Cover Sheet for Lab Experiment #3

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1 The University of Toledo EECS:1100 R2 Digital Logic Design Dr. Anthony D. Johnson Cover Sheet for Lab Experiment #3 Student Names Course Section Anthony Phillips 003 Alexander Beck 003 Report turned in late Grade /2 Final Grade /2

2 1. Introduction to Lab Report 1.1 Objectives 1. Becoming familiar with two standard forms of logic functions: Sum of Products (SOP), and Product of Sums (POS) 2. Becoming familiar with two canonical forms of logic functions: Sum of Minterms, and Product of Maxterms 3. Applying the algebraic manipulation method to transform standard to canonical forms 4. Learning a procedure for deriving the truth table of a logic function which is known in algebraic form 5. Learning how to derive the minterm list (decimal sum of minterms) form of a logic function whose truth table is known 6. Learning how to derive the maxterm list (decimal product of maxterms) form of a logic function whose truth table is known 7. Exercising two-level implementation of logic functions 8. Becoming familiar with degenerate two-level logic circuits: AND-AND 9. Developing skills in analyzing and testing the behavior of combinational logic circuits.

3 2. Report on Prelab Work 2.1 SOP Form of Logic Functions For this lab we will be considering the following function in minimal SOP form: F = f(a, B, C, D) = B'C + AD' We are first asked to algebraically derive the canonical minterm expression. The work is as follows: First we expand the term B'C B'C = B'C (A + A') (D + D') = (B'CA + B'CA') (D + D') = AB'CD + AB'CD' + A'B'CD + A'B'CD' Next we expand the term AD' AD' = AD' (B + B') (C + C') = (AD'B + AD'B') (C + C') = ABCD' + ABC'D' + AB'CD' + AB'C'D' We then substitute for B'C and AD' in F=B'C+AD' F = AB'CD + AB'CD' + A'B'CD + A'B'CD' + ABCD' + ABC'D' + AB'CD' + AB'C'D Lastly, we remove the duplicate terms AB'CD' (x + x = x) and arrive at the canonical minterm expression F = AB'CD + AB'CD' + A'B'CD + A'B'CD' + ABCD' + ABC'D' + AB'C'D'

4 2.1.2 Using the canonical minterm expression, we can derive the truth table T F = AB'CD + AB'CD' + A'B'CD + A'B'CD' + ABCD' + ABC'D' + AB'C'D' Note that the 1-minterms in the table are color-coded with their corresponding term in the canonical minterm expression. Table T2.1-1 Truth table for the function F=B'C+AD' including min / max terms and inverse. A B C D m n M n F F' A'B'C'D'=m 0 A+B+C+D=M A'B'C'D=m 1 A+B+C+D'=M A'B'CD'=m 2 A+B+C'+D=M A'B'CD=m 3 A+B+C'+D'=M A'BC'D'=m 4 A+B'+C+D=M 4 A'BC'D=m 5 A+B'+C+D'=M 5 A'BCD'=m 6 A+B'+C'+D=M A'BCD=m 7 A+B'+C'+D'=M AB'C'D'=m 8 A'+B+C+D=M 8 AB'C'D=m 9 A'+B+C+D'=M AB'CD'=m 10 A'+B+C'+D=M AB'CD=m 11 A'+B+C'+D'=M ABC'D'=m 12 A'+B'+C+D=M ABC'D=m 13 A'+B'+C+D'=M ABCD'=m 14 A'+B'+C'+D=M ABCD=m 15 A'+B'+C'+D'=M 15

5 2.1.3 We are asked now to represent the function in minterm list form, or decimal Sum of Minterms form. According to our canonical minterm expression: F = AB'CD + AB'CD' + A'B'CD + A'B'CD' + ABCD' + ABC'D' + AB'C'D' Now, using table T2.1-1, we substitute the decimal values for each minterm: A B C D m n 0 0 A'B'CD'=m A'B'CD=m AB'C'D'=m AB'CD'=m AB'CD=m ABC'D'=m ABCD'=m 14 F = AB'CD + AB'CD' + A'B'CD + A'B'CD' + ABCD' + ABC'D' + AB'C'D' = m 11 + m 10 + m 3 + m 2 + m 14 + m 12 + m 8 = Finally, we put this in summation form: F = = Σ (11, 10, 3, 2, 14, 12, 8) Equation E2.1-3 F = Σ (2, 3, 8, 10, 11, 12, 14) Its inverse is then represented by summation of the 0-minterms (or the 1-minterms of F'): Equation E2.1-3 F' = Σ (0, 1, 4, 5, 6, 7, 9, 13, 15)

6 2.1.4 / a) b) Figure 2.1-1

7 2.2 Degenerate Two-Level AND-AND Logic Circuit / a) b) Figure 2.2-1

8 2.2 The function given by the circuit in figure 2.2-1a is: F = f(a, B, C, D) = { [ (B'C)' ][ (AD')' ] }' This function generates the truth table shown in T Table T2.2-1 Truth table for the function F={ [ (B'C)' ][ (AD')' ] }' including minterms, maxterms and inverse. A B C D m n M n F F' A'B'C'D'=m 0 A+B+C+D=M A'B'C'D=m 1 A+B+C+D'=M A'B'CD'=m 2 A+B+C'+D=M A'B'CD=m 3 A+B+C'+D'=M A'BC'D'=m 4 A+B'+C+D=M 4 A'BC'D=m 5 A+B'+C+D'=M 5 A'BCD'=m 6 A+B'+C'+D=M A'BCD=m 7 A+B'+C'+D'=M AB'C'D'=m 8 A'+B+C+D=M 8 AB'C'D=m 9 A'+B+C+D'=M AB'CD'=m 10 A'+B+C'+D=M AB'CD=m 11 A'+B+C'+D'=M ABC'D'=m 12 A'+B'+C+D=M ABC'D=m 13 A'+B'+C+D'=M ABCD'=m 14 A'+B'+C'+D=M ABCD=m 15 A'+B'+C'+D'=M 15

9 2.2.3 If we extract the 1-minterms of F from table T2.2-1 we can prepare the canonical minterm expression: A B C D m n F 0 0 A'B'CD'=m A'B'CD=m AB'C'D'=m AB'CD'=m AB'CD=m ABC'D'=m ABCD'=m 14 1 Equation E2.2-1 F = A'B'CD' + A'B'CD + AB'C'D' + AB'CD' + AB'CD + ABC'D' + ABCD' It should be noted that this expression is identical to the canonical minterm expression derived in from the function F = B'C + AD'. Extracting the 0-maxterms of F from table 2.2-1, we can also gather the maxterm list: A B C D M n F A+B+C+D=M A+B+C+D'=M A+B'+C+D=M 4 0 A+B'+C+D'=M 5 0 A+B'+C'+D=M A+B'+C'+D'=M 7 0

10 A'+B+C+D'=M A'+B'+C+D'=M A'+B'+C'+D'=M 15 0 F = M 0 + M 1 + M 4 + M 5 + M 6 + M 7 + M 9 + M 13 + M 15 = Equation E2.2-2 F = Π (0, 1, 4, 5, 6, 7, 9, 13, 15) It should be noted that this maxterm list is identical to the 0-minterm list we derived in As we have observed, the truth tables and minterm expressions are identical for both F 0 = B'C + AD' and F 1 ={ [ (B'C)' ][ (AD')' ] }'. This means they represent the same function. Here we further prove that these functions are equivalent by applying DeMorgan's Theorem: F 0 = B'C + AD' = B'(C')' + (A')'D' = (B + C')' + (A' + D)' = [ (B + C')(A' + D) ]' = { [ (B')' + C' ][ A' + (D')' ] }' = { [ (B'C)' ][ (AD')' ] }' = F 1

11 2.3 POS Form of Logic Functions We are now asked to algebraically derive the POS standard form of the equation given in We can do this by applying DeMorgan's Law: F = B'C + AD' = B'(C')' + (A')'D' = (B + C')' + (A' + D)' Equation E2.3-1 F = [ (B + C')(A' + D) ]' We will now determine the product of maxterms canonical form: First we expand the term B+C': B + C' = B + C' + AA' + DD' = (A + B + C' +D)(A' + B + C' + D)(A + B + C' + D')(A' + B + C + D') Next we expand the term A'+D: A' + D = A' + D + BB' + CC' = (A' + B + C + D)(A' + B' + C + D)(A' + B + C' + D)(A' + B' + C' + D) We then substitute for B+C' and A'+D: F = [ (B + C')(A' + D) ]' = [ (A + B + C' +D)(A' + B + C' + D)(A + B + C' + D')(A' + B + C + D')(A' + B + C + D)(A' + B' + C + D)(A' + B + C' + D)(A' + B' + C' + D) ]' We eliminate duplicate terms: F = [ (A + B + C' +D)(A' + B + C' + D)(A + B + C' + D')(A' + B + C + D')(A' + B + C + D)(A' + B' + C + D)(A' + B' + C' + D) ]'

12 Finally, we should see that our expression is a complement; this means that the maxterms in our expression are the 1-maxterms. We now convert this to an expression of 0-maxterms: Equation E2.3-2 F = (A' + B' + C +D')(A + B' + C + D')(A' + B' + C + D)(A + B' + C' + D)(A + B' + C' + D')(A + B + C' + D')(A + B + C + D') If we compare the maxterms we derived in Equation E2.3-2 to the maxterms contained in the truth table T2.2.1, we can see that our canonical maxterm expression is verified: F = (A' + B' + C +D')(A + B' + C + D')(A' + B' + C + D)(A + B' + C' + D)(A + B' + C' + D')(A + B + C' + D')(A + B + C + D') A B C D M n F F' A+B+C+D=M A+B+C+D'=M A+B'+C+D=M 4 A+B'+C+D'=M 5 A+B'+C'+D=M A+B'+C'+D'=M 7 A'+B+C+D'=M A'+B'+C+D'=M A'+B'+C'+D'=M 15

13 2.3.4 / a) b) Figure 2.3-1

14 3. Experimental Results and Discussion 3.1 AND-OR Implementation of f(d,c,b,a) Figure Output produced by AND-OR implementation.

15 3.2 Degenerate Two-Level AND-AND Logic Circuit Figure Output produced by AND-AND implementation.

16 3.3 OR-AND Implementation of f(d,c,b,a) Figure Output produced by OR-AND implementation.

17 4. Answers to Questions 4.1 (from 4.2.6) What is the maximum number of inputs (fan-in) of an AND gate which can be implemented using the IC 7408? An IC 7408 contains four 2-Input AND gates therefore the maximum number of inputs possible for IC 7408 is (from 4.2.6) How many different implementations of the maximum fan-in AND gate can be constructed using the IC 7408? The number of implementations is 2 n where n is the number of inputs. In our case n=8, so: 2 8 = 256

18 Helpful Sources: Semantics: Deriving minterm / maxterm expressions: df Function Checker: Circuit Modeling:

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