Simplify each numerical expression. Show all work! Only use a calculator to check. 1) x ) 25 ( x 2 3) 3) 4)
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1 NAME HONORS ALGEBRA II REVIEW PACKET To maintain a high quality program, students entering Honors Algebra II are expected to remember the basics of the mathematics taught in their Algebra I course. In order to review the basic concepts prior to taking Honors Algebra II, the mathematics department has prepared this review packet. For each algebra topic addressed, this packet contains several review examples with online tutorials followed by problems for the student to practice. Since this material is designed as review, you are responsible for completing this packet on your own. The packet will be collected and checked by the teacher to assess the student s efforts to recall this information. Be sure to SHOW ALL WORK to receive credit. We will take a quiz on this material in September. I. Order of Operations (PEMDAS) Parenthesis and other grouping symbols. Exponential expressions. Multiplication, Division, & taking the Opposite. Addition & Subtraction. Tutorial: Simplify each numerical expression. Show all work! Only use a calculator to check. 1) x ) 25 ( x 2 3) 3) 4)
2 II. Evaluating Algebraic Expressions To evaluate an algebraic expression: Substitute the given value(s) of the variable(s). Use order of operations to find the value of the resulting numerical expression. Evaluate. 1) 2) 12a 4a 2 + 7a 3 if a = - 3 3) 4) 5) if x = 3 and y = 4 6)
3 III. Simplifying Radicals An expression under a radical sign is in simplest radical form when: 1) there is no integer under the radical sign with a perfect square factor, 2) there are no fractions under the radical sign, 3) there are no radicals in the denominator Express the following in simplest radical form. 1) 2) 3) 4) 5) 6) 7) 8) IV. Properties of Exponents Complete the example problems. PROPERTY Product of Powers a m a n = a m + n x 4 x 2 = Power of a Power (a m ) n = a m n (x 4 ) 2 = Power of a Product (ab) m = a m b m (2x) 3 = Negative Power x a - n = (a 0) - 3 = EXAMPLE Zero Power a 0 = 1 (a 0) 4 0 = Quotient of Powers = a m n (a 0) = Power of Quotient = (b 0) = Simplify each expression. Answers should be written using positive exponents. 1) g 5 g 11 2) (b 6 ) 3 3) w - 7 4) 5) (3x 7 )(- 5x - 3 ) 6) (- 4a - 5 b 0 c) 2 7) 8)
4 V. Solving Linear Equations To solve linear equations, first simplify both sides of the equation. If the equation contains fractions, multiply the equation by the LCD to clear the equation of fractions. Use the addition and subtraction properties of equality to get variables on one side and constants on the other side of the equal sign. Use the multiplication and division properties of equality to solve for the variable. Express all answers as fractions in lowest terms. Solving Linear Equations: Solving Equations: Examples: Solve for the indicated variable: 1) 3n + 1 = 7n 5 2) 2[x + 3(x 1)] = 18 3) 6(y + 2) - 4 = ) 2x 2 = 50 5) 5 + 2(k + 4) = 5(k - 3) ) 6 + 2x(x 3) = 2x 2 7) 8)
5 VI. Rewriting Formulas and Equations Simplify both sides of the equations to isolate the variable you are solving for. Solve the equation for y. 1) 8y 3x =18 2) xy 6y = ) Solve for C, 4) Solve, for h. VII. Absolute Value Equations To solve an absolute value equation, you must remember that there are two possible solutions. Absolute-value equations always work this way: to be able to remove the absolute-value bars, you have to isolate the absolute value onto one side, and then split the equation into the two possible cases. Remember to check your work to see if the solutions work! Solve each absolute value equation. 1) 2) 3) 4)
6 VIII. Solve Linear Inequalities Solve each inequality. Graph the solutions on a number line. 1) 2) 4x 1 = 2 (2x + 3) 3) 12 3(6x 2) > 4(x + 5) (9 x) 4) 5x 11 x > 2x ) 6) 7) 8)
7 IX. Operations With Polynomials To add or subtract polynomials, just combine like terms. To multiply polynomials, multiply the numerical coefficients and apply the rules for exponents. Polynomials (adding & subtracting): Polynomials (multiplying): Examples: a) (x 2 + 3x - 2) - (3x 2 - x + 5) x 2 + 3x - 2-3x 2 + x - 5-2x 2 + 4x - 7 c) 4(5x 2 + 3x - 4) + 3(- 2x 2-2x + 3) 20x x x 2-6x x 2 + 6x - 7 b) 3x(2x + 5) 2 3x(4x x + 25) 12x x x d) (4x - 5)(3x + 7) 12x x - 15x x x - 35 Perform the indicated operations and simplify: 1) (7x 2 + 4x - 3) - (- 5x 2-3x + 2) 2) (7x - 3)(3x + 7) 3) (4x + 5)(5x + 4) 4) (n 2 + 5n + 3) + (2n 2 + 8n + 8) 5) (5x 2-4) 2(3x 2 + 8x + 4) 6) - 2x(5x + 11) 7) (2m + 6)(2m + 6) 8) (5x 6) 2
8 X. Factoring Polynomials Examples: Factoring out the GCF Difference of Squares Perfect Square Trinomial a) 6x x b) x 2-64 c) x 2-10x x(2x + 7) (x - 8)(x + 8) (x 5) 2 Trinomial d) 3x 2 + 7x + 2 Trinomial e) 2x 2-13x + 15 Trinomial f) 6x 2 + x 1 (3x + l)(x + 2) (2x - 3)(x - 5) (3x - 1)(2x + 1) Factoring Trinomials (skip substitution method): i.htm Factoring Polynomials (video): Factoring a Trinomial: Factoring: topic.cfm?topiccode=factor Factor Completely. 1) 16y 2 + 8y 2) 18x 2-12x 3) 6m 2-60m ) 6y 2-13y 5 5) 20x x - 7 6) 12x x ) x 2-2x ) 8x 2-6x - 9 9) x 2 121
9 XI. Linear Equations in Two Variables Examples: a) Find the slope of the line passing through the points (- 1, 2) and (3, 5). b) Graph y = 2/3 x - 4 with slope- intercept method. Reminder: y = mx + b is slope- intercept form where m = slope and b = y- intercept. Therefore, slope is 2/3 and the y- intercept is 4. Graph accordingly. c) Graph 3x - 2y - 8 = 0 with slope- intercept method. Put in Slope- Intercept form: y = - 3/2 x + 4 m = 3/2 b = - 4 d) Write the equation of the line with a slope of 3 and passing through the point (2, - 1) y = mx + b - 1 = 3(2) + b - 7 = b Equation: y = 3x 7 Using the slope and y- intercept to graph lines: Straight- line equations (slope- intercept form): Slopes and Equations of Lines: Find the slope of the line passing through each pair of points: 1) (- 3, - 4) (- 4, 6) 2) (- 4, - 6) (- 4, - 8) 3) (- 5, 3) (- 11, 3) Write an equation, in slope- intercept form using the given information. 6) (- 6, - 3) (- 2, - 5) 4) (5, 4) m = 5) (- 2, 4) m = - 3
10 XII. Solving Systems of Equations Solve for x and y: x = 2y + 5 3x + 7y = 2 Using substitution method: 3(2y + 5) + 7y = 2 6y y = 2 13y = - 13 y = - 1 x = 2(- 1) + 5 x=3 Solution: (3, - 1) Solve for x and y: 3x + 5y = 1 2x + 3y = 0 Using linear combination (addition/ subtraction) method: 3(3x + 5y = 1) - 5(2x + 3y = 0) 9x + 15y = 3 - l0x - 15y = 0-1x = 3 x = - 3 2(- 3) + 3y = 0 y=2 Solution: (- 3, 2) Solve each system of equations by either the substitution method or the linear combination (addition/ subtraction) method. Write your answer as an ordered pair. Solve systems of linear equations: topic.cfm?topiccode=syslin Solve systems of equations (video): Systems of Linear Equations: 1) y = 2x + 4 2) 2x + 3y = 6-3x + y = - 9-3x + 2y = 17 3) x 2y = 5 4) 3x + 7y = - 1 3x 5y = 8 6x + 7y = 0
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