Prepared by: B.ELANGOVAN. M.Sc., M.Ed., M.Phil.,

Transcription

1 Book back One Mark questions And answers Prepared by: B.ELANGOVAN. M.Sc., M.Ed., M.Phil., (Tamil Nadu Dr. Radhakrishnan Best Teacher Award recipient) Post Graduate Teacher in Physics ( Date of Appointment : ), Pachaiyappa s Hr.Sec.School, Kanchipuram Phone: ********** B.E., PHSS, KPM. Page 1

2 +2 Physics - One mark questions Minimum Learning Material ( Units: 1, 4, 5, 6 and 8 ) B.E., PHSS, KPM. Page 2

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18 +2 Physics Unit:2. CURRENT ELECTRICITY Minimum Learning Material- Three Marks 1. Define Drift Velocity.Give its unit. ( M 07,O 08,J 09,O 09, M 10,O 10,M 11,O 11, J 13,J - 15 ) It is the velocity with which free electrons get drifted towards the positive terminal, when an electric field is applied. Its unit is m/s 2. Define Mobility and give its unit. ( O 06, M 08, M 09, O 15, M 16 ) It is the drift velocity acquired per unit electric field. It takes the unit m 2 V -1 s State Ohm s Law. ( M 06, O 07, O 09, M 10,J 12, O 12, M 13, O 14, J - 16 ) At a constant temperature, the steady current flowing through a conductor is directly proportional to the potential difference between the two ends of the conductor. (i.e) V = IR 4. State the three applications of superconductors? ( J 07,O 07, J 06,O 06, O 07, J 13, M - 15 ) 1. Superconductors form the basis of energy saving power system, namely the superconducting generators, which are smaller in size and weight. 2. Superconducting magnets have been used to levitate train above its rails. They can be driven at high speed with minimal expenditure of energy. 3. Superconducting magnetic propulsion systems may be used to launch satellites into orbits directly from the earth without the use of rockets. 5. State Kirchoff s first law (Current law). ( J 06, M 08, J 11, O 15 ) The algebraic sum of the currents meeting at any junction in a circuit is zero. This law is a consequence of conservation of charges. 6. State Kirchoff s second law (voltage law).( M 07, J 06, M 08, M 09, J 11, M 12,M 14,M 15 ) The algebraic sum of the products of resistance and current in each part of any closed circuit is equal to the algebraic sum of the emf s in that closed circuit. This law is a consequence of conservation of energy. B.E., PHSS, KPM. Page 1

19 Unit-2 Three marks MLM 7. Compare the emf and the potential difference. ( J 07, O 08, J 11, J 12, M 13, M - 15 ) Comparison of emf and potential difference 1. The difference of potentials between the two terminals of a cell in an open circuit is called the electromotive force (emf) of a cell. The difference in potentials between any two points in a closed circuit is called potential difference. 2. The emf is independent of external resistance of the circuit, whereas potential difference is proportional to the resistance between any two points. 8. State Faraday s laws of electrolysis. ( M 06, J 06, J 10,O -10, J 13, J 15 ) First Law : The mass of a substance liberated at an electrode is directly proportional to the charge passing through the electrolyte. Second Law : The mass of a substance liberated at an electrode by a given amount of charge is proportional to the chemical equivalent of the substance. 9. The resistance of a nichrome wire at 0 o C is 10 Ω. If the temperature coefficient of resistance is / o C, find its resistance at boiling point of water. Comment on the result. ( J 07, O 07, M 08, J 09, O-10, O -11, O 12, O 13, J - 15 ) Resistance at boiling point of water Rt = Ro (1+ α t) = 10 (1 + ( )) Rt = 14 Ω. Result : The resistance increases with the temperature. 10. Define: the temperature coefficient of resistance. ( J 08, M 11, J 14, M 16 ) The ratio of increase in resistance per degree rise in temperature to its resistance at 0 o C is called as temperature coefficient of resistance. Its unit is per o C. 11. Give any three uses of secondary cells. ( O 08, O 11, M 12 ) i) The secondary cells are rechargeable. ii) They have very low internal resistance. iii) They can deliver a high current if required. iv) They are used in all automobiles like cars, two wheelers, trucks etc. B.E., PHSS, KPM. Page 2

20 Unit-2 Three marks MLM 12. Distinguish between electric power and electric energy. ( J 08, J 09, O 13, J 14, O 14 ) Electric power i) Electric power is defined as the rate of doing electric work. ii) Electric power is the product of potential difference and current strength. iii) Unit: watt Electric energy 1) Electric energy is defined as the capacity to do work. 2) Its unit is joule. 13. A manganin wire of length 2m has a diameter of 0.4 mm with a resistance of 70 ohm. Find its resistivity. ( J 06, M 13 ) ρ = ( P X π r 2 ) / L = ( 70 X 22 X 2 X 10-4 X 2 X 10-4 ) / 7 X 2 = 44 X 10-7 = 4.4 X 10-6 Ωm = 4.4 μ Ωm. 14. In the given circuit, calculate the current through the circuit and mention its direction. ( M 06, O 14) Let the current be I. 7 I + 3 I + 5I + 5 I = (i.e) 20 I = 16 I = 0.8 A Current flows along the path ABCD. 15. What are the changes that occur at the superconducting transition temperature? At the transition temperature the following changes are observed : (i) The electrical resistivity drops to zero. (ii) The conductivity becomes infinity (iii) The magnetic flux lines are excluded from the material. ( J 10, M 14 ) ***** BEST WISHES ***** B.E., PHSS, KPM. Page 3

21 +2 Physics Unit: 9 Semiconductor devices and their applications Minimum Learning Material- Three Marks 1. State the advantages of IC over the discrete components. ( M 06, O 06, J 10, J -11, M 14, M 16 ) (i) Extremely small in size. (ii) Low power consumption (iii) Reliability (iv) Reduced cost (v) Very small weight (vi) Easy replacement 2. Define input impedance. ( J 06, J 11 ) The input impedance of the transistor is defined as the ratio of small change in baseemitter voltage to the corresponding change in base current at a given V CE. Input impedance, r i = (ΔV BE / Δ I B ) VCE The unit of input impedance is ohm. 3. Define output impedance. ( O 08, O 09 ) The output impedance r o is defined as the ratio of variation in the collector emitter voltage to the corresponding variation in the collector current at a constant base current. Output impedance, r 0 = (ΔV CE / Δ I C ) IB The unit of output impedance is ohm. 4. When the negative feedback is applied to an amplifier of gain 50, the gain falls to 25. Calculate the feedback ratio. ( J 06, O 09, M 10, O 10, J 14, M 16 ) Af = A / 1 + Aβ 25 = 50 / β 1 = 2 / β β = 2 (i.e) 50 β= 1 Β = 1 /50 = What is an extrinsic semiconductor? ( J 06, J 08, O 10, M 11, J 13, J 14 ) An extrinsic semiconductor is one in which an impurity with a valency higher or lower than the valency of the pure semiconductor is added, so as to increase the electrical conductivity of the semiconductor. B.E., PHSS, KPM. Page 4

22 Unit - 9 Three marks MLM 6. Define rectification and rectifier. ( M 07, M 09, O 14 ) The process in which alternating voltage or alternating current is converted into direct voltage or direct current is known as rectification. The device used for this process is called as rectifier. 7. Define Zener breakdown. ( O 06, J 07, M 08, M 12, J 12, J 13, J 16 ) Zener diode is a reverse biased, heavily doped semiconductor (silicon or germanium) PN junction diode, which is operated exclusively in the breakdown region. As the reverse voltage applied to the PN junction is increased, at a particular voltage, the current increases enormously from its normal cut off value. This voltage is called Zener voltage or breakdown voltage (v z ). 8. What are the advantages of negative feedback? ( J 07, J 08, O 07, M -11,M -12, M 13 ) i) Highly stabilized gain ii) Reduction in the noise level iii) Increased bandwidth. iv) Increased input impedance and decreased output impedance v) Less distortion 9. State Demorgans theorems. ( M 08, M 09, J -10, M 12, M 13, M 15 ) FIRST THEOREM: The complement of the sum is equal to the product of the complements. SECOND THEOREM: The complement of the product is equal to the sum of the complements. 10. What is an integrated circuit? ( J 08, J 09, O 12, O 14 ) An integrated circuit consists of single-crystal chip of silicon containing both active and passive elements and inters connections. B.E., PHSS, KPM. Page 5

23 Unit - 9 Three marks MLM 11. Give the Barkhausen criteria for oscillations. ( O 07, O 08, J 09, M 10, O 15, J 16 ) The essential conditions for the maintenance of oscillation: (i) The loop gain Aβ =1 and (ii) the net phase shift round the loop is 0 or integral multiples of 2π. 12. The voltage gain of an amplifier without feedback is 100. If negative feedback is applied with feedback fraction 0.1, calculate the voltage gain with feedback. ( O 06, O - 11 ) A F = A / 1 + A β = 100 / X 1/10 = 100 / 11 = Find the output of the following logic circuit. ( O 08, M -09 ) 14. Give the circuit diagram of NOT gate using a transistor. ( J 10, O 11, O 13, J 15 ) B.E., PHSS, KPM. Page 6

24 Unit - 9 Three marks MLM 15. What are universal gates? Why are they called so? ( J 12, J 13, M 16 ) NAND and NOR gates are called universal gates because they can perform all the three basic logic functions i.e. the functions of OR, AND and NOT gates. 16. Draw the circuit for summing amplifier. ( M 09, M 13, J 13 ) 17. Collector current I c =25mA and base current I b = 50µA. Find current gain β of a transistor. ( J 10, O 12, M 13 ) β = I C / I B = 25X 10-3 / 50 X 10-6 = 500 α = β / ( 1 + β ) = 500/501 = y Best wishes y B.E., PHSS, KPM. Page 7

25 +2 Physics Minimum Learning Material Unit - 2 Current Electricity Five marks Questions and Answers B.E., PHSS, KPM. Page 1

26 +2 Physics Minimum Learning Material Unit - 2 Current Electricity Page - 2 B.E., PHSS, KPM. Page 2

27 Unit - 2 Current Electricity MLM -- Five marks Questions and Answers B.E., PHSS, KPM. Page 3

28 +2 Physics Minimum Learning Material Five Marks Unit - 7 Dual Nature of Radiation and Matter and Relativity B.E., PHSS, KPM. Page 4

29 +2 Physics * Unit - 7 Minimum Learning Material * Five Marks * Page- 2 B.E., PHSS, KPM. Page 5

30 +2 Physics * Unit - 7 Minimum Learning Material * Five Marks * Page- 3 y Best wishes y B.E., PHSS, KPM. Page 6

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32 +2 Physics Unit: 1 Electrostatics Ten Marks Minimum Learning Material Page : 1 B.E., PHSS, KPM Page 2

33 +2 Physics Unit: 1 Electrostatics Ten Marks Minimum Learning Material Page : 2 B.E., PHSS, KPM Page 3

34 +2 Physics Unit: 1 Electrostatics Ten Marks Minimum Learning Material Page : 3 B.E., PHSS, KPM Page 4

35 +2 Physics Unit: 1 Electrostatics Ten Marks Minimum Learning Material Page : 4 B.E., PHSS, KPM Page 5

36 Unit: 4 Electromagnetic Induction and Alternating current Ten Marks Minimum Learning Material B.E., PHSS, KPM Page 6

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