Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., Outer Ring Road New Delhi , Ph. : ,

Size: px
Start display at page:

Download "Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., Outer Ring Road New Delhi , Ph. : ,"

Transcription

1 MSS SEQUENCE AND SERIES CA SEQUENCE A sequece is fuctio of tul ubes with codoi is the set of el ubes (Coplex ubes. If Rge is subset of el ubes (Coplex ubes the it is clled el sequece (Coplex sequece. Exple (i (ii (Hee ech te of the sequece c be obtied by ddig to the pecedig te 5...(Hee ech te of the sequece c be obtied by subtctig fo the pecedig te (iii (Hee ech te c be obtied by ultiplyig the pecedig te by. CB SERIES By ddig o subtctig the tes of sequece we get expessio which is clled seies. Thus ( +...(i 5 + ( +... to...(ii + ( ( to...(iii Above expessios e the exples of seies. CC TYPES OF SEQUENCES...(iv CA CB (i Fiite Sequeces A sequece is sid to be fiite if it hs fiite ube of tes. (ii Ifiite Sequeces A sequece is sid to be ifiite if it hs ifiite ube of tes. Aithetic Sequece o Aithetic Pogessio A Aithetic sequece is sequece i which the diffeece betwee y te d its just pecedig te is costt thoughout. This costt is clled the coo diffeece. th te of A.P. T = + ( d CC Su of tes of A.P. S [ ( d] If l is lst te (o th te the S ( d S [ l] l Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

2 CD Popeties of A.P.. If...e i A.P. The ± k ± k ± k... e i A.P.. If...e i A.P. The k k k...e i A.P. MSS CE & k k k... e i A.P.. If...e i A.P. & b b b e i A.P. The ± b ± b ± b...e i A.P. 4. If...e i A.P. & b b b e i A.P. The b b b...e ot i A.P. 5. If... e i A.P. The su of the tes equidistt fo the begiig d ed is costt i.e. k + (k = + (fist te + lst te 6. If th te of y sequece is lie expessio i the sequece is A.P. If th te of fo A + B the coo diffeece of A.P. is A. 7. If su of tes of y sequece is qudtic i the sequece is A.P. If the su of te is i the fo A + B + C the coo diffeece of A.P. is A. Selectio of Tes i A.P. No. of Choose tes Coo No. of Choose Coo tes is Diffeeces tes is tes Diffeece odd eve d + d d 4 d d d + d + d 5. d d + d d 6 5d d d + d d + d + d + 5d. The lest vlue of fo which 5 + x + 5 x 5 x + 5 x e thee cosecutive tes of A.P. is ( 5 0 (c oe of these. The fist secod d iddle tes of A.P. e b c espectively. Thei su is (c c(c c(b b(c ( c (c b b c b. If S S...S q e the sus of tes of q A.Ps whose fist tes e...q d coo diffeeces e 5...(q espectively. Show tht S + S + S S q = q(q. 4. The fist d lst te of A.P. e & l espectively. If s be the su of ll the tes of the A.P. show tht the coo diffeece is l s ( l Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

3 MSS 5. Show tht if...e i A.P. d S = k k the S k. k 6. The su of tes of itheticl pogessio e S S S...S. the fist te d coo diffeeces e... espectively. Pove tht S + S +... S = ( + ( The pth te of A.P. is d qth te is b. Pove tht su of its (p + q tes is p q b b p q [Aswes ( c ( b] CA Geoetic Sequece o Geoetic Pogessio CB A Geoetic pogessio (G.P. is sequece i which the tio of y te d its just pecedig te is costt thoughout. This costt is clled the coo tio. Exple (i th Te of G.P. (ii If is fist te d is the coo tio of geoetic pogessio the th te t = ( CC Su of Fist Tes S = If < the S (su of ifiite tes = ( CD Popeties of G.P.. If...e i G.P. The k k k...e i G.P. &. If...e i G.P. k k k...e i G.P. The...e i G.P.. If...& b b b...e i G.P. The b b b...e i G.P. & b b b...e i G.P. 4. If... & b b b...e i G.P hvig diffeet coo tio the ± b ± b ± b...e ot i G.P. 5. If... e i G.P. The log log log...e i A.P. & Viceves 6. If... e i G.P. The = =. =... Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

4 MSS 4 7. If...e i G.P. The = = 4 ; 4 = 5 ;... Selectio of tes i G.P. No. of Choose tes Coo No. of Choose Coo tes is tio tes is tes tio odd eve 4 5. Pctice Pobles If b c e i G.P. d log c log b c log b e i A.P. the the coo diffeece o the A.P. is ( / (c / / log.5... to. The vlue of ( 0.6 is ( (c 4 oe of these. If x y z e i GP d x = b y = c z the ( log b = log c log c b = log c (c log b = log c b oe of these 4. The cosecutive digits of thee digit ube e i G.P. If the iddle digit be icesed by the they fo o A.P. If 79 is substcted fo this ube the we get the ube cosistig of the se thee digits but i evese ode. Fid the ube. 5. Does thee exist G.P. cotiig 7 8 d s thee of its tes? If it exists how y such pogessios e possible? 6. Fid the su of the ifiitely decesig G.P. whose thid te the thee ties the poduct of the fist d fouth tes d the secod te fo i the idicted ode A.P. with the coo diffeece equl to / Pove tht the su of fist tes of the seies is [Aswes ( b ( c ( c (4 9(6 ] C4A Aithetic - Geoetic Seies A seies is sid to be ithetico-geoetic seies if its ech te is foed by ultiplyig the coespodig te of A.P. d G.P. e.g. x + 4x + 6x + 8x 4... Hee e i A.P. d x x x x 4...e i G.P. C4B th Te of Aithetico-Geoetic Seies th te of ithetico-geoetic seies c be obtied by ultiplyig the th te of A.P & th te of G.P. e.g. The th tes of the seies x + 4x + 6x + 8x is { + ( }(x. x =. x C4C Su of tes of ithetico- geoetic seies Let S = + ( + d + ( + d [ + ( d] Multiplyig both sides of (i by coo tio of (G.P. d wite s follows S = + ( + d +... [ + ( d]...(i...(ii Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

5 Fo (i (ii S ( = + [d + d d ] [ + ( d] MSS 5 d( S ( [ ( d] S d( ( [ ( d] ( d ( Su of Ifiite Tes S Pctice Pobles. The su if i i upto 00 tes whee i = is ( 50( i 5i (c 5 ( + i 00 ( i [Aswes ( ] C5 Hoic Pogessio A sequece is sid to be Hoic Pogessio (H.P. if the ecipocls of its tes e i Aithetic Pogessio (A.P. If... e i H.P. the. th te of this H.P. fo stt... e i A.P. T (. th te of this H.P. fo ed ( ( T ( ( (. th te of H.P.fo stt th te of H.P.fo lst i.e. T T Pctice Pobles fist te lst te. Show tht the sequece... is H.P. Also fid its 0th te Show tht is H.P. Fid its 8th te d th te.. The 8th d 4th te of H.P. e d espectively. Fid its 0th te. Also fid its geel te. Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

6 MSS 6 4. Which te of the H.P. 7...is 0? 5. If 0th te of H.P. is d 0th te is 7. Fid its lgest te. 6. If th te of H.P. is d th te is the pove tht its th te is. 7. The th te of H.P. is d the th te is. Pove tht its th te is. 8. If ( + th te of H.P. is twice the ( + th te pove tht its ( + + th te is twice the ( + th te. q p p q 9. If pth qth d th te of H.P. e b c espectively pove tht 0. b c 0. If > b > c > e i G.P. the show tht log log b log c e e e e i H.P. b c d c d d b b c. If b c d e i H.P. the pove tht e i H.P. b c d. Thee ubes fo H.P. The su of the ubes is d the su of thei ecipocls is. Fid the ubes.. If... e i HP. Pove tht = ( 4. Fid the lgest positive te of the H.P. whose fist two tes e d 5 x y z 5. If d p q be i A.P. the pove tht x y z e i H.P. px qy z 6. Let b c be thee distict el ube i A.P. such tht < b < d c <. If 0 0 x y b z c the pove tht x y z e i H.P. 0. [Aswes ( /8 ( 4 0 ( 6 (4 st te (5 ( 6 o 6 (4 6] 4 4 Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

7 MSS 7 C6A Aithetic Me Geoetic Me d Hoic Me Aithtic Me Geoetic Me Hoic Me Defiitio If thee tes i A.P. the the iddle te is clled the Aithetic e (A.M. betwee the othe two. e.g. If b c e i A.P. the b is ithetic e of d c If thee tes e i G.P. the iddle te is clled the Geoetic e (G.M. betwee the othe two. e.g. If b c e i G.P. the b is geoetic e of d c If thee tes e i H.P. the iddle te is clled the Hoic e (H.M. betwee the othe two. e.g. If b c e i H.P. the b is hoic e of d c Sigle e of positive ubes A (A = Aithetic e G = (..... / (G = Geoetic e Specil Cse If d b e two give ubes the H i (H = Hoic e i b A G = / b H b e betwee two ubes d b. A A A A A...;A b (b (b (sy G G G G G G b b b...g / / (sy H H H H H...H b ( b (sy ( b ( b ( b ( b Su of ithetic es betwee two give ubes i ties the sigle A.M. betwee the. i.e. su of A.M. = (A.M. Poduct of Geoetic e betwee two give ubes is th powe of the sigle G.M. betwee the. i.e. poduct of G.M. = (oe G.M. The su of ecipocls of Hoic es betwee two give ubes is ties the ecipocl of sigle H.M. betwee the. Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

8 C6B Popeties of A.M. G.M. d H.M.. If A G d H be ithetic d geoetic es of two ubes d b. The G = AH. The equtio hvig d b s its oot is witte i the fo x Ax + G = 0.. Applictio to the questios of Iequlities I geel A.M. G.M. H.M. 4. Applictio to questios of Mxi d Mii MSS 8 The ithetic e of positive ubes which e ot ll equl to oe othe is gete th thei geoetic e. I the theoe the iequlities becoe equlities whe ll the ubes e equl. We dw the followig coclustios Suppose tht x y z...w e positive vibles d tht c is costt the. If x + y + z w = c the vlue of xyz...w is getest whe x = y =...= w = c/ so tht the getest vlue of xyz...w is (c/.. If xyz...w = c the vlue of x + y +... w is tlest whe x = y =... = w so thtthe lst vlue of x + y w is c /. Applictios. Fid the getest vlue of xyz fo positive vlues of x y z subject to the coditio yz + zx + xy =. Sice yz + zx + xy = the vlue of (yz (zx (xy is getest whe yz = zx = xy tht is whe x = y = z =. Hece the getest vlue of (yz (zx (xy is 6 d the getest vlue xyz is 8.. If the su of the sides of tigle is give pove tht the e is getest whe the tigle is equiltel. Let b c be the sides of the tigle d let + b + c = s. If is the e the Now = s(s (s b (s c. (s + (s b + (s c = s = costt Hece the vlue of (s (s b (s c is getest whe s = s b = s c Theefoe the vlue of is getest whe = b = c.. Fid the lest vlue of x + 4y fo positive vlues of x d y subject to the coditio x y = 6. Sice x y = 6 if µ e y costts we hve (x (x (µy (µy (µy = 6 µ. Theefoe x + x + µy + µy + µy is lest whe x = µy = (6 µ /5. Hece the lest vlue of x + µy is 5(6 µ /5. Puttig = d µ = 4 it follows tht the lest vlue of x + 4y is Pctice Pobles. If A A ; G G d H H e two ithetic geoetic d hoic es espectively betwee two qutities d b pove tht 4 5 (i GG H H A A (ii A H H H = A H = G G = b. If 9 hoic es be iseted betwee d pove tht A + H 6 = 5 whee A is y of the A.M s d H the coespodig H.M.. If A be the A.M. d H the H.M. betwee two ubes d b the show tht A b A H b H A. H Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

9 MSS 9 4. ithetic es hve bee iseted betwee d i such wy tht the tio of the 7th d the ( th es is 5 9. Fid the vlue of. 5. If G be the geoetic e betwee two give ubes d A A be the two ithetic e betwee the pove tht G = (A A (A A. [Aswes (4 = 4] C7 Miscelleous ppoch of sutio. Method Wokig Rule fo Sutio of Seies Fid the th te of the seies. Siplify the th tes. Now evlute S t with the help of. (. Method of diffeeces ( ( 6 d ( If the diffeece of the successive tes of sequece is i A.P. o G.P. we fid the th te of this sequece by ethod of diffeece which is give s follows S = t + t + t t...( S = t + t t + t...( Fo ( (; 0 = t + (t t + (t t (t t t t = t + (t t + (t t (t t So. V Method S t To fid the su of the seies of the fos (i (ii whee......e i A.P. Solutio of fo (i Let d be the coo diffeece of A.P. the = + ( d Let su of the seies d th te e deoted by S d T espectively. The S T...(... Let V {levig fist fcto fo D to T }...(... Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

10 MSS 0 So V V V V V V V = T ( + {fo (} = T {[ + ( d] [ + ( + d]} = d( T (V V d( T d( o T {V V } Puttig = 4... we get (V d( T 0 (V d( V T (V d( V T T Addig the bove equtios we get (V d( V V ( d T + T + T T = (V V 0 S ( d... Hece the su of tes is... ( ( Usig the bove pove the followig S Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

11 MSS (i ( (ii ( ( 4 ( ( Solutio of Fo (ii Let S be the su d T be the th te of the seies the S = T = ( Let V = ( (Tkig oe ext fcto i T fo V V = V V = ( + = T ([ + ( + d] [ + ( d] = ( + d T ( d T (V V Puttig =... we get (V ( d T 0 (V ( d V T V T (V V ( d T (V V ( d Addig the bove equtios we get T T T...T (V V 0 ( d S ( ( [(... (... ] {Hee = d} Usig the bove pove the followig (i ( + = ( Pctice Pobles. Fid the su upto tes of the seies (. The seies of tul ubes is divided ito goups s follows {} ; { 4} ; { }... so o. Show tht the su of the ubes i the th goup is ( +.. Su up the seies to tes. Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

12 4. Fid the su of the followig seies to tes MSS ( totes (c (x + y + (x + xy + y + (x + x y + xy + y Fid the su of tes of the seies [Aswes (. S = ( (4 (. ( 9. 4 ( 5 x ( x (c. (x y ( x y ( y y 6 (5. ] Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

13 MSS SINGLE CORRECT CHOICE TYPE. If x + bx + cx + d is divisible by x + c the b c d e i ( A.P. G.P. (c H.P. oe of these. If ( + th ( + th d ( + th tes of AP e i GP; d e i HP the the tio of the fist te d coo diffeece of this AP is ( / / (c / /. If b c d d p e distict o-zeo el ubes such tht ( + b + c p (b + bc + cdp + (b + c + d 0. The b c d e i ( A.P. G.P. (c H.P. oe 4. If b c d e f e i A.P. the e c is equl to ( (c (d c (c (f (d c 5. Let S S... be sques such tht fo ech the legth of side of S equls the legth of digol of S +. If the legth of side of S is 0 c the fo which of the followig vlues of is the e of S less th sq. c ( 8 9 (c 0 ll 6. Choose the coect stteet fo the followig ( (c thee cot be A.P. whose tes e distict pie ubes. 0 cot be the tes of G.P. 5 cot be tes of sigle A.P. ll e coect 7. If x y d z e positive el ubes diffeet fo d x 8 = y = z 8 the log y x log z y 7log x z e i ( A.P. G.P. (c H.P. oe 8. If the sides of ight gled tigle e i G.P. the cosie of the gete cute gle is ( The thee seccessive tes of G.P. will fo the sides of tigle if the coo tio stisfies the iequlity ( (c oe 0. A sque of side legth is give A secod sque is de by joiig the iddle poits of the sides of the st sque d the d sque is de by joiig the iddle poits of the sides of the d sque. This pocess is epeted idefiitely. The e of the su of the es of ll the sques is ( (c 4. If b c be distict positive ubes i G.P. d log c log b c log b be i A.P. the coo diffeece of the pogessio is ( (c 5 oe. If + b + c = d > 0 b > 0 d c > 0 the getest vlue of b c is 0. ( (c oe. If log x y log z x log y z e i G.P. xyz = 64 d x y z e i A.P. the the vlue of y is ( 4 (c (c 5 5 Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

14 4. The su of tes of the seies 5 ( (c 5 5. If... upto... 7 of... to is 4 ( (c the the vlue 6. If is oot of the equtio x 0x + 64 = 0 d 0 4 ( cos cos cos cos...to e log e 4 the ube of solutio of betwee 0 to is ( (c If 0 the c b c b (i (ii ( (c b c e i H.P. b c e i A.P. both e coect oly (i is coect oly (ii is coect both e icoect 8. The coefficiet of x 98 i the cotiued poduct (x + (x + (x +... (x + 00 is ( (c oe 9. If b c e i HP the the vlue of MSS 4 ( (c 4 b b c is b b c 0. If oe ithetic e A d two geoetic es p d q be iseted betwee two give qutities the the vlue of ( (c A A 4 p q is q p A A. If log x + log y 6 the the sllest possibel vlue of x + y is ( 8 (c 6 0. If b c e positive fctios d + b + c = the the xiu vlue of is. b c ( 6 (c A A A... e poits i the fist qudt o the pbol y = 4x. If the x-coodites of the poits be i HP the fist two beig y-coodite of the poit A is is ( (c 4 4. If ( k k the the. The vlue of = 4 + b + c + d + e the d 6 (c e = 0 ll the bove 5. The oots of equtio x + ( x + 9 = 0 lie betwee 6 d d h h...h 0 [] e i H.P. whee [] deotes the itegl pt of the h h 8 = ( 6 (c 9 Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

15 6. If b c be the pth qth d th tes espectively of A.P. d G.P. both the the poduct of oots of equtio b b c c x bcx + c b c b = 0 is equl to ( (c bc 7. Let =... (55 digits b = c = the ( = b + c = bc (c b = c c = b 8. If pth qth d th te of G.P. be 7 8 d espectively the the equtio px + qx = 0 hs ( oly oe oot i (0 o oot i (0 (c both oots i (0 igiy oots 9. ABC is ight-gled tigle i which B = 90 0 d BC =. If poits L L...L o AB e such tht AB is divided i + equl pts d L M L M...L M e lie seget pllel to BC d M M...M e o AC the the vlue of of L M + L M L M is ( (c ( ( ipossible to fid fo the give dt 0. If b c be i G.P. whee s b c c b e i b c H.P. the the vlue of is ½ (c ( (c. If b c e i H.P.; b c d e i G.P. d c d e e i A.P. the the vlue of e i tes of d b is MSS 5. If S deotes the su of ifiity d S the su of thes of the seies.... such 4 8 tht S S < 000 the the lest vlue of ( 0 (c. If b c e i A.P; e i H.P. d b c e i G.P. (coo tio is ot equl to the b c is ( (c 4. If ithetic es... e iseted betwee 50 d 00 d hoic es h h..h e iseted betwee the se two ubes the h is equl to ( 500 (c Suppose b c e thee positive el ubes i A.P. such tht bc = 4. The iiu vlue of b is ( ( 4 ( (c ( 6 oe b ( ( b b (c ( b b ( b b ( b Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

16 MSS 6 EXCERCISE BASED ON NEW PATTERN COMPREHENSION TYPE Copehesio- Let x & x be the oots of the equtio x x + A = 0 d let x & x 4 be the oots of the equtio x x + B = 0. It is kow tht the ubes x x x x 4 (i the se ode fo icesig G.P.. The coo tio of G.P. is ( ± ± (c ± ±. The vlue of A is ( 8 (c 6. The vlue of B is ( ( 8 (c 6 Copehesio- If A G H e the ithetic geoetic d hoic es of two positive el ubes d b d if A = k H 4. Which of the followig eltio is coect ( A = kg A = kg (c G = k A G = k A 5. If the tio of to b will exists the choose the possible vlue of k is ( (c 6. Fo k = the vlue of b is ( (c 4 Copehesio- Weighted Mes Let... be positive el ubes d... be positive tiol ubes. The we defie weighted Aithetic Me (A * weighted Geoetic Me (G* d weighted Hoic e (H + s A G * * (... (.. d H * Aithetic Me of th powe Let... be positive el ubes (ot ll equl d let be el ube. The... if R [0 ]. Howeve if (0 the... Obviously if {0 } the Which of the followig is coect? ( A* G* H* A* H* G* (c H* G* A* G* A* H* 8. If b c e positive el ubes such tht + b + c = 8 the the xiu vlue of b c 4 is ( 7.. (c If b c e positive el ubes tht + b + c = the the iiu vlue of ( (c MATRIX-MATCH TYPE Mtchig- Colu - A b c b c c b Colu - B (A If b c e i G.P. d (P / b c b c e i H.P. the the vlue of + 4b + c (B If the pth qth d th (Q 0 tes of H.P. e b d c espectively the the vlue of b(p q + bc(q + c( p is is Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

17 (C If b c be distict (R 5/ positive ube i G.P. d log c log b c log b be i A.P. the coo diffeece of the pogessio is (D A sque is dw by (S joiig the id-poit of the sides of give sque. A thid sque is dw iside the secod sque i the se wy d this pocess cotiues idefiitely. If side of the fist sque is 4 c deteie the su of the es of ll the sques Mtchig- (T 64 Let A A A...A be ithetic es betwee d 07 d G G G...G be geoetic es betwee d 04. Poduct of geoetic es is 45 d su of ithetic es is 05 7 Colu - A Colu-B (A The vlue of is (P 6 (B The vlue of is (Q 0 (C The vlue of G i is (R 4 i (D The coo diffeece (S 9 of the pogessio A A A 5...A is (T oe MULTIPLE CORRECT CHOICE TYPE. If log y x log z y 5log x z e i A.P. the ( z = x x = y (c z = y x = y = z. If b c e i H.P. the the vlue of b c c ( bc b 4 c is b c MSS 7. If b b b (b > 0 e thee successive tes of G.P. with coo tio the vlue of fo which the iequlity b > 4b b holds is give by ( > < (c =.5 = If log x x/ d log b x e i G.P. the x is equl to ( log (log b log (log e log (log e b (c log (log b log (log e b log (log e 5. Let x b be i AP; y b be i GP d z b be i HP. If x = y + d = 5z the ( y = xz x > y > z (c = 9 b = = /4 b = 9/4 6. Thee positive ubes fo GP. If the iddle ube is icesed by 8 the thee ubes fo AP. If the lst ube is lso icesed by 64 log with the pevious icese i the iddle ube the esultig ube fo GP gi. The ( coo tio = fist ube = 4/9 (c coo tio = 5 fist ube = 4 7. If x y z e positive ubes i AP the ( (c y xz y xz x y y z y x y z vlue x y y z 4 y x y z hs the iiu 8. Fo the A.P. give by......the equtios stisfied e ( + + = 0 + = 0 (c + 4 = = 0 9. If the fist & the ( + th tes of A.P. G.P. & H.P. of positive tes e equl d thei ( + th tes e b & c espectively the ( = b = c b c (c + c = b c = b (c b b oe of these Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

18 0. Betwee two uequl ubes if e two AMs; g g e two GMs d h h e two HMs the g. g is equl to ( h h (c h h Assetio-Reso Type Ech questio cotis STATEMENT- (Assetio d STATEMENT- (Reso. Ech questio hs 4 choices (A (B (C d (D out of which ONLY ONE is coect. (A (B (C (D Stteet- is Tue Stteet- is Tue; Stteet- is coect expltio fo Stteet- Stteet- is Tue Stteet- is Tue; Stteet- is NOT coect expltio fo Stteet-.... e i A.P. Stteet- is Tue Stteet- is Flse Stteet- is Flse Stteet- is Tue STATEMENT- MSS 8. b c e thee uequl positive ubes. STATEMENT- The poduct of thei su d the su of thei ecipocl exceeds 9. STATEMENT- AM of positive ubes exceeds thei HM. 4. STATEMENT- If thee positive ubes i G.P. epeset sides of tigle the the coo tio of the G.P. ust lie betwee 5. 5 d STATEMENT- Thee positive el ubes c fo tigle if su of y two is gete th the thid. 5. STATEMENT- If the su of tes of A.P. is give by S = + b + c whee b c e idepedet of the = 0. STATEMENT- The coo diffeece of A.P. ust be b STATEMENT- + = + + fo.. STATEMENT ( > N. STATEMENT- The su of the fist tul ubes is equl to. (Aswes EXCERCISE BASED ON NEW PATTERN COMPREHENSION TYPE... d d d 9. c MATRIX-MATCH TYPE. [A-Q; B-Q; C-P; D-S]. [A-S; B-R C-Q D-P] MULTIPLE CORRECT CHOICE TYPE. b c d. b c. b c d 4. b 5. c 6. d 7. d 8. b d 9. b d 0. b d ASSERTION-REASON TYPE. A. D. A 4. A 5. C Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

19 MSS 9 INITIAL STEP EXERCISE (SUBJECTIVE. The su of sques of thee distict el ubes which e i G.P. is S. If thei su is S show tht (.. If exp {(si x + si 4 x + si 6 x log e } stisfy the equtio x 9x + 8 = 0 fid the vlue of. Show tht cos x fo 0 x cos x si x x 4 x x x is equl to x x. 4. Fid the su of tes of the seies log log log b b 5 log b A A.P. d G.P. ech hs s the fist te d b s the secod te (0 < b <. If S deotes the su of ifiity of the G.P. pove tht the su of fist tes of the A.P. c be witte s ( s. 6. If P is fist of ( > ithetic es betwee two positive ubes d q the fist of hoic es betwee the se two ubes show tht q cot lie betwee P d P. 7. If... e i A.P. ofc o o diffeece d the pove tht sec sec + sec sec +... tes t t si d 8. Pove tht the su to tes of the seies...is. 9. Suppose x & y e two el ubes such tht the th e betwee x & y is equl to the th e betwee x & y whe ithetic es e iseted betwee the i both the cses. Show tht y x 0. If b c e thee distict el ubes i G.P. d + b + c = xb the pove tht eithe x < o x >.. Fid ll the ubes x d y such tht x x + y x + y fo A.P. while the ubes (y + xy + 5 (x + fo G.P.. Fid out the lgest te of the sequece A A.P. G.P. d H.P. hve the se fist d the se ( th tes. If thei th tes e b c espectively the show tht b c fo G.P The vlue of xyz is 55 o ccodig s the 55 seies x y z b is A.P. o H.P. Fid the vlues of d b give tht they e positive iteges. 5. If < & b < the pove tht su upto of the seies ( + b + ( + b + ( + b +...is b. b 6. Fid the tul ube fo which k f ( k 6( whee the fuctio f stisfies the eltio f(x + y = f(x. f(y fo ll tul ubes x y d futhe f( =. 7. The vlue of the expessio.( ( + ( ( ( ( ( =. Fid give tht = d + + = If is oot of equtio x ( c x( + c ( + c = 0 d if H.M. s e iseted betwee d c show tht the diffeece betwee the fist d the lst e is equl to c( c. Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

20 MSS 0 FINAL STEP EXERCISE (SUBJECTIVE. Pove tht the su of ll poducts of fist positive ubes ie iteges tke two t tie is ( ( ( + ( + i.e. pove tht 4 i i j ( ( ( + ( +. ji 4. Let S deote the su of fist tes of the seies & deotes su of fist tes of the seies Thepove tht 8 S S + = 0.. If... e i ithetic pogessio with coo diffeece d the pove tht s ( s ( 7 d. ( d 4. If S S d S deote the sus upto (> tes of thee sequeces i A.P. whose fist tes e uity d coo diffeeces e i H.P. pove tht SS SS SS S S S 4 5. Show tht ( ( (...(.( (. 6. If A A A... A e ithetic es betwee x & y d H H...H e hoic es betwee x & y show tht A H + = xy fo. 7. If H H H...H e hoic es betwee d b the show tht H H H H b b 8. Let d be two distict positive oots of x x + b = 0 d b b S the show tht S b If b c e i H.P. the pove tht b c b 4. b c b 0. The fist thee tes of geoetic pogessio e give such tht if fou substcted fo the thid te the these ubes becoes the fist thee tes of ithetic pogessio. If we subtct uity fo the secod te d five fo the thid te of the give geoetic pogessio we get the ubes x y z such tht log z ;log z d (x (y fo hooic pogessio. Obti expessio fo the su of fist tes of the G.P. d the A.P. Hece show tht the su of fist two te of G.P. is equl to tht of the A.P.. If > b > 0 show tht fo evey positive itege. Pove tht b b... b b b... b (666...to digits + (888...to digits = ( to digits.. > 0 b > 0 e the fist te of the two G.P. s with coo tio x d y espectively whee x > y > 0. Pove tht the tio of the su of ( + tes to tht of tes of the fist G.P. is gete th the tio of the su of ( + tes to tht of tes of the secod G.P. 4. If b c e positive el ubes pove tht b c b c c c b b b c. 5. If b c d e f e i G.P. the pove tht x 5 + bx 4 + cx + dx + cx + f is divisible by x 4 + cx + e. Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

21 MSS ANSWERS (SINGLE CORRECT CHOICE TYPE. b. c. c.. b. c. c. b. b. b. b. b 4. b 4. d 4. d 4. c 5. d 5. b 5. b d b b 8. b b 9. c 0. b 0. d 0. d ANSWERS SUBJECTIVE (INITIAL STEP EXERCISE.. ( ( 4. log logb. y = x =. 4. = b = 7; = 7 b = 6. = 7. ( ( 8. ifiite ANSWERS SUBJECTIVE (FINAL STEP EXERCISE 0. su of fist tes of G.P. = ( (7 o 54 su of fist tes of A.P. = ( o 9 Eistei Clsses Uit No. 0 0 Vdh Rig Rod Plz Viks Pui Ext. Oute Rig Rod New Delhi 0 08 Ph

PROGRESSION AND SERIES

PROGRESSION AND SERIES INTRODUCTION PROGRESSION AND SERIES A gemet of umbes {,,,,, } ccodig to some well defied ule o set of ules is clled sequece Moe pecisely, we my defie sequece s fuctio whose domi is some subset of set of

More information

PLANCESS RANK ACCELERATOR

PLANCESS RANK ACCELERATOR PLANCESS RANK ACCELERATOR MATHEMATICS FOR JEE MAIN & ADVANCED Sequeces d Seies 000questios with topic wise execises 000 polems of IIT-JEE & AIEEE exms of lst yes Levels of Execises ctegoized ito JEE Mi

More information

BINOMIAL THEOREM SOLUTION. 1. (D) n. = (C 0 + C 1 x +C 2 x C n x n ) (1+ x+ x 2 +.)

BINOMIAL THEOREM SOLUTION. 1. (D) n. = (C 0 + C 1 x +C 2 x C n x n ) (1+ x+ x 2 +.) BINOMIAL THEOREM SOLUTION. (D) ( + + +... + ) (+ + +.) The coefficiet of + + + +... + fo. Moeove coefficiet of is + + + +... + if >. So. (B)... e!!!! The equied coefficiet coefficiet of i e -.!...!. (A),

More information

LEVEL I. ,... if it is known that a 1

LEVEL I. ,... if it is known that a 1 LEVEL I Fid the sum of first terms of the AP, if it is kow tht + 5 + 0 + 5 + 0 + = 5 The iterior gles of polygo re i rithmetic progressio The smllest gle is 0 d the commo differece is 5 Fid the umber of

More information

EXERCISE a a a 5. + a 15 NEETIIT.COM

EXERCISE a a a 5. + a 15 NEETIIT.COM - Dowlod our droid App. Sigle choice Type Questios EXERCISE -. The first term of A.P. of cosecutive iteger is p +. The sum of (p + ) terms of this series c be expressed s () (p + ) () (p + ) (p + ) ()

More information

Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., Outer Ring Road New Delhi , Ph. : ,

Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., Outer Ring Road New Delhi , Ph. : , MB BINOMIAL THEOREM Biomial Epessio : A algebaic epessio which cotais two dissimila tems is called biomial epessio Fo eample :,,, etc / ( ) Statemet of Biomial theoem : If, R ad N, the : ( + ) = a b +

More information

Progression. CATsyllabus.com. CATsyllabus.com. Sequence & Series. Arithmetic Progression (A.P.) n th term of an A.P.

Progression. CATsyllabus.com. CATsyllabus.com. Sequence & Series. Arithmetic Progression (A.P.) n th term of an A.P. Pogessio Sequece & Seies A set of umbes whose domai is a eal umbe is called a SEQUENCE ad sum of the sequece is called a SERIES. If a, a, a, a 4,., a, is a sequece, the the expessio a + a + a + a 4 + a

More information

PROGRESSIONS AND SERIES

PROGRESSIONS AND SERIES PROGRESSIONS AND SERIES A sequece is lso clled progressio. We ow study three importt types of sequeces: () The Arithmetic Progressio, () The Geometric Progressio, () The Hrmoic Progressio. Arithmetic Progressio.

More information

Lesson-2 PROGRESSIONS AND SERIES

Lesson-2 PROGRESSIONS AND SERIES Lesso- PROGRESSIONS AND SERIES Arithmetic Progressio: A sequece of terms is sid to be i rithmetic progressio (A.P) whe the differece betwee y term d its preceedig term is fixed costt. This costt is clled

More information

ME 501A Seminar in Engineering Analysis Page 1

ME 501A Seminar in Engineering Analysis Page 1 Fobeius ethod pplied to Bessel s Equtio Octobe, 7 Fobeius ethod pplied to Bessel s Equtio L Cetto Mechicl Egieeig 5B Sei i Egieeig lsis Octobe, 7 Outlie Review idte Review lst lectue Powe seies solutios/fobeius

More information

«A first lesson on Mathematical Induction»

«A first lesson on Mathematical Induction» Bcgou ifotio: «A fist lesso o Mtheticl Iuctio» Mtheticl iuctio is topic i H level Mthetics It is useful i Mtheticl copetitios t ll levels It hs bee coo sight tht stuets c out the poof b theticl iuctio,

More information

M5. LTI Systems Described by Linear Constant Coefficient Difference Equations

M5. LTI Systems Described by Linear Constant Coefficient Difference Equations 5. LTI Systes Descied y Lie Costt Coefficiet Diffeece Equtios Redig teil: p.34-4, 245-253 3/22/2 I. Discete-Tie Sigls d Systes Up til ow we itoduced the Fouie d -tsfos d thei popeties with oly ief peview

More information

[ 20 ] 1. Inequality exists only between two real numbers (not complex numbers). 2. If a be any real number then one and only one of there hold.

[ 20 ] 1. Inequality exists only between two real numbers (not complex numbers). 2. If a be any real number then one and only one of there hold. [ 0 ]. Iequlity eists oly betwee two rel umbers (ot comple umbers).. If be y rel umber the oe d oly oe of there hold.. If, b 0 the b 0, b 0.. (i) b if b 0 (ii) (iii) (iv) b if b b if either b or b b if

More information

MATH Midterm Solutions

MATH Midterm Solutions MATH 2113 - Midtem Solutios Febuay 18 1. A bag of mables cotais 4 which ae ed, 4 which ae blue ad 4 which ae gee. a How may mables must be chose fom the bag to guaatee that thee ae the same colou? We ca

More information

BINOMIAL THEOREM An expression consisting of two terms, connected by + or sign is called a

BINOMIAL THEOREM An expression consisting of two terms, connected by + or sign is called a BINOMIAL THEOREM hapte 8 8. Oveview: 8.. A epessio cosistig of two tems, coected by + o sig is called a biomial epessio. Fo eample, + a, y,,7 4 5y, etc., ae all biomial epessios. 8.. Biomial theoem If

More information

CHAPTER 5 : SERIES. 5.2 The Sum of a Series Sum of Power of n Positive Integers Sum of Series of Partial Fraction Difference Method

CHAPTER 5 : SERIES. 5.2 The Sum of a Series Sum of Power of n Positive Integers Sum of Series of Partial Fraction Difference Method CHAPTER 5 : SERIES 5.1 Seies 5. The Sum of a Seies 5..1 Sum of Powe of Positive Iteges 5.. Sum of Seies of Patial Factio 5..3 Diffeece Method 5.3 Test of covegece 5.3.1 Divegece Test 5.3. Itegal Test 5.3.3

More information

VERY SHORT ANSWER TYPE QUESTIONS (1 MARK)

VERY SHORT ANSWER TYPE QUESTIONS (1 MARK) VERY SHORT ANSWER TYPE QUESTIONS ( MARK). If th term of a A.P. is 6 7 the write its 50 th term.. If S = +, the write a. Which term of the sequece,, 0, 7,... is 6? 4. If i a A.P. 7 th term is 9 ad 9 th

More information

BINOMIAL THEOREM NCERT An expression consisting of two terms, connected by + or sign is called a

BINOMIAL THEOREM NCERT An expression consisting of two terms, connected by + or sign is called a 8. Oveview: 8.. A epessio cosistig of two tems, coected by + o sig is called a biomial epessio. Fo eample, + a, y,,7 4, etc., ae all biomial 5y epessios. 8.. Biomial theoem BINOMIAL THEOREM If a ad b ae

More information

UNIT V: Z-TRANSFORMS AND DIFFERENCE EQUATIONS. Dr. V. Valliammal Department of Applied Mathematics Sri Venkateswara College of Engineering

UNIT V: Z-TRANSFORMS AND DIFFERENCE EQUATIONS. Dr. V. Valliammal Department of Applied Mathematics Sri Venkateswara College of Engineering UNIT V: -TRANSFORMS AND DIFFERENCE EQUATIONS D. V. Vllimml Deptmet of Applied Mthemtics Si Vektesw College of Egieeig TOPICS:. -Tsfoms Elemet popeties.. Ivese -Tsfom usig ptil fctios d esidues. Covolutio

More information

EXERCISE - 01 CHECK YOUR GRASP

EXERCISE - 01 CHECK YOUR GRASP EXERISE - 0 HEK YOUR GRASP 3. ( + Fo sum of coefficiets put ( + 4 ( + Fo sum of coefficiets put ; ( + ( 4. Give epessio c e ewitte s 7 4 7 7 3 7 7 ( 4 3( 4... 7( 4 7 7 7 3 ( 4... 7( 4 Lst tem ecomes (4

More information

Auchmuty High School Mathematics Department Sequences & Series Notes Teacher Version

Auchmuty High School Mathematics Department Sequences & Series Notes Teacher Version equeces ad eies Auchmuty High chool Mathematics Depatmet equeces & eies Notes Teache Vesio A sequece takes the fom,,7,0,, while 7 0 is a seies. Thee ae two types of sequece/seies aithmetic ad geometic.

More information

On the k-lucas Numbers of Arithmetic Indexes

On the k-lucas Numbers of Arithmetic Indexes Alied Mthetics 0 3 0-06 htt://d.doi.og/0.436/.0.307 Published Olie Octobe 0 (htt://www.scirp.og/oul/) O the -ucs Nubes of Aithetic Idees Segio lco Detet of Mthetics d Istitute fo Alied Micoelectoics (IUMA)

More information

For this purpose, we need the following result:

For this purpose, we need the following result: 9 Lectue Sigulities of omplex Fuctio A poit is clled sigulity of fuctio f ( z ) if f ( z ) is ot lytic t the poit. A sigulity is clled isolted sigulity of f ( z ), if f ( z ) is lytic i some puctued disk

More information

2002 Quarter 1 Math 172 Final Exam. Review

2002 Quarter 1 Math 172 Final Exam. Review 00 Qute Mth 7 Fil Exm. Review Sectio.. Sets Repesettio of Sets:. Listig the elemets. Set-uilde Nottio Checkig fo Memeship (, ) Compiso of Sets: Equlity (=, ), Susets (, ) Uio ( ) d Itesectio ( ) of Sets

More information

jfpr% ekuo /kez iz.ksrk ln~xq# Jh j.knksm+nklth egkjkt ( )( ) n n + 1 b c d e a a b c d e = + a + b c

jfpr% ekuo /kez iz.ksrk ln~xq# Jh j.knksm+nklth egkjkt ( )( ) n n + 1 b c d e a a b c d e = + a + b c Dwld FREE Study Pckge fm www.tekclsses.cm & Le Vide www.mthsbysuhg.cm Phe : 0 90 90 7779, 9890 888 WhtsApp 9009 60 9 SEQUENCE & SERIES PART OF f/u fpkj Hkh# tu] ugh vkjehks dke] fif s[k NksMs qj e/;e eu

More information

THEORY OF EQUATIONS SYNOPSIS. Polyomil Fuctio: If,, re rel d is positive iteger, the f)x) = + x + x +.. + x is clled polyomil fuctio.. Degree of the Polyomil: The highest power of x for which the coefficiet

More information

a= x+1=4 Q. No. 2 Let T r be the r th term of an A.P., for r = 1,2,3,. If for some positive integers m, n. we 1 1 Option 2 1 1

a= x+1=4 Q. No. 2 Let T r be the r th term of an A.P., for r = 1,2,3,. If for some positive integers m, n. we 1 1 Option 2 1 1 Q. No. th term of the sequece, + d, + d,.. is Optio + d Optio + (- ) d Optio + ( + ) d Optio Noe of these Correct Aswer Expltio t =, c.d. = d t = + (h- )d optio (b) Q. No. Let T r be the r th term of A.P.,

More information

We show that every analytic function can be expanded into a power series, called the Taylor series of the function.

We show that every analytic function can be expanded into a power series, called the Taylor series of the function. 10 Lectue 8 We show tht evey lytic fuctio c be expded ito powe seies, clled the Tylo seies of the fuctio. Tylo s Theoem: Let f be lytic i domi D & D. The, f(z) c be expessed s the powe seies f( z) b (

More information

EXERCISE - 01 CHECK YOUR GRASP

EXERCISE - 01 CHECK YOUR GRASP J-Mathematics XRCIS - 0 CHCK YOUR GRASP SLCT TH CORRCT ALTRNATIV (ONLY ON CORRCT ANSWR). The maximum value of the sum of the A.P. 0, 8, 6,,... is - 68 60 6. Let T r be the r th term of a A.P. for r =,,,...

More information

Greatest term (numerically) in the expansion of (1 + x) Method 1 Let T

Greatest term (numerically) in the expansion of (1 + x) Method 1 Let T BINOMIAL THEOREM_SYNOPSIS Geatest tem (umeically) i the epasio of ( + ) Method Let T ( The th tem) be the geatest tem. Fid T, T, T fom the give epasio. Put T T T ad. Th will give a iequality fom whee value

More information

Q.11 If S be the sum, P the product & R the sum of the reciprocals of a GP, find the value of

Q.11 If S be the sum, P the product & R the sum of the reciprocals of a GP, find the value of Brai Teasures Progressio ad Series By Abhijit kumar Jha EXERCISE I Q If the 0th term of a HP is & st term of the same HP is 0, the fid the 0 th term Q ( ) Show that l (4 36 08 up to terms) = l + l 3 Q3

More information

Semiconductors materials

Semiconductors materials Semicoductos mteils Elemetl: Goup IV, Si, Ge Biy compouds: III-V (GAs,GSb, ISb, IP,...) IV-VI (PbS, PbSe, PbTe,...) II-VI (CdSe, CdTe,...) Tey d Qutey compouds: G x Al -x As, G x Al -x As y P -y III IV

More information

POWER SERIES R. E. SHOWALTER

POWER SERIES R. E. SHOWALTER POWER SERIES R. E. SHOWALTER. sequeces We deote by lim = tht the limit of the sequece { } is the umber. By this we me tht for y ε > 0 there is iteger N such tht < ε for ll itegers N. This mkes precise

More information

INFINITE SERIES. ,... having infinite number of terms is called infinite sequence and its indicated sum, i.e., a 1

INFINITE SERIES. ,... having infinite number of terms is called infinite sequence and its indicated sum, i.e., a 1 Appedix A.. Itroductio As discussed i the Chpter 9 o Sequeces d Series, sequece,,...,,... hvig ifiite umber of terms is clled ifiite sequece d its idicted sum, i.e., + + +... + +... is clled ifite series

More information

( ) ( ) ( ) ( ) Solved Examples. JEE Main/Boards = The total number of terms in the expansion are 8.

( ) ( ) ( ) ( ) Solved Examples. JEE Main/Boards = The total number of terms in the expansion are 8. Mathematics. Solved Eamples JEE Mai/Boads Eample : Fid the coefficiet of y i c y y Sol: By usig fomula of fidig geeal tem we ca easily get coefficiet of y. I the biomial epasio, ( ) th tem is c T ( y )

More information

CHAPTER - 9 SEQUENCES AND SERIES KEY POINTS A sequece is a fuctio whose domai is the set N of atural umbers. A sequece whose rage is a subset of R is called a real sequece. Geeral A.P. is, a, a + d, a

More information

Chapter 2 Infinite Series Page 1 of 9

Chapter 2 Infinite Series Page 1 of 9 Chpter Ifiite eries Pge of 9 Chpter : Ifiite eries ectio A Itroductio to Ifiite eries By the ed of this sectio you will be ble to uderstd wht is met by covergece d divergece of ifiite series recogise geometric

More information

x a y n + b = 1 0<b a, n > 0 (1.1) x 1 - a y = b 0<b a, n > 0 (1.1') b n sin 2 + cos 2 = 1 x n = = cos 2 6 Superellipse (Lamé curve)

x a y n + b = 1 0<b a, n > 0 (1.1) x 1 - a y = b 0<b a, n > 0 (1.1') b n sin 2 + cos 2 = 1 x n = = cos 2 6 Superellipse (Lamé curve) 6 Supeellipse (Lmé cuve) 6. Equtios of supeellipse A supeellipse (hoizotlly log) is epessed s follows. Implicit Equtio y + b 0 0 (.) Eplicit Equtio y b - 0 0 (.') Whe 3, b, the supeellipses fo

More information

Objective Mathematics

Objective Mathematics . If sum of '' terms of a sequece is give by S Tr ( )( ), the 4 5 67 r (d) 4 9 r is equal to : T. Let a, b, c be distict o-zero real umbers such that a, b, c are i harmoic progressio ad a, b, c are i arithmetic

More information

THEORY OF EQUATIONS OBJECTIVE PROBLEMS. If the eqution x 6x 0 0 ) - ) 4) -. If the sum of two oots of the eqution k is -48 ) 6 ) 48 4) 4. If the poduct of two oots of 4 ) -4 ) 4) - 4. If one oot of is

More information

SEQUENCE AND SERIES NCERT

SEQUENCE AND SERIES NCERT 9. Overview By a sequece, we mea a arragemet of umbers i a defiite order accordig to some rule. We deote the terms of a sequece by a, a,..., etc., the subscript deotes the positio of the term. I view of

More information

Chapter 7 Infinite Series

Chapter 7 Infinite Series MA Ifiite Series Asst.Prof.Dr.Supree Liswdi Chpter 7 Ifiite Series Sectio 7. Sequece A sequece c be thought of s list of umbers writte i defiite order:,,...,,... 2 The umber is clled the first term, 2

More information

Chapter 5. The Riemann Integral. 5.1 The Riemann integral Partitions and lower and upper integrals. Note: 1.5 lectures

Chapter 5. The Riemann Integral. 5.1 The Riemann integral Partitions and lower and upper integrals. Note: 1.5 lectures Chpter 5 The Riem Itegrl 5.1 The Riem itegrl Note: 1.5 lectures We ow get to the fudmetl cocept of itegrtio. There is ofte cofusio mog studets of clculus betwee itegrl d tiderivtive. The itegrl is (iformlly)

More information

DETERMINANT. = 0. The expression a 1. is called a determinant of the second order, and is denoted by : y + c 1

DETERMINANT. = 0. The expression a 1. is called a determinant of the second order, and is denoted by : y + c 1 NOD6 (\Dt\04\Kot\J-Advced\SMP\Mths\Uit#0\NG\Prt-\0.Determits\0.Theory.p65. INTRODUCTION : If the equtios x + b 0, x + b 0 re stisfied by the sme vlue of x, the b b 0. The expressio b b is clled determit

More information

Linear Programming. Preliminaries

Linear Programming. Preliminaries Lier Progrmmig Prelimiries Optimiztio ethods: 3L Objectives To itroduce lier progrmmig problems (LPP To discuss the stdrd d coicl form of LPP To discuss elemetry opertio for lier set of equtios Optimiztio

More information

ANSWER KEY PHYSICS. Workdone X

ANSWER KEY PHYSICS. Workdone X ANSWER KEY PHYSICS 6 6 6 7 7 7 9 9 9 0 0 0 CHEMISTRY 6 6 6 7 7 7 9 9 9 0 0 60 MATHEMATICS 6 66 7 76 6 6 67 7 77 7 6 6 7 7 6 69 7 79 9 6 70 7 0 90 PHYSICS F L l. l A Y l A ;( A R L L A. W = (/ lod etesio

More information

BINOMIAL THEOREM & ITS SIMPLE APPLICATION

BINOMIAL THEOREM & ITS SIMPLE APPLICATION Etei lasses, Uit No. 0, 0, Vadhma Rig Road Plaza, Vikas Pui Et., Oute Rig Road New Delhi 0 08, Ph. : 9690, 87 MB Sllabus : BINOMIAL THEOREM & ITS SIMPLE APPLIATION Biomia Theoem fo a positive itegal ide;

More information

3sin A 1 2sin B. 3π x is a solution. 1. If A and B are acute positive angles satisfying the equation 3sin A 2sin B 1 and 3sin 2A 2sin 2B 0, then A 2B

3sin A 1 2sin B. 3π x is a solution. 1. If A and B are acute positive angles satisfying the equation 3sin A 2sin B 1 and 3sin 2A 2sin 2B 0, then A 2B 1. If A ad B are acute positive agles satisfyig the equatio 3si A si B 1 ad 3si A si B 0, the A B (a) (b) (c) (d) 6. 3 si A + si B = 1 3si A 1 si B 3 si A = cosb Also 3 si A si B = 0 si B = 3 si A Now,

More information

ALGEBRA. Set of Equations. have no solution 1 b1. Dependent system has infinitely many solutions

ALGEBRA. Set of Equations. have no solution 1 b1. Dependent system has infinitely many solutions Qudrtic Equtios ALGEBRA Remider theorem: If f() is divided b( ), the remider is f(). Fctor theorem: If ( ) is fctor of f(), the f() = 0. Ivolutio d Evlutio ( + b) = + b + b ( b) = + b b ( + b) 3 = 3 +

More information

Objective Mathematics

Objective Mathematics . o o o o {cos 4 cos 9 si cos 65 } si 7º () cos 6º si 8º. If x R oe of these, the mximum vlue of the expressio si x si x.cos x c cos x ( c) is : () c c c c c c. If ( cos )cos cos ; 0, the vlue of 4. The

More information

[ 11 ] z of degree 2 as both degree 2 each. The degree of a polynomial in n variables is the maximum of the degrees of its terms.

[ 11 ] z of degree 2 as both degree 2 each. The degree of a polynomial in n variables is the maximum of the degrees of its terms. [ 11 ] 1 1.1 Polyomial Fuctios 1 Algebra Ay fuctio f ( x) ax a1x... a1x a0 is a polyomial fuctio if ai ( i 0,1,,,..., ) is a costat which belogs to the set of real umbers ad the idices,, 1,...,1 are atural

More information

Remarks: (a) The Dirac delta is the function zero on the domain R {0}.

Remarks: (a) The Dirac delta is the function zero on the domain R {0}. Sectio Objective(s): The Dirc s Delt. Mi Properties. Applictios. The Impulse Respose Fuctio. 4.4.. The Dirc Delt. 4.4. Geerlized Sources Defiitio 4.4.. The Dirc delt geerlized fuctio is the limit δ(t)

More information

EXAMPLES. Leader in CBSE Coaching. Solutions of BINOMIAL THEOREM A.V.T.E. by AVTE (avte.in) Class XI

EXAMPLES. Leader in CBSE Coaching. Solutions of BINOMIAL THEOREM A.V.T.E. by AVTE (avte.in) Class XI avtei EXAMPLES Solutios of AVTE by AVTE (avtei) lass XI Leade i BSE oachig 1 avtei SHORT ANSWER TYPE 1 Fid the th tem i the epasio of 1 We have T 1 1 1 1 1 1 1 1 1 1 Epad the followig (1 + ) 4 Put 1 y

More information

ALGEBRA II CHAPTER 7 NOTES. Name

ALGEBRA II CHAPTER 7 NOTES. Name ALGEBRA II CHAPTER 7 NOTES Ne Algebr II 7. th Roots d Rtiol Expoets Tody I evlutig th roots of rel ubers usig both rdicl d rtiol expoet ottio. I successful tody whe I c evlute th roots. It is iportt for

More information

2.Decision Theory of Dependence

2.Decision Theory of Dependence .Deciio Theoy of Depedece Theoy :I et of vecto if thee i uet which i liely depedet the whole et i liely depedet too. Coolly :If the et i liely idepedet y oepty uet of it i liely idepedet. Theoy : Give

More information

Math 7409 Homework 2 Fall from which we can calculate the cycle index of the action of S 5 on pairs of vertices as

Math 7409 Homework 2 Fall from which we can calculate the cycle index of the action of S 5 on pairs of vertices as Math 7409 Hoewok 2 Fall 2010 1. Eueate the equivalece classes of siple gaphs o 5 vetices by usig the patte ivetoy as a guide. The cycle idex of S 5 actig o 5 vetices is 1 x 5 120 1 10 x 3 1 x 2 15 x 1

More information

= 5! 3! 2! = 5! 3! (5 3)!. In general, the number of different groups of r items out of n items (when the order is ignored) is given by n!

= 5! 3! 2! = 5! 3! (5 3)!. In general, the number of different groups of r items out of n items (when the order is ignored) is given by n! 0 Combiatoial Aalysis Copyight by Deiz Kalı 4 Combiatios Questio 4 What is the diffeece betwee the followig questio i How may 3-lette wods ca you wite usig the lettes A, B, C, D, E ii How may 3-elemet

More information

UNIVERSITY OF BRISTOL. Examination for the Degrees of B.Sc. and M.Sci. (Level C/4) ANALYSIS 1B, SOLUTIONS MATH (Paper Code MATH-10006)

UNIVERSITY OF BRISTOL. Examination for the Degrees of B.Sc. and M.Sci. (Level C/4) ANALYSIS 1B, SOLUTIONS MATH (Paper Code MATH-10006) UNIVERSITY OF BRISTOL Exmitio for the Degrees of B.Sc. d M.Sci. (Level C/4) ANALYSIS B, SOLUTIONS MATH 6 (Pper Code MATH-6) My/Jue 25, hours 3 miutes This pper cotis two sectios, A d B. Plese use seprte

More information

MATRIX ALGEBRA, Systems Linear Equations

MATRIX ALGEBRA, Systems Linear Equations MATRIX ALGEBRA, Systes Lier Equtios Now we chge to the LINEAR ALGEBRA perspective o vectors d trices to reforulte systes of lier equtios. If you fid the discussio i ters of geerl d gets lost i geerlity,

More information

0 otherwise. sin( nx)sin( kx) 0 otherwise. cos( nx) sin( kx) dx 0 for all integers n, k.

0 otherwise. sin( nx)sin( kx) 0 otherwise. cos( nx) sin( kx) dx 0 for all integers n, k. . Computtio of Fourier Series I this sectio, we compute the Fourier coefficiets, f ( x) cos( x) b si( x) d b, i the Fourier series To do this, we eed the followig result o the orthogolity of the trigoometric

More information

[Q. Booklet Number]

[Q. Booklet Number] 6 [Q. Booklet Numer] KOLKATA WB- B-J J E E - 9 MATHEMATICS QUESTIONS & ANSWERS. If C is the reflecto of A (, ) i -is d B is the reflectio of C i y-is, the AB is As : Hits : A (,); C (, ) ; B (, ) y A (,

More information

In an algebraic expression of the form (1), like terms are terms with the same power of the variables (in this case

In an algebraic expression of the form (1), like terms are terms with the same power of the variables (in this case Chpter : Algebr: A. Bckgroud lgebr: A. Like ters: I lgebric expressio of the for: () x b y c z x y o z d x... p x.. we cosider x, y, z to be vribles d, b, c, d,,, o,.. to be costts. I lgebric expressio

More information

Mathematical Induction (selected questions)

Mathematical Induction (selected questions) Mtheticl Iductio (selected questios). () Let P() e the propositio : For P(), L.H.S. R.H.S., P() is true. Assue P() is true for soe turl uer, tht is, () For P( ),, y () By the Priciple of Mtheticl Iductio,

More information

MTH 146 Class 16 Notes

MTH 146 Class 16 Notes MTH 46 Clss 6 Notes 0.4- Cotiued Motivtio: We ow cosider the rc legth of polr curve. Suppose we wish to fid the legth of polr curve curve i terms of prmetric equtios s: r f where b. We c view the cos si

More information

a) The average (mean) of the two fractions is halfway between them: b) The answer is yes. Assume without loss of generality that p < r.

a) The average (mean) of the two fractions is halfway between them: b) The answer is yes. Assume without loss of generality that p < r. Solutios to MAML Olympiad Level 00. Factioated a) The aveage (mea) of the two factios is halfway betwee them: p ps+ q ps+ q + q s qs qs b) The aswe is yes. Assume without loss of geeality that p

More information

Advanced Higher Maths: Formulae

Advanced Higher Maths: Formulae Advced Highe Mths: Fomule Advced Highe Mthemtics Gee (G): Fomule you solutely must memoise i ode to pss Advced Highe mths. Rememe you get o fomul sheet t ll i the em! Ame (A): You do t hve to memoise these

More information

1. (25 points) Use the limit definition of the definite integral and the sum formulas to compute. [1 x + x2

1. (25 points) Use the limit definition of the definite integral and the sum formulas to compute. [1 x + x2 Mth 3, Clculus II Fil Exm Solutios. (5 poits) Use the limit defiitio of the defiite itegrl d the sum formuls to compute 3 x + x. Check your swer by usig the Fudmetl Theorem of Clculus. Solutio: The limit

More information

Summary: Binomial Expansion...! r. where

Summary: Binomial Expansion...! r. where Summy: Biomil Epsio 009 M Teo www.techmejcmth-sg.wes.com ) Re-cp of Additiol Mthemtics Biomil Theoem... whee )!!(! () The fomul is ville i MF so studets do ot eed to memoise it. () The fomul pplies oly

More information

The Definite Integral

The Definite Integral The Defiite Itegrl A Riem sum R S (f) is pproximtio to the re uder fuctio f. The true re uder the fuctio is obtied by tkig the it of better d better pproximtios to the re uder f. Here is the forml defiitio,

More information

Review of the Riemann Integral

Review of the Riemann Integral Chpter 1 Review of the Riem Itegrl This chpter provides quick review of the bsic properties of the Riem itegrl. 1.0 Itegrls d Riem Sums Defiitio 1.0.1. Let [, b] be fiite, closed itervl. A prtitio P of

More information

F x = 2x λy 2 z 3 = 0 (1) F y = 2y λ2xyz 3 = 0 (2) F z = 2z λ3xy 2 z 2 = 0 (3) F λ = (xy 2 z 3 2) = 0. (4) 2z 3xy 2 z 2. 2x y 2 z 3 = 2y 2xyz 3 = ) 2

F x = 2x λy 2 z 3 = 0 (1) F y = 2y λ2xyz 3 = 0 (2) F z = 2z λ3xy 2 z 2 = 0 (3) F λ = (xy 2 z 3 2) = 0. (4) 2z 3xy 2 z 2. 2x y 2 z 3 = 2y 2xyz 3 = ) 2 0 微甲 07- 班期中考解答和評分標準 5%) Fid the poits o the surfce xy z = tht re closest to the origi d lso the shortest distce betwee the surfce d the origi Solutio Cosider the Lgrge fuctio F x, y, z, λ) = x + y + z

More information

BRAIN TEASURES INDEFINITE INTEGRATION+DEFINITE INTEGRATION EXERCISE I

BRAIN TEASURES INDEFINITE INTEGRATION+DEFINITE INTEGRATION EXERCISE I EXERCISE I t Q. d Q. 6 6 cos si Q. Q.6 d d Q. d Q. Itegrte cos t d by the substitutio z = + e d e Q.7 cos. l cos si d d Q. cos si si si si b cos Q.9 d Q. si b cos Q. si( ) si( ) d ( ) Q. d cot d d Q. (si

More information

MAS221 Analysis, Semester 2 Exercises

MAS221 Analysis, Semester 2 Exercises MAS22 Alysis, Semester 2 Exercises Srh Whitehouse (Exercises lbelled * my be more demdig.) Chpter Problems: Revisio Questio () Stte the defiitio of covergece of sequece of rel umbers, ( ), to limit. (b)

More information

Using Difference Equations to Generalize Results for Periodic Nested Radicals

Using Difference Equations to Generalize Results for Periodic Nested Radicals Usig Diffeece Equatios to Geealize Results fo Peiodic Nested Radicals Chis Lyd Uivesity of Rhode Islad, Depatmet of Mathematics South Kigsto, Rhode Islad 2 2 2 2 2 2 2 π = + + +... Vieta (593) 2 2 2 =

More information

Mathacle. PSet Stats, Concepts In Statistics Level Number Name: Date:

Mathacle. PSet Stats, Concepts In Statistics Level Number Name: Date: APPENDEX I. THE RAW ALGEBRA IN STATISTICS A I-1. THE INEQUALITY Exmple A I-1.1. Solve ech iequlity. Write the solutio i the itervl ottio..) 2 p - 6 p -8.) 2x- 3 < 5 Solutio:.). - 4 p -8 p³ 2 or pî[2, +

More information

THE NATIONAL UNIVERSITY OF IRELAND, CORK COLÁISTE NA hollscoile, CORCAIGH UNIVERSITY COLLEGE, CORK SUMMER EXAMINATION 2005 FIRST ENGINEERING

THE NATIONAL UNIVERSITY OF IRELAND, CORK COLÁISTE NA hollscoile, CORCAIGH UNIVERSITY COLLEGE, CORK SUMMER EXAMINATION 2005 FIRST ENGINEERING OLLSCOIL NA héireann, CORCAIGH THE NATIONAL UNIVERSITY OF IRELAND, CORK COLÁISTE NA hollscoile, CORCAIGH UNIVERSITY COLLEGE, CORK SUMMER EXAMINATION 2005 FIRST ENGINEERING MATHEMATICS MA008 Clculus d Lier

More information

,... are the terms of the sequence. If the domain consists of the first n positive integers only, the sequence is a finite sequence.

,... are the terms of the sequence. If the domain consists of the first n positive integers only, the sequence is a finite sequence. Chpter 9 & 0 FITZGERALD MAT 50/5 SECTION 9. Sequece Defiitio A ifiite sequece is fuctio whose domi is the set of positive itegers. The fuctio vlues,,, 4,...,,... re the terms of the sequece. If the domi

More information

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11 UTCLIFFE NOTE: CALCULU WOKOWKI CHAPTER Ifiite eries Coverget or Diverget eries Cosider the sequece If we form the ifiite sum 0, 00, 000, 0 00 000, we hve wht is clled ifiite series We wt to fid the sum

More information

Advanced Higher Maths: Formulae

Advanced Higher Maths: Formulae : Fomule Gee (G): Fomule you bsolutely must memoise i ode to pss Advced Highe mths. Remembe you get o fomul sheet t ll i the em! Ambe (A): You do t hve to memoise these fomule, s it is possible to deive

More information

Consider unordered sample of size r. This sample can be used to make r! Ordered samples (r! permutations). unordered sample

Consider unordered sample of size r. This sample can be used to make r! Ordered samples (r! permutations). unordered sample Uodeed Samples without Replacemet oside populatio of elemets a a... a. y uodeed aagemet of elemets is called a uodeed sample of size. Two uodeed samples ae diffeet oly if oe cotais a elemet ot cotaied

More information

Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., Outer Ring Road New Delhi , Ph. : ,

Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., Outer Ring Road New Delhi , Ph. : , MT TRIGONOMETRIC FUNCTIONS AND TRIGONOMETRIC EQUATIONS C Trigonometric Functions : Bsic Trigonometric Identities : + cos = ; ; cos R sec tn = ; sec R (n ),n cosec cot = ; cosec R {n, n I} Circulr Definition

More information

Week 13 Notes: 1) Riemann Sum. Aim: Compute Area Under a Graph. Suppose we want to find out the area of a graph, like the one on the right:

Week 13 Notes: 1) Riemann Sum. Aim: Compute Area Under a Graph. Suppose we want to find out the area of a graph, like the one on the right: Week 1 Notes: 1) Riem Sum Aim: Compute Are Uder Grph Suppose we wt to fid out the re of grph, like the oe o the right: We wt to kow the re of the red re. Here re some wys to pproximte the re: We cut the

More information

(n 1)n(n + 1)(n + 2) + 1 = (n 1)(n + 2)n(n + 1) + 1 = ( (n 2 + n 1) 1 )( (n 2 + n 1) + 1 ) + 1 = (n 2 + n 1) 2.

(n 1)n(n + 1)(n + 2) + 1 = (n 1)(n + 2)n(n + 1) + 1 = ( (n 2 + n 1) 1 )( (n 2 + n 1) + 1 ) + 1 = (n 2 + n 1) 2. Paabola Volume 5, Issue (017) Solutions 151 1540 Q151 Take any fou consecutive whole numbes, multiply them togethe and add 1. Make a conjectue and pove it! The esulting numbe can, fo instance, be expessed

More information

Mathematical Statistics

Mathematical Statistics 7 75 Ode Sttistics The ode sttistics e the items o the dom smple ed o odeed i mitude om the smllest to the lest Recetl the impotce o ode sttistics hs icesed owi to the moe equet use o opmetic ieeces d

More information

We will begin by supplying the proof to (a).

We will begin by supplying the proof to (a). (The solutios of problem re mostly from Jeffrey Mudrock s HWs) Problem 1. There re three sttemet from Exmple 5.4 i the textbook for which we will supply proofs. The sttemets re the followig: () The spce

More information

By the end of this section you will be able to prove the Chinese Remainder Theorem apply this theorem to solve simultaneous linear congruences

By the end of this section you will be able to prove the Chinese Remainder Theorem apply this theorem to solve simultaneous linear congruences Chapte : Theoy of Modula Aithmetic 8 Sectio D Chiese Remaide Theoem By the ed of this sectio you will be able to pove the Chiese Remaide Theoem apply this theoem to solve simultaeous liea cogueces The

More information

Counting Functions and Subsets

Counting Functions and Subsets CHAPTER 1 Coutig Fuctios ad Subsets This chapte of the otes is based o Chapte 12 of PJE See PJE p144 Hee ad below, the efeeces to the PJEccles book ae give as PJE The goal of this shot chapte is to itoduce

More information

, we would have a series, designated as + j 1

, we would have a series, designated as + j 1 Clculus sectio 9. Ifiite Series otes by Ti Pilchowski A sequece { } cosists of ordered set of ubers. If we were to begi ddig the ubers of sequece together s we would hve series desigted s. Ech iteredite

More information

M3P14 EXAMPLE SHEET 1 SOLUTIONS

M3P14 EXAMPLE SHEET 1 SOLUTIONS M3P14 EXAMPLE SHEET 1 SOLUTIONS 1. Show tht for, b, d itegers, we hve (d, db) = d(, b). Sice (, b) divides both d b, d(, b) divides both d d db, d hece divides (d, db). O the other hd, there exist m d

More information

MATH /19: problems for supervision in week 08 SOLUTIONS

MATH /19: problems for supervision in week 08 SOLUTIONS MATH10101 2018/19: poblems fo supevisio i week 08 Q1. Let A be a set. SOLUTIONS (i Pove that the fuctio c: P(A P(A, defied by c(x A \ X, is bijective. (ii Let ow A be fiite, A. Use (i to show that fo each

More information

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11 SUTCLIFFE S NOTES: CALCULUS SWOKOWSKI S CHAPTER Ifiite Series.5 Altertig Series d Absolute Covergece Next, let us cosider series with both positive d egtive terms. The simplest d most useful is ltertig

More information

( a n ) converges or diverges.

( a n ) converges or diverges. Chpter Ifiite Series Pge of Sectio E Rtio Test Chpter : Ifiite Series By the ed of this sectio you will be ble to uderstd the proof of the rtio test test series for covergece by pplyig the rtio test pprecite

More information

In the case of a third degree polynomial we took the third difference and found them to be constants thus the polynomial difference holds.

In the case of a third degree polynomial we took the third difference and found them to be constants thus the polynomial difference holds. Jso Mille 8 Udestd the piciples, popeties, d techiques elted to sequece, seies, summtio, d coutig sttegies d thei pplictios to polem solvig. Polomil Diffeece Theoem: f is polomil fuctio of degee iff fo

More information

FOURIER SERIES PART I: DEFINITIONS AND EXAMPLES. To a 2π-periodic function f(x) we will associate a trigonometric series. a n cos(nx) + b n sin(nx),

FOURIER SERIES PART I: DEFINITIONS AND EXAMPLES. To a 2π-periodic function f(x) we will associate a trigonometric series. a n cos(nx) + b n sin(nx), FOURIER SERIES PART I: DEFINITIONS AND EXAMPLES To -periodic fuctio f() we will ssocite trigoometric series + cos() + b si(), or i terms of the epoetil e i, series of the form c e i. Z For most of the

More information

Chapter Real Numbers

Chapter Real Numbers Chpter. - Rel Numbers Itegers: coutig umbers, zero, d the egtive of the coutig umbers. ex: {,-3, -, -,,,, 3, } Rtiol Numbers: quotiets of two itegers with ozero deomitor; termitig or repetig decimls. ex:

More information

National Quali cations SPECIMEN ONLY

National Quali cations SPECIMEN ONLY AH Ntiol Quli ctios SPECIMEN ONLY SQ/AH/0 Mthemtics Dte Not pplicble Durtio hours Totl mrks 00 Attempt ALL questios. You my use clcultor. Full credit will be give oly to solutios which coti pproprite workig.

More information

07 - SEQUENCES AND SERIES Page 1 ( Answers at he end of all questions ) b, z = n

07 - SEQUENCES AND SERIES Page 1 ( Answers at he end of all questions ) b, z = n 07 - SEQUENCES AND SERIES Page ( Aswers at he ed of all questios ) ( ) If = a, y = b, z = c, where a, b, c are i A.P. ad = 0 = 0 = 0 l a l

More information

Section IV.6: The Master Method and Applications

Section IV.6: The Master Method and Applications Sectio IV.6: The Mster Method d Applictios Defiitio IV.6.1: A fuctio f is symptoticlly positive if d oly if there exists rel umer such tht f(x) > for ll x >. A cosequece of this defiitio is tht fuctio

More information

Linford 1. Kyle Linford. Math 211. Honors Project. Theorems to Analyze: Theorem 2.4 The Limit of a Function Involving a Radical (A4)

Linford 1. Kyle Linford. Math 211. Honors Project. Theorems to Analyze: Theorem 2.4 The Limit of a Function Involving a Radical (A4) Liford 1 Kyle Liford Mth 211 Hoors Project Theorems to Alyze: Theorem 2.4 The Limit of Fuctio Ivolvig Rdicl (A4) Theorem 2.8 The Squeeze Theorem (A5) Theorem 2.9 The Limit of Si(x)/x = 1 (p. 85) Theorem

More information

Fourier Series and Applications

Fourier Series and Applications 9/7/9 Fourier Series d Applictios Fuctios epsio is doe to uderstd the better i powers o etc. My iportt probles ivolvig prtil dieretil equtios c be solved provided give uctio c be epressed s iiite su o

More information