3.1 Derivatives of Polynomials and Exponential Functions. m(x) = f(x) + g(x) m (x) = f (x) + g (x) (The Sum Rule)
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1 f Chapter 3 Differentiation Rules 3.1 Derivatives of Polynomials and Exponential Functions Aka The Short Cuts! Yay! f(x) c f (x) 0 g(x) x g (x) 1 h(x) x n h (x) n x n1 (The Power Rule) k(x) c f(x) k (x) c f (x) m(x) f(x) + g(x) m (x) f (x) + g (x) (The Sum Rule) n(x) f(x) g(x) n (x) f (x) g (x) (The Difference Rule) p(x) e x p (x) e x Ex: Prove!!" # % & # % (&) *ti90 c getting staffed fino fc C [ faith ) thing ( xth ) (D I in a. n 0 FED Note: Proof of Power Rule on page 175 uses the Binomial Theorem.
2 C2) ] ' Ex: Differentiate + a) y & Ex 's y ' 's x 's ' I ' st x Ex b), + / 0 c) 1 " 2 f G) f ' Cr ) er + i 4 2 text 4 4. exit. 3 ' ) 8 8 #.
3 Definition of e It s clear from the study of exponential functions that the slope of the tangent to f(x) a x at x 0 is 1 for some value of a between 2 and 3. Mathematicians wanted to find that value. The slope of the tangent line at x 0 is given by the first derivative at 0: 9 8:6 ;9(8) < ;<> < ;? f (0) lim lim lim So the definition of e is E C C D C 1
4 3.2 The Product and Quotient Rules H H& % J &? Ex: Find m (x) if m(x) x 3 x 4. Is the derivative of m(x) equal to the product of the derivatives of its factors? MG )x'x4 7 mtx ) 7 6 X 33 2 di x44 3
5 . Geometric Explanation of the Product Rule (via Gottfried Wilhelm Leibniz, one of the two fathers of calculus along with Sir Isaac Newton) Start with f(x)g(x), which can be visualized as the white rectangle above. Let s imagine that we change x by an amount equal to &. Now we have a new product, f(x 0 + &) g(x 0 + &), which is the larger rectangle. We see from the picture that Whole Rectangle White Rectangle + Side Blue + Top Blue + Grey f(x 0 + &)g(x 0 + &) f(x 0 )g(x 0 ) + f(x 0 ) J + g(x 0 ) %+ % J So the change in the product is just the blue and grey rectangles: %J f(x 0 + &)g(x 0 + &) f(x 0 )g(x 0 ) f(x 0 ) J + g(x 0 ) %+ % J If we divide the whole thing by &, we get (MN) M(O >) P " " + N(O >) 9 + % P " " Then, if we let & 0, H H& % & J & % & JS & + J & % (&) (Note: % f(x 0 + &) %(&) à 0 as & à 0)
6 . 2e te x2 The Product Rule U UV W V X V W V U UV X V + X V U UV W V See page 187 for a similar explanation of what happens with the quotient of two functions: The Quotient Rule f.gl + t x) ftx ) FG g. )g' G) U UV W V X(V) X V U UV W V W V [X V ] [ U UV X V Ex: Differentiate a) f(x) (x 2 2x)(1 + e x ) Tfafdiolfcxtzx ) 'a+ed+ ( xiixkitey ' " 0 or (2 2) ( HeD+G±2D(e ) C h k+e HGhD a+e sh 2 +2 xe e x2 2e xe Nole: x x'1x"1x _
7 . Cfg) fg ' + f ' g ftgtfg ' m( ) 3 4 m '( ) x3(4x3)+( (F) Fg g 'f
8 b) g(x) "2 ;\"?:0 ] : gas) a'b axtzx de 2 2 bl+e dgb e g 'HEHteh DGI [l+e ] xixexxexxtxex [1+23 ' e x2+4xe 2e t2 ] 2 2
9 3.3 Derivatives of Trigonometric Functions z LI.! (sin ") cos "!"! (cos ") sin "!" Ex: Using the above, find the derivative of y tan x abc " dea " adzcsiwxiasxdxtfosxjesnxccosx ) ' cosx C ( cos x ). SNX ) ( sin x ) T 0 I 0 I I 0 f*f* ZT 0 / }. cos xtsn# osty seix ' or ( sec xp! (tan ")!" sec[! " (cot ")!" csc[ "! (csc ") csc " cot "! (sec ") sec " tan "!"!"
10 3.4 The Chain Rule The Chain Rule If g is differentiable at x and f is differentiable at g(x), then the composite function F!"# defined by F(x) f(g(x)) is differentiable at x and F' is given by the product F'(x) f'(g(x)) g'(x) In Leibniz notation, if y f(u) and u g(x) are both differentiable functions, then!j!j!k!"!k!" Ex: Differentiate 1) f(x) (x+1) 2 + 2) g(x) 3 + [ 3) y sin (x 2 )
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13 0 cs 0 (e) O 3, ( In 6) O 4 ( eh6+4r}p w; 0 5 ( ) City ) ( ( 5 3x ) 3
14 9 ki ) (x+± 26+2 ) ' ( xtz ) ZC xtz ) ( i ) ( ( e , ( (6 +5)
15 Using the Chain Rule to come up with the derivatives of exponential functions:!!" /" / ", but what is!!" 0"? First: a x (e ln a ) x Then:!!" 0"!!" (/no< ) " (/ no< ) "! (780)+!" (/no< ) " 780 a x ln a fan a). ex ' not ex ha Question: What happens when a e? fit ± (e) ax In a ex he ex. e I
16 3.5 Implicit Differentiation Ex: If y x 2 + 4, find!j!" : Ex: If y x 2 4, find!j!" dxtt Ex: If y 2 x 2 4, find!j!" (Hint: Use the Chain Rule) optional : Zydaxt GY k7 C4 ) Zydatx Zx Ty Ty x
17 Ex: a) Find y if x 2 + y ,4+± G4 GD , xo, yy *z 4$ A I Yh# b) Find the slope of the tangent line to the curve at x 3 4y±25 at ( 3,4 ) : y1 y±4 ( 3,4) at ( 3 4), or (354) y ' I c) Looking at the graph, does part b make sense?!*.#kiht*n, 2 Y y ' at (34) Tm
18 Inverse Trig Functions If x sin y, then y sin 1 x for r [ < y < r [ (prounounced arcsine ) But what s the derivative? Use x sin y, and solve for!j!" : Ex cosyd, J %sxj sec y 1 cosy II so!j!"? dea j??;sto 2 j??; " 2 ' Derivatives of Inverse Trig Functions:!!" sin1 x?!?; " 2!" csc1 x? " " 2 ;?!!" cos1 x?!?; " 2!" sec1 x? " " 2 ;?!?!!" tan1 x?:" 2!" cot1 x??:" 2
19 3.6 Derivatives of Logarithmic Functions What is!!" #$% <'? Start with y #$% < ', then ( j x. * *' (j * *' (') ( j ln ( *1 *' 1 *1 *' 1 ( j ln ( So,!j??!" < xyz {\ c < " c < If y ln x, then!j!"? " c 0? " In general, * *' (ln <) < < Ex: Find f (x) if f(x) ln(x 3 + 1) ftp.x#i,
20 Cool Tricks: Ex: Find y if y ln "+ : ~";B [" Ä ;1" in Yates Yuck this one looks horrible, until you remember that: ln "+ : ~";B [" Ä ;1" ln ('~ + 3' 5)? [ ln (2'1 4') Exits XXX 1 x4t Ex: Find!!" '[" (Hint: Try this y ' [" ln y ln ' [" ln y 2x ln x)
21 3.7 Rates of Change in the Natural and Social Sciences Whoo hooo! Word problems!!!!! Ex: (#8) If a ball is thrown vertically upward with a velocity of 80 ft/s, then its height after t seconds is s(t) 80t 16t 2. a) What is the maximum height reached by the ball? b) What is the velocity of the ball when it is 96 feet above the ground on its way up? On its way down? Notes: Marginal Cost C (x) The change in cost when you produce one more item Velocity Gradient instantaneous rate of change of velocity wrt r dv/dr
22 3.8 Exponential Growth and Decay Radioactive Decay Fact: Radioactive substances decay at a rate proportional to the remaining mass. Simply speaking, a big pile decays faster than a small pile. So, for m mass and t time,!ñ %&, for some constant k. In other words, m(t) m 0 e kt, where m 0 is the initial mass.!ö Ex: (#8) Strontium90 has a halflife of 28 days. a) A sample has a mass of 50 mg initially. Find a formula for the mass remaining after t days. b) Find the mass remaining after 40 days. c) How long does it take the sample to decay to a mass of 2 mg? d) Look at the graph of the function. Does it make sense?
23 3.9 Related Rates This section offers applications of Implicit Differentiation. We ll use our understanding of one change to compute another change possibly one that s hard to measure directly. Ex: Air is being pumped into a spherical balloon so that its volume increases at a rate of 100 cm 3 /s. How fast is the radius of the balloon increasing in general? How about when the diameter reaches 50 cm? Hint: Volume of a Sphere 1 ~ )*~ We know:!â!ö 100 cm3 /s We want to find:!!ö
24 Ex: Car A is traveling west at 50 miles per hour and car B is traveling north at 60 miles per hour. Both are headed for the intersection of the two roads. At what rate are the cars approaching one another when car A is 0.3 miles and car B is 0.4 miles from the intersection? Ex: A water tank has the shape of an inverted circular cone with base radius 2m and height 4 m. If water is being pumped into the tank at a rate of 2 m 3 /minute, find the rate at which the water level is rising when the water is 3 m deep. Hint: Volume of a cone? ~ )*[ h, and use similar triangles to eliminate r.
25 3.10 Linear Approximations and Differentials
26 3.11 Hyperbolic Functions
3.1 Derivatives of Polynomials and Exponential Functions. m(x) = f(x) + g(x) m (x) = f (x) + g (x) (The Sum Rule)
f Chapter 3 Differentiation Rules 31 Derivatives of Polynomials and Exponential Functions Aka The Short Cuts! Yay! f(x) c f (x) 0 g(x) x g (x) 1 h(x) x n h (x) n x n1 (The Power Rule) k(x) c f(x) k (x)
More informationm(x) = f(x) + g(x) m (x) = f (x) + g (x) (The Sum Rule) n(x) = f(x) g(x) n (x) = f (x) g (x) (The Difference Rule)
Chapter 3 Differentiation Rules 3.1 Derivatives of Polynomials and Exponential Functions Aka The Short Cuts! Yay! f(x) = c f (x) = 0 g(x) = x g (x) = 1 h(x) = x n h (x) = n x n-1 (The Power Rule) k(x)
More informationm(x) = f(x) + g(x) m (x) = f (x) + g (x) (The Sum Rule) n(x) = f(x) g(x) n (x) = f (x) g (x) (The Difference Rule) thing CFAIHIHD fkthf.
. Chapter 3 Differentiation Rules 3.1 Derivatives of Polynomials and Exponential Functions Aka The Short Cuts! Yay! f(x) c f (x) 0 g(x) x g (x) 1 h(x) x n h (x) n x n-1 (The Power Rule) k(x) c f(x) k (x)
More informationm(x) = f(x) + g(x) m (x) = f (x) + g (x) (The Sum Rule) n(x) = f(x) g(x) n (x) = f (x) g (x) (The Difference Rule) thing CFAIHIHD fkthf.
Chapter 3 Differentiation Rules 31 Derivatives of Polynomials and Exponential Functions Aka The Short Cuts! Yay! f(x) c f (x) 0 g(x) x g (x) 1 h(x) x n h (x) n x n1 (The Power Rule) k(x) c f(x) k (x) c
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Chapter 3 Differentiation Rules 31 Derivatives of Polynomials and Exponential Functions Aka The Short Cuts! Yay! f(x) c f (x) 0 g(x) x g (x) 1 h(x) x n h (x) n x n1 (The Power Rule) k(x) c f(x) k (x) c
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