels along a straight line? A) B) 1. The data table below lists the mass and speed of four different objects. 6. Which graph best represents the motion of an object that is not in equilibrium as it travels along a straight line? Which

More information

When a rigid body is in equilibrium, both the resultant force and the resultant couple must be zero.

When a rigid body is in equilibrium, both the resultant force and the resultant couple must be zero. When a rigid body is in equilibrium, both the resultant force and the resultant couple must be zero. 0 0 0 0 k M j M i M M k R j R i R F R z y x z y x Forces and moments acting on a rigid body could be

More information

+ + ( indicator ) + (display, printer, memory)

+ + ( indicator ) + (display, printer, memory) CERTIFICATION OF STRAIN GAUGE LOAD CELL FAMILIES B. Meissner Physikalisch-Technische Bundesanstalt Weighing Instruments Laboratory 38116 Braunschweig, Germany Abstract: Testing and certification of load

More information

is the study of and. We study objects. is the study of and. We study objects.

is the study of and. We study objects. is the study of and. We study objects. Static Equilibrium Translational Forces Torque Unit 4 Statics Dynamics vs Statics is the study of and. We study objects. is the study of and. We study objects. Recall Newton s First Law All objects remain

More information

Structural design of helicopter landing platform for super-yacht

Structural design of helicopter landing platform for super-yacht Structural design of helicopter landing platform for super-yacht Daniel Heredia Chávez Master Thesis presented in partial fulfillment of the requirements for the double degree: Advanced Master in Naval

More information

CE : CIVIL ENGINEERING

CE : CIVIL ENGINEERING 2009 CE : CIVIL ENGINEERING Duration : Three Hours Read the following instructions carefully. l. This question paper contains 16 printed pages including pages for rough work. Please check all pages and

More information

To study applications of Newton s Laws as they. To study conditions that establish equilibrium. To consider contact forces and the effects of

To study applications of Newton s Laws as they. To study conditions that establish equilibrium. To consider contact forces and the effects of Chap. 5: More Examples with Newton s Law Chap.5: Applying Newton s Laws To study conditions that establish equilibrium. To study applications of Newton s Laws as they apply when the net force is not zero.

More information

+F N = -F g. F g = m٠a g

+F N = -F g. F g = m٠a g Force Normal = F N Force Normal (or the Normal Force, abbreviated F N ) = F N = The contact force exerted by a surface on an object. The word Normal means perpendicular to Therefore, the Normal Force is

More information

Physics 207 Lecture 9. Lecture 9

Physics 207 Lecture 9. Lecture 9 Lecture 9 Today: Review session Assignment: For Thursday, Read Chapter 8, first four sections Exam Wed., Feb. 18 th from 7:15-8:45 PM Chapters 1-7 One 8½ X 11 note sheet and a calculator (for trig.) Place:

More information

PHY131 Summer 2011 Class 5 Notes

PHY131 Summer 2011 Class 5 Notes PHY131 Summer 2011 Class 5 Notes 5/31/11 PHY131H1F Summer Class 5 Today: Equilibrium Mass, Weight, Gravity Friction, Drag Rolling without slipping Examples of Newton s Second Law Pre-class Reading Quiz.

More information