) = 12(7)

Size: px
Start display at page:

Download ") = 12(7)"

Transcription

1 Chapter 6 Maintaining Mathematical Proficienc (p. 89). ( ) + 9 = (7) + 9 = (7) = = = 7 8 = = = = = = 0 = (0 ) = (0 6) = ( 6) = ( 6) = ( 6) = 6 + ( 6) =. Because 8 = 6, 6 = 8 = 8.. represents the negative square root. Because =, = =. 6. represents the negative square root. Because =, = =. 7. ± represents the positive or negative square root. Because =, ± = ± = ±. 8. The first term is, and the common difference is. a n = a + (n )d a n = + (n ) a n = + n() () a n = + n a n = n The first term is 6, and the common difference is. a n = a + (n )d a n = 6 + (n )( ) a n = 6 + n( ) ( ) a n = 6 n + a n = n The first term is, and the common difference is 7. a n = a + (n )d a n = + (n )( 7) a n = + n( 7) ( 7) a n = 7n + 7 a n = 7n + 9. es; no; The product of two perfect squares can be represented b m n = (mm)(nn) = (mn)(mn) = (mn). If m and n are integers, their product is also an integer. So, (mn) is an integer. There are man counterexamples illustrating that the quotient of two perfect squares does not have to be a perfect square, such as 9. Chapter 6 Mathematical Practices (p. 90). Year Population So, the population in the tenth ear is rabbits.. Row Sum So, the sum of the numbers in the tenth row is. 6. Explorations (p. 9). a. i. ( )( ) = ( ) ( ) = = ii. ( )( ) = ()( ) = = 6 iii. ( )( ) = ( )( ) = = 8 iv. (x )(x 6 ) = (x x)( x x x x x x) = x x x x x x x x = x 8 In each example, the exponent of the product is the sum of the exponents of the factors. So, a general rule is a m a n = a m+n. Copright Big Ideas Learning, LLC Algebra 0

2 b. i. = ii. iii. x6 iv. = = = = x = x x x x x x = x x x x x x = = = 0 = = x In each example, the exponent of the quotient is the difference of the exponents of the powers that are being divided. So, a general rule is am a n = am n. c. i. ( ) = ( )( )( )( ) = ( )( )( )( ) = = 8 ii. (7 ) = (7 )(7 ) = (7 7 7) (7 7 7) = = 7 6 iii. ( ) = ( )( )( ) = ( )( )( ) = = 9 iv. (x ) = (x )(x ) = (x x x x)(x x x x) = x x x x x x x x = x 8 In each example, the exponent of the single power is the product of the other two exponents. So, a general rule is (a m ) n = a mn. d. i. ( ) = ( )( ) = = = ii. ( ) = ( )( )( ) = = = iii. (6a) = (6a)(6a) = 6 a 6 a = 6 6 a a = 6 a iv. (x) = (x)(x) = x x = x x = x So, to find a power of a product, find the power of each factor and multipl, or (ab) m = a m b m. e. i. ( ) = ( ) ( ) = = ) = ( ) ( ) ( ) = 06 Algebra Copright Big Ideas Learning, LLC ii. ( iii. ( ) x = ( ) x ( ) x ( x iv. ( a b) = ( a b) ( a b) ( a b) ( a = ) = x x x = x b) = a a a a b b b b = a b So, to find the power of a quotient, find the power of the numerator and the power of the denominator and divide, or ( a b ) m = am b m.. Sample answer: Tr several examples to find a pattern. Then express the pattern using variables.. Because each side of the large cube has the same length as 9 small cubes, an expression for the number of small cubes in the large cube is = Monitoring Progress (pp. 9 9). ( 9) 0 =. = = 7. 0 = = =. x = 0 x = 9x = 0 +( 6) = 0 = 0 = x 9 x 9 = x 9+( 9) = x 0 = 7. 8 = 8 = = = 6 7 = = 9. (6 ) = 6 ( )( ) = 6 = 6

3 0. (w ) = w = w 60. (0) = (0) = 0 = 000. ( n ) = ( ) n = 0 n = 0. ( k ) = (k ) = (k ) = k = k 0. ( 6c 7 ) (6c) = 7 = 7 (6c) = 7 6 c = 9 6c. The base of a clinder is a circle. The formula for the area of a circle is A = πr. Also, r = h. A = πr = π ( h ) = π ( h ) = πh. So, two expressions that represent the area of a base of the clinder are πr and πh = = = = = 9. 0 n ) = π ( h So, Pluto orbits the Sun 9. 0, or 90,000, times while the Sun completes one orbit around the center of the Milk Wa. 6. Exercises (pp ) Vocabular and Core Concept Check. Sample answer: First, use the Product of Powers Propert to simplif the expression inside the parentheses to. Then, use the Power of a Power Propert to simplif the entire expression to 8. Then, use the definition of negative exponents to produce the final answer, 8 = 6,6.. Use the Power of a Product Propert when a product of factors is in parentheses, and the whole product is being raised to a power. In order to use this propert, find the power of each factor and then multipl the powers.. Use the Quotient of Powers Propert when powers with the same base are being divided. In order to use the propert, find the difference of the exponents of the numerator and denominator. The answer is the common base raised to this difference.. The one that is different is Simplif 6. This answer is 6 = 8. The other three expressions are each equal to +6 = 9. Monitoring Progress and Modeling with Mathematics. ( 7) 0 = 6. 0 = 7. = = 6 8. ( ) = ( ) = = 9. = 0 = = 0 = = 6 = 6 = 6 7 =.. ( 8) =. x 7 = x 7. 0 = ( 8) = x 0 = 9 = 9 6. c 8 d 0 = c 8 = c 8 7. m = n r s = 9. a 0 b 7 m = m = b7 s r = s 9r = b7 6 p q = 7 q 9 9 p 8 = 9q9 p z 0 x = 8 x = 8 x7 6. x 0 = x7 6 z = z 0 0 x = z0 x. 6 = 6 = = 6. ( 6)8 ( 6) = ( 6)8 = ( 6) = 6. ( 9) ( 9) = ( 9) + 6. = + = 0 = 7. (p 6 ) = p 6 = p = ( 9) = 66 = 6z0 x Copright Big Ideas Learning, LLC Algebra 07

4 8. (s ) = s = s = s = 6 8+ = 6 = 6 = ( 7) = ( 7) ( 7). x x x = x x = x x = x + = x = ( 7) +( ) = ( 7) = ( 7) = =. z8 z = z8+ z z = z0 z = z0 = z = 0 7+ = 0 So, the magnified length of the object is 0, or 00, meter (which is the same as centimeter).. a b 8ab = 8 a b = a b microns So, the length of the computer chip is a b microns.. The Product of Powers Propert should be used because powers with the same base are being multiplied. So, the product should have a base of, not. = + = 9 6. In the second step, the Quotient of Powers Propert should be used because powers with the same base are being divided. The exponents should be subtracted, not divided. x x x = x+ x = x8 x = x8 = x 7. ( z) = ( ) z = z 8. (x) = (x) = x = 6x 9. ( 6 n) 6 = n n = 6 = n 6 0. ( t ) = ( t) = ( ) t 9 = t 9 = t 9. (s 8 ) = (s 8 ) = (s 8 ) = s 8 = s 0. ( p ) = ( ) (p ) = p = p 9. ( w 6 ) = ( ) (w ) 6 = 6 ( ) (w ) = 6 w = 6 w 6 6. ( r ) 6 = 6 (r 6 ) 6 = (r 6 ) 6 6 = 6 (r 6 ) 6 = 6 r 6 6 = 6r 6. B, C, D; V = πr = π(s ) = π (s ) = π 8 s6 = πs6 An expression equivalent to πs6 represents the volume of the sphere. ( πs 6 )( ) = (πs 6 )( ) = πs6 (s) πs = s πs = πs s = πs6 None of the other expressions are equivalent to πs6. So, the answers are B, C, and D, because these expressions simplif to the volume of the sphere, which is πs6. 6. t = x D = (0 ) (0 ) = 0 0 = = = 0 8+ = 0 It takes about 0, or 0.000, second for the ink to diffuse micrometer. 7. ( x x x ) = ( + x ) + = ( 7 x ) x ) = ( 8. ( s t 7 = (7 ) (x ) = ( 7 ) (x ) = 67 8x = 68 8x s t ) = ( s s t t ) 7 = ( s+ t ) +7 = ( s7 ) (t ) = ( ) (s 7 ) t = ( s7 t ) = 8s7 t = 8s t 08 Algebra Copright Big Ideas Learning, LLC

5 9. ( m n m n ) ( mn 0 0. ( x 0 x ) ( x m ) ( mn 9n ) = ( m n x 8 ) = ( n m ) ( mn ) = (n ) (m ) (mn ) ( ) 9 ) = n m n m = n m n 6 m 6 n +6 = m n 0 = 6 9 m n 0 = m = ( x x ) ( 8 = ( x + ) ( +8 = (x ) ( 0 x ) = x 0 (x ) = 8 x0 0 x = 8 x0 0 x = 8x 0 x ) +. ( 0 )(. 0 ) = (.) (0 )(0 ) =. 0 +( ) =. 0 The product is. 0, or (6. 0 )(8 0 9 ) = 6.(8) (0 )(0 9 ) = = = = The product is , or 8,800,000.. (6. 07 ) (.6 0 ) = = 0 7 = 0 The quotient is 0, or 00. m x m x x ). (.9 0 ) ( ) = = 0. 0 ( 8) = = 0 0 = 0 + = 0 The quotient is 0, or = ( ) On average, about. 0, or,0, pounds of potatoes were produced for each acre harvested. 6. t = d = r 0 = = =.6 0 So, it takes.6 0, or 600, seconds for sunlight to reach Jupiter. 7. a. You should use the Power of a Product Propert because for each cube, ou must raise a product of two factors to the third power to find the volume. b. Use the Power of a Quotient Propert to express (6x) (x) as ( 6x x ). Simplif the expression inside the parentheses to produce (), so the volume is 7 times greater. 8. a. kilobte 0 btes 0 btes terabtes = 0 kilobtes 0 terabtes = 0 0 kilobtes per terabte = 0 kilobtes per terabte So, there are 0 kilobtes in terabte. b. megabte 0 btes 0 btes gigabte 6 gigabtes = 0 0 megabtes = 0+ = 0 megabtes 0 megabtes = 0 megabtes = megabtes So, there are, or 6,8, megabtes in 6 gigabtes. Copright Big Ideas Learning, LLC Algebra 09

6 c. In order to convert the number of btes in each unit of measure to bits, multipl each number in the table b 8. Because 8 can be expressed as, multipl each number in the table b. Because the values have a common base of, the can be simplified using the Product of Powers Propert. So, ou can simpl add to each of the exponents in the table. 9. 8a b = a b = (ab) 60. 6r s = r s = (rs) 6. 6w 8 z = 6 w 6 z 6 = (w z ) x 8 = x = (x ) or 8x 8 = 9 x = (9x ) 6. a. ( 6. a. 6) n = n 6 n = 6 n b. 6 = n 6 = 96 c. ; The probabilit of flipping heads once is, and the probabilit of flipping heads five times in a row is ( =. ) = Figure The shaded part is of the original. Figure The shaded part is of the original. b. Figure : = Figure : = = Figure : 8 = = Figure : 6 = = Figure The shaded part is 8 of the original. 6. Using the Quotient of Powers Propert and the first Figure The shaded part is 6 of the original. equation bx b = b9, ou can conclude that x = 9. Using the Product of Powers Propert, the Quotient of Powers Propert, and the second equation bx b = b, ou can conclude that x + =. Use these equations to solve a sstem of linear equations b substitution. Step : x = 9 x + = 9 + x = 9 + b Step : x + = (9 + ) + = Step : + = x = 9 x ( ) = 9 x + = 9 x = 8 = = = So, x = 8 and =. 66. Sample answer: Let r = 9x. V = πr h 7πx 8 = π(9x ) h 7πx 8 = π 9 x h 7πx 8 = π 8 x h 7πx 8 = 7πx h x 7πx 8 7πx = 7πx h 7πx x = h So, one possibilit is r = 9x and h = x (0 6 ) = 0 0+( 6) = 0 0 g kg 0 g = 0 kg 0 = 0 kg = 0 kg So, the mass of the seed from the double coconut palm is 0 kilograms, which means our friend is incorrect. 68. a. Each of the questions has choices. So, represents the number of different was that a student can answer all the questions in Part. b. Each of the questions has choices. So, represents the number of different was that a student can answer all the questions on the entire surve. c. Because each question now has choices, the answer for part (a) becomes, and the answer for part (b) becomes. 0 Algebra Copright Big Ideas Learning, LLC

7 69. a. When a > and n < 0, a n < a n because a n will be less than and a n will be greater than. When a > and n = 0, a n = a n =, because an number to the zero power is. When a > and n > 0, a n > a n because a n will be greater than and a n will be less than. b. When 0 < a < and n < 0, a n > a n, because a n will be greater than and a n will be less than. When 0 < a < and n = 0, a n = a n =, because an number to the zero power is. When 0 < a < and n > 0, a n < a n because a n will be less than and a n will be greater than. Maintaining Mathematical Proficienc 70. Because =, = = represents the negative square root. Because 0 = 00, 00 = 0 = ± represents the positive or negative square root. 6 Because ( 8) = 6, ± 6 = ± ( 8) = ± is a natural number, whole number, integer, rational number, and real number is a rational number and a real number π is an irrational number and a real number. 6. Explorations (p. 99). a. 7 ft = ft Check: =? 7 =? 7 9 =? 7 7 = 7 b. cm = cm Check: =? =? =? = c. 7 in. = in. Check: =? 7 =? 7 =? 7 7 = 7 d..7 m =. m Check:. =?.7... =?.7.. =?.7.7 =.7 e. d = d Check: =? =? =? = f. 8 mm = mm, or. mm Check: ( ) =? 8 =? 8 =? 8 8 = 8 Of the sides measured in metric units, the longest length is. meters. Of the sides measured in standard units, the longest length is ard. Because meter is approximatel the same length as ard, the cube in part (d) has the largest side length of. meters. The cubes in parts (a) and (e) have equal side lengths because feet = ard.. a. Sample answer:., which is represented b point C. is between = 6 and = 8, and C is the onl point on the graph between and. b. Sample answer: , which is represented b point A. 0. is between 0 = 0 and =, and A is the onl point on the graph between 0 and. Also, 0. is close to 0.9, which equals 0.7 because (0.7) =.9. c. Sample answer:.., which is represented b point B.. is between = and =, and B is the onl point on the graph between and. d. Sample answer: 6.0, which is represented b point E. 6 is between = 6 and =, and E is the onl point on the graph between and. e. Sample answer:.8, which is represented b point D. is between = 7 and = 6, and D is the onl point on the graph between and. f. Sample answer: 6 0,000., which is represented b point F. 0,000 is between 6 =,6 and 6 6 = 6,66, and F is the onl point on the graph between and 6.. Find what real number multiplied b itself n times gives ou that number. If that is not possible, determine which nth powers the number is between and estimate the decimal part.. m = (0.0006)C = (0.0006)C = (0.0006)C ,000,000 = C = C.7 Use guess and check with a calculator: So, the circumference of its femur was about.7 millimeters. Copright Big Ideas Learning, LLC Algebra

8 6. Monitoring Progress (pp. 00 0). The index n = is odd, so has one real cube root. Because ( ) =, the cube root of is 7 =, or ( ) / =.. The index n = 6 is even, and a > 0. So, 6 has two real sixth roots. Because 6 = 6 and ( ) 6 = 6, the sixth roots of 6 are ± 6 6 = ±, or ±6 /6 = ±.. = ( ) ( ) ( ) =. ( 6) / = ( 6 / ) =( ) =6. 9 / = (9 / ) = = 6. 6 / = (6 / ) 7. r = ( V = = 6 π ) / = ( (7,000) (.) ) / = (,000.6 ) / 6 So, the radius of the beach ball is about 6 inches. 8. r = ( F P) /n = (, ) /8.88 / The annual inflation rate is about 6.0%. 6. Exercises (pp. 0 0) Vocabular and Core Concept Check. Find the fourth root of 8, or what real number multiplied b itself four times produces 8.. The expression that does not belong is ( 7 ) because it is the onl one that is not equivalent to 9. Monitoring Progress and Modeling with Mathematics. 0 = 0 /. = /. / = 6. 0 /8 = The index n = is even and a > 0. So, 6 has two real square roots. Because 6 = 6 and ( 6) = 6, the square roots of 6 are ± 6 = ±6, or ±6 / = ±6. 8. The index n = is even and a > 0. So, 8 has two real fourth roots. Because = 8 and ( ) = 8, the fourth roots of 8 are ± 8 = ±, or ±8 / = ±. 9. The index n = is odd, so 000 has one real cube root. Because 0 = 000, the cube root of 000 is 000 = 0, or (000) / = The index n = 9 is odd, so has one real ninth root. Because ( ) 9 =, the ninth root of is 9 =, or ( ) /9 =.. 6 in. = in. Check: =? 6 =? 6 So, each side of the cube is inches. 6 =? 6 6 = 6. 6 cm = 6 cm Check: 6 =? =? =? 6 6 = 6 So, each side of the cube is 6 centimeters.. 6 = =. 6 = ( 6) ( 6) ( 6) = 6. = ( 7) ( 7) ( 7) = = ( ) = () = 7. 8 /7 = 7 8 = 7 = 8. ( 6) / is not a real number because there is no real number that can be multiplied b itself two times to produce ( 8 ) = (8 / ) = 8 / 0. ( ) 6 = [( ) / ] 6 = ( ) 6/. ( ) /7 = [( ) /7 ]. 9 / = (9 / ) = ( 7 ) = ( 9 ). / = ( / ) = = 8 Algebra Copright Big Ideas Learning, LLC

9 . / = ( / ) = =. ( 6) / is not a real number because ( 6) / = [( 6) / ], and there is no real number that can be multiplied b itself two times to produce ( ) / = [( ) / ] = ( ) = 9 8. V = 6 π S/ = 6 π (60)/ 0.67 (6.78).7 The volume of the sphere is about cubic meters. 9. Write the radicand, a, as the base and write the exponent as a fraction with the power, m, as the numerator and the index, n, as the denominator. 7. ( 8) /7 = [( 8) /7 ] = ( ) = 8. / = ( / ) = 7 = 0 9. The numerator and denominator are reversed. ( ) = ( / ) = / 0. ( 8) / is not a real number because there is no real number that can be multiplied b itself four times to produce 8.. ( 000) / / = 000 / = 000. ( 6) /6 /6 6 = 6 /6 = = 6 6. (7) / = 7 / =. (9) / = 9 / =. A = w ( 7 ) = ( 9 ) = = 0 = 9 = = ( 6 79 ) ( / ) = ( 6 ) ( ) = () ( ) = ()() = 6 The area of the bake sale sign is 6 square feet = 7 / = (7 / ) = = One side of the box is millimeters. 7. r = ( V πh ) / = ( () (.)()) / = (.6) / (.9) / The radius of the paper cup is about inch. 0. A = s Copright Big Ideas Learning, LLC Algebra x = s x = s x = s x / = s An expression that represents the side length of the square is x / inches.. r = ( F P) /n = (,00, ,000 ) /6 = (.7) /6 0.0 The annual inflation rate is about.%.. r = ( F P) /n = (..6) /0 (.78) / The annual inflation rate is about 9.%.. = / =, 0 = 0 / = 0, = ( ) / = So, x = x / is true for x =, x = 0, and x =.. no; The value of n a is not alwas positive, and the value of n a is not alwas negative. If n is odd and a is negative, then n a will be negative and n a will be positive.. ( /6 ) x = (/6) x / = / x / ( 6 = 6 = 6, or = (x) / The simplified expression is (x) /, or x. )

10 6. ( / ) / = ( +/ ) / ) = ( / ) / ( + = + = = (/)(/) = ( The simplified expression is. = 6 ), or 7. x 6 + x = x 6/ + x / = x + x = (x ) = x The simplified expression is x. 8. (x / / ) 9 = x (/) 9 (/) 9 / = x 9/ 9/ / = x (9/)+(/) = x 0/ = x The simplified expression is x. 9. V = = = The edge length of the dodecahedron is approximatel.8 feet. 0. Sample answer: The formula for the period of a pendulum is T = π g (, or T = π g ) /.. The statement (x / ) = x is alwas true because (x / ) = x (/) = x / = x = x b the Power of a Power Propert.. The statement x / = x is sometimes true. If x =, then x / = / = = and x = = = =. So, the statement is true if x =. Otherwise, it is false.. The statement x / = x is alwas true because of the definition of a rational exponent.. The statement x / = x is sometimes true because it is onl true for x = 0 and x =.. 0 / =? 0 / =? 0 =? =? 0 0 =? =? 0 = 0 = 8 / =? 8 8 =? =? 6 8 x / x / =? x x (/) (/) =? x / x / = x / The statement x/ x / = x is sometimes true. It is true b the Quotient of Powers Propert and the definition of rational exponents except when x = 0 because division b 0 is undefined. 6. x = x / x Let x =. x = x (/)+ x = x 0/ x = x (/)+(9/) =? ( ) 0/ x = x 0/ =? ( ) 0 =? ( ) 0 Let x = 0. Let x =. x = x 0/ x = x 0/ 0 =? 0 0/ =? 0/ 0 =? ( 0 ) 0 =? ( ) 0 0 =? 0 0 =? 0 0 = 0 = Let x = 8. So, the statement x = x / x is x = x 0/ sometimes true. If x = 0 or x =, 8 =? 8 0/ the statement is true. Otherwise 8 =? ( 8 ) 0 it is false. 8 =? Algebra Copright Big Ideas Learning, LLC

11 Chapter 6 Maintaining Mathematical Proficienc 7. f (x) = x 0 f (x) = x 0 f ( ) = ( ) 0 f (0) = (0) 0 = 6 0 = 0 0 = 6 = 0 f (x) = x 0 f (8) = (8) 0 = 6 0 = 6 So, f ( ) = 6, f (0) = 0, and f (8) = w(x) = x w(x) = x w( ) = ( ) w(0) = (0) = = 0 = = w(x) = x w(8) = (8) = 0 = So, w( ) =, w(0) =, and w(8) =. 9. h(x) = x h(x) = x h(x) = x h( ) = ( ) h(0) = 0 h(8) = 8 = + = = = 6 So, h( ) = 6, h(0) =, and h(8) =. 6. Explorations (p. 0). x 6() x 0 6() () + 6() 6 + 6() 8 + 6() 6 + 6() x 6() x 0 6() () 6 + 6() () () () 0 6,8 Each value of x increases b the same amount, while each value of is multiplied b the same factor. 60. g(x) = 8x + 6 g(x) = 8x + 6 g(x) = 8x + 6 g( ) = 8( ) + 6 g(0) = 8(0) + 6 g(8) = 8(8) + 6 = + 6 = = = 8 = 6 = 80 So, g( ) = 8, g(0) = 6, and g(8) = 80. Copright Big Ideas Learning, LLC Algebra

12 Chapter 6. x 6 ( x ) 0 6 ( ) ( ) ( ) + 6 ( ) + 6 ( ) + 6 ( x 6 ( x ) ) 0 6 ( ) ( ) + 6 ( ) ( ) ( ) ( 6 ) 0 The statement seems to be true because as the exponent increases b a constant amount, the base is multiplied b itself the same number of additional times.. a. x 0 6 x = x x b. x 0 6 () x () () 0 () () () = () x x c. x 0 6 (.) x (.) (.) 0 (.) (.) (.) ,000, = 6( ) x 0 0 = (.) x 000 = 6() x x 8 x 6 x Both are curved and do not intersect the x-axis; The graph from Exploration is increasing, the graph from Exploration is decreasing.. Sample answer: All graphs of an exponential function seem to have a similar curved shape, and the do not intersect the x-axis. 6 Algebra Copright Big Ideas Learning, LLC

13 d. x 6 ( ( ) x ) 6 = 6 ( ) = 6 6 f. x 6 ( ) x ) 6 = ( 6 ) 6 ( ) = ( (. 6. ) x 0 ( ( ) x ) = ( ) 0 = ( ) = x 0 ) x ( ) = ( ) ( ) 0 = () ( ) = ( (.6. ) = ( ) x 6 80 = ( ) x x e. 6 x x 6 ( x ) ( ) 6 = (6) ( ) = (6) 9 8 x 0 ) x ( ) = () ( ) 0 = () ( ) = ( ( 0.7 ) These graphs have the same characteristics as the graphs from Exploration. The have the same general curved shape, and the do not intersect the x-axis. 6. Monitoring Progress (pp ) x 0 8 As x increases b, is multiplied b. So, the function is exponential. 6 = ( ) x x x ( ) +( ) +( ) As x increases b, decreases b. The rate of change is constant. So, the function is linear.. = (9) x = (9) x = (9) x = (9) = (9) 0 = (9) = ( 8) = () = ( 9 ) Copright Big Ideas Learning, LLC Algebra 7 = 8 = = (). =.() x =.() x =.() x =.() =.() 0 =.() =.(0.) =.() =. = 0.7 =..(.).

14 . x 0 () x () () () 0 () () f (x) x f(x) = () x 8 7. x () x+ () () 9 x 0 () x+ () 0 () () x The parent function is g(x) = x. The graph of f is a vertical stretch b a factor of and a reflection in the x-axis of the graph of g. The -intercept of the graph of f,, is below the -intercept of the graph of g,. From the graph of f, ou can see that the domain is all real numbers and the range is < x 0 ( ) x ( ) ( ) ) 0 ( ) ( ) ( f (x) = () x From the graph, ou can see that the domain is all real numbers and the range is <. x (0.) x + (0.) + (0.) + f (x) 9 7 x 0 (0.) x + (0.) 0 + (0.) + (0.) + f (x) f(x) = ( ) x 8 0 x 0 The parent function is g(x) = ( ) x. The graph of f is a vertical stretch b a factor of of the graph of g. The -intercept of the graph of f,, is above the -intercept of the graph of g,. From the graph of f, ou can see that the domain is all real numbers and the range is > = (0.) x + x From the graph, ou can see that the domain is all real numbers and the range is >. x 0 g(x) x Both functions have the same value when x = 0, but the value of f is less than the value of g over the rest of the interval. 8 Algebra Copright Big Ideas Learning, LLC

15 Chapter 6 0. a. Because the graph crosses the -axis at (0, 00), the -intercept is 00. Also, the -values increase b a factor of 00 = as x increases b. 00 = ab x = 00() x So, the population can be modeled b = 00() x. b. = 00() x = 00() 6 = 00(6) = 600 So, there are 600 bacteria after 6 das. c. The bacteria population in Example 7 is growing b a factor of, and the bacteria population in this problem is onl growing b a factor of. So, this bacteria population does not grow faster. 6. Exercises (pp. 0 ) Vocabular and Core Concept Check. Sample answer: 8 6 x. The -intercept occurs when x = 0. So, when x = 0, the value of the function is = ab 0 = a = a.. The graph of = x is the parent function for the graph of = () x. The graph of = () x is a vertical stretch b a factor of of the graph of = x. The -intercept of = () x,, is above the -intercept of = x,. The both have a domain of all real numbers and a range of > 0.. The equation that does not belong is f (x) = ( ) x. Because the base of the power is a negative number, this is not an exponential function. The other three equations represent exponential functions. Monitoring Progress and Modeling with Mathematics. The equation = (7) x represents an exponential function because it fits the pattern = ab x, where a = and b = The equation = 6x does not represent an exponential function because it fits the pattern = mx + b, and therefore represents a linear function. 7. The equation = x does not represent an exponential function because the exponent is a constant. 8. The equation = x represents an exponential function because it fits the pattern = ab x, where a = and b =. 9. The equation = 9( ) x does not represent an exponential function. Although it fits the pattern = ab x, the definition of an exponential function states that b cannot be negative. 0. The equation = ()x does not represent an exponential function. Although it fits the pattern = ab x, the definition of an exponential function states that b cannot be x As x increases b, increases b. The rate of change is constant. So, the function is linear x 6 8 As x increases b, is multiplied b. So, the function is exponential x As x increases b, is multiplied b. So, the function is exponential x ( 9) +( 9) +( 9) +( 9) As x increases b, decreases b 9. The rate of change, 9, or, is constant. So, the function is linear.. = x = = 9 6. f (x) = () x f ( ) = () ) = ( = Copright Big Ideas Learning, LLC Algebra 9

16 7. = () x = () = () = f (x) = 0. x f ( ) = 0. = ( = = 8 9. f (x) = (6)x ) f () = (6) = (6) = 7 0. = ()x = () = ( ) = ( ) = () = (8) =. C; The parent function of f (x) = (0.) x is g(x) = (0.) x. The graph of the parent function, g, decreases as x increases because 0 < b <. The graph of f is a vertical stretch of the graph of g, and the -intercept of f is because a =. So, the function f matches graph C.. B; The parent function of f (x) = (0.) x is g(x) = (0.) x. The graph of the parent function, g, decreases as x increases because 0 < b <. The graph of f is a vertical stretch and a reflection in the x-axis of the graph of g, and the -intercept of f is because a =. So, the function f matches graph B.. x 0 (0.) x (0.) (0.) (0.) 0 (0.) (0.) f (x) f(x) = (0.) x x The parent function is g(x) = (0.) x. The graph of f is a vertical stretch b a factor of of the graph of g. The -intercept of the graph of f,, is above the -intercept of the graph of g,. From the graph of f, ou can see that the domain is all real numbers and the range is > x 0 x 0 f (x) x f(x) = x 6 The parent function is g(x) = x. The graph of f is a reflection in the x-axis of the graph of g. The -intercept of the graph of f,, is below the -intercept of the graph of g,. From the graph of f, ou can see that the domain is all real numbers and the range is < 0.. A; The parent function of f (x) = () x is g(x) = () x. The graph of the parent function, g, increases as x increases because b >. The graph of f is a vertical stretch of the graph of g, and the -intercept of f is because a =. So, the function f matches graph A.. D; The parent function of f (x) = () x is g(x) = () x. The graph of the parent function, g, increases as x increases because b >. The graph of f is a vertical stretch and a reflection in the x-axis of the graph of g, and the -intercept of f is because a =. So, the function f matches graph D. 0 Algebra Copright Big Ideas Learning, LLC

17 7. x 0 (7) x (7) (7) (7) 0 (7) (7) f (x) x f(x) = (7) x x 0 (8)x (8) (8) (8)0 (8) (8) f (x) f(x) = (8)x 60 x The parent function is g(x) = 7 x. The graph of f is a vertical stretch b a factor of and a reflection in the x-axis of the graph of g. The -intercept of the graph of f,, is below the -intercept of the graph of g,. From the graph of f, ou can see that the domain is all real numbers and the range is < x 0 6 ( ) x 6 ( ) 6 ( ) ) 0 6 ( ) 6 ( ) 6 ( f (x) 8 6 The parent function is g(x) = 8 x. The graph of f is a vertical shrink of the graph of g b a factor of. The -intercept of the graph of f,, is below the -intercept of the graph of g,. From the graph of f, ou can see that the domain is all real numbers and the range is > x 0 (0.)x (0.) (0.) (0.)0 (0.) (0.) f (x) f(x) = 6( ) x 6 8 f(x) = (0.)x x The parent function is g(x) = ( x ). The graph of f is a vertical stretch b a factor of 6 of the graph of g. The -intercept of the graph of f, 6, is above the -intercept of the graph of g,. From the graph of f, ou can see that the domain is all real numbers and the range is > 0. x The parent function is g(x) = (0.) x. The graph of f is a vertical stretch of the graph of g b a factor of. The -intercept of the graph of f,, or., is above the -intercept of the graph of g,. From the graph of f, ou can see that the domain is all real numbers and the range is > 0. Copright Big Ideas Learning, LLC Algebra

18 . x 0 x 0 f (x) x ( ) x+ ( ) ( ) 7 8 x 0 f(x) = x x ( ) x+ ( ) 0 ( ) ( ) From the graph, ou can see that the domain is all real numbers and the range is >.. x x+ 0 f (x) x = ( ) x+ 8 6 f(x) = x From the graph, ou can see that the domain is all real numbers and the range is <. 6 x x From the graph, ou can see that the domain is all real numbers and the range is > 0.. x 0 x = x + 7 8(0.7) x+ 8(0.7) 8(0.7) x 0 8(0.7) x+ 8(0.7) 0 8(0.7) 8(0.7) x = 8(0.7) x+ 6 x From the graph, ou can see that the domain is all real numbers and the range is > 7. 6 From the graph, ou can see that the domain is all real numbers and the range is <. Algebra Copright Big Ideas Learning, LLC

19 6. x 0 (6) x (6) (6) f (x).97.. x 0 g(x) f (x) x (6) x (6) 0 (6) (6) f (x) x The value of f is less than the value of g over the entire interval. x 6 f(x) = (6) x From the graph, ou can see that the domain is all real numbers and the range is >. 7. The graph of g is a vertical shrink b a factor of of the graph of f. So, a =. 8. The graph of g is a vertical translation units up of the graph of f. So, k =. 9. The graph of g is a horizontal translation units right of the graph of f. So, h =. 0. The graph of g is a horizontal translation units left of the graph of f. So, h =.. According to the order of operations, the power should be simplified before multipling b 6. g(x) = 6(0.) x ; x = g( ) = 6(0.) = 6() =. The graph approaches the line =, not = 0. The domain is all real numbers and the range is <.. x 0 h(x) 6 8 f (x) x Both functions have the same value when x =, but the value of h is greater than the value of f over the rest of the interval.. a. x 0 0. x Portion of screen displa Zoom Displa = 0. x x Zooms Based on the context of the problem, because ou cannot zoom a negative number of times, the domain is x 0. From the graph, ou can see that the range is 0 <. Copright Big Ideas Learning, LLC Algebra

20 b. The -intercept is. This means that when ou do not zoom in, 00%, or all, of the original screen displa is seen. c. = 0. x = 0. = 0.06 So, ou see 6.% of the original screen if ou zoom in twice. 6. a. x 0 () x () 0 () () () () 0 Population Coote Population = () x 0 0 x Twent-ear periods Based on the context of the problem, because ou cannot have a negative number of 0-ear periods, the domain is x 0. From the graph, ou can see that the range is. b. The -intercept is. This means that the coote population was at the beginning of the first interval. c. = () x = () = (9) = In 0 ears, twent-ear periods have passed. So, there will be cootes in 0 ears x x When x = 0, the value of is 0. So, the -intercept is 0. Each -value is multiplied b a factor of as x increases b. Using a = 0 and b =, an exponential function of the form = ab x that is represented b the table is = 0 ( ) x x 0 0. The graph crosses the -axis at (0, 0.). So, the -intercept is 0.. The -values increase b a factor of as x increases b. Using a = 0. and b =, an exponential function of the form = ab x that is represented b the table is = 0.() x x 0 8 The graph crosses the -axis at (0, 8). So, the -intercept is 8. Each -value is multiplied b a factor of as x increases b. Using a = 8 and b =, an exponential function of the form = ab x that is represented b the graph is = 8 ( ) x. When x = 0, the value of is. So, the -intercept is. The -values increase b a factor of 7 as x increases b. Using a = and b = 7, an exponential function of the form = ab x that is represented b the table is = (7) x. Algebra Copright Big Ideas Learning, LLC

21 . a x When x = 0, the value of is 0. So, the -intercept is 0. The -values increase b a factor of as x increases b. Using a = 0 and b =, an exponential function of the form = ab x that is represented b the graph is = 0 ( x. ) x ) = 0 ( b. = 0 ( ) = 0(7.97) = 0.7 So, after months, the number of visitors is about 0.. The -intercept is 00 because that is the initial value. The -values increase b a factor of + 6% =.06 as the number of ears x increases b. Using a = 00 and b =.06, an exponential function of the form = ab x that represents this situation is = 00(.06) x. = 00(.06) x = 00(.06) 6 00(.8) 68 The store expects to sell about 68 grills in Year 6.. x 0 f (x) = x g(x) = x g(x) = x 8 6 x f(x) = x 7. Your friend is incorrect. This is not an exponential function because even though the values of are being multiplied b a common factor, the values of x are not increasing at a constant rate.. When a is positive, it causes a vertical stretch (for a > ) or shrink (for 0 > a > ) of the graph of the parent function. If a is negative, it causes a vertical stretch (for a > ) or shrink (for 0 > a > ) and a reflection in the x-axis of the graph of the parent function. 6. Sample answer: The equation f(x) = x represents a horizontal translation units right of the graph of h(x) = x. 7. Using the form = ab x h + k, where h = and k =, an equation is g(x) = x a. The point on the graph with a -value of 0 has an x-value of. So, the stock will be worth $0 after weeks. b. The stock price in Week is $0, and the stock price in Week is $0. So, the stock price drops $0 $0 = $0 from Week to Week. 9. The graph crosses the -axis at (0,.). So, the -intercept is.. Each -value is multiplied b a factor of. = 6 = as x increases b. Using a =. and b =, an exponential function of the form = ab x that is represented b the graph is f(x) =.() x. f (x) =.() x f (7) =.() 7 =.(8) = 9 So, f (7) = Sample answer: If ou were to do something nice for people and then ask each of those people to do something nice for more people who will each do something nice for more people and so on, this situation can be modeled b the exponential function = () x. The -intercept is a = because initiall people had someone do something nice for them, and b = because the number of people who have someone do something nice for them is increasing b a common factor of. f(x + k) 6. f(x) = abx+k ab x = bx+k b x = b(x+k) x = b k 6. Using a = and b = =, an exponential function of the form = ab x that represents this situation is f(x) = () x. The -intercept of g is units below the -intercept of f. The domain of both functions is all real numbers. The range of g is < and the range of f is < 0. Copright Big Ideas Learning, LLC Algebra

22 6. Sample answer: Let f(0) = 8. So, a = 8. Use the equation for slope. Solve for f(). f() f(0) m = 0 = f() 8 = f() 8 = f() = f() Use the exponential form of a function. Solve for b. f(x) = a(b) x = 8(b) = 8b 8 8 = b = b = b Using a = 8 and b =, an exponential function for this situation is f(x) = 8() x. Maintaining Mathematical Proficienc 6. % = 00 = % = 00 = % = 8 00 = % = 0 00 =. 6. Explorations (p. ) x As x increases b, is multiplied b about.. So, this situation can be described as exponential growth. Using a = 88 and b =., an exponential function of the form = ab t that can approximatel model this situation is = 88(.) t, where t represents the number of -ear intervals since 98. = 88(.) t 00,000 = 88(.) t 00, = 88(.)t (.) t Use a table of values, or Guess, Check, and Revise to find that if t =, then , which is close to 8.7. So, the population will return to about 00,000 nesting pairs after intervals of -ears, or about ears after 98, which is the ear 06.. a = = = , or about 9.8% b. Time (h) Temperature difference ( F) Bod temperature ( F) = ( 0.098) = 9.8.8( 0.098) = 9..( 0.098) = ( 0.098) = 8..( 0.098) = ( 0.098) = 80.7 So, the time of death was about 6 hours prior to midnight, or about 6 p.m.. As the independent variable changes b a constant amount, the dependent variable is multiplied b a constant factor.. a. Sample answer: the value of a CD each ear that earns.% interest compounded annuall b. Sample answer: the worth of a farm tractor that depreciates at a rate of 0% per ear 6. Monitoring Progress (pp. 8). a. The initial amount is 00,000 and the rate of growth is %, or 0.. = a( + r) t = 00,000( + 0.) t = 00,000(.) t The website membership can be represented b = 00,000(.) t. 6 Algebra Copright Big Ideas Learning, LLC

23 b. The value t = 6 represents 06 because t = 0 represents 00. = 00,000(.) t = 00,000(.) 6 00,000(.),6,0 So, in 06, the website will have about,60,000 members x As x increases b, is multiplied b. So, the table represents an exponential deca function x As x increases b, increases b 7. The function has a constant rate of change. So, it is a linear function and therefore neither an exponential growth nor an exponential deca function.. The function is of the form = a( r) t, where r <. So, it represents exponential deca. Use the deca factor r to find the rate of deca. r = 0.9 r = 0.08 r = 0.08 r = 0.08 So, the rate of deca is 8%.. The function is of the form = a( + r) t, where + r >. So, it represents exponential growth. Use the growth factor + r to find the rate of growth. + r =. r = 0. So, the rate of growth is 0%. 7. = (0.9) t+ = (0.9) t (0.9) (0.9) t (0.9) t So, the function represents exponential deca. 8. = P ( + r n) nt = 00 ( ) t = 00(.007) t Balance (dollars) t Savings Account = 00(.007) t t Year 9. a. The initial value is $,00, and the rate of deca is 9%, or = a( r) t =,00( 0.09) t =,00(0.9) t The value of the car can be represented b =,00(0.9) t. b. =,00(0.9) t =,00(0.9) (/)(t) =,00(0.9 / ) t,00(0.99) t So, r 0.99 r r r The monthl percent decrease is about 0.8%. 6. f(t) = (.0) 0t = (.0 0 ) t (.) t So, the function represents exponential growth. Copright Big Ideas Learning, LLC Algebra 7

24 c. t 0 8 6,00,7 0, Value (dollars),000,000 8,000,000, Value of a Car =,00(0.9) t t Year From the graph, ou can see that the -value is about 7000 when t =. So, the value of the car is about $7000 after ears. 6. Exercises (pp. 9 ) Vocabular and Core Concept Check. In the exponential growth function = a( + r) t, the quantit r is called the rate of growth.. The deca factor is r.. Exponential growth occurs when a quantit increases b the same factor over equal intervals of time. Exponential deca occurs when a quantit decreases b the same factor over equal intervals of time.. The function = ab x represents exponential growth when b > and x represents time. The function = ab x represents exponential deca when 0 < b < and x represents time. Monitoring Progress and Modeling with Mathematics. The initial amount is a = 0, and the rate of growth is r = 0.7, or 7%. = 0( + 0.7) t = 0(.7) 0(6.) 7.6 So, the value of is about 7.6 when t =. 6. The initial amount is a = 0, and the rate of growth is r = 0., or 0%. = 0( + 0.) t = 0(.) 0(.78).8 So, the value of is about.8 when t = r =. r = 0. The initial amount is a =, and the rate of growth is r = 0., or 0%. = (.) t = (.) (.88) 6. So, the value of is about 6. when t = r =.0 r = 0.0 The initial amount is a =, and the rate of growth is r = 0.0, or %. = (.0) t = (.0) (.76). So, the value of is about. when t = r =.07 r = 0.07 The initial amount is a = 00, and the rate of growth is r = 0.07, or 7.%. f (t) = 00(.07) t f () = 00(.07) 00(.9). So, the value of f(t) is about. when t = r =.08 r = 0.08 The initial amount is a = 7, and the rate of growth is r = 0.08, or.8%. h(t) = 7(.08) t h() = 7(.08) 7(.8) 00.9 So, the value of h(t) is about 00.9 when t =. 8 Algebra Copright Big Ideas Learning, LLC

25 . + r = r = The initial amount is a = 6.7, and the rate of growth is r =, or 00%. g(t) = 6.7() t g() = 6.7() = 6.7() =.0 So, the value of g(t) is about.0 when t =.. + r =.8 r = 0.8 The initial amount is a =, and the rate of growth is r = 0.8, or 80%. p(t) =.8 t p() = So, the value of p(t) is about 8.9 when t =.. The initial amount is 0,000, and the rate of growth is 6%, or 0.6. = a( + r) t = 0,000( + 0.6) t = 0,000(.6) t The sales can be represented b = 0,000(.6) t.. The initial amount is,000, and the rate of growth is %, or 0.0. = a( + r) t =,000( + 0.0) t =,000(.0) t Your salar can be represented b =,000(.0) t.. The initial amount is 0,000, and the rate of growth is.%, or 0.. = a( + r) t = 0,000( + 0.) t = 0,000(.) t The population can be represented b = 0,000(.) t. 6. The initial amount is., and the rate of growth is.%, or 0.0. = a( + r) t =.( + 0.0) t =.(.0) t The cost of the item can be represented b =.(.0) t. 7. a. The initial amount is,000, and the rate of growth is %, or 0.0. = a( + r) t =,000( + 0.0) t =,000(.0) t The population of Brookfield can be represented b =,000(.0) t. b. The value t = 0 represents 00 because t = 0 represents 000. =,000(.0) t =,000(.0) 0,000(.89) 68,07 So, in 00, the population will be about 68, a. The initial amount is 0., and the rate of growth is %, or 0.. = a( + r) t = 0.( + 0.) t = 0.(.) t The weight of the catfish during the 8-week period can be represented b = 0.(.) t. b. = 0.(.) t = 0.(.) 0.(.89) 0.9 So, after weeks, the catfish will weigh about 0.9 pound. 9. r = 0.6 r = 0.6 r = 0.6 r = 0.6 The initial amount is a = 7, and the rate of deca is r = 0.6, or 60%. = 7( 0.6) t = 7(0.) = 7(0.06) = 6.8 So, the value of is 6.8 when t =. Copright Big Ideas Learning, LLC Algebra 9

26 0. r = 0. r = 0. r = 0. r = 0. The initial amount is a = 8, and the rate of deca is r = 0., or %. = 8( 0.) t = 8(0.8) 8(0.6).9 So, the value of is about.9 when t =.. r = 0.7 r = 0. r = 0. r = 0. The initial amount is a = 0, and the rate of deca is r = 0., or %. g(t) = 0(0.7) t g() = 0(0.7) 0(0.) 0. So, the value of g(t) is about 0. when t =.. r = 0..0 r = 0. r = 0. r = 0. The initial amount is a = 7, and the rate of deca is r = 0., or 0%. f (t) = 7(0.) t f() = 7(0.) = 7(0.) 9. So, the value of f(t) is about 9. when t =.. r = r = 0.00 r = 0.00 r = 0.00 The initial amount is a = 700, and the rate of deca is r = 0.00, or 0.%. w(t) = 700(0.99) t w() = 700(0.99) 700(0.98) So, the value of w(t) is about when t =.. r = r = 0. r = 0. r = 0. The initial amount is a = 0, and the rate of deca is r = 0., or.%. h(t) = 0(0.86) t h() = 0(0.86) 0(0.67) So, the value of h(t) is about when t =.. r = 7 8 r = 8 ( 7 8 = = 8) ( r) = ( r =, or 0. 8 The initial amount is a =, and the rate of deca is r = 0., or.%. = ( 7 t 8) = ( 7 8) 0.7 So, the value of is about 0.7 when t =. 8) 0 Algebra Copright Big Ideas Learning, LLC

27 6. r = r = ( = = ) ( r) = ( r =, or 0. The initial amount is a = 0., and the rate of deca is r = 0., or %. = 0. ( ) t = 0. ( ) 0.(0.) 0. So, the value of is about 0. when t =. 7. The initial amount is 00,000, and the rate of deca is %, or 0.0. = a( r) t = 00,000( 0.0) t = 00,000(0.98) t The population can be represented b = 00,000(0.98) t. 8. The initial amount is 900, and the rate of deca is 9%, or = a( r) t = 900( 0.09) t = 900(0.9) t The cost of the sound sstem can be represented b = 900(0.9) t. 9. The initial amount is 00, and the rate of deca is 9.%, or = a( r) t = 00( 0.09) t = 00(0.90) t The value of the stock can be represented b = 00(0.90) t. 0. The initial amount is 0,000, and the rate of deca is.%, or 0.. = a( r) t = 0,000( 0.) t = 0,000(0.866) t The compan s profit can be represented b = 0,000(0.866) t. ). Because the rate of growth is 0%, or., the growth factor is +. =., not just.. = a( + r) t b(t) = 0( +.) t b(8) = 0(.) 8 0(.879),9 After 8 hours, there are about,9 bacteria in the culture.. Because % is the rate of deca, the deca factor is 0. not = a( r) t v(t) =,000( 0.) t v() =,000(0.86),000(0.70),76 The value of the car in 0 is about $, x As x increases b, is multiplied b. So, the table represents an exponential deca function x ( ) +( ) +( ) As x increases b, decreases b. The function has a constant rate of change. So, it is a linear function and therefore neither an exponential growth nor an exponential deca function x ( 6) +( 6) +( 6) As x increases b, decreases b 6. The function has a constant rate of change. So, it is a linear function and therefore neither an exponential growth nor an exponential deca function x 7 9 As x increases b, is multiplied b. So, the table represents an exponential growth function. Copright Big Ideas Learning, LLC Algebra

28 x As x increases b, is multiplied b. So, the table represents an exponential growth function.. The function is of the form = a( + r) t, where + r >. So, it represents exponential growth. Use the growth factor + r to find the rate of growth. + r =. r = 0. So, the rate of growth is 0% a. x As x increases b, is multiplied b 6 represents an exponential deca function t Value $7,000 $9,600 $,680 $8, So, the table As t increases b, the value is multiplied b 0.8. So, the table represents an exponential deca function. b. (8,9)(0.8) =,. So, after ears, the value of the camper is about $,. 0. a t Visitors,000,00,0,6... As t increases b, the number of visitors is multiplied b.. So, the table represents an exponential growth function. b. + + t 6 7 Visitors,000,00,0,6 6,0 7,76 So, after the website is online 7 das, about 7,76 people will have visited it.... The function is of the form = a( r) t, where r <. So, it represents exponential deca. Use the deca factor r to find the rate of deca. r = 0.8 r = 0. r = 0. r = 0. So, the rate of deca is 0%.. The function is of the form = a( r) t, where r <. So, it represents exponential deca. Use the deca factor r to find the rate of deca. r = 0.9 r = 0.0 r = 0.0 r = 0.0 So, the rate of deca is %.. The function is of the form = a( + r) t, where + r >. So, it represents exponential growth. Use the growth factor + r to find the rate of growth. + r =.08 r = 0.08 So, the rate of growth is 8%.. The function is of the form = a( + r) t, where + r >. So, it represents exponential growth. Use the growth factor + r to find the rate of growth. + r =.06 r = 0.06 So, the rate of growth is 6%. 6. The function is of the form = a( r) t, where r <. So, it represents exponential deca. Use the deca factor r to find the rate of deca. r = 0.8 r = 0. r = 0. r = 0. So, the rate of deca is %. 7. The function is of the form = a( + r) t, where + r >. So, it represents exponential growth. Use the growth factor + r to find the rate of growth. + r = r = (, or 0. = = So, the rate of growth is %. Algebra Copright Big Ideas Learning, LLC )

29 8. The function is of the form = a( r) t, where r <. So, it represents exponential deca. Use the deca factor r to find the rate of deca. r = r = (, or 0. = = So, the rate of deca is 0%. 9. = (0.9) t = (0.9)t (0.9) = (0.9)t 0.66 = 0.66 (0.9)t.(0.9) t The function is of the form = a( r) t, where r <. So, it represents exponential deca. 0. = (.) t+8 = (.) t (.) 8 (.) t (.8).8(.) t The function is of the form = a( + r) t, where + r >. So, it represents exponential growth.. = (.06) 9t = (.06 9 ) t (.69) t The function is of the form = a( + r) t, where + r >. So, it represents exponential growth.. = (0.8) t = (0.8) ( ) t = (0.8 ) t = ( 0.8 ) t (0.96) t The function is of the form = a( r) t, where r <. So, it represents exponential deca.. x(t) = (.) t = (.) ( ) t = (. ) t = (. ) t (.0) t The function is of the form = a( + r) t, where + r >. So, it represents exponential growth. ). f(t) = 0.(.6) t = 0. (.6)t (.6) = 0..6 (.6)t 0.(.6) t The function is of the form = a( + r) t, where + r >. So, it represents exponential growth.. b(t) = (0.) t+ = (0.) t (0.) = (0.) (0.) t = (0.667) (0.) t 0.67(0.) t The function is of the form = a( r) t, where r <. So, it represents exponential deca. 6. r(t) = (0.88) t = (0.88 ) t (0.60) t The function is of the form = a( r) t, where r <. So, it represents exponential deca. 7. = P ( + n) r nt = 000 ( ) t = 000( + 0.0) t = 000(.0) t 8. = P ( + n) r nt = 00 ( ) t = 00( + 0.0) t = 00(.0) t 9. = P ( + n) r nt = 600 ( ) t = 600( ) t = 600(.007) t 60. = P ( + n) r nt = 00 ( ) t = 00( + 0.0) t = 00(.0) t Copright Big Ideas Learning, LLC Algebra

30 6. a. Tree A Year, t 0 Basal area, A From the table, ou know the initial basal area of Tree A is 0 square inches, and it is multiplied b a growth factor of. each ear. So, P = 0 and + r =.. = P( + r) t = 0(.) t The initial basal area of Tree B is square inches, and the rate of growth is 6%, or = P( + r) t = ( ) t = (.06) t So, the function that represents the basal area of Tree A after t ears is = 0(.) t and the basal area of Tree B after t ears is = (.06) t. b. Tree B Year, t 0 Basal area, A Basal area (in. ) Tree Basal Area A A A = 0(.) t t Year A B = (.06) t The basal area of Tree B is larger than the basal area of Tree A, but the difference between the basal areas is decreasing. 6. a. The principal of the investment account is $00, the annual interest rate is 6%, or 0.06, and because the interest is compounded quarterl, n =. = P ( + n) r nt = 00 ( + 0. ) t = 00( + 0.0) t = 00(.0) t The graph crosses the -axis at (0, 00). So, the principal of the savings account is $00. The points on the graph are approximatel (, ), (, 0), and (, 7). Because ,.08, and.07, the 00 balance of the savings account has a growth factor of about.08. So, P = 00 and + r =.08. = P( + r) t = 00(.08) t So, the function that represents the balance of the investment account is = 00(.0) t, and the function that represents the balance of the savings account is = 00(.08) t. b. Investment account: Year, t 0 Balance (dollars), Balance (dollars) Accounts = 00(.0) t = 00(.08) t t Year Both accounts start with the same balance. The investment account balance is increasing at a faster rate, so it is greater than the savings account balance after the start. 6. a. The initial value is,000, and the rate of growth is.%, or 0.0. = P( + r) t =,000( + 0.0) t =,000(.0) t A function that represents the cit s population is =,000(.0) t. b. Use the fact that t = (t) and the properties of exponents to rewrite the function in a form that reveals the monthl rate of growth. =,000(.0) t =,000(.0) (/)(t) =,000(.0 (/) ) (t),000(.007) (t) + r.007 r So, the monthl percent increase is about 0.%. Algebra Copright Big Ideas Learning, LLC

Chapter 9. Worked-Out Solutions. Check. Chapter 9 Maintaining Mathematical Proficiency (p. 477) y = 2 x 2. y = 1. = (x + 5) 2 4 =?

Chapter 9. Worked-Out Solutions. Check. Chapter 9 Maintaining Mathematical Proficiency (p. 477) y = 2 x 2. y = 1. = (x + 5) 2 4 =? Maintaining Mathematical Proficienc (p. ). x + 0x + x + (x)() + (x + ). x 0x + 00 x (x)(0) + 0 (x 0). x + x + x + (x)() + (x + ). x x + x (x)(9) + 9 (x 9). x + x + x + (x)() + (x + ) Check x x +? ()? ()

More information

Maintaining Mathematical Proficiency

Maintaining Mathematical Proficiency Chapter Maintaining Mathematical Proficiency Simplify the expression. 1. 8x 9x 2. 25r 5 7r r + 3. 3 ( 3x 5) + + x. 3y ( 2y 5) + 11 5. 3( h 7) 7( 10 h) 2 2 +. 5 8x + 5x + 8x Find the volume or surface area

More information

5.1 Practice A. Name Date ( ) 23 15, , x = 20. ( ) 2

5.1 Practice A. Name Date ( ) 23 15, , x = 20. ( ) 2 Name Date. Practice A In Exercises, find the indicated real nth root(s) of a.. n =, a =. n =, a = 9. n =, a = 8 In Exercises 9, evaluate the expression without using a calculator.. 7. 6 8. ( ) 7. 6 6.

More information

c) domain {x R, x 3}, range {y R}

c) domain {x R, x 3}, range {y R} Answers Chapter 1 Functions 1.1 Functions, Domain, and Range 1. a) Yes, no vertical line will pass through more than one point. b) No, an vertical line between = 6 and = 6 will pass through two points..

More information

Answers. Chapter Warm Up. Sample answer: The graph of h is a translation. 3 units right of the parent linear function.

Answers. Chapter Warm Up. Sample answer: The graph of h is a translation. 3 units right of the parent linear function. Chapter. Start Thinking As the string V gets wider, the points on the string move closer to the -ais. This activit mimics a vertical shrink of a parabola... Warm Up.. Sample answer: The graph of f is a

More information

The P/Q Mathematics Study Guide

The P/Q Mathematics Study Guide The P/Q Mathematics Study Guide Copyright 007 by Lawrence Perez and Patrick Quigley All Rights Reserved Table of Contents Ch. Numerical Operations - Integers... - Fractions... - Proportion and Percent...

More information

Subtract 16 from both sides. Divide both sides by 9. b. Will the swing touch the ground? Explain how you know.

Subtract 16 from both sides. Divide both sides by 9. b. Will the swing touch the ground? Explain how you know. REVIEW EXAMPLES 1) Solve 9x + 16 = 0 for x. 9x + 16 = 0 9x = 16 Original equation. Subtract 16 from both sides. 16 x 9 Divide both sides by 9. 16 x Take the square root of both sides. 9 4 x i 3 Evaluate.

More information

4.5 Practice B. 4.5 Practice A. Name Date. Possible zeros: Possible zeros: 5. Justify. your answer. your answer. In Exercises 1 6, solve the equation.

4.5 Practice B. 4.5 Practice A. Name Date. Possible zeros: Possible zeros: 5. Justify. your answer. your answer. In Exercises 1 6, solve the equation. Practice A Practice B In Eercises, solve the equation.. q q 0q 0. k + k + 9k 0.. p p. 8u u n + n 9n 8 0 In Eercises 7 0, find the zeros of the function. Then sketch a graph of the function. 7. f + 8. g

More information

Logarithms. Bacteria like Staph aureus are very common.

Logarithms. Bacteria like Staph aureus are very common. UNIT 10 Eponentials and Logarithms Bacteria like Staph aureus are ver common. Copright 009, K1 Inc. All rights reserved. This material ma not be reproduced in whole or in part, including illustrations,

More information

where a 0 and the base b is a positive number other

where a 0 and the base b is a positive number other 7. Graph Eponential growth functions No graphing calculators!!!! EXPONENTIAL FUNCTION A function of the form than one. a b where a 0 and the base b is a positive number other a = b = HA = Horizontal Asmptote:

More information

CHAPTER 3 Polynomial Functions

CHAPTER 3 Polynomial Functions CHAPTER Polnomial Functions Section. Quadratic Functions and Models............. 7 Section. Polnomial Functions of Higher Degree......... 7 Section. Polnomial and Snthetic Division............ Section.

More information

UNIT 3: MODELING AND ANALYZING QUADRATIC FUNCTIONS

UNIT 3: MODELING AND ANALYZING QUADRATIC FUNCTIONS UNIT 3: MODELING AND ANALYZING QUADRATIC FUNCTIONS This unit investigates quadratic functions. Students study the structure of quadratic expressions and write quadratic expressions in equivalent forms.

More information

Algebra I EOC Review (Part 2)

Algebra I EOC Review (Part 2) 1. Let x = total miles the car can travel Answer: x 22 = 18 or x 18 = 22 2. A = 1 2 ah 1 2 bh A = 1 h(a b) 2 2A = h(a b) 2A = h a b Note that when solving for a variable that appears more than once, consider

More information

Summary for a n = b b number of real roots when n is even number of real roots when n is odd

Summary for a n = b b number of real roots when n is even number of real roots when n is odd Day 15 7.1 Roots and Radical Expressions Warm Up Write each number as a square of a number. For example: 25 = 5 2. 1. 64 2. 0.09 3. Write each expression as a square of an expression. For example: 4. x

More information

Glossary. Also available at BigIdeasMath.com: multi-language glossary vocabulary flash cards. An equation that contains an absolute value expression

Glossary. Also available at BigIdeasMath.com: multi-language glossary vocabulary flash cards. An equation that contains an absolute value expression Glossar This student friendl glossar is designed to be a reference for ke vocabular, properties, and mathematical terms. Several of the entries include a short eample to aid our understanding of important

More information

MODELING WITH FUNCTIONS

MODELING WITH FUNCTIONS MATH HIGH SCHOOL MODELING WITH FUNCTIONS Copright 05 b Pearson Education, Inc. or its affiliates. All Rights Reserved. Printed in the United States of America. This publication is protected b copright,

More information

On a video game, Jacob got 1685 points and earned two bonuses worth 193 and 270 points. What is his total score? Answer: 2148 points

On a video game, Jacob got 1685 points and earned two bonuses worth 193 and 270 points. What is his total score? Answer: 2148 points Chapter Numerical Expressions and Factors Information Frame 9. Sample answers are given.. Ke Words: the sum of, the total of Real-Life Application : On a video game, Jacob got 68 points and earned two

More information

Using the Laws of Exponents to Simplify Rational Exponents

Using the Laws of Exponents to Simplify Rational Exponents 6. Explain Radicals and Rational Exponents - Notes Main Ideas/ Questions Essential Question: How do you simplify expressions with rational exponents? Notes/Examples What You Will Learn Evaluate and simplify

More information

Algebra 2 Notes Powers, Roots, and Radicals Unit 07. a. Exponential equations can be solved by taking the nth

Algebra 2 Notes Powers, Roots, and Radicals Unit 07. a. Exponential equations can be solved by taking the nth Algebra Notes Powers, Roots, and Radicals Unit 07 Exponents, Radicals, and Rational Number Exponents n th Big Idea: If b a, then b is the n root of a. This is written n a b. n is called the index, a is

More information

Algebra 1. Math Review Packet. Equations, Inequalities, Linear Functions, Linear Systems, Exponents, Polynomials, Factoring, Quadratics, Radicals

Algebra 1. Math Review Packet. Equations, Inequalities, Linear Functions, Linear Systems, Exponents, Polynomials, Factoring, Quadratics, Radicals Algebra 1 Math Review Packet Equations, Inequalities, Linear Functions, Linear Systems, Exponents, Polynomials, Factoring, Quadratics, Radicals 2017 Math in the Middle 1. Clear parentheses using the distributive

More information

Answers. Chapter Warm Up. Sample answer: The graph of f is a translation 3 units right of the parent linear function.

Answers. Chapter Warm Up. Sample answer: The graph of f is a translation 3 units right of the parent linear function. Chapter. Start Thinking As the string V gets wider, the points on the string move closer to the -ais. This activit mimics a vertical shrink of a parabola... Warm Up.. Sample answer: The graph of f is a

More information

Solving Multi-Step Equations

Solving Multi-Step Equations 1. Clear parentheses using the distributive property. 2. Combine like terms within each side of the equal sign. Solving Multi-Step Equations 3. Add/subtract terms to both sides of the equation to get the

More information

Essential Question How can you determine whether a polynomial equation has imaginary solutions? 2 B. 4 D. 4 F.

Essential Question How can you determine whether a polynomial equation has imaginary solutions? 2 B. 4 D. 4 F. 5. TEXAS ESSENTIAL KNOWLEDGE AND SKILLS 2A.7.A The Fundamental Theorem of Algebra Essential Question How can ou determine whether a polnomial equation has imaginar solutions? Cubic Equations and Imaginar

More information

Maintaining Mathematical Proficiency

Maintaining Mathematical Proficiency Name Date Chapter 3 Maintaining Mathematical Proficienc Plot the point in a coordinate plane. Describe the location of the point. 1. A( 3, 1). B (, ) 3. C ( 1, 0). D ( 5, ) 5. Plot the point that is on

More information

Solutions Key Exponential and Radical Functions

Solutions Key Exponential and Radical Functions CHAPTER 11 Solutions Key Exponential and Radical Functions xzare YOU READY, PAGE 76 1. B; like terms: terms that contain the same variable raised to the same power. F; square root: one of two equal factors

More information

Rational Exponents and Radical Functions

Rational Exponents and Radical Functions .1..... Rational Eponents and Radical Functions nth Roots and Rational Eponents Properties of Rational Eponents and Radicals Graphing Radical Functions Solving Radical Equations and Inequalities Performing

More information

Evaluate nth Roots and Use Rational Exponents. p Evaluate nth roots and study rational exponents. VOCABULARY. Index of a radical

Evaluate nth Roots and Use Rational Exponents. p Evaluate nth roots and study rational exponents. VOCABULARY. Index of a radical . Georgia Performance Standard(s) MMA2a, MMA2b, MMAd Your Notes Evaluate nth Roots and Use Rational Eponents Goal VOCABULARY nth root of a p Evaluate nth roots and stud rational eponents. Inde of a radical

More information

Essential Question How can you use a rational exponent to represent a power involving a radical?

Essential Question How can you use a rational exponent to represent a power involving a radical? 5.1 nth Roots and Rational Exponents Essential Question How can you use a rational exponent to represent a power involving a radical? Previously, you learned that the nth root of a can be represented as

More information

Chapter 8 Notes SN AA U2C8

Chapter 8 Notes SN AA U2C8 Chapter 8 Notes SN AA U2C8 Name Period Section 8-: Eploring Eponential Models Section 8-2: Properties of Eponential Functions In Chapter 7, we used properties of eponents to determine roots and some of

More information

Chapter 1 ( )? Chapter 1 Opener. Section 1.1. Worked-Out Solutions. 2π π = π. Try It Yourself (p. 1) So, x = 95.3.

Chapter 1 ( )? Chapter 1 Opener. Section 1.1. Worked-Out Solutions. 2π π = π. Try It Yourself (p. 1) So, x = 95.3. Chapter Chapter Opener Try It Yourself (p. ). + ( ) 7.. + 8. ( ) +. 7. ( 7) + 7 7. 8 () 0 + 8. 7. ( 7) 8 0.. 8. Section.. Activity (pp. ). Triangle Angle A (degrees) Angle B (degrees). a. The sum of the

More information

Algebra 1 S1 Lesson Summaries. Lesson Goal: Mastery 70% or higher

Algebra 1 S1 Lesson Summaries. Lesson Goal: Mastery 70% or higher Algebra 1 S1 Lesson Summaries For every lesson, you need to: Read through the LESSON REVIEW which is located below or on the last page of the lesson and 3-hole punch into your MATH BINDER. Read and work

More information

Intermediate Algebra Math 097. Evaluates/Practice Tests. For solutions, refer to the back of the PAN.

Intermediate Algebra Math 097. Evaluates/Practice Tests. For solutions, refer to the back of the PAN. Intermediate Algebra Math 097 Evaluates/Practice Tests For solutions, refer to the back of the PAN. Page of 8 Take this practice test to be sure that ou are prepared for the final quiz in Evaluate.. Solve

More information

Maintaining Mathematical Proficiency

Maintaining Mathematical Proficiency Name Date Chapter Maintaining Mathematical Proficienc Use the graph to answer the question. A H B F G E C D x 1. What ordered pair corresponds to point A?. What ordered pair corresponds to point H? 3.

More information

7-1. Exploring Exponential Models. Vocabulary. Review. Vocabulary Builder. Use Your Vocabulary. 1. Cross out the expressions that are NOT powers.

7-1. Exploring Exponential Models. Vocabulary. Review. Vocabulary Builder. Use Your Vocabulary. 1. Cross out the expressions that are NOT powers. 7-1 Eploring Eponential Models Vocabular Review 1. Cross out the epressions that are NOT powers. 16 6a 1 7. Circle the eponents in the epressions below. 5 6 5a z Vocabular Builder eponential deca (noun)

More information

Chapter 4. Chapter 4 Opener. Section 4.1. Big Ideas Math Blue Worked-Out Solutions. x 2. Try It Yourself (p. 147) x 0 1. y ( ) x 2

Chapter 4. Chapter 4 Opener. Section 4.1. Big Ideas Math Blue Worked-Out Solutions. x 2. Try It Yourself (p. 147) x 0 1. y ( ) x 2 Chapter Chapter Opener Tr It Yourself (p. 7). As the input decreases b, the output increases b.. Input As the input increases b, the output increases b.. As the input decreases b, the output decreases

More information

Learn how to use the multiplication properties of exponents to evaluate powers and simplify expressions

Learn how to use the multiplication properties of exponents to evaluate powers and simplify expressions 8.1 Multiplication Properties of Exponents Objectives: Learn how to use the multiplication properties of exponents to evaluate powers and simplif expressions Learn how to use powers and the exponential

More information

Exponential and Logarithmic Functions

Exponential and Logarithmic Functions Eponential and Logarithmic Functions.1 Eponential Growth and Deca Functions. The Natural Base e.3 Logarithms and Logarithmic Functions. Transformations of Eponential and Logarithmic Functions.5 Properties

More information

Index. Index. Index A53

Index. Index. Index A53 A Addition of integers, 1 linear equations, 4 linear inequalities, 54 of polynomials, 337, 340 341, 396 Property of Equality, 4 of Inequality, 54 of radicals and square roots, 465, 470 in units of measure,

More information

4. exponential decay; 20% 9.1 Practice A found square root instead of cube root 16 =

4. exponential decay; 20% 9.1 Practice A found square root instead of cube root 16 = 9.. eponential deca; 0% 9. Practice A.. 7. 7.. 6. 9. 0 7.. 9. 0. found square root instead of cube root 6 = = = 9. = 7, 9. =,.. 7n 7n. 96. =, 97. =, 9. linear function: = + 0 99. quadratic function: =

More information

ACTIVITY: Comparing Types of Decay

ACTIVITY: Comparing Types of Decay 6.6 Eponential Deca eponential deca? What are the characteristics of 1 ACTIVITY: Comparing Tpes of Deca Work with a partner. Describe the pattern of deca for each sequence and graph. Which of the patterns

More information

Glossary. Also available at BigIdeasMath.com: multi-language glossary vocabulary flash cards

Glossary. Also available at BigIdeasMath.com: multi-language glossary vocabulary flash cards Glossar This student friendl glossar is designed to be a reference for ke vocabular, properties, and mathematical terms. Several of the entries include a short eample to aid our understanding of important

More information

Algebra II Vocabulary Word Wall Cards

Algebra II Vocabulary Word Wall Cards Algebra II Vocabulary Word Wall Cards Mathematics vocabulary word wall cards provide a display of mathematics content words and associated visual cues to assist in vocabulary development. The cards should

More information

ALGEBRA 1 FINAL EXAM TOPICS

ALGEBRA 1 FINAL EXAM TOPICS ALGEBRA 1 FINAL EXAM TOPICS Chapter 2 2-1 Writing Equations 2-2 Solving One Step Equations 2-3 Solving Multi-Step Equations 2-4 Solving Equations with the Variable on Each Side 2-5 Solving Equations Involving

More information

NOTES: EXPONENT RULES

NOTES: EXPONENT RULES NOTES: EXPONENT RULES DAY 2 Topic Definition/Rule Example(s) Multiplication (add exponents) x a x b = x a+b x 4 x 8 x 5 y 2 x 2 y Power to a Power (multiply exponents) x a ( ) b = x ab ( x ) 7 ( x ) 2

More information

Reteaching Using Deductive and Inductive Reasoning

Reteaching Using Deductive and Inductive Reasoning Name Date Class Reteaching Using Deductive and Inductive Reasoning INV There are two types of basic reasoning in mathematics: deductive reasoning and inductive reasoning. Deductive reasoning bases a conclusion

More information

Maintaining Mathematical Proficiency

Maintaining Mathematical Proficiency Chapter Maintaining Mathematical Proficienc Find the -intercept of the graph of the linear equation. 1. = + 3. = 3 + 5 3. = 10 75. = ( 9) 5. 7( 10) = +. 5 + 15 = 0 Find the distance between the two points.

More information

Reteaching (continued)

Reteaching (continued) Zero and Negative Eponents Eercises Write each epression as an integer, a simple fraction, or an epression that contains onl positive eponents. Simplif...3 0. 0-0,000 3. a -5. 3.7 0 a 5 5. 9-6. 3-3 9 p

More information

Chapter 11 Exponential and Logarithmic Function

Chapter 11 Exponential and Logarithmic Function Chapter Eponential and Logarithmic Function - Page 69.. Real Eponents. a m a n a mn. (a m ) n a mn. a b m a b m m, when b 0 Graphing Calculator Eploration Page 700 Check for Understanding. The quantities

More information

What Did You Learn? Key Terms. Key Concepts. 158 Chapter 1 Functions and Their Graphs

What Did You Learn? Key Terms. Key Concepts. 158 Chapter 1 Functions and Their Graphs 333371_010R.qxp 12/27/0 10:37 AM Page 158 158 Chapter 1 Functions and Their Graphs Ke Terms What Did You Learn? equation, p. 77 solution point, p. 77 intercepts, p. 78 slope, p. 88 point-slope form, p.

More information

CHAPTER 1 Functions and Their Graphs

CHAPTER 1 Functions and Their Graphs PART I CHAPTER Functions and Their Graphs Section. Lines in the Plane....................... Section. Functions........................... Section. Graphs of Functions..................... Section. Shifting,

More information

Accessible Topic - Topics accessible to visually impaired students using a screen reader.

Accessible Topic - Topics accessible to visually impaired students using a screen reader. Course Name: Winter 2018 Math 95 - Course Code: ALEKS Course: Developmental Math Instructor: Course Dates: Begin: 01/07/2018 End: 03/23/2018 Course Content: 390 Topics (172 goal + 218 prerequisite) / 334

More information

8.1 Apply Exponent Properties Involving Products. Learning Outcome To use properties of exponents involving products

8.1 Apply Exponent Properties Involving Products. Learning Outcome To use properties of exponents involving products 8.1 Apply Exponent Properties Involving Products Learning Outcome To use properties of exponents involving products Product of Powers Property Let a be a real number, and let m and n be positive integers.

More information

Use Properties of Exponents

Use Properties of Exponents 4. Georgia Performance Standard(s) MMAa Your Notes Use Properties of Eponents Goal p Simplif epressions involving powers. VOCABULARY Scientific notation PROPERTIES OF EXPONENTS Let a and b be real numbers

More information

c. Find the slope and y-intercept of the graph of the linear equation. Then sketch its graph.

c. Find the slope and y-intercept of the graph of the linear equation. Then sketch its graph. Name Solve. End-of-Course. 7 =. 5 c =. One cell phone plan charges $0 per month plus $0.5 per minute used. A second cell phone plan charges $5 per month plus $0.0 per minute used. Write and solve an equation

More information

Coached Instruction Supplement

Coached Instruction Supplement Practice Coach PLUS Coached Instruction Supplement Mathematics 8 Practice Coach PLUS, Coached Instruction Supplement, Mathematics, Grade 8 679NASP Triumph Learning Triumph Learning, LLC. All rights reserved.

More information

STANDARD FORM is a QUADRATIC FUNCTION and its graph is a PARABOLA. The domain of a quadratic function is the set of all real numbers.

STANDARD FORM is a QUADRATIC FUNCTION and its graph is a PARABOLA. The domain of a quadratic function is the set of all real numbers. EXERCISE 2-3 Things to remember: 1. QUADRATIC FUNCTION If a, b, and c are real numbers with a 0, then the function f() = a 2 + b + c STANDARD FORM is a QUADRATIC FUNCTION and its graph is a PARABOLA. The

More information

Essential Question How can you factor a polynomial completely?

Essential Question How can you factor a polynomial completely? REASONING ABSTRACTLY 7.8 To be proficient in math, ou need to know and flexibl use different properties of operations and objects. Factoring Polnomials Completel Essential Question How can ou factor a

More information

CHAPTER SEVEN. Volume = 1 5 πr3 = 1 5 π 23 = 8 5 π cm3. Volume = 1 5 πr3 = 1 5 π 43 = 64 5 π cm3. Depth = 4.9t 2 = = 78.4 meters.

CHAPTER SEVEN. Volume = 1 5 πr3 = 1 5 π 23 = 8 5 π cm3. Volume = 1 5 πr3 = 1 5 π 43 = 64 5 π cm3. Depth = 4.9t 2 = = 78.4 meters. CHAPTER SEVEN 7. SOLUTIONS 25 Solutions for Section 7. EXERCISES. Since A = x 2, the exponent is 2 and the constant of proportionality is. 2. Since P = 4x, the exponent is and the constant of proportionality

More information

An equation is a statement that states that two expressions are equal. For example:

An equation is a statement that states that two expressions are equal. For example: Section 0.1: Linear Equations Solving linear equation in one variable: An equation is a statement that states that two expressions are equal. For example: (1) 513 (2) 16 (3) 4252 (4) 64153 To solve the

More information

Chapter 7 - Exponents and Exponential Functions

Chapter 7 - Exponents and Exponential Functions Chapter 7 - Exponents and Exponential Functions 7-1: Multiplication Properties of Exponents 7-2: Division Properties of Exponents 7-3: Rational Exponents 7-4: Scientific Notation 7-5: Exponential Functions

More information

Practice A ( 1, 3 ( 0, 1. Match the function with its graph. 3 x. Explain how the graph of g can be obtained from the graph of f. 5 x.

Practice A ( 1, 3 ( 0, 1. Match the function with its graph. 3 x. Explain how the graph of g can be obtained from the graph of f. 5 x. 8. Practice A For use with pages 65 7 Match the function with its graph.. f. f.. f 5. f 6. f f Lesson 8. A. B. C. (, 6) (0, ) (, ) (0, ) ( 0, ) (, ) D. E. F. (0, ) (, 6) ( 0, ) (, ) (, ) (0, ) Eplain how

More information

Summer Math Packet (revised 2017)

Summer Math Packet (revised 2017) Summer Math Packet (revised 07) In preparation for Honors Math III, we have prepared a packet of concepts that students should know how to do as these concepts have been taught in previous math classes.

More information

Review questions for Math 111 final. Please SHOW your WORK to receive full credit Final Test is based on 150 points

Review questions for Math 111 final. Please SHOW your WORK to receive full credit Final Test is based on 150 points Please SHOW your WORK to receive full credit Final Test is based on 150 points 1. True or False questions (17 pts) a. Common Logarithmic functions cross the y axis at (0,1) b. A square matrix has as many

More information

Algebra 2. Curriculum (524 topics additional topics)

Algebra 2. Curriculum (524 topics additional topics) Algebra 2 This course covers the topics shown below. Students navigate learning paths based on their level of readiness. Institutional users may customize the scope and sequence to meet curricular needs.

More information

Section 10.1 Radical Expressions and Functions. f1-152 = = = 236 = 6. 2x 2-14x + 49 = 21x = ƒ x - 7 ƒ

Section 10.1 Radical Expressions and Functions. f1-152 = = = 236 = 6. 2x 2-14x + 49 = 21x = ƒ x - 7 ƒ 78 CHAPTER 0 Radicals, Radical Functions, and Rational Exponents Chapter 0 Summary Section 0. Radical Expressions and Functions If b a, then b is a square root of a. The principal square root of a, designated

More information

Algebra II. Slide 1 / 261. Slide 2 / 261. Slide 3 / 261. Linear, Exponential and Logarithmic Functions. Table of Contents

Algebra II. Slide 1 / 261. Slide 2 / 261. Slide 3 / 261. Linear, Exponential and Logarithmic Functions. Table of Contents Slide 1 / 261 Algebra II Slide 2 / 261 Linear, Exponential and 2015-04-21 www.njctl.org Table of Contents click on the topic to go to that section Slide 3 / 261 Linear Functions Exponential Functions Properties

More information

algebraic expression angle exponent equation Vocabulary Flash Cards Review Review Review Review Review Review Big Ideas Math Red

algebraic expression angle exponent equation Vocabulary Flash Cards Review Review Review Review Review Review Big Ideas Math Red algebraic expression angle base (of a power) coordinate plane equation exponent expression factor A figure formed by two rays with the same endpoint An expression that contains numbers, operations, and

More information

Reading Mathematical Expressions & Arithmetic Operations Expression Reads Note

Reading Mathematical Expressions & Arithmetic Operations Expression Reads Note Math 001 - Term 171 Reading Mathematical Expressions & Arithmetic Operations Expression Reads Note x A x belongs to A,x is in A Between an element and a set. A B A is a subset of B Between two sets. φ

More information

Florida Math Curriculum (433 topics)

Florida Math Curriculum (433 topics) Florida Math 0028 This course covers the topics shown below. Students navigate learning paths based on their level of readiness. Institutional users may customize the scope and sequence to meet curricular

More information

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. B) x y =

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. B) x y = Santa Monica College Practicing College Algebra MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Write the standard equation for the circle. 1) Center

More information

3.4 The Fundamental Theorem of Algebra

3.4 The Fundamental Theorem of Algebra 333371_0304.qxp 12/27/06 1:28 PM Page 291 3.4 The Fundamental Theorem of Algebra Section 3.4 The Fundamental Theorem of Algebra 291 The Fundamental Theorem of Algebra You know that an nth-degree polynomial

More information

( 3x. Chapter Review. Review Key Vocabulary. Review Examples and Exercises 6.1 Properties of Square Roots (pp )

( 3x. Chapter Review. Review Key Vocabulary. Review Examples and Exercises 6.1 Properties of Square Roots (pp ) 6 Chapter Review Review Ke Vocabular closed, p. 266 nth root, p. 278 eponential function, p. 286 eponential growth, p. 296 eponential growth function, p. 296 compound interest, p. 297 Vocabular Help eponential

More information

Summary, Review, and Test

Summary, Review, and Test 45 Chapter Equations and Inequalities Chapter Summar Summar, Review, and Test DEFINITIONS AND CONCEPTS EXAMPLES. Eponential Functions a. The eponential function with base b is defined b f = b, where b

More information

Properties of Rational Exponents PROPERTIES OF RATIONAL EXPONENTS AND RADICALS. =, a 0 25 º1/ =, b /3 2. b m

Properties of Rational Exponents PROPERTIES OF RATIONAL EXPONENTS AND RADICALS. =, a 0 25 º1/ =, b /3 2. b m Page of 8. Properties of Rational Eponents What ou should learn GOAL Use properties of rational eponents to evaluate and simplif epressions. GOAL Use properties of rational eponents to solve real-life

More information

addend angle composite number capacity Vocabulary Flash Cards Review Review Review Review Review Review

addend angle composite number capacity Vocabulary Flash Cards Review Review Review Review Review Review addend angle area bar graph capacity composite number cubic units difference A figure formed by two rays with the same endpoint A number to be added to another number. 2 or 3 in the sum 2 + 3. A graph

More information

CHAPTER FIVE. Solutions for Section 5.1. Skill Refresher. Exercises

CHAPTER FIVE. Solutions for Section 5.1. Skill Refresher. Exercises CHAPTER FIVE 5.1 SOLUTIONS 265 Solutions for Section 5.1 Skill Refresher S1. Since 1,000,000 = 10 6, we have x = 6. S2. Since 0.01 = 10 2, we have t = 2. S3. Since e 3 = ( e 3) 1/2 = e 3/2, we have z =

More information

Chapter 4 Exponents and Radicals 4.1 Square Roots and Cube Roots 1. a) 81 b) 225 c) 625 d) 4 9

Chapter 4 Exponents and Radicals 4.1 Square Roots and Cube Roots 1. a) 81 b) 225 c) 625 d) 4 9 Chapter Exponents and Radicals.1 Square Roots and Cube Roots 1. a) 1 5 c) 5 d) 9 e) 5 f ) ( 9 ). a) 79 7 c) 1 d) e) 1 f ) 15. a) 5 1 c) d) e) f ) 7 g) 1 h) x i) 7a 1b. a) c) 1 d) 0 e) f ) 5 g) 7 h) 5y

More information

be an nth root of a, and let m be a positive integer. ( ) ( )

be an nth root of a, and let m be a positive integer. ( ) ( ) Chapter 7: Power, Roots, and Radicals Chapter 7.1: Nth Roots and Rational Exponents Evaluating nth Roots: Relating Indices and Powers Real nth Roots: Let be an integer greater than 1 and let be a real

More information

CHAPTER 3 Exponential and Logarithmic Functions

CHAPTER 3 Exponential and Logarithmic Functions CHAPTER Eponential and Logarithmic Functions Section. Eponential Functions and Their Graphs......... Section. Logarithmic Functions and Their Graphs......... Section. Properties of Logarithms..................

More information

Practice 6-1: Exponential Equations

Practice 6-1: Exponential Equations Name Class Date Practice 6-1: Exponential Equations Which of the following are exponential functions? For those that are exponential functions, state the initial value and the base. For those that are

More information

Function: State whether the following examples are functions. Then state the domain and range. Use interval notation.

Function: State whether the following examples are functions. Then state the domain and range. Use interval notation. Name Period Date MIDTERM REVIEW Algebra 31 1. What is the definition of a function? Functions 2. How can you determine whether a GRAPH is a function? State whether the following examples are functions.

More information

Functions. Essential Question What are some of the characteristics of the graph of an exponential function? ) x e. f (x) = ( 1 3 ) x f.

Functions. Essential Question What are some of the characteristics of the graph of an exponential function? ) x e. f (x) = ( 1 3 ) x f. 7. TEXAS ESSENTIAL KNOWLEDGE AND SKILLS A..A Eponential Growth and Deca Functions Essential Question What are some of the characteristics of the graph of an eponential function? You can use a graphing

More information

Solving Quadratic Equations

Solving Quadratic Equations 9 Solving Quadratic Equations 9. Properties of Radicals 9. Solving Quadratic Equations b Graphing 9. Solving Quadratic Equations Using Square Roots 9. Solving Quadratic Equations b Completing the Square

More information

Using Properties of Exponents

Using Properties of Exponents 6.1 Using Properties of Exponents Goals p Use properties of exponents to evaluate and simplify expressions involving powers. p Use exponents and scientific notation to solve real-life problems. VOCABULARY

More information

Solutions to MAT 117 Test #3

Solutions to MAT 117 Test #3 Solutions to MAT 7 Test #3 Because there are two versions of the test, solutions will only be given for Form C. Differences from the Form D version will be given. (The values for Form C appear above those

More information

The Quadratic Formula. ax 2 bx c 0 where a 0. Deriving the Quadratic Formula. Isolate the constant on the right side of the equation.

The Quadratic Formula. ax 2 bx c 0 where a 0. Deriving the Quadratic Formula. Isolate the constant on the right side of the equation. SECTION 11.2 11.2 The Quadratic Formula 11.2 OBJECTIVES 1. Solve quadratic equations by using the quadratic formula 2. Determine the nature of the solutions of a quadratic equation by using the discriminant

More information

Divide and simplify. Assume that all variables are positive. Rationalize the denominator of the expression if necessary. pg.

Divide and simplify. Assume that all variables are positive. Rationalize the denominator of the expression if necessary. pg. Spring 011 Final Exam Review Show all work and answers on SEPARATE PAPER The review for the final must be completed b the date of the original final exam in order to be eligible for a reassessment in the

More information

Diagnostic Tests Study Guide

Diagnostic Tests Study Guide California State Universit, Sacramento Department of Mathematics and Statistics Diagnostic Tests Stud Guide Descriptions Stud Guides Sample Tests & Answers Table of Contents: Introduction Elementar Algebra

More information

Cover Image Credits: Death Valley Felix Stensson/Alamy. Copyright by Houghton Mifflin Harcourt Publishing Company

Cover Image Credits: Death Valley Felix Stensson/Alamy. Copyright by Houghton Mifflin Harcourt Publishing Company Solutions Ke Cover Image Credits: Death Valle Feli Stensson/Alam Copright b Houghton Mifflin Harcourt Publishing Compan No part of this work ma be reproduced or transmitted in an form or b an means, electronic

More information

7.4 Adding, Subtracting, and Multiplying Radical Expressions. OBJECTIVES 1 Add or Subtract Radical Expressions. 2 Multiply Radical Expressions.

7.4 Adding, Subtracting, and Multiplying Radical Expressions. OBJECTIVES 1 Add or Subtract Radical Expressions. 2 Multiply Radical Expressions. CHAPTER 7 Rational Exponents, Radicals, and Complex Numbers Find and correct the error. See the Concept Check in this section. 11. 116. 6 6 = 6 A6 = 1 = 1 16 = 16 A = Simplify. See a Concept Check in this

More information

Maintaining Mathematical Proficiency

Maintaining Mathematical Proficiency Name Date Chapter 5 Maintaining Mathematical Proficienc Graph the equation. 1. + =. = 3 3. 5 + = 10. 3 = 5. 3 = 6. 3 + = 1 Solve the inequalit. Graph the solution. 7. a 3 > 8. c 9. d 5 < 3 10. 8 3r 5 r

More information

Algebra 1 (cp) Midterm Review Name: Date: Period:

Algebra 1 (cp) Midterm Review Name: Date: Period: Algebra 1 (cp) Midterm Review Name: Date: Period: Chapter 1 1. Evaluate the variable expression when j 4. j 44 [1] 2. Evaluate the variable expression when j 4. 24 j [2] 3. Find the perimeter of the rectangle.

More information

review for math TSI 182 practice aafm m

review for math TSI 182 practice aafm m Eam TSI 182 Name review for math TSI 182 practice 01704041700aafm042430m www.alvarezmathhelp.com MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Simplif.

More information

Algebra I Vocabulary Cards

Algebra I Vocabulary Cards Algebra I Vocabulary Cards Table of Contents Expressions and Operations Natural Numbers Whole Numbers Integers Rational Numbers Irrational Numbers Real Numbers Order of Operations Expression Variable Coefficient

More information

Math Literacy. Curriculum (457 topics)

Math Literacy. Curriculum (457 topics) Math Literacy This course covers the topics shown below. Students navigate learning paths based on their level of readiness. Institutional users may customize the scope and sequence to meet curricular

More information

Name Advanced Math Functions & Statistics. Non- Graphing Calculator Section A. B. C.

Name Advanced Math Functions & Statistics. Non- Graphing Calculator Section A. B. C. 1. Compare and contrast the following graphs. Non- Graphing Calculator Section A. B. C. 2. For R, S, and T as defined below, which of the following products is undefined? A. RT B. TR C. TS D. ST E. RS

More information

6 p p } 5. x 26 x 5 x 3 5 x Product of powers property x4 y x 3 y 2 6

6 p p } 5. x 26 x 5 x 3 5 x Product of powers property x4 y x 3 y 2 6 Chapter Polnomials and Polnomial Functions Copright Houghton Mifflin Harcourt Publishing Compan. All rights reserved. Prerequisite Skills for the chapter Polnomials and Polnomial Functions. and. 4. a b

More information

Simplifying Radical Expressions

Simplifying Radical Expressions Simplifying Radical Expressions Product Property of Radicals For any real numbers a and b, and any integer n, n>1, 1. If n is even, then When a and b are both nonnegative. n ab n a n b 2. If n is odd,

More information

Answer Explanations SAT Practice Test #1

Answer Explanations SAT Practice Test #1 Answer Explanations SAT Practice Test #1 2015 The College Board. College Board, SAT, and the acorn logo are registered trademarks of the College Board. 5KSA09 Section 4: Math Test Calculator QUESTION 1.

More information

8th Grade Math Definitions

8th Grade Math Definitions 8th Grade Math Definitions Absolute Value: 1. A number s distance from zero. 2. For any x, is defined as follows: x = x, if x < 0; x, if x 0. Acute Angle: An angle whose measure is greater than 0 and less

More information