Physics 1C Fall 2011: Quiz 1 Version A 1

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1 Physics 1C Fall 2011: Quiz 1 Vesion A 1 Depatment of Physics Physics 1C Fall Quate D. Mak Paddock INSTRUCTIONS: 1. Pint you full name below LAST NAME FIRST NAME MIDDLE INITIAL 2. You code numbe is. WRITE THIS NUMBER ON EVERY SCANTRON FOR THIS COURSE. 3. Tea off bottom pat of this page as indicated by the dotted line and keep fo you own ecods. Retun the top potion with you test. 4. In compliance with the Pivacy Act, you scoes will be posted by code numbe on a website set up fo this couse. YOUR CODE NUMBER MUST BE WRITTEN ON EVERY SCANTRON FORM YOU USE FOR THIS COURSE. ****************************************************************** Physics 1C Fall Quate MY CODE NUMBER IS: YOUR CODE NUMBER MUST BE WRITTEN ON EVERY SCANTRON FOR THIS COURSE. TEAR OFF AT DOTTED LINE AND TURN IN BOTTOM PORTION OF THIS PAGE.

2 Physics 1C Fall 2011: Quiz 1 Vesion A 2 Depatment of Physics Physics 1C Fall Quate 2011 D. Paddock Vesion A DO NOT TURN OVER THIS PAGE UNTIL INSTRUCTED TO DO SO PUT AWAY ALL BOOKS, NOTES, PHONES, COMPUTERS AND STUDY AIDS INSTRUCTION READ ME! 1. ENTER YOUR CODE NUMBER INTO THE EXAM NUMBER PART OF YOUR SCANTRON. 2. ENTER THE TEST VERSION IN THE TEST FORM BOX ON YOUR SCANTRON. 3. WRITE YOUR NAME LEGIBLY ON YOUR SCANTRON. 4. Flip ove this page when instucted to begin exam. 5. Thee ae 10 poblems anging in difficulty. 6. All answes should be maked on the scanton fom WITH PENCIL; no wok needs to be shown. 7. An equation sheet is povided on the last page of the exam fo efeence. 8. Answe all questions. GOOD LUCK!

3 Physics 1C Fall 2011: Quiz 1 Vesion A 3 Closed book. No wok needs to be shown fo multiple-choice questions. 1. Conside a mass on a sping that is undegoing simple hamonic motion. In this simple hamonic motion system, the magnitude of the acceleation is geatest when: a. the displacement is maximum. b. the displacement is zeo. c. the speed is maximum. d. the foce is zeo. e. the speed is exactly half of its maximum value. 2. A 3.0 kg block, attached to a sping, executes simple hamonic motion accoding to the position expession: x = 2.0 cos(50t), whee x is in metes and t is in seconds. The sping constant of this sping is: a. 7,500 N/m. b. 1,200 N/m. c. 150 N/m. d. 100 N/m. e. 2,500 N/m. 3. The peiod of a simple pendulum on Eath is 1.00 seconds. When bought to anothe planet whee g is one tenth that on Eath, its peiod becomes: a seconds. b seconds. c seconds. d seconds. e seconds. 4. A unifom cod has a mass of kg and a length of 12.0 m. The tension in the cod is 19.6 N. What is the speed of a wave on the cod? a m/s. b m/s. c m/s. d m/s. e m/s. 5. In an engine, a piston oscillates with simple hamonic motion so that its position vaies accoding to the expession: x = (7.5 cm) cos(4.0t + π/2), whee x is in centimetes and t is in seconds. At t = 0 seconds, the magnitude of the velocity of the piston is: a. zeo. b. 7.5 cm/s. c. 30 cm/s. d. 120 cm/s. e cm/s.

4 Physics 1C Fall 2011: Quiz 1 Vesion A 4 6. A block attached to a sping undegoes simple hamonic motion on a hoizontal fictionless suface. Its total enegy is 50.0 J. When the displacement is half the amplitude, the kinetic enegy is: a J. b J. c J. d J. e J. 7. Conside a mass on a sping that is undegoing simple hamonic motion. As this simple hamonic motion system goes though one complete cycle it has: a. constant speed. b. vaying amplitude. c. vaying peiod. d. vaying acceleation. e. all of the above choices ae coect. 8. A pendulum consists of a massive bob at the end of a sting (as shown to the ight). If the mass of the bob is doubled, what happens to the peiod of the pendulum? a. The peiod of the pendulum will decease. b. The peiod of the pendulum will incease. c. The peiod of the pendulum will emain the same. 9. A mass on a sping is undegoing simple hamonic motion with a fequency of 0.20 Hz. At time t = 0 it is at the equilibium point. At which one of the following times is it futhest in distance fom the equilibium point? a. t = 7.5 seconds. b. t = 3.5 seconds. c. t = 5.0 seconds. d. t = 7.0 seconds. e. t = 2.5 seconds.

5 Physics 1C Fall 2011: Quiz 1 Vesion A A 0.20-kg block ests on a level suface and is attached to a hoizontally aligned sping with a sping constant of 40 N/m. The block is initially displaced 4.0 cm fom the equilibium point and then eleased to set up a simple hamonic motion. A fictional foce of 0.3 N exists between the block and suface. What is the speed of the block when it fist passes though the equilibium point afte being eleased fom the 4.0-cm displacement point? a m/s. b m/s. c m/s. d m/s. e m/s.

6 Physics 1C Fall 2011: Quiz 1 Vesion A 6 Equations and constants: ( " x = cos! = x 2 + y 2, # & y = sin! ' ; * * ) " y -; *! = tan -1 ' + # x & *. #!v ' a = lim!t "0!t (;!x v = lim &!t "0!t ) " 0! f s! µ s F & N # f k = µ k F N ' ; F g = mg ( " v = v o + at &!x = 1 v + v 2 ( o )t #!x = v o t + 1 at ' 2 ; 2 v 2 = v 2 o + 2a!x( #! F = 0; a = 0 '! F = m a F 2on1 = " F ( & 1on2 ) #!x = x f " x i ' speed avg = d (; &!t ) ; p = m v ; P = F! v = W "t ; " a avg =!v &!t # ' ; v avg =!x!t (! F = "k Hooke's sping (# x ); a =! k sping m x ; v = ± k sping ( m A2! x 2 ); T mass!sping = 2" m k ; T pend = 2! L g ; T physpend = 2! I mgd ; f = 1 T ;! = v = dx dt =!A" sin "t + # ( ) =!2Af sin 2ft + # ( ); k sping m ; x = Acos!t + " a = d 2 x dt 2 =!A" 2 cos "t + # ( ) =! 2f ( ) 2 Acos 2ft + # ( ); U gav = mgh ; K = 1 mv 2 = ma2! 2 sin 2 (!t + "); U sping = 1 k (!x 2 sping )2 = 1 k 2 sping A2 cos 2 ("t + #); W = ( ) = Acos 2#ft + " F! x cos" ; W nc =!E mec ; E mec = K +U gav +U sping ; E SHM = 1 2 ka2 ; k wave! 2" # ;! = 2"f = 2" T ; y = Asin ( kx!"t ); v wave =!f =! T ; v =! ; v k sting = wave v = 343m sound ai at 20 o C s ; P = 1 µ! 2 A 2 v ; f 2! = " v f sound ± v o ';! # v sound m v s & F T µ ; ( ) con = 2 " 1 = n#; (! ) = " = # n + 1 &! des () ; y = ( 2Asinkx)cos!t ; f n,sting = nf 1 = n v! # & = n # & ' " 2L " 2L F T µ ; ( ); " f n,ai!open = nf 1 = n v " ' n =1,2,3,...; f # 2L& n,ai!closed = nf 1 = n v ' n =1,3,5,...; f # 4L& beat = f 2! f 1 ; A cicle =! 2 ; A sphee = 4! 2 ; g = 9.80 m/s 2 ; x =!b ± b2! 4ac ; 1,000 m =1 km; 60 s = 1 min; 2a 60 min =1 h; 2.54 cm =1 in; 12 in =1 ft ; 5,280 ft =1 mi; 1,609 m =1 mi; m =1 ft.

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