Refrigeration. 05/04/2011 T.Al-Shemmeri 1
|
|
- Barnaby Gardner
- 6 years ago
- Views:
Transcription
1 Refrigeration is a process of controlled removal of heat from a substance to keep it at a temperature below the ambient condition, often below the freezing point of water (0 O C) 05/04/0 T.Al-Shemmeri
2 Refrigeration In principle, It is based on the fact that when a liquid is allowed to evaporate, it will absorb heat from its surroundings. 05/04/0 T.Al-Shemmeri
3 Domestic: fridges, freezers. Transportation: refrigerated containers Industrial: dairies, brewing, ice cream, Commercial: supermarkets, hotels and restaurants. Air-conditioning: hospitals, offices, aeroplanes, trains, cars. Leisure and Sports : ice rinks. 05/04/0 T.Al-Shemmeri 3
4 The principle of a Heat Engine in which fuel is burnt to produce work (drive the car), the exhaust rejects lower quality heat to the ambient. = Q - Q according to the first law of thermodynamics HOT RESERVOIR Q HEAT ENGINE COLD RESERVOIR Q 05/04/0 T.Al-Shemmeri 4
5 The principle of a Heat Pump in which work (motor), is used to drive a compressor pumping the gas to a higher pressure, then let it through a condenser to loose heat, and finally suddenly drop its pressure allowing to vapourise and hence absorb heat from its surroundings, hence Q = Q - according to the first law of thermodynamics HOT RESERVOIR Q HOT RESERVOIR Q HEAT PUMP HEAT ENGINE COLD RESERVOIR Q COLD RESERVOIR Q 05/04/0 T.Al-Shemmeri 5
6 The reason this is known as Heat Pump because it is possible to utilise both heat terms Q and Q. HOT RESERVOIR Q HEAT PUMP COLD RESERVOIR Q 05/04/0 T.Al-Shemmeri 6
7 Both COP are related to each other, According to Energy Conservation : Q Q = Or Q = Q + Divide equation by, to get : Q / = Q / + COP H = COP R + 05/04/0 T.Al-Shemmeri 7
8 05/04/0 T.Al-Shemmeri 8
9 Simple Refrigeration cycle: 4 processes: - Isentropic compression 3 CONDENSER - 3 Condensation at constant pressure 3-4 Throttling at constant enthalpy EVAPORATOR 4 - Evaporation at constant pressure 4 05/04/0 T.Al-Shemmeri 9
10 3 CONDENSER P 3 EVAPORATOR 4 4 h 05/04/0 T.Al-Shemmeri 0
11 Calculations for ideal compression, 00% isentropic: 3 Input ork = m r ( h h ) Refrigeration Effect Q 4 = m r ( h h 4 ) Heating Effect Q 3 = m r (h h 3 ) If the Refrigerant mass is not specified, calculate on kg/s basis. Q COP = 3 H 4 h Q COP = 4 R 05/04/0 T.Al-Shemmeri
12 Calculations for irreverible compression, less than 00%: 3 if h is the actual enthalpy after compression, and h is the ideal value, at constant entropy curve. Then the compressor s isentropic efficiency is defined as: η c 4 = h h ' h h h 05/04/0 T.Al-Shemmeri
13 Calculations for irreverible compression, less than 00%: 3 Input ork = m r ( h h ) Refrigeration Effect Q 4 = m r ( h h 4 ) Heating Effect Q 3 = m r (h h 3 ) If the Refrigerant mass is not specified, calculate on kg/s basis. Q COP = 4 R 05/04/0 T.Al-Shemmeri 3 4 h Q COP = 3 H
14 05/04/0 T.Al-Shemmeri 4
15 Enthalpy h (kj/kg) Pressure P( bar ) X- axis Y-axis Temp T ( C) on inside of the Curve Volume v( m 3 /kg) lines ( curves ) at 0 o to horizontal Entropy s (kj/kgk) lines ( curves ) at o to horizontal 05/04/0 T.Al-Shemmeri 5
16 3 condenser 4 Heat Exchanger 5 6 evaporator compressor p Expansion Valve h 05/04/0 T.Al-Shemmeri 6
17 05/04/0 T.Al-Shemmeri 7
18 SOLVED EXAMPLE A heat pump is used to heat a factory during winter with average outside temperature being 0 o C and the factory temperature is to be maintained at 0 o C. The building heating load is estimated as 00 k. Determine the minimum power requirement to drive the HP unit for this application. 05/04/0 T.Al-Shemmeri 8
19 SOLUTION EXAMPLE COP but H COP hence min max = = T / T 73/ 93 = H max = = Q COP Q max L = H = 6. 8 k /04/0 T.Al-Shemmeri 9
20 SOLVED EXAMPLE A refrigerator using R as the working fluid. The refrigerant enters the compressor as saturated vapour at bar and on leaving the condenser it is saturated liquid at 8 bar (absolute). Assume that the compression process is 00% isentropic, and that there is no superheating or subcooling effects and that pressure losses are negligible. Calculate using the chart: the work of compression, the refrigerating effect, the coefficient of performance - compare this value with the Carnot performance Solution: Construct the cycle on the P-h chart find h=45 kj/kg h=70 kj/kg h3 = h4 = 30 kj/kg Hence: ork of compressor c = h-h=4 kj/kg Refrigeration effect RE = h-h4=6 kj/kg COP R = RE/c=4.83 Note that COP ideal T = T T 60 = =. 05/04/0 T.Al-Shemmeri 0
21 SOLVED EXAMPLE 3 A refrigerator using R34a as a Retrofit working fluid to replace R in the system of example 7.5. The refrigerant enters the compressor as saturated vapour at bar and on leaving the condenser it is saturated liquid at 8 bar (absolute). Assume that the compression process is 00% isentropic, and that there is no superheating or subcooling effects and that pressure looses are negligible. Calculate using the chart: the work of compression, the refrigerating effect, the coefficient of performance. Solution: Construct the cycle on the P-h chart, find enthalpies at key state points: h =95 kj/kg h =35 kj/kg h3 = h4 =45 kj/kg Hence: ork of compressor c= h-h=30 kj/kg Refrigeration effect RE=h-h4=50 kj/kg Coefficient of Performance COP R =RE/c= 5.0 which is better than that for R but still not as good as the ideal value of /04/0 T.Al-Shemmeri
R13 SET - 1 '' ''' '' ' '''' Code No RT21033
SET - 1 II B. Tech I Semester Supplementary Examinations, June - 2015 THERMODYNAMICS (Com. to ME, AE, AME) Time: 3 hours Max. Marks: 70 Note: 1. Question Paper consists of two parts (Part-A and Part-B)
More informationCHAPTER 7 ENTROPY. Copyright Hany A. Al-Ansary and S. I. Abdel-Khalik (2014) 1
CHAPTER 7 ENTROPY S. I. Abdel-Khalik (2014) 1 ENTROPY The Clausius Inequality The Clausius inequality states that for for all cycles, reversible or irreversible, engines or refrigerators: For internally-reversible
More information5/6/ :41 PM. Chapter 6. Using Entropy. Dr. Mohammad Abuhaiba, PE
Chapter 6 Using Entropy 1 2 Chapter Objective Means are introduced for analyzing systems from the 2 nd law perspective as they undergo processes that are not necessarily cycles. Objective: introduce entropy
More informationUnit Workbook 2 - Level 5 ENG U64 Thermofluids 2018 UniCourse Ltd. All Rights Reserved. Sample
Pearson BTEC Level 5 Higher Nationals in Engineering (RQF) Unit 64: Thermofluids Unit Workbook 2 in a series of 4 for this unit Learning Outcome 2 Vapour Power Cycles Page 1 of 26 2.1 Power Cycles Unit
More informationReadings for this homework assignment and upcoming lectures
Homework #3 (group) Tuesday, February 13 by 4:00 pm 5290 exercises (individual) Thursday, February 15 by 4:00 pm extra credit (individual) Thursday, February 15 by 4:00 pm Readings for this homework assignment
More informationUBMCC11 - THERMODYNAMICS. B.E (Marine Engineering) B 16 BASIC CONCEPTS AND FIRST LAW PART- A
UBMCC11 - THERMODYNAMICS B.E (Marine Engineering) B 16 UNIT I BASIC CONCEPTS AND FIRST LAW PART- A 1. What do you understand by pure substance? 2. Define thermodynamic system. 3. Name the different types
More informationTwo mark questions and answers UNIT II SECOND LAW 1. Define Clausius statement. It is impossible for a self-acting machine working in a cyclic process, to transfer heat from a body at lower temperature
More informationChemical Engineering Thermodynamics Spring 2002
10.213 Chemical Engineering Thermodynamics Spring 2002 Test 2 Solution Problem 1 (35 points) High pressure steam (stream 1) at a rate of 1000 kg/h initially at 3.5 MPa and 350 ºC is expanded in a turbine
More informationLecture 35: Vapor power systems, Rankine cycle
ME 00 Thermodynamics I Spring 015 Lecture 35: Vapor power systems, Rankine cycle Yong Li Shanghai Jiao Tong University Institute of Refrigeration and Cryogenics 800 Dong Chuan Road Shanghai, 0040, P. R.
More information8.21 The Physics of Energy Fall 2009
MIT OpenCourseWare http://ocw.mit.edu 8.21 The Physics of Energy Fall 2009 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms. 8.21 Lecture 10 Phase Change
More informationLecture 44: Review Thermodynamics I
ME 00 Thermodynamics I Lecture 44: Review Thermodynamics I Yong Li Shanghai Jiao Tong University Institute of Refrigeration and Cryogenics 800 Dong Chuan Road Shanghai, 0040, P. R. China Email : liyo@sjtu.edu.cn
More information20 m neon m propane. g 20. Problems with solutions:
Problems with solutions:. A -m tank is filled with a gas at room temperature 0 C and pressure 00 Kpa. How much mass is there if the gas is a) Air b) Neon, or c) Propane? Given: T7K; P00KPa; M air 9; M
More informationCommon Terms, Definitions and Conversion Factors
1 Common Terms, Definitions and Conversion Factors 1. Force: A force is a push or pull upon an object resulting from the object s interaction with another object. It is defined as Where F = m a F = Force
More informationSpring_#7. Thermodynamics. Youngsuk Nam.
Spring_#7 Thermodynamics Youngsuk Nam ysnam1@khu.ac.kr You can t connect the dots looking forward; you can only connect them looking backwards. So you have to trust that the dots will somehow connect in
More information7. Development of the 2nd Law
7-1 7. Development of the 2nd Law 7.1 1st Law Limitations The 1 st Law describes energy accounting. Once we have a process (or string of processes) we can calculate the relevant energy interactions. The
More informationME6301- ENGINEERING THERMODYNAMICS UNIT I BASIC CONCEPT AND FIRST LAW PART-A
ME6301- ENGINEERING THERMODYNAMICS UNIT I BASIC CONCEPT AND FIRST LAW PART-A 1. What is meant by thermodynamics system? (A/M 2006) Thermodynamics system is defined as any space or matter or group of matter
More informationMARIA COLLEGE OF ENGINEERING AND TECHNOLOGY
MARIA COLLEGE OF ENGINEERING AND TECHNOLOGY ATTOOR ENGINEERING THERMODYNAMICS (TWO MARK QUESTION BANK) UNIT 1 (BASIC COMCEPTS AND FIRST LAW) 1. Define the term thermal engineering. Thermal engineering
More informationII/IV B.Tech (Regular) DEGREE EXAMINATION. (1X12 = 12 Marks) Answer ONE question from each unit.
Page 1 of 8 Hall Ticket Number: 14CH 404 II/IV B.Tech (Regular) DEGREE EXAMINATION June, 2016 Chemical Engineering Fourth Semester Engineering Thermodynamics Time: Three Hours Maximum : 60 Marks Answer
More informationR13. II B. Tech I Semester Regular Examinations, Jan THERMODYNAMICS (Com. to ME, AE, AME) PART- A
SET - 1 II B. Tech I Semester Regular Examinations, Jan - 2015 THERMODYNAMICS (Com. to ME, AE, AME) Time: 3 hours Max. Marks: 70 Note 1. Question Paper consists of two parts (Part-A and Part-B) 2. Answer
More information1. INTRODUCTION TO REFRIGERATION AND AIR CONDITION
CHAPTER ONE 1. INTRODUCTION TO REFRIGERATION AND AIR CONDITION Refrigeration may be defined as the process of reducing and maintaining a temperature of a space or material below that of the surroundings.
More informationME Thermodynamics I. Lecture Notes and Example Problems
ME 227.3 Thermodynamics I Lecture Notes and Example Problems James D. Bugg September 2018 Department of Mechanical Engineering Introduction Part I: Lecture Notes This part contains handout versions of
More informationMAE 320 HW 7B. 1e. For an isolated system, please circle the parameter which will change with time. (a) Total energy;
MAE 320 HW 7B his comprehensive homework is due Monday, December 5 th, 206. Each problem is worth the points indicated. Copying of the solution from another is not acceptable. Multi-choice, multi-answer
More informationClassification following properties of the system in Intensive and Extensive
Unit I Classification following properties of the system in Intensive and Extensive Extensive : mass, weight, volume, potential energy, Kinetic energy, Internal energy, entropy, exergy, energy, magnetization
More informationME 200 Final Exam December 14, :00 a.m. to 10:00 a.m.
CIRCLE YOUR LECTURE BELOW: First Name Last Name 7:30 a.m. 8:30 a.m. 10:30 a.m. 11:30 a.m. Boregowda Boregowda Braun Bae 2:30 p.m. 3:30 p.m. 4:30 p.m. Meyer Naik Hess ME 200 Final Exam December 14, 2015
More informationSEM-2017(03HI MECHANICAL ENGINEERING. Paper II. Please read each of the following instructions carefully before attempting questions.
We RoU No. 700095 Candidate should write his/her Roll No. here. Total No. of Questions : 7 No. of Printed Pages : 7 SEM-2017(03HI MECHANICAL ENGINEERING Paper II Time ; 3 Hours ] [ Total Marks : 0 Instructions
More information(Refer Slide Time: 00:00:43 min) Welcome back in the last few lectures we discussed compression refrigeration systems.
Refrigeration and Air Conditioning Prof. M. Ramgopal Department of Mechanical Engineering Indian Institute of Technology, Kharagpur Lecture No. # 14 Vapour Absorption Refrigeration Systems (Refer Slide
More informationME 354 THERMODYNAMICS 2 MIDTERM EXAMINATION. Instructor: R. Culham. Name: Student ID Number: Instructions
ME 354 THERMODYNAMICS 2 MIDTERM EXAMINATION February 14, 2011 5:30 pm - 7:30 pm Instructor: R. Culham Name: Student ID Number: Instructions 1. This is a 2 hour, closed-book examination. 2. Answer all questions
More informationBasic Thermodynamics Module 1
Basic Thermodynamics Module 1 Lecture 9: Thermodynamic Properties of Fluids Thermodynamic Properties of fluids Most useful properties: Properties like pressure, volume and temperature which can be measured
More informationFINAL EXAM. ME 200 Thermodynamics I, Spring 2013 CIRCLE YOUR LECTURE BELOW:
ME 200 Thermodynamics I, Spring 2013 CIRCLE YOUR LECTURE BELOW: Div. 5 7:30 am Div. 2 10:30 am Div. 4 12:30 am Prof. Naik Prof. Braun Prof. Bae Div. 3 2:30 pm Div. 1 4:30 pm Div. 6 4:30 pm Prof. Chen Prof.
More informationME 2322 Thermodynamics I PRE-LECTURE Lesson 23 Complete the items below Name:
Lesson 23 1. (10 pt) Write the equation for the thermal efficiency of a Carnot heat engine below: 1 L H 2. (10 pt) Can the thermal efficiency of an actual engine ever exceed that of an equivalent Carnot
More informationThermodynamics is the Science of Energy and Entropy
Definition of Thermodynamics: Thermodynamics is the Science of Energy and Entropy - Some definitions. - The zeroth law. - Properties of pure substances. - Ideal gas law. - Entropy and the second law. Some
More informationMAHALAKSHMI ENGINEERING COLLEGE
MAHALAKSHMI ENGINEERING COLLEGE TIRUCHIRAPALLI 621 213. Department: Mechanical Subject Code: ME2202 Semester: III Subject Name: ENGG. THERMODYNAMICS UNIT-I Basic Concept and First Law 1. What do you understand
More informationSecond Law of Thermodynamics -
Second Law of Thermodynamics - REVIEW ENTROPY EXAMPLE Dr. Garrick 1/19/09 First Law of Thermodynamics you can t win! First Law of Thermodynamics: Energy cannot be Created or Destroyed the total energy
More informationME 2322 Thermodynamics I PRE-LECTURE Lesson 23 Complete the items below Name:
Lesson 23 1. (10 pt) Write the equation for the thermal efficiency of a Carnot heat engine below: T η = T 1 L H 2. (10 pt) Can the thermal efficiency of an actual engine ever exceed that of an equivalent
More informationSOLUTION: Consider the system to be the refrigerator (shown in the following schematic), which operates over a cycle in normal operation.
Soln_21 An ordinary household refrigerator operating in steady state receives electrical work while discharging net energy by heat transfer to its surroundings (e.g., the kitchen). a. Is this a violation
More informationBrown Hills College of Engineering & Technology
UNIT 4 Flow Through Nozzles Velocity and heat drop, Mass discharge through a nozzle, Critical pressure ratio and its significance, Effect of friction, Nozzle efficiency, Supersaturated flow, Design pressure
More informationBME-A PREVIOUS YEAR QUESTIONS
BME-A PREVIOUS YEAR QUESTIONS CREDITS CHANGE ACCHA HAI TEAM UNIT-1 Introduction: Introduction to Thermodynamics, Concepts of systems, control volume, state, properties, equilibrium, quasi-static process,
More informationw = -nrt hot ln(v 2 /V 1 ) nrt cold ln(v 1 /V 2 )[sincev/v 4 3 = V 1 /V 2 ]
Chemistry 433 Lecture 9 Entropy and the Second Law NC State University Spontaneity of Chemical Reactions One might be tempted based on the results of thermochemistry to predict that all exothermic reactions
More informationQUESTION BANK UNIT-1 INTRODUCTION. 2. State zeroth law of thermodynamics? Write its importance in thermodynamics.
QUESTION BANK UNIT-1 INTRODUCTION 1. What do you mean by thermodynamic equilibrium? How does it differ from thermal equilibrium? [05 Marks, June-2015] 2. State zeroth law of thermodynamics? Write its importance
More informationS.E. (Chemical Engineering) (Second Semester)EXAMINATION, 2012 THERMODYNAMICS-I (2008 PATTERN) Time : Three Hours Maximum Marks : 100
Total No. of Questions 12] [Total No. of Printed Pages 7 Seat No. [4162]-189 S.E. (Chemical Engineering) (Second Semester)EXAMINATION, 2012 THERMODYNAMICS-I (2008 PATTERN) Time : Three Hours Maximum Marks
More informationTHERMODYNAMICS NOTES. These notes give a brief overview of engineering thermodynamics. They are based on the thermodynamics text by Black & Hartley.
THERMODYNAMICS NOTES These notes give a brief overview of engineering thermodynamics. They are based on the thermodynamics text by Black & Hartley. Topics covered include: concepts; properties; conservation
More informationME 200 Thermodynamics I, Spring 2015, Exam 3, 8 p.m. to 9 p.m. on April 14, 2015
ME 200 Thermodynamics I, Spring 2015, Exam 3, 8 p.m. to 9 p.m. on April 14, 2015 CIRCLE YOUR LECTURE BELOW: 7:30 a.m. 10:30 a.m. 12:30 p.m. 2:30 p.m. 4:30 p.m. Joglekar Chen Chen Kittel Naik INSTRUCTIONS
More informationHandout 12: Thermodynamics. Zeroth law of thermodynamics
1 Handout 12: Thermodynamics Zeroth law of thermodynamics When two objects with different temperature are brought into contact, heat flows from the hotter body to a cooler one Heat flows until the temperatures
More informationThermodynamic Analysis of the Effect of Generator Temperature on the Performance of a Single-Effect Absorption Refrigeration Cycle
Thermodynamic Analysis of the Effect of Generator Temperature on the Performance of a Single-Effect Absorption Refrigeration Cycle Abstract Debendra Nath Sarkar 1, Dipankar Narayan Basu 2 1 UG 4 th Year
More information10 minutes reading time is allowed for this paper.
EGT1 ENGINEERING TRIPOS PART IB Tuesday 31 May 2016 2 to 4 Paper 4 THERMOFLUID MECHANICS Answer not more than four questions. Answer not more than two questions from each section. All questions carry the
More informationME Thermodynamics I
Homework - Week 01 HW-01 (25 points) Given: 5 Schematic of the solar cell/solar panel Find: 5 Identify the system and the heat/work interactions associated with it. Show the direction of the interactions.
More informationME 200 Final Exam December 12, :00 a.m. to 10:00 a.m.
CIRCLE YOUR LECTURE BELOW: First Name Last Name 7:30 a.m. 8:30 a.m. 10:30 a.m. 1:30 p.m. 3:30 p.m. Mongia Abraham Sojka Bae Naik ME 200 Final Exam December 12, 2011 8:00 a.m. to 10:00 a.m. INSTRUCTIONS
More informationIn the next lecture...
16 1 In the next lecture... Solve problems from Entropy Carnot cycle Exergy Second law efficiency 2 Problem 1 A heat engine receives reversibly 420 kj/cycle of heat from a source at 327 o C and rejects
More informationExisting Resources: Supplemental/reference for students with thermodynamics background and interests:
Existing Resources: Masters, G. (1991) Introduction to Environmental Engineering and Science (Prentice Hall: NJ), pages 15 29. [ Masters_1991_Energy.pdf] Supplemental/reference for students with thermodynamics
More informationc Dr. Md. Zahurul Haq (BUET) Thermodynamic Processes & Efficiency ME 6101 (2017) 2 / 25 T145 = Q + W cv + i h 2 = h (V2 1 V 2 2)
Thermodynamic Processes & Isentropic Efficiency Dr. Md. Zahurul Haq Professor Department of Mechanical Engineering Bangladesh University of Engineering & Technology (BUET Dhaka-1000, Bangladesh zahurul@me.buet.ac.bd
More informationFirst Steps in Thermodynamics: Absolute Beginners
2 First Steps in Thermodynamics: Absolute Beginners Abstract: The purpose of this chapter is to discuss key concepts which should be presented to absolute beginners in order to enable them to understand
More informationCourse: MECH-341 Thermodynamics II Semester: Fall 2006
FINAL EXAM Date: Thursday, December 21, 2006, 9 am 12 am Examiner: Prof. E. Timofeev Associate Examiner: Prof. D. Frost READ CAREFULLY BEFORE YOU PROCEED: Course: MECH-341 Thermodynamics II Semester: Fall
More informationMAHARASHTRA STATE BOARD OF TECHNICAL EDUCATION (Autonomous) (ISO/IEC Certified) SUMMER 17 EXAMINATION
Important Instructions to examiners: 1) The answers should be examined by key words and not as word-to-word as given in the model answer scheme. 2) The model answer and the answer written by candidate
More information5.2. The Rankine Cycle
Figure 5.1. Illustration of a Carnot cycle based on steam in T-S coordinates. The Carnot cycle has a major advantage over other cycles. It operates at the highest temperature available for as long as possible,
More informationCHAPTER 8 ENTROPY. Blank
CHAPER 8 ENROPY Blank SONNAG/BORGNAKKE SUDY PROBLEM 8-8. A heat engine efficiency from the inequality of Clausius Consider an actual heat engine with efficiency of η working between reservoirs at and L.
More informationEntropy & the Second Law of Thermodynamics
PHYS102 Previous Exam Problems CHAPTER 20 Entropy & the Second Law of Thermodynamics Entropy gases Entropy solids & liquids Heat engines Refrigerators Second law of thermodynamics 1. The efficiency of
More information1. j&& 100 &o 2. %4k%-ig#3g%m+~%%a*&4+s 5fl~J6?~+* O
1. j&& 100 &o 2. %4k%-ig#3g%m+~%%a*&4+s 5fl~J6?~+* O 3. Mathematical and governing equations are listed in page 6. Problem 1. &$Fa ( ff- 10 /J.% 9 $./J.% 2 @ ff- 20 %) ( ) 1. Compressibility factor, Z,
More informationHandout 12: Thermodynamics. Zeroth law of thermodynamics
1 Handout 12: Thermodynamics Zeroth law of thermodynamics When two objects with different temperature are brought into contact, heat flows from the hotter body to a cooler one Heat flows until the temperatures
More informationMAE 11. Homework 8: Solutions 11/30/2018
MAE 11 Homework 8: Solutions 11/30/2018 MAE 11 Fall 2018 HW #8 Due: Friday, November 30 (beginning of class at 12:00p) Requirements:: Include T s diagram for all cycles. Also include p v diagrams for Ch
More informationThis follows from the Clausius inequality as a consequence of the second law of thermodynamics. Therefore. (for reversible process only) (22.
Entropy Clausius inequality can be used to analyze the cyclic process in a quantitative manner. The second law became a law of wider applicability when Clausius introduced the property called entropy.
More informationChapter 20 Second Law of Thermodynamics. Copyright 2009 Pearson Education, Inc.
Chapter 20 Second Law of Thermodynamics It is easy to produce thermal energy using work, but how does one produce work using thermal energy? This is a heat engine; mechanical energy can be obtained from
More informationElements of Mechanical Engineering
2011 Elements of Mechanical Engineering AMRAT PATEL Asst. Professor 1/17/2011 Smt Shantaben Haribhai Gajera Charitable Trust, Surat LAXMI INSTITUTE OF TECHNOLOGY, SARIGAM BE I, Sem I (Section: A, B & C)
More informationRECORD AND ANALYSE THE PRESSURE-ENTHALPY DIAGRAM FOR A COMPRESSION HEAT PUMP
Thermodynamics Heat cycles Heat Pump RECORD AND ANALYSE THE PRESSURE-ENTHALPY DIAGRAM FOR A COMPRESSION HEAT PUMP Demonstrate how an electric compression heat pump works Quantitatively investigate of the
More informationCHAPTER 6 THE SECOND LAW OF THERMODYNAMICS
CHAPTER 6 THE SECOND LAW OF THERMODYNAMICS S. I. Abdel-Khalik (2014) 1 CHAPTER 6 -- The Second Law of Thermodynamics OUTCOME: Identify Valid (possible) Processes as those that satisfy both the first and
More informationAn introduction to thermodynamics applied to Organic Rankine Cycles
An introduction to thermodynamics applied to Organic Rankine Cycles By : Sylvain Quoilin PhD Student at the University of Liège November 2008 1 Definition of a few thermodynamic variables 1.1 Main thermodynamics
More informationDEPARTMENT OF MECHANICAL ENGINEERING ME6301-ENGINEERING THERMODYNAMICS
SYED AMMAL ENGINEERING COLLEGE (Approved by the AICTE, New Delhi, Govt. of Tamilnadu and Affiliated to Anna University, chennai) Established in 1998 - An ISO 9001:2008 Certified Institution Dr. E.M.Abdullah
More informationLecture 38: Vapor-compression refrigeration systems
ME 200 Termodynamics I Lecture 38: Vapor-compression refrigeration systems Yong Li Sangai Jiao Tong University Institute of Refrigeration and Cryogenics 800 Dong Cuan Road Sangai, 200240, P. R. Cina Email
More informationME 2322 Thermodynamics I PRE-LECTURE Lesson 10 Complete the items below Name:
Lesson 10 1. (5 pt) If P > P sat (T), the phase is a subcooled liquid. 2. (5 pt) if P < P sat (T), the phase is superheated vapor. 3. (5 pt) if T > T sat (P), the phase is superheated vapor. 4. (5 pt)
More informationMATHEMATICAL MODEL OF A VAPOUR ABSORPTION REFRIGERATION UNIT
ISSN 1726-4529 Int j simul model 9 (2010) 2, 86-97 Original scientific paper MATHEMATICAL MODEL OF A VAPOUR ABSORPTION REFRIGERATION UNIT Micallef, D. & Micallef, C. University of Malta, Department of
More informationCHAPTER 5 MASS AND ENERGY ANALYSIS OF CONTROL VOLUMES
Thermodynamics: An Engineering Approach 8th Edition in SI Units Yunus A. Çengel, Michael A. Boles McGraw-Hill, 2015 CHAPTER 5 MASS AND ENERGY ANALYSIS OF CONTROL VOLUMES Lecture slides by Dr. Fawzi Elfghi
More informationChapter 1 Introduction and Basic Concepts
Chapter 1 Introduction and Basic Concepts 1-1 Thermodynamics and Energy Application Areas of Thermodynamics 1-2 Importance of Dimensions and Units Some SI and English Units Dimensional Homogeneity Unity
More informationBasic thermodynamics. heat to the high temperature reservoir.
Consider a heat engine that is operating in a cyclic process takes heat (QH) from a high temperature reservoir & converts completely into work (W), violating the Kelvin Planck statement. Let the work W,
More informationLaws of Thermodynamics
Laws of Thermodynamics The Three Laws of Thermodynamics - The first lawof thermodynamics, also called conservation of energy. We can use this knowledge to determine the amount of energy in a system, the
More informationDishwasher. Heater. Homework Solutions ME Thermodynamics I Spring HW-1 (25 points)
HW-1 (25 points) (a) Given: 1 for writing given, find, EFD, etc., Schematic of a household piping system Find: Identify system and location on the system boundary where the system interacts with the environment
More informationAvailability and Irreversibility
Availability and Irreversibility 1.0 Overview A critical application of thermodynamics is finding the maximum amount of work that can be extracted from a given energy resource. This calculation forms the
More informationThermal Energy Final Exam Fall 2002
16.050 Thermal Energy Final Exam Fall 2002 Do all eight problems. All problems count the same. 1. A system undergoes a reversible cycle while exchanging heat with three thermal reservoirs, as shown below.
More information1. Basic state values of matter
1. Basic state values of matter Example 1.1 The pressure inside a boiler is p p = 115.10 5 Pa and p v = 9.44.10 4 Pa inside a condenser. Calculate the absolute pressure inside the boiler and condenser
More informationThermodynamics Lecture Series
Thermodynamics Lecture Series Second Law uality of Energy Applied Sciences Education Research Group (ASERG) Faculty of Applied Sciences Universiti Teknologi MARA email: drjjlanita@hotmail.com http://www.uitm.edu.my/faculties/fsg/drjj.html
More informationDepartment of Mechanical Engineering Indian Institute of Technology New Delhi II Semester MEL 140 ENGINEERING THERMODYNAMICS
PROBLEM SET 1: Review of Basics Problem 1: Define Work. Explain how the force is generated in an automobile. Problem 2: Define and classify Energy and explain the relation between a body and energy. Problem
More informationINSTITUTE OF AERONAUTICAL ENGINEERING (Autonomous) Dundigal, Hyderabad
INSTITUTE OF AERONAUTICAL ENGINEERING (Autonomous) Dundigal, Hyderabad -500 043 MECHANICAL ENGINEERING TUTORIAL QUESTION BANK Name : THERMODYNAMICS Code : A30306 Class : II B. Tech I Semester Branch :
More informationInvestigations on Performance of an Auto-Cascade Absorption Refrigeration System Operating with Mixed Refrigerants
Purdue University Purdue e-pubs International Refrigeration and Air Conditioning Conference School of Mechanical Engineering 2016 Investigations on Performance of an Auto-Cascade Absorption Refrigeration
More informationChapter 3 PROPERTIES OF PURE SUBSTANCES
Chapter 3 PROPERTIES OF PURE SUBSTANCES PURE SUBSTANCE Pure substance: A substance that has a fixed chemical composition throughout. Air is a mixture of several gases, but it is considered to be a pure
More informationChapter 5. Mass and Energy Analysis of Control Volumes. by Asst. Prof. Dr.Woranee Paengjuntuek and Asst. Prof. Dr.Worarattana Pattaraprakorn
Chapter 5 Mass and Energy Analysis of Control Volumes by Asst. Prof. Dr.Woranee Paengjuntuek and Asst. Prof. Dr.Worarattana Pattaraprakorn Reference: Cengel, Yunus A. and Michael A. Boles, Thermodynamics:
More informationfirst law of ThermodyNamics
first law of ThermodyNamics First law of thermodynamics - Principle of conservation of energy - Energy can be neither created nor destroyed Basic statement When any closed system is taken through a cycle,
More informationIntroduction to Thermodynamic Cycles Part 1 1 st Law of Thermodynamics and Gas Power Cycles
Introduction to Thermodynamic Cycles Part 1 1 st Law of Thermodynamics and Gas Power Cycles by James Doane, PhD, PE Contents 1.0 Course Oeriew... 4.0 Basic Concepts of Thermodynamics... 4.1 Temperature
More informationCHAPTER INTRODUCTION AND BASIC PRINCIPLES. (Tutorial). Determine if the following properties of the system are intensive or extensive properties: Property Intensive Extensive Volume Density Conductivity
More informationI. (20%) Answer the following True (T) or False (F). If false, explain why for full credit.
I. (20%) Answer the following True (T) or False (F). If false, explain why for full credit. Both the Kelvin and Fahrenheit scales are absolute temperature scales. Specific volume, v, is an intensive property,
More informationChapter 7. Dr Ali Jawarneh. Department of Mechanical Engineering Hashemite University
Chapter 7 ENTROPY Dr Ali Jawarneh Department of Mechanical Engineering Hashemite University Objectives Apply the second law of thermodynamics to processes. Define a new property called entropy to quantify
More informationME 2202 ENGINEERING THERMODYNAMICS TWO MARKS QUESTIONS AND ANSWERS UNIT I BASIC CONCEPTS AND FIRST LAW
ME 2202 ENGINEERING THERMODYNAMICS TWO MARKS QUESTIONS AND ANSWERS UNIT I BASIC CONCEPTS AND FIRST LAW 1. What is thermodynamics? It is a basic science that deals with energy and its transformations. The
More informationTtions, and its relation to states of matter. This chapter covers the
Related Commercial Resources CHAPTER 1 THERMODYNAMICS AND REFRIGERATION CYCLES THERMODYNAMICS... 1.1 First Law of Thermodynamics... 1.2 Second Law of Thermodynamics... 1.2 Thermodynamic Analysis of Refrigeration
More informationME 200 Exam 2 October 16, :30 p.m. to 7:30 p.m.
CIRCLE YOUR LECTURE BELOW: First Name Solution Last Name 7:30 am 8:30 am 10:30 am 11:30 am Joglekar Bae Gore Abraham 1:30 pm 3:30 pm 4:30 pm Naik Naik Cheung ME 200 Exam 2 October 16, 2013 6:30 p.m. to
More informationTHE METHOD OF THE WORKING FLUID SELECTION FOR ORGANIC RANKINE CYCLE (ORC) SYSTEM WITH VOLUMETRIC EXPANDER. * Corresponding Author ABSTRACT
Paper ID: 79, Page 1 THE METHOD OF THE WORKING FLUID SELECTION FOR ORGANIC RANKINE CYCLE (ORC) SYSTEM WITH VOLUMETRIC EXPANDER Piotr Kolasiński* 1 1 Wrocław University of Technology, Department of Thermodynamics,
More informationClass 22 - Second Law of Thermodynamics and Entropy
Class 22 - Second Law of Thermodynamics and Entropy The second law of thermodynamics The first law relates heat energy, work and the internal thermal energy of a system, and is essentially a statement
More informationMathematical Modelling for Refrigerant Flow in Diabatic Capillary Tube
Mathematical Modelling for Refrigerant Flow in Diabatic Capillary Tube Jayant Deshmukh Department of Mechanical Engineering Sagar Institute of Research and Technology, Bhopal, M.P., India D.K. Mudaiya
More informationECE309 THERMODYNAMICS & HEAT TRANSFER MIDTERM EXAMINATION. Instructor: R. Culham. Name: Student ID Number:
ECE309 THERMODYNAMICS & HEAT TRANSFER MIDTERM EXAMINATION June 19, 2015 2:30 pm - 4:30 pm Instructor: R. Culham Name: Student ID Number: Instructions 1. This is a 2 hour, closed-book examination. 2. Permitted
More informationIS A PARTICULAR PROCESS / REACTION FEASIBLE? TO WHAT EXTENT DOES THE PROCESS / REACTION PROCEED?
Limitations of First Law of Thermodynamics The first law of thermodynamics is a law of conservation of energy. It does not specify the direction of the process. All spontaneous processes processed in one
More informationUNIT I Basic concepts and Work & Heat Transfer
SIDDHARTH GROUP OF INSTITUTIONS :: PUTTUR Siddharth Nagar, Narayanavanam Road 517583 QUESTION BANK (DESCRIPTIVE) Subject with Code: Engineering Thermodynamics (16ME307) Year & Sem: II-B. Tech & II-Sem
More informationEngineering Thermodynamics. Chapter 5. The Second Law of Thermodynamics
5.1 Introduction Chapter 5 The Second aw of Thermodynamics The second law of thermodynamics states that processes occur in a certain direction, not in just any direction. Physical processes in nature can
More informationPure Substances Phase Change, Property Tables and Diagrams
Pure Substances Phase Change, Property Tables and Diagrams In this chapter we consider the property values and relationships of a pure substance (such as water) which can exist in three phases - solid,
More informationPart III: Planes, Trains, and Automobiles: Making Heat Work for You
Contents at a Glance Introduction... 1 Part I: Covering the Basics in Thermodynamics... 7 Chapter 1: Thermodynamics in Everyday Life...9 Chapter 2: Laying the Foundation of Thermodynamics...15 Chapter
More information