Unsupervised dimensionality reduction

Transcription

1 Unsupervised dimensionality reduction Guillaume Obozinski Ecole des Ponts - ParisTech SOCN course 2014 Guillaume Obozinski Unsupervised dimensionality reduction 1/30

2 Outline 1 PCA 2 Kernel PCA 3 Multidimensional scaling 4 Laplacian Eigenmaps 5 Locally Linear Embedding Guillaume Obozinski Unsupervised dimensionality reduction 2/30

3 PCA Guillaume Obozinski Unsupervised dimensionality reduction 4/30

4 A direction that maximizes the variance Data are points in R d. Looking for a direction v in R d such that the variance of the signals projected on v is maximized: Var((v x i )...n ) = 1 n = 1 n (v x i ) 2 v x i x i v = v ( 1 n = v Σ v x i x i ) v Need to solve max v 2 =1 v Σ v Solution: eigenvector associated to the largest eigenvalue of Σ Guillaume Obozinski Unsupervised dimensionality reduction 5/30

5 Principal directions Assume the design matrix is centered, i.e. X 1 = 0. Principal directions as eigenvectors of the covariance Consider the eigenvalue decomposition of Σ = X X: Σ = VS 2 V with S = Diag(s 1,..., s n ) and s 1... s n. The principal directions are the columns of V Principal directions as singular vectors of the design matrix Consider the singular value decomposition of X X = USV The principal directions are the right singular vectors. Guillaume Obozinski Unsupervised dimensionality reduction 6/30

6 Principal components Obtained by projection of the rows of X on V. But XV = USV V = US. So the principal components are obtained with the left singular vectors and the singular values. Guillaume Obozinski Unsupervised dimensionality reduction 7/30

7 Kernel PCA Guillaume Obozinski Unsupervised dimensionality reduction 9/30

8 Centering implicitly in feature space Assume that we use a mapping φ so that the representation of the data is the design matrix Then φ(x 1 ) Φ =.. φ(x n ) φ = 1 n φ(x i ) = Φ 1. So that if φ(x i ) = φ(x i ) φ then Φ = Φ 11 Φ = ( I n 1 n 11 ) Φ Finally, the center kernel matrix is computed as K = Φ Φ = HKH with H = I n 1 n 11. Guillaume Obozinski Unsupervised dimensionality reduction 10/30

9 Principal function in a RKHS (Schölkopf et al., 1998) Find a function f with f H = 1 that maximizes Equivalently, max f f, h xi 2 H. f (x i ) 2 s.t. f 2 H 1. By the representer theorem, f (x) = n j=1 α jk(x, x j ). So, f (x i ) 2 = = ( ) 2 α j K(x i, x j ) j=1 j,j =1 = α K K α α j α j K(x i, x j )K(x i, x j ) So the problem can be written as max α α K K α s.t. α K α. Guillaume Obozinski Unsupervised dimensionality reduction 11/30

10 Solution of kernel PCA Write K = US 2 U. If β = U α, then the problem is formulated as max β β2 i s 4 i s.t. β 2 i s 2 i 1 This is attained for β = ( 1 s 1, 0,..., 0) and thus α = 1 s 1 u 1. So the first principal function is f (x) = 1 s 1 U i1 K(x i, x) And the kth principal function is f (x) = 1 s k U ik K(x i, x) Guillaume Obozinski Unsupervised dimensionality reduction 12/30

11 Multidimensional scaling Guillaume Obozinski Unsupervised dimensionality reduction 14/30

12 Multidimensional scaling Goal: Given a collection of not necessarily Euclidean distances δ ij between pairs of points indexed by {1,..., n}. Construct a collection of points y i in a Euclidean space such that y i y j 2 δ ij Original formulation: Minimize a function called stress function ( ) 2 min yi y j 2 δ ij Y ij Classical formulation: min Y ( yi y j 2 2 δij 2 ij ) 2 Guillaume Obozinski Unsupervised dimensionality reduction 15/30

13 Centered kernel matrix from a Euclidean distance matrix Lemma If D 2 = ( dij 2 ) 1 i,j n is a matrix of squared Euclidean distances, then K = 1 2 HD 2H with H = I n 1 n 11, is the corresponding centered kernel matrix. Proof: d 2 ij = φ(x i ) φ(x j ) 2 2 = K ii + K jj 2K jj With κ = (K 11,..., K nn ), we have 2K = κ1 + 1κ D 2 K = HKH = 1 2 H ( κ1 + 1κ D 2 ) H. Guillaume Obozinski Unsupervised dimensionality reduction 16/30

14 Classical MDS algorithm Algorithm: 1 Compute K = 1 2 HD 2H. 2 Remove negative eigenvalues from K. 3 Solve kernel PCA on K If D 2 are Euclidean distances, step 2 is unnecessary and it can be shown that this solves the classical MDS problem. Guillaume Obozinski Unsupervised dimensionality reduction 17/30

15 Isomap (Tenenbaum et al., 2000) Algorithm: 1 Compute a k-nn graph on the data 2 Compute geodesic distances on the k-nn graph using the l 2 distance on each edge. 3 Apply classical MDS to the obtained distances Remarks: Isomap assumes that we can rely on the l 2 distance locally will fail if there are too many noise dimensions. geodesic distances can be computed with e.g. the Floyd Warshall algorithm Guillaume Obozinski Unsupervised dimensionality reduction 18/30

16 Laplacian Eigenmaps Guillaume Obozinski Unsupervised dimensionality reduction 20/30

17 Graph Laplacians Assume a similarity matrix W is available on the data, e.g. a kernel matrix such as W = (w ij ) 1 i,j n with ( w ij = exp 1 ) h x i x j 2 2 We can think of W as defining a weighted graph on the data. We say that a function is smooth on the weighted graph if its Laplacian L (f ) := 1 w ij (f (x i ) f (x j )) 2 2 ij is small. We say that a vector f is smooth on the weighted graph if its Laplacian L (f) := 1 w ij (f i f j ) 2 2 is small. ij Guillaume Obozinski Unsupervised dimensionality reduction 21/30

18 Laplacian and normalized Laplacian matrices Define D = Diag(d) with d i = j w ij. We then have L (f) = 1 w ij (f i f j ) 2 2 = 1 2 = 1 2 ij ij i w ij f 2 i d i f 2 i ij j w ij f 2 j d j f 2 j = f Df f Wf = f Lf Laplacian matrix: L Normalized Laplacian matrix: ij ij w ij f i f j w ij f i f j L := D 1 2 LD 1 2 = I D 1 2 WD 1 2. Guillaume Obozinski Unsupervised dimensionality reduction 22/30

19 Laplacian embeddings (Belkin and Niyogi, 2001) Principle: Given a weight matrix W find an embedding y i R K for point i that, given scaling and centering constraints on y i, solves We have min Y w ij y i y j 2 2 with Y = [ ] y 1... y n. ij w ij y i y j 2 2 = ( ) 2 w ij Yik Y ij ij ij k=1 K ( ) 2 = w ij Yik Y jk = k=1 ij K K Y k L Y k = tr(y L Y) k=1 Guillaume Obozinski Unsupervised dimensionality reduction 23/30

20 Laplacian embedding formulation min Y tr(y L Y) s.t. Y D Y = I, Y 1 = 0. With the change of variable Ỹ = D 1 2 Y, then Ỹ solves min Ỹ tr(ỹ L Ỹ) s.t. Ỹ Ỹ = I, Ỹ D = 0. But LD = 0, so the columns of Ỹ are the eigenvectors associated with the smallest eigenvalues except for the one D Equivalently, the columns of Y are the solutions of the generalized eigenvalue problem Lu = λdu for the smallest generalized eigenvalues except for the one 1. The rows of the obtained matrix form the embedding. Guillaume Obozinski Unsupervised dimensionality reduction 24/30

21 Locally Linear Embedding Guillaume Obozinski Unsupervised dimensionality reduction 26/30

22 Locally Linear Embedding (Roweis and Saul, 2000) Let x 1,..., x p be a collection of vectors in R p. 1 Construct a k-nn graph 2 Approximate x i by a linear combination of its neighbors, by finding the vector of weights solving the constrained linear regressions: xi min 2 w ij x j, with w ij = 1. w i 2 j N (i) j N (i) 3 Set w ij = 0 for j / N (i). 4 Find a centered set of points y i in R d with white covariance, which minimizes 2 y i w ij y j j=1 2 Guillaume Obozinski Unsupervised dimensionality reduction 27/30

23 LLE step 2: constrained regressions xi min 2 w ij x j, with w ij = 1. w i 2 j N (i) j N (i) But if j N (i) w ij = 1, then x i 2 w ij x j = Need to solve j N (i) 2 j N (i) = j N (i) w ij (x i x j ) min u 1 2 u Ku s.t. u 1 = w ij w ik (x i x j ) (x i x k ) }{{} K (i) jk L(u, λ) = 1 2 u Ku λ(u 1 1) and u L = 0 Ku = λ1 Solved for u = K K 1 1. Guillaume Obozinski Unsupervised dimensionality reduction 28/30

24 LLE step 4: final optimization problem min y 1,...,y n s.t. y i y i = 1, 2 w ij y j j=1 1 n 2 y i y i = I p. Equivalently, denoting Y = [ y 1... y n ], we have to solve Or, min Y min Y Y WY 2 F s.t. 1 Y = 0, Y (I n W) (I n W) Y s.t. Y1 = 0, 1 n Y Y = I p. 1 n Y Y = I p. So the columns of 1 n Y are the k eigenvectors associated with the smallest k non-zero eigenvalues. Guillaume Obozinski Unsupervised dimensionality reduction 29/30

25 References I Belkin, M. and Niyogi, P. (2001). Laplacian eigenmaps and spectral techniques for embedding and clustering. In NIPS, volume 14, pages Roweis, S. T. and Saul, L. K. (2000). Nonlinear dimensionality reduction by locally linear embedding. Science, 290(5500): Schölkopf, B., Smola, A., and Müller, K.-R. (1998). Nonlinear component analysis as a kernel eigenvalue problem. Neural computation, 10(5): Tenenbaum, J. B., De Silva, V., and Langford, J. C. (2000). A global geometric framework for nonlinear dimensionality reduction. Science, 290(5500): Guillaume Obozinski Unsupervised dimensionality reduction 30/30