Nondeterministic Finite Automata and Regular Expressions
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1 Nondeterministic Finite Automata and Regular Expressions CS 2800: Discrete Structures, Spring 2015 Sid Chaudhuri
2 Recap: Deterministic Finite Automaton A DFA is a 5-tuple M = (Q, Σ, δ, q 0, F) Q is a finite set of states Σ is a finite input alphabet (e.g. {0, 1}) δ is a transition function δ : Q Σ Q q 0 Q is the start/initial state F Q is the set of final/accepting states 0 Yes 1 1 No 0
3 csunplugged.com, clubpenguin.wikia.com
4 P = NP!!! csunplugged.com, clubpenguin.wikia.com
5 P = NP!!! csunplugged.com, clubpenguin.wikia.com
6 A NON-deterministic finite automaton lets you try all possible choices in parallel. If ANY choice leads you to the treasure, the pirate can't harm you! P = NP!!! csunplugged.com, clubpenguin.wikia.com
7 A non-deterministic finite automaton q 0 1 0,1 0,1 q 1 0,1 q 2
8 A non-deterministic finite automaton Different transitions from q 0 on input 1 q 0 1 0,1 0,1 q 1 0,1 q 2
9 A non-deterministic finite automaton Different transitions from q 0 on input 1 q 0 1 0,1 0,1 q 1 0,1 q 2 An NFA accepts a string x if it can get to an accepting state on input x
10 A non-deterministic finite automaton q 0 1 0,1 0,1 q 1 0,1 q 2 What language does this automaton accept?
11 A non-deterministic finite automaton q 0 1 0,1 0,1 q 1 0,1 q 2 Answer: All strings ending with 1
12 Another NFA 1 0,1 0,1 0,1 q 0 q q 0,1 1 2 q 3 What language does this automaton accept?
13 Another NFA 1 0,1 0,1 0,1 q 0 q q 0,1 1 2 q 3 Answer: All strings with 1 in the penultimate place
14 Non-deterministic Finite Automaton An NFA is a 5-tuple M = (Q, Σ, δ, q 0, F)
15 Non-deterministic Finite Automaton An NFA is a 5-tuple M = (Q, Σ, δ, q 0, F) Q is a finite set of states q 0 q 1 q 2 q 3
16 Non-deterministic Finite Automaton An NFA is a 5-tuple M = (Q, Σ, δ, q 0, F) Q is a finite set of states Σ is a finite input alphabet (e.g. {0, 1}) q 0 q 1 q 2 q 3
17 Non-deterministic Finite Automaton An NFA is a 5-tuple M = (Q, Σ, δ, q 0, F) Q is a finite set of states Σ is a finite input alphabet (e.g. {0, 1}) δ is a transition function δ : Q Σ 2 Q 1 0,1 0,1 0,1 q 2 0,1 q 0 q 1 q 3
18 Non-deterministic Finite Automaton An NFA is a 5-tuple M = (Q, Σ, δ, q 0, F) Q is a finite set of states Σ is a finite input alphabet (e.g. {0, 1}) δ is a transition function δ : Q Σ 2 Q Only change from DFAs 1 0,1 0,1 0,1 q 2 0,1 q 0 q 1 q 3
19 Non-deterministic Finite Automaton An NFA is a 5-tuple M = (Q, Σ, δ, q 0, F) Q is a finite set of states Σ is a finite input alphabet (e.g. {0, 1}) δ is a transition function δ : Q Σ 2 Q Only change from DFAs q 0 Q is the start/initial state 1 0,1 0,1 0,1 q 2 0,1 q 0 q 1 q 3
20 Non-deterministic Finite Automaton An NFA is a 5-tuple M = (Q, Σ, δ, q 0, F) Q is a finite set of states Σ is a finite input alphabet (e.g. {0, 1}) δ is a transition function δ : Q Σ 2 Q Only change from DFAs q 0 Q is the start/initial state F Q is the set of final/accepting states 1 0,1 0,1 0,1 q 2 0,1 q 0 q 1 q 3
21 Non-deterministic Finite Automaton An NFA accepts a string x if it can get to an accepting state on input x
22 Non-deterministic Finite Automaton An NFA accepts a string x if it can get to an accepting state on input x Think of it as trying many options in parallel, and hoping one path gets lucky
23 Non-deterministic Finite Automaton An NFA accepts a string x if it can get to an accepting state on input x Think of it as trying many options in parallel, and hoping one path gets lucky Transition f (state, symbol) is possible
24 Non-deterministic Finite Automaton An NFA accepts a string x if it can get to an accepting state on input x Think of it as trying many options in parallel, and hoping one path gets lucky Transition f (state, symbol) is possible the NFA treats this as a rejecting path (the string may still reach an accepting state by another path)
25 Non-deterministic Finite Automaton An NFA accepts a string x if it can get to an accepting state on input x Think of it as trying many options in parallel, and hoping one path gets lucky Transition f (state, symbol) is possible the NFA treats this as a rejecting path (the string may still reach an accepting state by another path) A convenient shortcut for our hell/black-hole state
26 Non-deterministic Finite Automaton An NFA accepts a string x if it can get to an accepting state on input x Think of it as trying many options in parallel, and hoping one path gets lucky Transition f (state, symbol) is possible the NFA treats this as a rejecting path (the string may still reach an accepting state by another path) A convenient shortcut for our hell/black-hole state Class convention: Draw all possible transitions for DFA. Not required for NFA (missing transitions lead to hell).
27 Non-deterministic Finite Automaton Every DFA is an NFA
28 Non-deterministic Finite Automaton Every DFA is an NFA If we're strict with our notation, we need to replace the transition f (state 1, symbol) state 2 with f (state 1, symbol) {state 2 }
29 Non-deterministic Finite Automaton Every DFA is an NFA If we're strict with our notation, we need to replace the transition f (state 1, symbol) state 2 with f (state 1, symbol) {state 2 } Every NFA can be simulated by a DFA
30 Non-deterministic Finite Automaton Every DFA is an NFA If we're strict with our notation, we need to replace the transition f (state 1, symbol) state 2 with f (state 1, symbol) {state 2 } Every NFA can be simulated by a DFA i.e. they accept exactly the same language
31 Non-deterministic Finite Automaton Every DFA is an NFA If we're strict with our notation, we need to replace the transition f (state 1, symbol) state 2 with f (state 1, symbol) {state 2 } Every NFA can be simulated by a DFA i.e. they accept exactly the same language Exponential blowup: if the NFA has n states, the DFA can require up to 2 n states
32 Thought for the Day #1 Find an NFA with n states that can't be simulated by a DFA with less than 2 n states
33 Every NFA can be simulated by a DFA
34 Every NFA can be simulated by a DFA p a a q r NFA (fragment)
35 Every NFA can be simulated by a DFA p a a q r NFA (fragment) DFA (fragment) a {p} {q, r}
36 Every NFA can be simulated by a DFA p a a q r Subset construction Main idea: ONE state of DFA tracks current states of ALL evolving paths of NFA NFA (fragment) DFA (fragment) a {p} {q, r} (This is merely illustrative formal construction on following slides)
37 Every NFA can be simulated by a DFA NFA Equivalent DFA Specification States Alphabet Transition Function Initial State Accepting States
38 Every NFA can be simulated by a DFA NFA Equivalent DFA Specification (Q, Σ, δ, q 0, F) (2 Q, Σ, δ', q' 0, F') States Alphabet Transition Function Initial State Accepting States
39 Every NFA can be simulated by a DFA NFA Equivalent DFA Specification (Q, Σ, δ, q 0, F) (2 Q, Σ, δ', q' 0, F') States Q 2 Q Alphabet Transition Function Initial State Accepting States
40 Every NFA can be simulated by a DFA NFA Equivalent DFA Specification (Q, Σ, δ, q 0, F) (2 Q, Σ, δ', q' 0, F') States Q 2 Q Alphabet Σ Σ Transition Function Initial State Accepting States
41 Every NFA can be simulated by a DFA NFA Equivalent DFA Specification (Q, Σ, δ, q 0, F) (2 Q, Σ, δ', q' 0, F') States Q 2 Q Alphabet Σ Σ Transition Function δ δ'(s, a) = s S δ(s, a) Initial State Accepting States
42 Every NFA can be simulated by a DFA NFA Equivalent DFA Specification (Q, Σ, δ, q 0, F) (2 Q, Σ, δ', q' 0, F') States Q 2 Q Alphabet Σ Σ Transition Function δ δ'(s, a) = s S δ(s, a) Initial State q 0 q' 0 = {q 0 } Accepting States
43 Every NFA can be simulated by a DFA NFA Equivalent DFA Specification (Q, Σ, δ, q 0, F) (2 Q, Σ, δ', q' 0, F') States Q 2 Q Alphabet Σ Σ Transition Function δ δ'(s, a) = s S δ(s, a) Initial State q 0 q' 0 = {q 0 } Accepting States F F' = {S 2 Q S F }
44 Why NFAs?
45 Why NFAs? They can be way more compact than DFAs
46 Why NFAs? They can be way more compact than DFAs 0,1 1 q 0 q 1 0,1 q 3 q 2 0,1 NFA
47 Why NFAs? They can be way more compact than DFAs 1 1 q 0 q q 000 q 001 q 010 q ,1 0, q 3 q 2 0,1 0 q 100 q 101 q 110 q NFA Equivalent minimal DFA
48 Why NFAs? They can be way more compact than DFAs 1 1 q 0 q q 000 q 001 q 010 q ,1 0, q 3 q 2 0,1 0 q 100 q 101 q 110 q NFA Equivalent minimal DFA It's easier to directly convert regular expressions ( wildcard search on steroids) to NFAs
49 XKCD
50 Playing with regexes
51 Regular expressions ( regex -es) are defined by structural induction (start with simple base expressions, construct more complicated ones recursively)
52 Empty set L( ) =
53 Empty string L(ε) = {ε}
54 Literal character L(x) = {x} e.g. L(1) = {1}, L(2) = {2}, L(a) = {a}
55 Concatenation L(AB) = {ab a L(A), b L(B)} e.g. L(12) = {12}, L(aabb) = {aabb}
56 Concatenation L(AB) = {ab a L(A), b L(B)} e.g. L(12) = {12}, L(aabb) = {aabb}, L(aε) =?
57 Concatenation L(AB) = {ab a L(A), b L(B)} e.g. L(12) = {12}, L(aabb) = {aabb}, L(aε) = {a}
58 Concatenation L(AB) = {ab a L(A), b L(B)} e.g. L(12) = {12}, L(aabb) = {aabb}, L(aε) = {a}, L(a ) =?
59 Concatenation L(AB) = {ab a L(A), b L(B)} e.g. L(12) = {12}, L(aabb) = {aabb}, L(aε) = {a}, L(a ) =
60 Alternation L(A B) = L(A) L(B) e.g. L(1 2) = {1, 2}, L(aa bb) = {aa, bb}
61 Alternation L(A B) = L(A) L(B) e.g. L(1 2) = {1, 2}, L(aa bb) = {aa, bb}, L(a ε) =?
62 Alternation L(A B) = L(A) L(B) e.g. L(1 2) = {1, 2}, L(aa bb) = {aa, bb}, L(a ε) = {a, ε}
63 Alternation L(A B) = L(A) L(B) e.g. L(1 2) = {1, 2}, L(aa bb) = {aa, bb}, L(a ε) = {a, ε}, L(a ) =?
64 Alternation L(A B) = L(A) L(B) e.g. L(1 2) = {1, 2}, L(aa bb) = {aa, bb}, L(a ε) = {a, ε}, L(a ) = {a}
65 Kleene star L(A*) = {ε} { x 1 x 2...x n n N, x i L(A) } e.g. L(a*) = {ε, a, aa, aaa, aaaa,...}
66 Kleene star L(A*) = {ε} { x 1 x 2...x n n N, x i L(A) } e.g. L(a*) = {ε, a, aa, aaa, aaaa,...}, L((ab)*) =?
67 Kleene star L(A*) = {ε} { x 1 x 2...x n n N, x i L(A) } e.g. L(a*) = {ε, a, aa, aaa, aaaa,...}, L((ab)*) = {ε, ab, abab, ababab,...}
68 Kleene star L(A*) = {ε} { x 1 x 2...x n n N, x i L(A) } e.g. L(a*) = {ε, a, aa, aaa, aaaa,...}, L((ab)*) = {ε, ab, abab, ababab,...}, L((a b)*) =?
69 Kleene star L(A*) = {ε} { x 1 x 2...x n n N, x i L(A) } e.g. L(a*) = {ε, a, aa, aaa, aaaa,...}, L((ab)*) = {ε, ab, abab, ababab,...}, L((a b)*) = {ε, a, b, aa, ab, ba, bb, aaa, aab, aba,...}
70 Kleene star L(A*) = {ε} { x 1 x 2...x n n N, x i L(A) } e.g. L(a*) = {ε, a, aa, aaa, aaaa,...}, L((ab)*) = {ε, ab, abab, ababab,...}, L((a b)*) = {ε, a, b, aa, ab, ba, bb, aaa, aab, aba,...}, L(ε*) =?
71 Kleene star L(A*) = {ε} { x 1 x 2...x n n N, x i L(A) } e.g. L(a*) = {ε, a, aa, aaa, aaaa,...}, L((ab)*) = {ε, ab, abab, ababab,...}, L((a b)*) = {ε, a, b, aa, ab, ba, bb, aaa, aab, aba,...}, L(ε*) = {ε}
72 Kleene star L(A*) = {ε} { x 1 x 2...x n n N, x i L(A) } e.g. L(a*) = {ε, a, aa, aaa, aaaa,...}, L((ab)*) = {ε, ab, abab, ababab,...}, L((a b)*) = {ε, a, b, aa, ab, ba, bb, aaa, aab, aba,...}, L(ε*) = {ε}, L( *) =?
73 Kleene star L(A*) = {ε} { x 1 x 2...x n n N, x i L(A) } e.g. L(a*) = {ε, a, aa, aaa, aaaa,...}, L((ab)*) = {ε, ab, abab, ababab,...}, L((a b)*) = {ε, a, b, aa, ab, ba, bb, aaa, aab, aba,...}, L(ε*) = {ε}, L( *) = {ε}
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