Grade 4 Conversion of Units

Transcription

1 ID : cn-4-conversion-of-units [] Grade 4 Conversion of Units For more such worksheets visit Answer t he quest ions () Convert the units: 9 meter = decameter (2) Convert the units: 8 hectalitre = litre (3) What is the total length of the pole in centimeters if 30 cm is buried in the ground? (4) A small dam contains 490 kl 39 l 694 ml of water. One day, the dam authorities let out 572 kl 3 l 566 ml of water. How much water is remaining in the dam now (in litres)? (5) An elevator in a mall can carry adults or 22 children at one time. Suppose there are 7 adults in the lif t, how many additional children can be accomodated? (6) Lian has a 4 meter long rope. He needs to cut out pieces of length 0 cm f rom it. How many pieces can he cut? Choose correct answer(s) f rom given choice (7) Shan is driving down to Lu'an f or a vacation, and has already traveled kms. If he has traveled 7 20 of the distance, then what is the total distance he drives to get to Lu'an? a. 6 km b. 90 km c. 7 km d. 2 km (8) A tank of water contains 90 liters and 920 milliliters of water. There's a hole in the bottom of the tank through which l 460 ml water leaks away every hour. How many liters of water are lef t in the tank af ter 3 hours? a. 86 liters 540 milliliters b. 85 liters 96 milliliters c. 89 liters 282 milliliters d. 83 liters 40 milliliters

2 ID : cn-4-conversion-of-units [2] Fill in the blanks (9) Yue Wan takes a bus and travels 65 km 30 m. She then travels 7.42 km by taxi, and walks 3 km 90 m. The total distance she travels is km m. (0) Convert the units: A) centilitre = decalitre B) kilogram = 70 hectagram C) kilogram = 4000 gram D) 6 kilolitre = decilitre () Each bag of oranges weighs 5 kgs 240 grams. If the total weight of a sack containing oranges bags is kgs, then bags are in the sack. (2) The diagram below shows the weights of two bags of rice. The scale would be balanced if grams of rice is added to the bag Q. (3) Solve the f ollowing: A) 70 cm 8 dam 7 m = mm B) 55 dag 50 kg 28 mg = g C) 42 m 22 mm 59 dam = D) 4 dal 7 cl 85 ml = l hm (4) Solve the f ollowing: A) centimeter to hectometer B) centimeter to meter C) decigram to gram D) milligram to hectogram (5) A large container in a depot contains 9 litres and 645 millilitre of diesel. Each of 3 workers added 6 L 59 ml of diesel to the container. The amount of diesel in the container now is l ml.

3 ID : cn-4-conversion-of-units [3] 206 Edugain ( All Rights Reserved Many more such worksheets can be generated at

4 Answers ID : cn-4-conversion-of-units [4] ().9 (2) 800 (3) 580 cms The total length of the pole is the sum of lengths of the part above the ground and the part buried in the ground. By looking at the f igure, we know the length of the pole above the ground = 5.5 m = 550 cm. The length of the pole buried in the ground = 30 cm. Total length of the pole = 550 cm + 30 cm = 580 cms (4) l Total water in a small dam = 490 kl 39 l 694 ml 490 kl into l = = l 694 ml into l = 694/000 = l Total water in the dam in l = l + 39 l l = l Water let out f rom the dam = 572 kl 3 l 566 ml 572 kl into l = = l 566 ml into l = 566/000 = l Water let out f rom the dam in l = l + 3 l l = l Water lef t in the dam = Total water in the dam in l - Water let out f rom the dam in l = = l Theref ore, l water is remaining in the dam.

5 (5) 8 ID : cn-4-conversion-of-units [5] According to the question, an elevator in a mall can carry adults or 22 children at one time. It means that weight of adults is equal to the weight of 22 children. Theref ore the average weight of an adult is equal to the average weight of 22 = 2 children. Now, adults in the lif t = 7 Number of the additional adults that lif t can carry = - 7 = 4 Theref ore the number of additional children that lif t can carry = 4 2 = 8 Theref ore, the number of additional children that can be accommodated are 8. (6) 40 Total length of the rope = 4 meter Length of each piece needed = 0 Total number of pieces that Lian can cut = Total length of the rope Length of the piece = 4 meter 0 cm = = cm 0 cm Theref ore, Lian can cut 40 pieces of length 0 cm f rom a rope 4 meter long. (7) c. 7 km

6 (8) a. 86 liters 540 milliliters ID : cn-4-conversion-of-units [6] Amount of water leaked in one hour = liters and 460 milliliters Theref ore water leaked in 3 hours = = liters There remaining water, = Original amount of water - leaked water = = liters = 86 liters 540 milliliters (9) Distance Yue Wan traveled by bus = 65 km 30 m Distance Yue Wan traveled by taxi = 7.42 km Distance Yue Wan covered by walk = 3 km 90 m Total distance traveled by the Yue Wan = Distance traveled by bus + Distance traveled by taxi + Distance traveled by walk = 65 km 30 m km + 3 km 90 m = km km km = km Step 5 Theref ore, the total distance traveled by Yue Wan is km. (0) A) B) C) D)

7 () 32 ID : cn-4-conversion-of-units [7] Since we know that kg = 000 grams, 240 grams = 240/000 = kgs, 5 kgs 240 grams = kgs. According to the question, the weight of each bag of oranges = 5 kgs 240 grams. or we can say that, kgs weighs of the oranges contained by the bag = bag. or kg weighs of the oranges contained by the bags = bags. Theref ore, kgs weight of the oranges contained by the number of bags = = = = 32 bags Thus, the number of bags in the sack = 32 bags (2) 500 We know that a scale is balanced, when weight on both sides are equal. Lef t span of balance has 5.7kg rice, while right span has 5.2kg rice. Theref ore we need to add dif f erence between two weights to right side span in order to balance the scale Theref ore amount of rice to be added right span, = 5.7 kg kg = 0.5 kg = grams = 500 grams

8 (3) A) ID : cn-4-conversion-of-units [8] We know that, Centimeter(cm) = 0.0 meter(m) Dakameter(dam) = 0 meter(m) 70 cm = m = 0.7 meter(m) 8 dam = 8 0 m = 80 meter(m) Theref ore, 70 cm 8 dam 7 m = 0.7 m + 80 m + 7 m = 97.7 m Since, meter = 000 Millimeter(mm) Theref ore, 97.7 m = mm = mm Thus, 70 cm 8 dam 7 m is equal to mm. B) We know that, Dakagram(dag) = 0 gram(g) Kilogram(kg) = 000 gram(g) Milligram(mg) = 0.00 gram(g) 55 dag = 55 0 g = 550 gram(g) 50 kg = g = gram(g) 28 mg = g = gram(g) Theref ore, 55 dag 50 kg 28 mg = 550 g g g = g Thus, 55 dag 50 kg 28 mg is equal to g.

9 C) ID : cn-4-conversion-of-units [9] We know that, Millimeter(mm) = 0.00 meter(m) Dakameter(dam) = 0 meter(m) 22 mm = m = meter(m) 59 dam = 59 0 m = 590 meter(m) Theref ore, 42 m 22 mm 59 dam = 42 m m m = m Since, meter = 0.0 Hectometer(hm) Theref ore, m = hm = hm Thus, 42 m 22 mm 59 dam is equal to hm. D) We know that, Dakaliter(dal) = 0 liter(l) Centiliter(cl) = 0.0 liter(l) Milliliter(ml) = 0.00 liter(l) 4 dal = 4 0 l = 40 liter(l) 7 cl = l = 0.7 liter(l) 85 ml = l = liter(l) Theref ore, 4 dal 7 cl 85 ml = 40 l l l = l Thus, 4 dal 7 cl 85 ml is equal to l.

10 (4) A) ID : cn-4-conversion-of-units [0] We have been asked to Convert centimeter to hectometer. We know that meter = 00 centimeter or centimeter = meter = 0.0 meter 00 or centimeter = meter = meter Since, hectometer = 00 meter or meter = 00 hectometer = 0.0 hectometer or meter = hectometer = hectometer T hus, centimeter is equal to hectometer. B) We have been asked to Convert centimeter to meter. We know that meter = 00 centimeter or centimeter = meter = 0.0 meter 00 or centimeter = meter = meter T hus, centimeter is equal to meter.

11 C) ID : cn-4-conversion-of-units [] We have been asked to Convert decigram to gram. We know that gram = 0 decigram or decigram = gram = 0. gram 0 or decigram = gram = gram T hus, decigram is equal to gram. D) We have been asked to Convert milligram to hectogram. We know that gram = 000 milligram or milligram = gram = 0.00 gram 000 or milligram = gram = gram Since, hectogram = 00 gram or gram = hectogram = 0.0 hectogram 00 or gram = hectogram = hectogram T hus, milligram is equal to hectogram.

12 (5) ID : cn-4-conversion-of-units [2] Lets convert the quantity of the diesel in the same unit i.e. litres. We know that ml = /000 l Total diesel in the container = 9 litres 645 millilitre = /000 litres = litres The diesel added to the container by each worker = 6 litre 59 ml = /000 litres = 6.59 litres The diesel added to the container by 3 workers = 6.59 * 3 = litres Step 5 Total amount of diesel in the container = = litre = 39 litre 20 ml Step 6 Theref ore, the total amount of diesel in the container is 39 litre 20 ml.