Determinants: summary of main results
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1 Determinants: summary of main results A determinant of an n n matrix is a real number associated with this matrix. Its definition is complex for the general case We start with n = 2 and list important properties for this case. DETERMINANTS CHAP. 3 Determinant of a 2 2 matrix is: Notation : det (A) or a b c d det a b = ad bc c d Next we list the main properties of determinants. These properties are also true for n n case to be defined later. Det(A) for n n case can be defined from GE when permutation is not used: Det(A) = product of pivots in GE. More on this later Text: DET Properties written for columns (easier to write) but are also true for rows Notation: We let A = [u, v] columns u, and v are in R 2. 1 If v = αu then det (A) = 0. Determinant of linearly dependent vectors is zero If any one column is zero then determinant is zero 2 Interchanging columns or rows: 3 Linearity: det [v, u] = det [u, v] det [u, αv + βw] = αdet [u, v] + βdet [u, w] det (A) = linear function of each column (individually) det (A) = linear function of each row (individually) What is the determinant det [u, v + αu]? 4 Determinant of transpose det (A) = det (A T ) 5 Determinant of Identity det (I) = 1 6 Determinant of a diagonal: det (D) = d 1 d 2 d n 10-3 Text: DET 10-4 Text: DET
2 7 Determinant of a triangular matrix (upper or lower) det (T ) = a 11 a 22 a nn 8 Determinant of product of matrices [IMPRTANT] det (AB) = det (A)det (B) 9 Consequence: Determinant of inverse det (A 1 ) = 1 det (A) What is the determinant of αa (for 2 2 matrices)? What can you say about the determinant of a matrix which satisfies A 2 = I? Is it true that det (A + B) = det (A) + det (B)? 10-5 Text: DET Determinants 3 3 case We will define 3 3 determinants from 2 2 determinants: a 11 a 12 a 13 a 21 a 22 a 23 a 31 a 32 a 33 = a 11 a 22 a 23 a 32 a 33 a 12 a 21 a 23 a 31 a 33 + a 13 a 21 a 22 a 31 a 32 This is an expansion of the det. with respect to its 1st row. 1st term = a 11 det of matrix obtained by deleting 1st row and 1st column. 2nd term = a 12 det of matrix obtained by deleting row 1 and column 2. Note the sign change. 3rd term = a 13 det of matrix obtained by deleting row 1 and column Text: DET Calculate We will now generalize this definition to any dimension recursively. Need to define following notation. We will denote by A ij is the (n 1) (n 1) matrix obtained by deleting row i and column j from the matrix A. Example: If A = A 12 = ; A = Then: A11 = 1 2 ; A = [ 2 ] ; Definition The determinant of a matrix A = [a ij ] is the sum det (A) = + a 11 det (A 11 ) a 12 det (A 12 ) + a 13 det (A 13 ) a 14 det (A 14 ) + + ( 1) 1+n a 1n det (A 1n ) Note the alternating signs We can write this as : n det (A) = ( 1) 1+j a 1j det (A 1j ) j=1 This is an expansion with respect to the 1st row Text: DET 10-8 Text: DET
3 Generalization: Cofactors Define c ij = ( 1) i+j det A ij = cofactor of entry i, j Then we get a more general expansion formula: det (A) can be expanded with respect to i-th as follows det (A) = a i1 c i1 + a i2 c i2 + + a in c in Note i is fixed. Can be done for any i [same result each time] Case i = 1 corresponds to definition given earlier Similar expressions for expanding w.r.t. column j (now j is fixed) Computing determinants using cofactors Compute the following deter minant by using co-factors. Ex pand with respect to 1st row Compute the above determinant by using co-factors. Expand with respect to last row. Then expand with respect to last column. Compute the following deter minant [expand with respect to last row!] Suppose two rows of A are swapped. Use the above definition to show that the determinant changes signs. det (A) = a 1j c 1j + a 2j c 2j + + a nj c nj 10-9 Text: DET Text: DET Let B be the matrix obtained from a matrix A by multiplying a certain row (or column) of A by a scalar α. Use the definition to show that: det (B) = αdet (A). What is the computational cost of evaluating the determinant using co-cofactor expansions? [Hint: It is BIG!] Compute F 2, F 3, F 4 1 when F n is the n-th dimensional determinant: 1 F n = (continuation) Challenge: Show a recurrence relation between F n, F n 1 and F n 2. Do you recognize this relation? Compute the first 8 values of F n Inverse of a matrix Let C = {c ij } the matrix of cofactors. Entry (i, j) of C has cofactor c ij. Then it is easy to prove that: Example: A 1 = 1 det (A) CT Inverse of a 2 2 matrix: 1 a b 1 d b = c d ad bc c a 2 2 Find the inverses of : and Text: DET Text: DET
4 Areas in R 2 Volumes in R 3 (a+c,b+d) (x3,y3) (x2, y2) z (x2,y2,z2) (c,d) (a,b) (x1, y1) (x3,y3,z3) (x1,y1,z1) y Left figure: Area of a parallelogram spanned [ by points (0, 0), (a, b), (c, d), (a+c, b+d) a c det is: b d] Right figure: Area of triangle spanned by 1 the points (x 1, y 1 ), (x 2, y 2 ), (x 3, y 3 ) is: 2 det x 1 x 2 x 3 y 1 y 2 y Text: DET Volume of parallelepiped spanned by origin and the 3 points (x 1, y 1, z 1 ), (x 2, y 2, z 2 ), (x 3, y 3, z 3 ) is: x det x 1 x 2 x 3 y 1 y 2 y 3 z 1 z 2 z 3 In summary: Volume (R 3 ) /area (R 2 ) of a box is det (A) when the box edges are the rows of A Text: DET Areas, Volumes, and Mappings Determinants are all about areas/volumes Text has a lot more detail See section Determinants as area or volume in text See example 4 in same section Linear mappings and determinants [p. 184 in text] Q: if a region in R 2 is transformed linearly (i.e., by a linear mapping T ) how does its area change? A: it is multiplied by the determinant of the matrix representing T. Stated in next theorem Theorem Let T the linear mapping from/to R 2 represented by a matrix A. If S is a parallelogram in R 2 then {area of T (S) } = det (A). {area of S } Similarly, if T is the linear mapping from/to R 3 represented by a matrix A and S is a parallelipiped in R 3 then {volume of T (S) } = det (A). {volume of S } Important point: Results also true for any region in R 2 (1st part) and R 3 (2nd part) See Example 4 in Section 3.2 which uses this to compute the area of an ellipse Text: DET Text: DET
5 How to compute determinants in practice? Co-factor expansion?? *Not practical*. Instead: Perform an LU factorization of A with pivoting. If a zero column is encountered LU fails but det(a) = 0 If not get det = product of diagonal entries multiplied by a sign ±1 depending on how many times we interchanged rows. Compute the determinants of the matrices A = B = Text: DET 10-17
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