AP Physics C: UNIT CONVERSION

Size: px

Start display at page:

Download "AP Physics C: UNIT CONVERSION"

Ira Douglas
6 years ago
Views:

AP Physics C: UNIT CONVERSION 1. Convert each of the following measurements into the specified units. a. 42.3 cm = 423 mm d. 0.023 mm = 0.23 cm 1 cm = 10 mm b. 6.2 pm = _0.0000000000062_ m e.

1 AP Physics C: UNIT CONVERSION 1. Convert each of the following measurements into the specified units. a cm = 423 mm d mm = 0.23 cm 1 cm = 10 mm b. 6.2 pm = _ _ m e. 214 µm = _ m 1 picometer = meters 1 micrometer = 10 6 meters c. 21 km = 21,000_ m f. 70 nm _ _ km 1 kilometer = 10 3 meters 1 nanometer = 10 9 meters 2. Rank the following mass measurements from smallest to largest: 11.6 mg = gm, 1021 µg = gm, kg = gm, 0.31 mg = gm gm gm gm gm 3. Convert each of the quantities to specified equivalents a. 33 ft to m c. cm 3 to _ _ m 3 1 m 33 ft 3.3 ft cm3 = m3 100 cm 100 cm 100 cm b. 2.0 in to 0. mm d m 2 /day to 3,974,80 ft 2 /year 1 ft 2.0 in 1 m 1000 mm 1 m2 36 days 3.3 ft = 0. mm in 3.3 ft 1 m day 1 yr 1 m 1 Warhol = 1 minutes of fame based on Andy Warhol s famous line: Everybody will have 1 minutes of fame. 1 Kardashian = 72 days Based on how long a Kardashian marriage lasts 1 m 1 m 1 m 3.3 ft = 3,974,80 1 m ft2 /year 1 Wheaton = half a million Twitter followers Based on the number of followers celebrity Will Wheaton had 1 Parsec = unit of astronomical distance = meters 4. Use the table of values above to solve the following problem. Mr. Spock ran x parsecs in 0.04 Kardashians. For his great feat he was awarded two Warhols during which his Twitter followership increased to 4 Wheatons. a m/s Find Spock s speed (in m/s) parsecs 1 Kardashian 1 day 1 hr m = 0.62 m/s 0.04 Kardashians 72 days 24 hrs s 1 parsec b hrs. Find the total time Spock ran + the time he was famous (in hours). 72 days 24 hrs. 1 min 0.04 Kardashians + 2 Warhols 1 hr = 69.6 hrs. 1 Kardashian 1 day 1 Warhol 60 min c followers/s What was the rate of growth of Mr. Spock s Twitter followership (in followers per second)? 4 Wheatons 2 Warhols 00,000 followers 1 Wheaton 1 Warhol 1 min. 1 min. 60 s = followers/s

2 AP Physics C: DIMENSIONAL ANALYSIS The following are dimensions of various physical parameters that will be discussed later on in the year. Here [L], [T], and [M] denote, respectively, fundamental dimensions of length, time, and mass. UNIT SYMBOL DIMENSION UNIT SYMBOL DIMENSION Distance x [L] Mass m [M] Acceleration a [L]/[T] 2 Energy E [M][L] 2 /[T] 2 Time t [T] Speed v [L]/[T] Force F [M][L]/[T] 2 Which of the following equations are dimensionally correct? Show the work that verifies this. 1. v 2 = v 1 t + a 6. F = m a L = L (T) + L T T T 2 L = L + L T T 2 L = L(T2 ) + L T T 2 T 2 L L(T2 )+L ML = (M)( L ML T T 2 T 2 T2) = ML T 2 T 2 2. v f = v 1+v 2 7. x = ½ a t 2 2 L = L + L T T T L = 2L L = L L = ( L T T T T T 2) T2 L = L 3. x = v t 2 + ½ a t 8. E = ½ m v L = ( L ) T T2 + L ML T2 T L = L T + L T L L T 2 = M L ML2 ML T 2 T T 2 T v 2 = v a x 2 9. E = m a x ( L T )2 = ( L T )2 + L T 2 L2 L2 L2 L3 T2 = T2 + T2 L2 L2 +L 3 ML 2 = (M) ( L ML2 T 2 T 2 T 2 T2) L = ML2 T 2 T 2. x = ½ v t 2 + a t Same as 3 above: L = ( L ) T T2 + L T2 T L = L T + L T L L T 10. v = F x m L = ML T 2 L T M L = T ML L T 2 M L = L 2 T M2 T 2 L ML T T 11. A spring is hanging down from the ceiling and an object of mass m is attached to the free end. The object oscillates up and down, and the time T required for one complete up-and-down oscillation is given by the equation T = 2 m, where k is k known as the spring constant. What must be the dimension of k for this equation to be dimensionally correct? T = 2 m k 2 T = M k T2 = ( M ) T 2 = M k = M kg k k T2 = s 2

3 AP Physics: TRIANGLE GEOMETRY AND TRIGONOMETRY DIRECTIONS: Find the missing values requested. un JI =? IL =? HK =? IH =? AG =? GF =? Ans. BFA = 90, because supplementary angles = 180 (90 + BFA = 180 ) AGF = 60 because supplementary angles = 180 (since AGC = 120 ). FAG = 30 because the sum of the angles of a triangle AFG = 180 CGJ = 60 because supplementary angles = 180 IKH = HKI = 60 because of the following ELJ = 120 since corresponding angles are congruent ( ELJ AGC), therefore ELM = 60 because supplementary angles = 180, JLI = 60, because vertical angles are congruent ( ELM JLI), IJL = 90 because supplementary angles = 180, LIJ = 30, because the sum of the angles of a triangle LIJ = 180, HIK = 30 because vertical angles are congruent ( LIJ HIK). IHK = 90 because BC DE and AK BC so it must also be DE. FGJ = 120 because vertical angles are congruent HIJ = 10 because supplementary angles = 180 To find JI : tan = opp. tan JLI = JI adj. JL tan 60 = JI ji = 3 tan 60 ji =. 20 un 3 un To find IL : a 2 + b 2 = c 2 c = a 2 + b 2 IL = = 36 = 6 un To find HK : cos = adj. cos HKI = HK HK cos 60 = hyp. HK = 4 cos 60 HK = 2 un KI 4 un To find : IH a 2 + b 2 = c 2 a = c 2 b 2 IH = = 12 = un To find : AG cos = adj. cos FAG = AF un cos 30 = hyp. AG AG = AG = =. 78 un AG cos 30 cos 30 To find FG : a 2 + b 2 = c 2 a = c 2 b 2 FG = = = un

4 AP Physics: AREA UNDER A CURVE DIRECTIONS: Find the area under the graph shown. B C A D Ans. Area A + Area B + Area C + Area D = ½ ½ = Answer: 0 Answer with units included: 0 (m/s s) = 0 m CONCLUSION: The units of your answer reveal that if you find the area between a velocity vs time graph of an object and the x-axis, you have actually found the distance travelled by the object.

5 AP Physics: VECTOR MATH 20 L G 60 C D I A B H F K E J 30 4 DIRECTIONS: Using the vector diagrams drawn, determine the magnitude and direction of each vector quantity. A = 4 units, 0 B = 6 units, 270 C = units, 180 G =8 units, 0 H =6 units, 90 I = sin = opp. 6 un. sin 60 = hyp. hyp. hyp = 6 un. sin 60. = 3.46 un D = 8 units, 90 J = 9 units, 180 E = cos = adj. un. cos 30 = hyp = hyp. un. cos 30. =.77 un hyp. K = 2 units, 270 F = sin = opp. 7 un. sin 4 = hyp. hyp. hyp = 7 un. sin 4. = 9.89 un L = cos = adj. 7 un. cos 20 = hyp. hyp. hyp = 7 un. = 7.4 un cos 20.

DIRECTIONS: In the blank grids below, perform each vector operation GRAPHICALLY using the head-to-tail method. State the magnitude and direction of the resultant vector.

6 DIRECTIONS: In the blank grids below, perform each vector operation GRAPHICALLY using the head-to-tail method. State the magnitude and direction of the resultant vector. A + G B + D 2 units, units, 0 A G 4 units, 180 D + J = 128 un, 4 E + G 2H A = 178 un, = tan -1 opp. adj. = tan = = 170 un, = tan -1 opp. adj. = tan = 18.4 = = 108.4

AP Physics: DISPLACEMENT, DISTANCE, SPEED, VELOCITY DIRECTIONS: Use the specific definitions of the terms displacement, distance, speed, and velocity to find the following. A. C. B. V D.

The displacement of the emoji from the origin for A D. For A = units, For B = units, For C = units, and For D = 0 units c. The speed of the emoji for A D if each trip took seconds.

7 AP Physics: DISPLACEMENT, DISTANCE, SPEED, VELOCITY DIRECTIONS: Use the specific definitions of the terms displacement, distance, speed, and velocity to find the following. A. C. B. V D. DIRECTIONS: The emoji starts at the origin in each of the above cases. Find: a. The distance the emoji traveled for A D. For A = units, For B = 1 units, For C = units, and For D = 20 units b. The displacement of the emoji from the origin for A D. For A = units, For B = units, For C = units, and For D = 0 units c. The speed of the emoji for A D if each trip took seconds. s = d, For A: s = = 1 un/s, For t B: s = 1 = 3 un/s, For C: s = 20 = 1 un/s, and For D: s = = 4 un/s d. The velocity of the emoji for A D if each trip took seconds. v = x, For A: v = = 1 un/s, For t B: v = = 1 un/s, For C: v = = 1 un/s, and For D: v = 0 = 0 un/s DIRECTIONS: The emoji goes 2-dimensional and moves on the graph paper as shown at right. a. The distance the emoji traveled from A B. b. Ans. 17 units c. The displacement of the emoji from A B = 89 un d. The speed of the emoji if it took 10 seconds to cover the distance. 17 un s = = 1. 7 un/s 10 s e. The velocity of the emoji if the trip took 10 seconds. v = x t = = un/s

REQUIRED Assignment (June 15 th August 24th)

REQUIRED Assignment (June 15 th August 24th) AP Physics C - Mechanics Due Date: August 24th Name BROAD RUN HIGH SCHOOL AP PHYSICS C: MECHANICS SUMMER ASSIGNMENT 2017-2018 Teacher: Mr. Manning Textbook: Physics for Scientists and Engineers, 9 th Edition,