On my honor, I have neither given nor received unauthorized aid on this examination.
|
|
- Sybil Anthony
- 6 years ago
- Views:
Transcription
1 Instructor(s): F.E. Dunnam PHYSICS DEPARTMENT PHY nd Exam 08 July 2008 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized aid on this examination. YOUR TEST NUMBER IS THE 5-DIGIT NUMBER AT THE TOP OF EACH PAGE. (1) Code your test number on your answer sheet (use for the 5-digit number). Code your name on your answer sheet. DARKEN CIRCLES COMPLETELY. Code your UFID number on your answer sheet. (2) Print your name on this sheet and sign it also. (3) Do all scratch work anywhere on this exam that you like. Circle your answers on the test form. At the end of the test, this exam printout is to be turned in. No credit will be given without both answer sheet and printout. (4) Blacken the circle of your intended answer completely, using a #2 pencil or blue or black ink. Do not make any stray marks or some answers may be counted as incorrect. (5) The answers are rounded off. Choose the closest to exact. There is no penalty for guessing. If you believe that no correct answer is listed, leave this item blank!! (6) Hand in the answer sheet separately. Useful (??) Constants: µ 0 = 4π 10 7 Tm/A ɛ 0 = C 2 /(Nm 2 ) electron charge = C electron mass = kg V=volt N=newton J=joule m=meter W=watt µ = micro- = 10 6 A = ampere pico = n = nano = 10 9 m = milli = 10 3 proton mass = kg c = m/s 1. Immediately after switch S in the circuit shown is closed, the current through the battery shown is: (1) V o /(R 1 + R 2 ) (2) V o /R 1 (3) V o /R 2 (4) 0 (5) V o (R 1 + R 2 )/(R 1 R 2 ) SOLUTION: At the instant of circuit-closure, L s back emf allows no current to pass through it, so I = V o /(R 1 +R 2 ) 2. For the above circuit, a long time after the switch is closed, the current through the inductor will be approximately (1) V o /R 1 (2) V o /(R 1 + R 2 ) (3) V o /R 2 (4) 0 (5) V o (R 1 + R 2 )/(R 1 R 2 ) SOLUTION: After a long time, L s back emf is zero, so V R1 = 0 and thus I = V o /R 1 3. When switch S is open, the ammeter in the circuit shown reads 2.0 A. When S is closed, the ammeter reading will: (1) increase slightly (2) remain the same (3) decrease slightly (4) double (5) halve SOLUTION: Closing S provides another conducting path, reducing the total R slightly, so A increases slightly
2 4. In the circuit shown, the capacitor is initially uncharged and V = 9.0 volts. At time t = 0, switch S is closed. If τ denotes the time constant, the approximate current through the 3Ω resistor when t = τ/100 is: (1) 1 A (2) 1/2 A (3) 3/4 A (4) 3/8 A (5) 3/2 A SOLUTION: I = E/R[1 e ( t/rc)]. The time constant = 1/RC. If 1/RC = 1/100, then we have I = 9v/9Ω[1 e ( 100)] = 1A[1 0] = 1A 5. An electron is moving southward in a region where the magnetic field is directed northward. The magnetic force exerted on the electron is: (1) zero (2) up (3) down (4) east (5) west SOLUTION: If v is parallel to B, the force is zero! 6. A beam of electrons is sent horizontally down the axis of a tube to strike a fluorescent screen at the end of the tube. On the way, the electrons encounter a magnetic field directed vertically downward. The spot on the screen will therefore be deflected: (1) to the right as seen from the electron source (2) upward (3) downward (4) to the left as seen from the electron source (5) not at all SOLUTION: By the right-hand-rule, the beam is deflected to the right 7. The figure shows the motion of electrons in a wire which is near the N pole of a magnet. The wire will be pushed: (1) upwards (2) toward the magnet (3) away from the magnet (4) downwards (5) along its length SOLUTION: Right-hand-rule: wire is pushed upward 8. A square loop of wire lies in the plane of the page and carries a current I as shown. There is a uniform magnetic field B parallel to the side MK as indicated. The loop will tend to rotate: (1) about PQ with KL coming out of the page (2) about PQ with KL going into the page (3) about RS with MK coming out of the page (4) about RS with MK going into the page (5) about an axis perpendicular to the page SOLUTION: Right-hand-rule: force on segment KL is up, on NM is down, so it rotates about PQ with KL moving upward
3 9. The magnitude of the magnetic field at point P, at the center of the semicircle shown, is given by: (1) µ 0 i/4r (2) µ 0 i/r 2 (3) µ 0 i/2πr (4) µ 0 i/4πr (5) µ 0 i/2r SOLUTION: This is half of a circular current loop, so I = 1 2 [µ 0i/2R] = µ 0 i/4r 10. Two long straight wires pierce the plane of the paper at vertices of an equilateral triangle as shown below. They each carry 2 A, out of the paper. The magnetic field at the third vertex (P) has magnitude (in T): (1) (2) (3) (4) (5) SOLUTION: Each of the currents produces a field at P equal to B = µ 0 i/2πr, but each of these is perpendicular to its side of the triangle at P. The net field is just the sum of the horizontal components: B = 2µ 0 (2A)/2π( m) cos 30 = T 11. Magnetic field lines inside the solenoid shown are: (1) toward the top of the page (2) clockwise circles as one looks down the axis from the top of the page (3) counterclockwise circles as one looks down the axis from the top of the page (4) toward the bottom of the page (5) in no direction since B = 0 SOLUTION: RHR again, B is upward 12. Four long straight wires carry equal currents into the page as shown. The magnetic force exerted on wire F is: (1) east (2) north (3) south (4) west (5) zero SOLUTION: eastward. The forces are all attractive and vertical components cancel. The net force thus is to the right, or 13. An 8.0-mH inductor and a 2.0-Ω resistor are wired in series to a 20-V ideal battery. A switch in the circuit is closed at time 0, at which time the current is 0. A long time after the switch is thrown the potential differences across the inductor and resistor are: (1) 0, 20 V (2) 20 V, 0 (3) 10 V, 10 V (4) 16 V, 4 V (5) unknown since the rate of change of the current is not given SOLUTION: After a long time, L s current is max, and its resistance is negligible. The only V thus is across R, so V L = 0; V R = 20V 14. An LC circuit has an oscillation frequency of 10 5 Hz. If C = 0.1µF, then L must be about: (1) 25 µh (2) 10 mh (3) 1 mh (4) 2.5 µh (5) 1 ph SOLUTION: f R = 1 2π LC LC = 1 4π 2 f 2 L = 1 4π 2 (10 5 ) F = H
4 15. A long straight wire lies in the plane of a rectangular conducting loop as shown. If the current i in the wire is decreasing, the current in the loop will be (1) clockwise (2) zero (3) counterclockwise (4) clockwise in the left side and counterclockwise in the right side (5) counterclockwise in the left side and clockwise in the right side SOLUTION: B due to current is down into page. By Lenz s law, since it s decreasing, induced emf in loop must reinforce B, so by RHR loop current is clockwise 16. The entire circuit shown is immersed in a uniform magnetic field that is into the page and is decreasing in magnitude at the rate 150 T/s. The current in the circuit (in amperes) is: (1) 0.18 (2) 0.22 (3) 0.40 (4) 0.62 (5) none of these SOLUTION: Without the flux change I = 4V/10Ω = 0.4A, CCW Induced V = dφ/dt = AdB/dt = (0.12m) 2 150T/s = 2.16V ; the induced current is then 2.16V/10Ω = 0.216A. B is decreasing so to reinforce it [Lenz s law] this induced current must be clockwise. The net current is thus 0.4A 0.216A = 0.18A 17. A rod with resistance R lies across frictionless conducting rails in a uniform magnetic field B, as shown. Assume the rails have negligible resistance. The force that must be applied by a person to pull the rod to the right at constant speed v is: (1) B 2 L 2 v/r (2) 0 (3) BLv (4) BLv/R (5) B 2 Lxv/R SOLUTION: The induced voltage = BLv. At constant speed, the ohmic heating V 2 /R = work done/t = Fx/t, = Fv, so F = B 2 L 2 v / R 18. In the circuit segment shown, the current I = 2.0 ma, flowing from A to B, and the potential difference, V A V B is +30V. At this instant, the charge and polarity of the capacitor C will be: (1) 1.5 mc, left plate is positive (2) 1.5 mc, right plate is positive (3) 0.50 mc, left plate is positive (4) 0.50 mc, right plate is positive (5) none of these SOLUTION: V A V B = 30V. Applying the loop rule: 30V + Q/C 40V 10kΩ(2mA) = 0 Q/C = 30V Q = 30V ( F ) = 1.5mC. In traversing the loop we took Q/C as +, = outgoing (left) side is In an ideal 1:8 step-down transformer the primary power is 10 kw and the secondary current is 25 A. The primary voltage must therefore be (1) 3200 (2) 25,600 (3) 400 (4) 50 (5) 6.25 SOLUTION: P in = P out V 1 I 1 = V 2 I 2 and for 8:1 step down, V 1 = 8V 2 So 10 kw = 25 V 2 V 2 = 10, 000 W/25V = 400 V V 1 = 8 (400V) = 3200 V
5 20. Electric utility companies provide alternating current (ac) instead of direct current (dc), primarily because (1) ac voltages may be conveniently transformed (2) ac is less lethal (3) ac minimizes magnetic effects (4) dc-powered incandescent bulbs are dimmer (5) the batteries required for large dc are prohibitively expensive SOLUTION: ac can be conveniently transformed (up or down), making transport of high power more efficient: high voltage lower current less ohmic loss in the lines.
On my honor, I have neither given nor received unauthorized aid on this examination.
Instructor(s): Kumar/Stewart PHYSIS DEPRTMENT PHY 05 Exam 1 September 7, 011 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized aid on this examination. YOUR
More informationOn my honor, I have neither given nor received unauthorized aid on this examination.
Instructor: Profs. Andrew Rinzler, Paul Avery, Selman Hershfield PHYSICS DEPARTMENT PHY 049 Exam 3 April 7, 00 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized
More informationPHYS 1102 EXAM - II. SECTION: (Circle one) 001 (TH 9:30 AM to 10:45AM) 002 (TH 3:30 PM to 4:45 PM) You have 1 hr 45 minutes to complete the test
PHYS 1102 EXAM - II SECTION: (Circle one) 001 (TH 9:30 AM to 10:45AM) 002 (TH 3:30 PM to 4:45 PM) Your Name: Student ID: You have 1 hr 45 minutes to complete the test PLEASE DO NOT START TILL YOU ARE INSTRUCTED
More informationChapter 12. Magnetism and Electromagnetism
Chapter 12 Magnetism and Electromagnetism 167 168 AP Physics Multiple Choice Practice Magnetism and Electromagnetism SECTION A Magnetostatics 1. Four infinitely long wires are arranged as shown in the
More informationPhysics 1308 Exam 2 Summer Instructions
Name: Date: Instructions All Students at SMU are under the jurisdiction of the Honor Code, which you have already signed a pledge to uphold upon entering the University. For this particular exam, you may
More informationPhysics 1308 Exam 2 Summer 2015
Physics 1308 Exam 2 Summer 2015 E2-01 2. The direction of the magnetic field in a certain region of space is determined by firing a test charge into the region with its velocity in various directions in
More information>>>>>>>>WHEN YOU FINISH <<<<<<<< Hand in the answer sheet separately. Constants ǫ 0 = F/m m e = kg
Instructor: Profs. Mitselmakher, Qiu PHYSICS DEPRTMENT PHY 2054 Final Exam pril 25, 2015 Name (PRINT, last, first): Signature: On my honor, I have neither given nor received unauthorized aid on this examination.
More informationPhysics 102 Exam 2 Spring Last Name: First Name Network-ID
Last Name: First Name Network-ID Discussion Section: Discussion TA Name: Turn off your cell phone and put it out of sight. Keep your calculator on your own desk. Calculators cannot be shared. This is a
More informationOn my honor, I have neither given nor received unauthorized aid on this examination.
Instructor: Profs. Selman Hershfield, Aneta Petkova PHYSICS DEPARTMENT PHY 049 Final Exam December, 00 Name (print, last first: Signature: On my honor, I have neither given nor received unauthorized aid
More informationA) I B) II C) III D) IV E) V
1. A square loop of wire moves with a constant speed v from a field-free region into a region of uniform B field, as shown. Which of the five graphs correctly shows the induced current i in the loop as
More informationPhysics 240 Fall 2005: Exam #3. Please print your name: Please list your discussion section number: Please list your discussion instructor:
Physics 240 Fall 2005: Exam #3 Please print your name: Please list your discussion section number: Please list your discussion instructor: Form #1 Instructions 1. Fill in your name above 2. This will be
More informationPhy207 Exam III (Form1) Professor Zuo Spring Semester 15
Phy207 Exam III (Form1) Professor Zuo Spring Semester 15 On my honor, I have neither received nor given aid on this examination Signature: Name: ID number: #1 14 #15/16 Total Enter your name and Form 1
More informationOn my honor, I have neither given nor received unauthorized aid on this examination.
Instructor: Profs. Andrew Rinzler, Paul Avery, Selman Hershfield PHYSICS DEPARTMENT PHY 2049 Final Exam April 24, 200 Name (print, last first): Signature: On my honor, I have neither given nor received
More informationPS I AP Physics 2 Electromagnetic Induction Multiple Choice Questions
PS I AP Physics 2 Electromagnetic Induction Multiple Choice Questions 1. A beam of electrons travels between two parallel coils of wire, as shown in the figures above. When the coils do not carry a current,
More informationP202 Practice Exam 2 Spring 2004 Instructor: Prof. Sinova
P202 Practice Exam 2 Spring 2004 Instructor: Prof. Sinova Name: Date: (5)1. How many electrons flow through a battery that delivers a current of 3.0 A for 12 s? A) 4 B) 36 C) 4.8 10 15 D) 6.4 10 18 E)
More informationPhysics 240 Fall 2005: Exam #3 Solutions. Please print your name: Please list your discussion section number: Please list your discussion instructor:
Physics 4 Fall 5: Exam #3 Solutions Please print your name: Please list your discussion section number: Please list your discussion instructor: Form #1 Instructions 1. Fill in your name above. This will
More informationSECTION B Induction. 1. The rate of change of flux has which of the following units A) farads B) joules C) volts D) m/s E) webers
SECTION B Induction 1. The rate of change of flux has which of the following units ) farads B) joules C) volts D) m/s E) webers 2. For the solenoids shown in the diagram (which are assumed to be close
More informationPHYSICS 3204 PUBLIC EXAM QUESTIONS (Magnetism &Electromagnetism)
PHYSICS 3204 PUBLIC EXAM QUESTIONS (Magnetism &Electromagnetism) NAME: August 2009---------------------------------------------------------------------------------------------------------------------------------
More informationInstructor: Biswas/Ihas/Whiting PHYSICS DEPARTMENT PHY 2053 Exam 3, 120 minutes December 12, 2009
77777 77777 Instructor: Biswas/Ihas/Whiting PHYSICS DEPARTMENT PHY 2053 Exam 3, 120 minutes December 12, 2009 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized
More informationa. Clockwise. b. Counterclockwise. c. Out of the board. d. Into the board. e. There will be no current induced in the wire
Physics 1B Winter 2012: Final Exam For Practice Version A 1 Closed book. No work needs to be shown for multiple-choice questions. The first 10 questions are the makeup Quiz. The remaining questions are
More informationExam 2 Solutions. Note that there are several variations of some problems, indicated by choices in parentheses.
Exam 2 Solutions Note that there are several variations of some problems, indicated by choices in parentheses. Problem 1 Part of a long, straight insulated wire carrying current i is bent into a circular
More informationFinal Exam. PHY2049 Fall11
Exam 1. Three charges form an equilateral triangle of side length d = 2 cm. The top charge is q3 = 3 μc, while the bottom two are q1 = q2 = - 6 μc. What is the magnitude of the net force acting on q3?
More informationPhysics 55 Final Exam Fall 2012 Dr. Alward Page 1
Physics 55 Final Exam Fall 2012 Dr. Alward Page 1 1. The specific heat of lead is 0.030 cal/g C. 300 g of lead shot at 100 C is mixed with 100 g of water at 70 C in an insulated container. The final temperature
More informationPhysics 2220 Fall 2010 George Williams THIRD MIDTERM - REVIEW PROBLEMS
Physics 2220 Fall 2010 George Williams THIRD MIDTERM - REVIEW PROBLEMS Solution sets are available on the course web site. A data sheet is provided. Problems marked by "*" do not have solutions. 1. An
More informationExam 2 Solutions. Answer: 3.0 W Solution: The total current is in the series circuit is 1 A, so the power dissipated in R 2 is i 2 R 2
Exam 2 Solutions Prof. Pradeep Kumar Prof. Paul Avery Mar. 21, 2012 1. A portable CD player does not have a power rating listed, but it has a label stating that it draws a maximum current of 159.0 ma.
More information21 MAGNETIC FORCES AND MAGNETIC FIELDS
CHAPTER 1 MAGNETIC FORCES AND MAGNETIC FIELDS ANSWERS TO FOCUS ON CONCEPTS QUESTIONS 1 (d) Right-Hand Rule No 1 gives the direction of the magnetic force as x for both drawings A and B In drawing C, the
More informationPHYS 241 EXAM #2 November 9, 2006
1. ( 5 points) A resistance R and a 3.9 H inductance are in series across a 60 Hz AC voltage. The voltage across the resistor is 23 V and the voltage across the inductor is 35 V. Assume that all voltages
More informationPhysics 106, Section 1
Physics 106, Section 1 Magleby Exam 2, Summer 2012 Exam Cid You are allowed a pencil and a testing center calculator. No scratch paper is allowed. Testing center calculators only. 1. A circular coil lays
More informationAP Physics 2 Electromagnetic Induction Multiple Choice
Slide 1 / 50 AP Physics 2 Electromagnetic Induction Multiple Choice www.njctl.org Slide 2 / 50 1 A beam of electrons travels between two parallel coils of wire, as shown in the figures above. When the
More informationLouisiana State University Physics 2102, Exam 3, November 11, 2010.
Name: Instructor: Louisiana State University Physics 2102, Exam 3, November 11, 2010. Please be sure to write your name and class instructor above. The test consists of 3 questions (multiple choice), and
More informationwhere the magnetic field is directed from south to north. It will be deflected:
Section: Magnetic Field Take Home Test Due Tues. Apr. 2----all work should be shown on test---you will hand in the scantron for scoring 1. A hydrogen atom that has lost its electron is moving east in a
More informationPHYS 1444 Section 02 Review #2
PHYS 1444 Section 02 Review #2 November 9, 2011 Ian Howley 1 1444 Test 2 Eq. Sheet Terminal voltage Resistors in series Resistors in parallel Magnetic field from long straight wire Ampére s Law Force on
More informationPRACTICE EXAM 2 for Midterm 2
PRACTICE EXAM 2 for Midterm 2 Multiple Choice Questions 1) In the circuit shown in the figure, all the lightbulbs are identical. Which of the following is the correct ranking of the brightness of the bulbs?
More informationExam 2, Phy 2049, Spring Solutions:
Exam 2, Phy 2049, Spring 2017. Solutions: 1. A battery, which has an emf of EMF = 10V and an internal resistance of R 0 = 50Ω, is connected to three resistors, as shown in the figure. The resistors have
More informationPhysics 102 Spring 2007: Final Exam Multiple-Choice Questions
Last Name: First Name: Physics 102 Spring 2007: Final Exam Multiple-Choice Questions 1. The circuit on the left in the figure below contains a battery of potential V and a variable resistor R V. The circuit
More informationSolutions to PHY2049 Exam 2 (Nov. 3, 2017)
Solutions to PHY2049 Exam 2 (Nov. 3, 207) Problem : In figure a, both batteries have emf E =.2 V and the external resistance R is a variable resistor. Figure b gives the electric potentials V between the
More information(1) +0.2 m/s (2) +0.4 m/s (3) +0.6 m/s (4) +1 m/s (5) +0.8 m/s
77777 77777 Instructor: Biswas/Ihas/Whiting PHYSICS DEPARTMENT PHY 2053 Exam 2, 120 minutes November 13, 2009 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized
More informationExam 2 Solutions. PHY2054 Spring Prof. Paul Avery Prof. Pradeep Kumar Mar. 18, 2014
Exam 2 Solutions Prof. Paul Avery Prof. Pradeep Kumar Mar. 18, 2014 1. A series circuit consists of an open switch, a 6.0 Ω resistor, an uncharged 4.0 µf capacitor and a battery with emf 15.0 V and internal
More informationAP Physics Electromagnetic Wrap Up
AP Physics Electromagnetic Wrap Up Here are the glorious equations for this wonderful section. This is the equation for the magnetic force acting on a moving charged particle in a magnetic field. The angle
More informationPHYS 2135 Exam II March 20, 2018
Exam Total /200 PHYS 2135 Exam II March 20, 2018 Name: Recitation Section: Five multiple choice questions, 8 points each. Choose the best or most nearly correct answer. For questions 6-9, solutions must
More informationOn my honor, I have neither given nor received unauthorized aid on this examination.
Instructor(s): Profs. D. Reitze, H. Chan PHYSICS DEPARTMENT PHY 2053 Exam 2 April 2, 2009 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized aid on this examination.
More informationPhysics 102 Exam 2 Fall 2012
Physics 102 Exam 2 Fall 2012 Last Name: First Name Network-ID Discussion Section: Discussion TA Name: Turn off your cell phone and put it out of sight. Keep your calculator on your own desk. Calculators
More informationPhysics 227 Final Exam December 18, 2007 Prof. Coleman and Prof. Rabe. Useful Information. Your name sticker. with exam code
Your name sticker with exam code Physics 227 Final Exam December 18, 2007 Prof. Coleman and Prof. Rabe SIGNATURE: 1. The exam will last from 4:00 p.m. to 7:00 p.m. Use a #2 pencil to make entries on the
More informationPHY2048 Exam 1 Formula Sheet. Vectors. a 2 x +a 2 y +a 2 z b = Motion. Equations of Motion for Constant Acceleration
Instructor(s): atcheva/yelton PHYSICS DEPARTENT PHY 2048 Exam 1 September 28, 2017 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized aid on this examination.
More informationPhysics 6b Winter 2015 Final Campagnari Section Test Form D
Physics 6b Winter 2015 Final Campagnari Section Test Form D Fill out name and perm number on the scantron. Do not forget to bubble in the Test Form (A, B, C, or, D). At the end, only turn in the scantron.
More informationPhysics 6b Winter 2015 Final Campagnari Section Test Form A
Physics 6b Winter 2015 Final Campagnari Section Test Form A Fill out name and perm number on the scantron. Do not forget to bubble in the Test Form (A, B, C, or, D). At the end, only turn in the scantron.
More informationSolution for Fq. A. up B. down C. east D. west E. south
Solution for Fq A proton traveling due north enters a region that contains both a magnetic field and an electric field. The electric field lines point due west. It is observed that the proton continues
More informationPhysics 2401 Summer 2, 2008 Exam III
Physics 2401 Summer 2, 2008 Exam e = 1.60x10-19 C, m(electron) = 9.11x10-31 kg, ε 0 = 8.845x10-12 C 2 /Nm 2, k e = 9.0x10 9 Nm 2 /C 2, m(proton) = 1.67x10-27 kg. n = nano = 10-9, µ = micro = 10-6, m =
More informationPhysics 6B Summer 2007 Final
Physics 6B Summer 2007 Final Question 1 An electron passes through two rectangular regions that contain uniform magnetic fields, B 1 and B 2. The field B 1 is stronger than the field B 2. Each field fills
More informationPHY 131 Review Session Fall 2015 PART 1:
PHY 131 Review Session Fall 2015 PART 1: 1. Consider the electric field from a point charge. As you move farther away from the point charge, the electric field decreases at a rate of 1/r 2 with r being
More informationX X. Name (printed) Name (signature as on ID) Lab Section. Chapts in Young&Geller
Physics 202 MWF 9:10 Exam II Name (printed) Name (signature as on ID) Spring 2010 (Ford) Chapts. 20 21 in Young&Geller Lab Section Multiple choice questions. Circle the correct answer. No work needs to
More informationFinal Exam: Physics Spring, 2017 May 8, 2017 Version 01
Final Exam: Physics2331 - Spring, 2017 May 8, 2017 Version 01 NAME (Please Print) Your exam should have 11 pages. This exam consists of 18 multiple-choice questions (2 points each, worth 36 points), and
More informationVersion The diagram below represents lines of magnetic flux within a region of space.
1. The diagram below represents lines of magnetic flux within a region of space. 5. The diagram below shows an electromagnet made from a nail, a coil of insulated wire, and a battery. The magnetic field
More informationc k wt+cl I\i Physics 202 MWF1O:20 Spring 2007 (Ford) Name (printed) Name (signature as on ID) Lab Section Exam II Chapts in Young&Geller
Physics 202 MWF1O:20 Exam Name (printed) Name (signature as on D) Spring 2007 (Ford) Chapts. 19 21 in Young&Geller Lab Section Multiple choice questions. Circle the correct answer. No work needs to be
More informationPhysics 2135 Exam 2 October 20, 2015
Exam Total / 200 Physics 2135 Exam 2 October 20, 2015 Printed Name: Rec. Sec. Letter: Five multiple choice questions, 8 points each. Choose the best or most nearly correct answer. 1. A straight wire segment
More informationName (Print): 4 Digit ID: Section:
Physics 11 Sample Common Exam 3: Sample 5 Name (Print): 4 Digit ID: Section: Honors Code Pledge: As an NJIT student I, pledge to comply with the provisions of the NJIT Academic Honor Code. I assert that
More informationVersion 001 HW 22 EM Induction C&J sizemore (21301jtsizemore) 1
Version 001 HW 22 EM Induction C&J sizemore (21301jtsizemore) 1 This print-out should have 35 questions. Multiple-choice questions may continue on the next column or page find all choices before answering.
More informationPhysics 42 Exam 3 Fall 2013 PRINT Name:
Physics 42 Exam 3 Fall 2013 PRINT Name: 1 2 3 4 Conceptual Questions : Circle the BEST answer. (1 point each) 1. A small plastic ball has an excess negative charge on it. If a magnet is placed close to
More informationPhysics 2B Winter 2012 Final Exam Practice
Physics 2B Winter 2012 Final Exam Practice 1) When the distance between two charges is increased, the force between the charges A) increases directly with the square of the distance. B) increases directly
More informationAP Physics C 1998 Multiple Choice Questions Electricity and Magnetism
AP Physics C 1998 Multiple Choice Questions Electricity and Magnetism The materials included in these files are intended for use by AP teachers for course and exam preparation in the classroom; permission
More informationPHY2049 Fall11. Final Exam Solutions (1) 700 N (2) 350 N (3) 810 N (4) 405 N (5) 0 N
Exam Solutions 1. Three charges form an equilateral triangle of side length d = 2 cm. The top charge is q3 = 3 μc, while the bottom two are q1 = q2 = - 6 μc. What is the magnitude of the net force acting
More informationThe next two questions pertain to the situation described below. Consider a parallel plate capacitor with separation d:
PHYS 102 Exams Exam 2 PRINT (A) The next two questions pertain to the situation described below. Consider a parallel plate capacitor with separation d: It is connected to a battery with constant emf V.
More informationOn my honor, I have neither given nor received unauthorized aid on this examination.
Instructor(s): Field/Furic PHYSICS DEPARTENT PHY 2053 Exam 1 October 5, 2011 Name (print, last first): Signature: On my honor, I hae neither gien nor receied unauthorized aid on this examination. YOUR
More informationPhysics 212 Question Bank III 2010
A negative charge moves south through a magnetic field directed north. The particle will be deflected (A) North. () Up. (C) Down. (D) East. (E) not at all.. A positive charge moves West through a magnetic
More informationDe La Salle University Manila Physics Fundamentals for Engineering 2 Quiz No. 3 Reviewer
De La Salle University Manila Physics Fundamentals for Engineering 2 Quiz No. 3 Reviewer Multiple Choice: 1. Which of the two arrangements shown has the smaller equivalent resistance between points a and
More informationExam 2 Solutions. ε 3. ε 1. Problem 1
Exam 2 Solutions Problem 1 In the circuit shown, R1=100 Ω, R2=25 Ω, and the ideal batteries have EMFs of ε1 = 6.0 V, ε2 = 3.0 V, and ε3 = 1.5 V. What is the magnitude of the current flowing through resistor
More informationOn my honor, I have neither given nor received unauthorized aid on this examination.
Instructor(s): Field/inzler PHYSICS DEPATMENT PHY 2053 Final Exam April 27, 2013 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized aid on this examination.
More informationChapter 23: Magnetic Flux and Faraday s Law of Induction
Chapter 3: Magnetic Flux and Faraday s Law of Induction Answers Conceptual Questions 6. Nothing. In this case, the break prevents a current from circulating around the ring. This, in turn, prevents the
More information1 Fig. 3.1 shows the variation of the magnetic flux linkage with time t for a small generator. magnetic. flux linkage / Wb-turns 1.
1 Fig. 3.1 shows the variation of the magnetic flux linkage with time t for a small generator. 2 magnetic 1 flux linkage / 0 10 2 Wb-turns 1 2 5 10 15 t / 10 3 s Fig. 3.1 The generator has a flat coil
More informationLouisiana State University Physics 2102, Exam 3 April 2nd, 2009.
PRINT Your Name: Instructor: Louisiana State University Physics 2102, Exam 3 April 2nd, 2009. Please be sure to PRINT your name and class instructor above. The test consists of 4 questions (multiple choice),
More informationExam II. Solutions. Part A. Multiple choice questions. Check the best answer. Each question carries a value of 4 points. The wires repel each other.
Exam II Solutions Part A. Multiple choice questions. Check the best answer. Each question carries a value of 4 points. 1.! Concerning electric and magnetic fields, which of the following is wrong?!! A
More informationStudent number: Question # Mark Maximum Mark. Multiple Choice 20
Name: Student number: Academic Honesty: Cheating in an examination includes the following: 1. the unauthorized sharing of material such as textbooks during an open book examination; 2. concealing information
More informationGen. Phys. II Exam 2 - Chs. 21,22,23 - Circuits, Magnetism, EM Induction Mar. 5, 2018
Gen. Phys. II Exam 2 - Chs. 21,22,23 - Circuits, Magnetism, EM Induction Mar. 5, 2018 Rec. Time Name For full credit, make your work clear. Show formulas used, essential steps, and results with correct
More informationExam 2 Fall 2014
1 95.144 Exam 2 Fall 2014 Section instructor Section number Last/First name Last 3 Digits of Student ID Number: Show all work. Show all formulas used for each problem prior to substitution of numbers.
More informationPhysics Grading Sheet.
Physics - Grading Sheet. Dept. of Physics and Astronomy. TAMU. Marking Instructions Fill oval completely Erase cleanly Students Fill Only this information. First Name: Last Name:. Section:. Clearly hand-write
More information18 - ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENTS ( Answers at the end of all questions ) Page 1
( Answers at the end of all questions ) Page ) The self inductance of the motor of an electric fan is 0 H. In order to impart maximum power at 50 Hz, it should be connected to a capacitance of 8 µ F (
More informationPHYS 272 (Spring 2018): Introductory Physics: Fields Problem-solving sessions
Figure 1: Problem 1 Figure 2: Problem 2 PHYS 272 (Spring 2018): Introductory Physics: Fields Problem-solving sessions (1). A thin rod of length l carries a total charge Q distributed uniformly along its
More informationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Exam Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) A jeweler needs to electroplate gold (atomic mass 196.97 u) onto a bracelet. He knows
More informationPhysics 212 Question Bank III 2006
A negative charge moves south through a magnetic field directed north. The particle will be deflected (A) North. () Up. (C) Down. (D) East. (E) not at all. The magnetic force on a moving charge is (A)
More informationChapter 21 Magnetic Induction Lecture 12
Chapter 21 Magnetic Induction Lecture 12 21.1 Why is it called Electromagnetism? 21.2 Magnetic Flux and Faraday s Law 21.3 Lenz s Law and Work-Energy Principles 21.4 Inductance 21.5 RL Circuits 21.6 Energy
More informationCh 17 Problem Set 31. A toaster is rated at 600 W when connected to a 120-V source. What current does the toaster carry, and what is its resistance?
Ch 17 Problem Set 31. A toaster is rated at 600 W when connected to a 120-V source. What current does the toaster carry, and what is its resistance? 33. How many 100-W lightbulbs can you use in a 120-V
More informationYour name: Your TA: Your section Day/Time: PHY 101 Practice in-class exam III Wednesday, November 28, 3:15-3:35PM
1 Your name: Your TA: Your section Day/Time: PHY 101 Practice in-class exam III Wednesday, November 28, 3:15-3:35PM Please be sure to show your work where it is requested. If no work is shown where it
More informationPhysics 240 Fall 2003: Final Exam. Please print your name: Please list your discussion section number: Please list your discussion instructor:
Physics 40 Fall 003: Final Exam Please print your name: Please list your discussion section number: Please list your discussion instructor: Form #1 Instructions 1. Fill in your name above. This will be
More informationLAST Name (print) ALL WORK MUST BE SHOWN FOR THE FREE RESPONSE QUESTION IN ORDER TO RECEIVE FULL CREDIT.
Physics 107 LAST Name (print) First Mid-Term Exam FIRST Name (print) Summer 2013 Signature: July 5 UIN #: Textbooks, cell phones, or any other forms of wireless communication are strictly prohibited in
More information(a) zero. B 2 l 2. (c) (b)
1. Two identical co-axial circular loops carry equal currents circulating in the same direction: (a) The current in each coil decrease as the coils approach each other. (b) The current in each coil increase
More informationPHYS102 Previous Exam Problems. Induction
PHYS102 Previous Exam Problems CHAPTER 30 Induction Magnetic flux Induced emf (Faraday s law) Lenz law Motional emf 1. A circuit is pulled to the right at constant speed in a uniform magnetic field with
More informationPhysics 2020 Exam 2 Constants and Formulae
Physics 2020 Exam 2 Constants and Formulae Useful Constants k e = 8.99 10 9 N m 2 /C 2 c = 3.00 10 8 m/s ɛ = 8.85 10 12 C 2 /(N m 2 ) µ = 4π 10 7 T m/a e = 1.602 10 19 C h = 6.626 10 34 J s m p = 1.67
More informationPHYS 272 Fall 2010 Thursday, December 16, 2010
PHYS 272 Fall 2010 Thursday, December 16, 2010 Final Exam The final exam has only this machine-graded part of 22 multiple choice questions. Each multiple choice problem is worth 10 points. Using a pencil,
More informationTwo point charges, A and B, lie along a line separated by a distance L. The point x is the midpoint of their separation.
Use the following to answer question 1. Two point charges, A and B, lie along a line separated by a distance L. The point x is the midpoint of their separation. 1. Which combination of charges would yield
More informationPhysics 2135 Exam 2 March 22, 2016
Exam Total Physics 2135 Exam 2 March 22, 2016 Key Printed Name: 200 / 200 N/A Rec. Sec. Letter: Five multiple choice questions, 8 points each. Choose the best or most nearly correct answer. B 1. An air-filled
More informationUniversity of the Philippines College of Science PHYSICS 72. Summer Second Long Problem Set
University of the Philippines College of Science PHYSICS 72 Summer 2012-2013 Second Long Problem Set INSTRUCTIONS: Choose the best answer and shade the corresponding circle on your answer sheet. To change
More informationOn my honor, I have neither given nor received unauthorized aid on this examination.
Instructor(s): N. Sullivan PHYSICS DEPARTMENT PHY 2004 Final Exam December 13, 2011 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized aid on this examination.
More informationMultiple Choice Questions for Physics 1 BA113 Chapter 23 Electric Fields
Multiple Choice Questions for Physics 1 BA113 Chapter 23 Electric Fields 63 When a positive charge q is placed in the field created by two other charges Q 1 and Q 2, each a distance r away from q, the
More information(D) Blv/R Counterclockwise
1. There is a counterclockwise current I in a circular loop of wire situated in an external magnetic field directed out of the page as shown above. The effect of the forces that act on this current is
More information2R R R 2R. Phys Test 1
Group test. You want to calculate the electric field at position (x o, 0, z o ) due to a charged ring. The ring is centered at the origin, and lies on the xy plane. ts radius is and its charge density
More informationOn my honor, I have neither given nor received unauthorized aid on this examination.
Instructor(s): J. Ipser PHYSICS DEPARTMENT PHY 2004 Final Exam April 25, 2005 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized aid on this examination. YOUR
More informationSP 212 and SP 212E Final Exam. Name Alpha Instructor Section # Tuesday, 11 May
SP 212 and SP 212E Final Exam Version A Name Alpha Instructor Section # Tuesday, 11 May 2004 0755-1055 INSTRUCTIONS, ETC. 1. Do not open or turn over the exam until told to do so. 2. Please fill in the
More informationCh. 23 Electromagnetic Induction, AC Circuits, And Electrical Technologies
Ch. 23 Electromagnetic Induction, AC Circuits, And Electrical Technologies Induced emf - Faraday s Experiment When a magnet moves toward a loop of wire, the ammeter shows the presence of a current When
More informationPhysics 126 Fall 2004 Practice Exam 1. Answer will be posted about Oct. 5.
Physics 126 Fall 2004 Practice Exam 1. Answer will be posted about Oct. 5. 1. Which one of the following statements best explains why tiny bits of paper are attracted to a charged rubber rod? A) Paper
More informationMULTIPLE CHOICE Choose the one alternative that best completes the statement or answers the question.
Instructor(s): S. Obukhov PHYSICS DEPARTMENT PHY 2020 Midterm Exam 1 September 20, 2017 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized aid on this examination.
More information