PREFACE. Synergy for Success in Mathematics 10 is designed for Grade 10 students. The textbook

Size: px
Start display at page:

Download "PREFACE. Synergy for Success in Mathematics 10 is designed for Grade 10 students. The textbook"

Transcription

1 Syergy for Success i Mthemtics 0 is desiged for Grde 0 studets. The textbook cotis ll the required lerig competecies d is supplemeted with some dditiol topics for erichmet. Lessos re preseted usig effective Sigpore Mth strtegies tht re iteded for esy uderstdig d grsp of ides for its trget reders. Vrious exercises re lso provided to help the lerers cquire the ecessry skills eeded. The book is orgized with the followig recurrig fetures i every chpter: Lerig Gols Itroductio Historicl Note This gives the specific objectives tht re iteded to be chieved i the ed. The reder is give bird's eye view of the cotets. A brief historicl ccout of relted topic is icluded givig the reder wreess of some importt cotributios of some gret mthemticis or eve stories of gret chievemets relted to mthemtics. Method/Exm Notes These dditiol tools help studets recll importt iformtio, formuls, d shortcuts, eeded i workig out solutios. Exmples Ehcig Skills Likig Together Chpter Test Chpter Project Mkig Coectio PREFACE Step-by-step d detiled demostrtios of how specific cocept or techique is pplied i solvig problems. These re prctice exercises foud fter every lesso, tht will cosolidte d reiforce wht the studets hve lered. This visul tool c help the studets relize the coectio of ll the ides preseted i the chpter. This is summtive test give t the ed i preprtio for the expected ctul clssroom exmitio cotiig the topics icluded i the chpter. A chllegig tsk is desiged for the lerer givig him opportuity to use wht he/she hs lered i the chpter. This my be mipultive type of ctivity tht is specificlly chose to ehce uderstdig of the cocepts lered i the chpter. The studets re exposed to fcts d iformtio tht coect mthemtics d culture. This is for the purpose of lettig the lerers pprecite the subject becuse of tgible or true-tolife stories tht show how mthemtics is useful d relevt. Every effort hs bee mde i order for ll the discussios i this book to be cler, simple, d strightforwrd. This book lso gives opportuities for the reders to see the beuty of mthemtics s essetil tool i uderstdig the world we live i. With this i mid, pprecitio of mthemtics goes beyod seeig; relizig its criticl pplictio to decisio mkig i life completes the purpose of kowig d uderstdig mthemtics.

2 Tble of C tets CHAPTER SEQUENCES AND THE BINOMIAL THEOREM Itroductio... Historicl Note.... Ptter d Sequeces...3 The Geerl Term of Sequece... 3 Fiite d Ifiite Sequece Arithmetic Sequece...9 Defiitio of Arithmetic Sequece... 9 The Geerl Term of Arithmetic Sequece... Arithmetic Series... 5 Grphig Arithmetic Sequece... 8 The Arithmetic Me of Arithmetic Sequece... Applictios of Arithmetic Sequece Geometric Sequece...9 The Geerl Term of Geometric Sequece... 3 Geometric Series Ifiite Geometric Series Grphig Geometric Sequece Geometric Me Applictio of Geometric Sequece Hrmoic d Fibocci Sequece...58 Hrmoic Sequece The Geerl term of Hrmoic Sequece Hrmoic Me... 6 Applictio of Hrmoic Sequece The Fibocci Sequece The Geerl Term of Fibocci Sequece The Golde Rtio The Biomil Theorem Biomil Theorem The rth term i Biomil Expsio... 80

3 Likig Together...86 Chpter Test Chpter Project Mkig Coectio CHAPTER POLYNOMIALS Itroductio Historicl Note Polyomils Review o Polyomils Review o Opertios Ivolvig Polyomils Fctorig d Solvig Polyomil Equtios... 8 Evlutig Polyomil Fuctio 0 Compositio of Fuctios.3 Polyomil Theorems Zeros of Polyomil Fuctios... 4 Descrtes' Rule of Sigs 4.5 Grphs of Polyomil Fuctios Costt Fuctio Lier Fuctio Qudrtic Fuctio Cubic Fuctio Specified Domi Likig Together...73 Chpter Test...74 Chpter Project...79 Mkig Coectio...80 CHAPTER 3 PLANE COORDINATE GEOMETRY Itroductio 8 Historicl Note 8 3. The Distce Betwee Two Poits i the Crtesi Coordite Ple 83 Review o the Crtesi Coordite System 83 Icremet i x d y 86 Distce Betwee Two Poits i the Crtesi Ple Review o Rdi Mesure d The Uit Circle 06 Review o the Midpoit Formul 06 Divisio of Lie Segmet 0

4 3.3 Review o the Slope d Equtio of Lie 3 Review o the Slope of Lie 3 Review o the Equtio of Lie 7 Likig Together 44 Chpter Test 45 Chpter Project 49 Mkig Coectio 50 CHAPTER 4 CIRCLES Itroductio 87 Historicl Note Tgets 89 Circle 89 Tget Cetrl Agles, Arc, d Chords 309 Cetrl Agles d Arcs 309 Arcs d Chords Iscribed Agles d Itercepted Arcs Other Agle Properties of Circle 344 Agle Formed by Chord d Tget 344 Lies Itersectig Iside or Outside Circle Legths of Segmets i Circle Equtio of Circles 38 Likig Together 40 Chpter Test 40 Chpter Project 405 Mkig Coectio 406 CHAPTER 5 MEASURES OF POSITION Itroductio 407 Historicl Note Smples d Dt 409 Revisio o Sttistics 409 Types of Smplig 4 Revisio o Types of Dt 47 Levels of Mesuremet 49

5 Methods of Dt Collectio Sttisticl Represettios 48 Revisio o Sttisticl Grphs d Chrts 48 Dot Digrm 33 Stem-d-Lef Disply Mesures of Positio d Box-d-Whisker Plot 447 Percetile 447 Qurtile 450 Box-d-Whisker Plot 454 Decile 464 Likig Together 47 Chpter Test 473 Chpter Project 476 Mkig Coectio 478 CHAPTER 6 PROBABILITY Itroductio 479 Historicl Note Review o Fudmetl Coutig Priciple Permuttio 495 Fctoril Nottio 495 Permuttio Combitio Probbility of Evets 5 The Uio d Itersectio of Evets 57 Likig Together 57 Chpter Test 58 Chpter Project 53 Mkig Coectio 53 Glossry 533 Idex 544 Bibliogrphy 550

6

7 SEQUENCES AND THE BINOMIAL THEOREM Lerig Gols At the ed of the chpter, you should be ble to:. Fid d geerte ptters.3 Describe d illustrte geometric sequece, give exmples of geometric sequeces, differetite fiite geometric sequece from ifiite geometric sequece, differetite rithmetic sequece from geometric sequece, fid the terms of geometric sequece icludig the geerl th term of the sequece, d fid the sum of terms of give geometric sequece. The piepple is tropicl plt. It is cocetrted i tropicl regios of the world. Sevety-five percet of piepple supplies ll over the world re produced i Thild, the Philippies, Brzil, Idi, Cost Ric, Nigeri, Mexico, d Idoesi. The fruit is med piepple becuse of its similrity to pie coe. Whe you look t the scles of the piepple, you see sets of spirl hexgos. There re three distict sets of hexgos. A set of five prllel spirls sceds t shllow gle to the right. The, set of eight prllel spirls rises more steeply th the previous set does d sceds to the left. Filly, set of 3 prllel spirls sceds very steep to the right. Notice tht the three sets represet segmet of the Fibocci sequece. Fibocci umber ptters, which re discussed i this chpter, coti terms just like the ptters o the scle of the piepple..4.5 Describe d illustrte rithmetic sequece, give exmples of rithmetic sequeces, fid the terms of rithmetic sequece icludig the geerl th term of the sequece, d fid the sum of terms of give rithmetic sequece Illustrte other types of sequeces (e.g., hrmoic d Fibocci) Solve problems ivolvig sequeces d series, icludig the biomil theorem

8 Historicl Note Leordo Piso Bigollo (70 50), lso kow s Leordo Fibocci or most commoly Fibocci, ws Itli mthemtici. He ws cosidered by some s the most tleted wester mthemtici of the Middle Ages. Fibocci is best kow for itroducig the Hidu-Arbic umerl system i Europe through his Liber Abci, which mes Book of Clcultio i 0. I his book, Fibocci itroduced the Modus Idorum (method of the Idis), which is trditiolly kow s Arbic umerls. He believed tht rithmetic with Hidu-Arbic umerls ws esier d more efficiet th with Rom umerls. He is lso kow for his umber sequece clled the Fibocci umbers.

9 Syergy for Success i Mthemtics Chpter. Ptters d Sequeces A umber sequece is set of umbers rrged i such wy tht ech successive umber follows the precedig umber ccordig to ptter or rule. A rule defies which wy to produce the vlue of ech term of sequece. Without defiite rule, sequece cot be formed. Defiitio of Sequece A sequece is set of umbers or object rrged i specific order. Ech umber or object i the sequece is clled term. The Geerl Term of Sequece Cosider the list of umbers below., 5, 9, 3, 7,, 5 The first umber is ; the secod is 5; the third is 9, d so o. The list of umbers is exmple of sequece sice it follows certi rule. The rule of the give sequece is to dd four to every term to fid the successive umber. Addig 4 to the first term results i 5, which is the secod term. Cotiue the process util the sum obtied is 5, which is the lst term. Exm Note The term of sequece c lso be clled the elemet or member of sequece Every elemet i the sequece is clled the term of the sequece. The ottio represets the th term or geerl term of sequece. The ottio represets the first term of the sequece; represets the secod term; 3 represets the third term; d so o. Thus, i the give sequece bove, =, = 5, = 9, d so o. 3 Exm Note The expressio represets the terms t the th positio i the sequece. The subscript is the term umber. 3

10 Fiite d Ifiite Sequeces The umber of terms i sequece is clled the legth of the sequece. To determie the legth of give sequece, fid out if it is fiite or ifiite sequece. A fiite sequece is sequece tht hs limited umber of terms. The terms re deoted by,, 3, where is turl umber. A ifiite sequece is sequece tht hs edless umber of terms. To idicte ifiite sequece, you my use ellipsis. The followig sets of umbers re exmples of fiite d ifiite sequeces. () 3, 7,, 5, 9 The set bove is fiite sequece. There re five terms: the first term is 3; the secod term is 7; d so o. The fifth d lst term is 9. (b),, 3, 4, 5, 6, ¼ The set bove is ifiite sequece. There re edless umber of terms: the first term is ; the secod term is ; the third is 3; d so o. The ellipsis fter 6 idicte tht there re more terms fter the term 6. You c fid the terms i sequece by substitutig positive itegers, strtig from, for the vrible i the geerl term of the sequece. Exm Note The sig fter give term is clled ellipsis. It idictes tht the sequece hs ifiite umber terms. Exmple Give the first five terms of the sequece whose th term is give by ech the followig formuls. () = + 5 (b) = (c) = ( ) () 4

11 Syergy for Success i Mthemtics Chpter SOLUTION () The first five terms of the sequece whose geerl term is = + 5 c be foud by substitutig,, 3, 4, d 5 for the vrible. First term: Secod term: Third term: Fourth term: Fifth term: = ()+ = 5 7 = ()+ = 5 9 = ()+ = 3 5 = 4 ( )+ 5= 3 = ()+ = Thus, the first five terms of the sequece re 7, 9,, 3, d 5. Method Note Substitute the turl umber for the vrible i the formul to fid the th term of the sequece. (b) = ( ) () First term: Secod term: Third term: Fourth term: Fifth term: ( ) ()= = = ( ) ()= 3 = ( ) ()= = ( ) ( 4)= 4 5 = ( ) ()= 5 5 (c) Thus, the first five terms of the sequece re -,, -3, 4, d -5. = First term: = = Secod term: = Third term: 3 = 3 Fourth term: 4 = 4 Fifth term: 5 = 5 Thus, the first five terms of the sequece re,, 3, 4, d 5. 5

12 You c lso fid the terms of sequece by ivestigtig its ptter d rule. Exmple Determie the ptter of ech give sequece. The, fid the ext term i the sequece. () 5, 0, 5, 30, (b) 4, 8, 6, 3, (c) -5, 5, -5, 5, (d) -8, -5, -,, SOLUTION () (b) (c) The ptter is ddig 5 to the previous term to get the ext term. Therefore, the ext term is 35. The ptter is multiplyig the term by to fid the ext term. Therefore, the ext term is 64. The costt multiplier is -. Thus, the ext term is -5. (d) The costt icrese is 3. Thus, the ext term is 4. Exmple 3 Fid the explicit formul for ech sequece. () 7, 0, 3, -4, (b) -40, -3, -4, -6, (c) 9, 9, 9, 39, (d) -4,, -36, 08, SOLUTION () = 4 7 (b) = (c) = (d) ( )( ) = 4 3 6

13 Syergy for Success i Mthemtics Chpter ENHANCING SKILLS A Give the first five terms of the sequece whose th term or geerl term is give by ech of the followig formuls. () = 5 + (6) ( ) + = () = 3 (7) = (3) = + (8) = 3 ( ) + ( ) (4) = 4 (9) = ( ) (5) = 3 (0) = + ( ) () 7

14 B Determie the ptter of ech give sequece d the fid the ext two terms of the sequece. (), 6, 0, (6) -5, -, -9, Ptter: Ptter: Next two terms: Next two terms: () 8, 3, 8, Ptter: (7), 8, 3, Ptter: Next two terms: Next two terms: (3) 3, 9, 7, Ptter: (8) 6, 8, 54, Ptter: Next two terms: Next two terms: (4) 4, 6, 64, Ptter: (9) -, 4, -8, Ptter: Next two terms: Next two terms: (5) -4, -8, -, Ptter: (0) 3, -9, 7, Ptter: Next two terms: Next two terms: 8

15 Syergy for Success i Mthemtics Chpter. Arithmetic Sequece The dt below show mothly ret of prtmet i Quezo City from yer 00 to 04. Yer Mothly retl fee i ( ) 5,500 6,000 6,500 7,000 7,500 Strtig t 5,500 i 00, the mothly ret icreses by 500 yerly. By yer 04, the ret becomes 7,500. The mothly ret the from 00 to 04, with differece of 500 betwee two cosecutive yers, forms sequece clled the rithmetic sequece. Defiitio of Arithmetic Sequece The vlues 5,000, 6,000, 6,500. 7,000, d 7,500 form rithmetic sequece. The vlue 500, the costt differece betwee the cosecutive terms of the sequece, is clled the commo differece. Defiitio of Arithmetic Sequece A rithmetic sequece is umber sequece whose every two cosecutive terms hve costt differece. The differece betwee the cosecutive terms is clled the commo differece. The first term i rithmetic sequece is deoted by while the commo differece is deoted by d. The commo differece is idetified by subtrctig two cosecutive terms i the sequece. Below re exmples of rithmetic sequeces. Give re the first term d commo differece of ech sequece. Method Note You c express the terms of rithmetic sequece give the vlues of d d s follows.,( + d),( + d),( + 3d), () 5, 7, 9,, = 5 d = () 00, 90, 80, 70, 60, = 00 d = -0 (3) 50, 00, 50, 00, = 50 d = 50 9

16 (4) 0, 9, 8, 7, 6, = 0 d = - (5) 3,,,, = d = Exmple Tell whether ech give sequece is rithmetic or ot. If the sequece is rithmetic, idetify its first term d the commo differece. (), 7,, 7, (b), 5, 7, 8, (c) 500, 400, 300, 00, (d) 3 4 5,,,, 3 3 (e),,,, 4 SOLUTION (), 7,, 7, = d = 5 (b), 5, 7, 8, The sequece is ot rithmetic becuse there is o commo differece. (c) 500, 400, 300, 00, = 500 d = 00 (d) 3 4 5,,,, 3 3 = 3 d = 3 (e),,,, 4 The sequece is ot rithmetic becuse there is o commo differece. 0

17 Syergy for Success i Mthemtics Chpter The Geerl Term of Arithmetic Sequece Cosider rithmetic sequece whose first term is d whose commo differece is d. The first five terms of the sequece re computed s follows. First term ( ): Secod term ( ): + d Third term ( 3 ): ( + d)+ d= + d Fourth term ( 4 ): ( +d)+ d= + 3d Fifth term ( 5 ): ( +3d)+ d= + 4d Followig the ptter bove, you c costruct equtio to fid the th term (or geerl term) of the give sequece.. The Geerl Term of Arithmetic Sequece The geerl term of rithmetic sequece is deoted by = + ( - ) d where is the geerl term of sequece, is the first term, is the positio of the term, d d is the commo differece. If the first term d the commo differece of rithmetic sequece re give, the geerl term of the sequece c be foud. To fid the vlue of the geerl term, we my substitute the give iformtio i the formul. The commo differece of rithmetic sequece c be foud usig y two cosecutive terms of the sequece. d= = 3 = 4 3 =

18 Exmple Fid the 0th term of rithmetic sequece whose first term is 8 d whose commo differece is 7. SOLUTION Use the formul for the geerl term of rithmetic sequece to fid the 0th term. = + d 0 0 ( ) = 8+ ( 0 )() 7 = 8+( 9)() 7 = = 7 Thus, the 0th term of the rithmetic sequece is 7. Without usig the formul for the geerl term of rithmetic sequece, c you still fid the vlue of certi term? Yes, you c by simply listig ll the terms of the sequece. The result i Exmple c be verified by listig the first 0 terms of the rithmetic sequece. Use the first term d the commo differece to fid the ext terms. Add 7 to the first term 8 to fid the secod term. Add 7 to the secod term to fid the third term. Do this util you rech the vlue of the 0th term. Therefore, the first 0 terms of the sequece re 8, 5,, 9, 36, 43, 50, 57, 64, d 7. Exmple 3 Fid the 7th term of rithmetic sequece whose first term is 85 d whose commo differece is -9. SOLUTION Apply the formul for fidig the geerl term of rithmetic sequece to fid the 7th term. = + ( ) d 7 7 = 85+ ( 7 ) ( 9) = 85+( 6) ( 9) = = 3 Thus, the 7th term of the rithmetic sequece is 3. Exm Note You c check the missig term by listig the umbers from the first term up to the geerl term usig the commo differece.

19 Wht if the rithmetic sequece is give, d you re sked to fid the defiig rule of the sequece? You c costruct equtio or formul to fid the geerl term wheever the rithmetic sequece is give. Exmple 4 Give the formul for the geerl term of the rithmetic sequece 5, 9, 3, 7, SOLUTION { } Syergy for Success i Mthemtics Chpter The first term i the give rithmetic sequece is 5. Thus, = 5. To get the commo differece, pply d=. d= = = = 9 5 = 4 Substitute the vlues 4 d 5 for d d, respectively, i the formul for the geerl term of rithmetic sequece. Costruct the resultig equtio or formul tht defies the geerl term of the sequece. = + ( ) d = 5+ ( ) = +( )( ) Method Note To fid the vlue of the commo differece d of rithmetic sequece, subtrct y two cosecutive terms; tht is, d = - -. Exmple 5 Fid the formul tht defies the geerl term of rithmetic sequece whose secod term is 9 d whose seveth term is 39. SOLUTION To determie the geerl term of rithmetic sequece, fid the first term d the commo differece d. The secod term of the rithmetic sequece is 9. Thus, = 9. Apply the formul to fid the geerl term of rithmetic sequece. 3

20 = + d = + d 9= + d ( )( ) ( )( ) + d= 9 () The seveth term of the sequece is 39. Apply the formul for the geerl term. = + d = + 7 d 7 39= + 6d ( )( ) ( )( ) + 6d= 39 () You ow hve two lier equtios with two ukows. Use equtios () d () to fid the vlues of d d. () + d= 9 () + 6d= 39 To elimite, multiply the secod equtio by -. ( ) ( + 6d)=( 39) ( ) 6d = 39 (3) Now, dd equtios () d (3) to elimite. + d= 9 6d= 39 The commo differece is 6. 5d = 30 5d 30 5 = 5 5d = 5 d = 6 ( )( ) Substitute the vlue of d i either of the equtios () d (), d fid the vlue of the first term. 4

21 + d= 9 + 6= 9 = 3 Use equtio (). Substitute d for 6. Subtrct 6 from both sides. Thus, the first term of the rithmetic sequece is 3. Now usig the vlue of d d, costruct formul tht defies the give sequece. Hece, the geerl term of the give rithmetic sequece is = + d = 3+ 6 = = 6 3. ( ) ( )( ) Syergy for Success i Mthemtics Chpter Arithmetic Series Cosider the followig rithmetic sequece. 35, 53, 7, 89, 07, 5, 43, 6, 79, 97 Fid the sum of the first te terms of the sequece. I solvig the problem, you my list ll the ddeds d dd directly = 60 If you were to fid the sum of the first 00 terms of rithmetic sequece, would you use the sme method tht is, listig the terms d ddig them directly? The sum of the first terms is deoted by S ; is the first term; d d is the commo differece. You c represet the sum S usig equtios () d (). S = + ( + d)+ + + ( ) d + + d () S = + ( ) () Add the two equtios () d (). 5

22 ( ) ( ) S = + + d d d S = + d d d ( ( ) ) + + ( ) ( ) ( ) + ( + ( ) ) S = ( + ( ) d)+ ( + ( ) d)+ + ( + ( ) d)+ + ( ) d ( ) + ( ) Simplify the sum. Divide both sides by. =( )( + ) S S = () + ( ) Method Note To sum up the terms of rithmetic sequece, we c use the followig formul. + ( + d)+ ( + d)+ ( + 3d)+ Arithmetic Series The sum S of the first terms of rithmetic sequece is S = + ( ) where is the first term d is the lst term. Exm Note A rithmetic series is the sum of the terms of rithmetic sequece. You c tke the sum of fiite umber of terms of rithmetic sequece. Exmple 6 Fid the sum of the first 50 terms of the followig rithmetic sequece., 5, 8,, 4, SOLUTION To fid the sum of the first 50 terms, determie first the commo differece d. d= = 5 = 3 Thus, the commo differece d is 3. Next, fid the 50th term of the give rithmetic sequece. 6

23 Syergy for Success i Mthemtics Chpter = + d 50 ( ) = + ( 50 )() 3 = +( 49)() 3 = + 47 = 49 Thus, the 50th term of the sequece is 49. Sice the 50th term is idetified, use it to fid the sum of the first 50 terms. S= ( + ) S = 50 ( + ) = 50 ( + ) 49 = ( 5)( 5) = 3775 Therefore, the sum of the first 50 terms of the rithmetic sequece is I the previous exmple, the th term is foud before gettig the sum S. You c lso fid the sum of the terms without determiig the vlue of. Sice = + ( - ) d, you c substitute ( + ( - )d) for i the formul for S. The formul for S c be expressed s follows. S= ( + ) S = + + ( ) d Substitute + ( - ) for. S = + ( ) d Simplify the equtio. Thus, the sum of the first terms of rithmetic sequece c be lso foud by usig the formul S = + ( ) d. 7

24 Exmple 7 Determie the sum of the first 00 odd umbers from zero. SOLUTION The give rithmetic sequece is the first 00 odd umbers. Hece, the sequece is, 3, 5, 7, The commo differece of the sequece is. Substitute 00 for, for d, d for = 00, d =, d = i the followig formul. S = + ( ) d S = 00 ()+( ) = ( 50) +( 99 ) =( )( + ) =( 50)( 00) = Thus, the sum of the first 00 odd umbers is Grphig Arithmetic Sequece Remember tht for you to locte d grph poit, you eed to hve coordites which specify the positio or loctio of poit. The x-coordite is the first umber i the coordites d represets the distce of the poit from the y-xis. The y-coordite is the secod umber i the coordites d represets the distce of the poit from the x-xis. The coordites of poit o Crtesi ple re represeted by ordered pir. (, b) x-coordite y-coordite The grph of sequece is formed by collectig ll poits with coordites (, ) where =,, 3,... d correspods to the th term of the sequece. 8

25 For exmple, grph the ifiite rithmetic sequece whose terms re { 3, 7,, 5, } Idetify ll ordered pirs (, ) tht stisfy the rithmetic sequece d list them i the tble. b (, b) 3 (, 3) 7 (, 7) 3 ( 3, ) 4 5 ( 4, 5) (, ) Syergy for Success i Mthemtics Chpter The grph of the give sequece is show below. 4 y (4, 5) 0 (3, ) 8 6 (, 7) 4 (, 3) x 9

26 Exmple 8 Grph the followig rithmetic sequeces. { } () 6, 4,, 0,, (b) { 05., 75., 5, 75., 95., } SOLUTION () The first five poits of the grph of the rithmetic sequece re (, 6), (, 4), ( 3, ), ( 4, 0), d ( 5, ). The grph of the sequece is show below with two more poits, ( 6, 4) d ( 7, 6), which stisfy the sequece. Method Note 6 4 y (5, ) (6, 4) (7, 6) Use the formul for the geerl term of rithmetic sequece to determie the poits tht re icluded i the grph of the give sequece. (4, 0) x (3, -) (, -4) (, -6) (b) The first five poits of the grph of the rithmetic sequece re (, 05. ), (, 75. ), ( 3, 5), ( 4, 75. ), d ( 5, 95. ). Cotiuig the ptter, the grph of the sequece is show i the followig figure. y 4 (7, 4) Method Note Collect smple poits for the grph of the first give sequece (6,.75) (5, 9.5) (4, 7.5) (3, 5) (,.75) 0 (, 0.5) x

27 The Arithmetic Me of Arithmetic Sequece Syergy for Success i Mthemtics Chpter Cosider two umbers d b. Oe or more umbers c be iserted betwee d b to form rithmetic sequece with my terms. The iserted umbers re clled the rithmetic mes of the give umbers. To fid the rithmetic me betwee two umbers d b such tht the three umbers form rithmetic sequece, you my use the formul for fidig the verge of two umbers. Exm Note I sttistics, the term rithmetic me lso refers to the sum of the terms of set of umbers divided by the umber of terms. It is lso clled me or verge. Let the rithmetic sequece be {, x, b}. The two terms of the sequece re d b, d x is the rithmetic me. Let d be the commo differece of the sequece. Hece, the commo differece c be expressed s d= x or d= b x. Now, fid the vlue of x i the followig equtio. d= d x = b x x= + b b x = + Apply substitutio. Combie similr terms. Divide both sides by. Therefore, the rithmetic me of two umbers d b is give by + b. The three terms of the sequece re, + b., d b. Fid the rithmetic me of the followig sequece.,, 6 The vlues of d b re to d 6, respectively. Let x be the rithmetic me of the sequece. To fid the vlue of the rithmetic me, clculte the verge d 6, of the first d the lst terms of the sequece. Hece, b x = + = = = 4.

28 Exmple 9 Isert four rithmetic mes betwee -0 d 5. SOLUTION Plce blks betwee -0 d 5. The blks represet the four rithmetic mes. -0,,,,, 5 Clerly, there re six terms i the sequece. Let,, 3, 4, 5, d, 6 represet the first, the secod, the third, the fourth, the fifth, d the sixth terms, respectively. Fid the vlue of commo differece d usig the formul for clcultig the geerl term of rithmetic sequece. ( ) = + d = 6 = 0+ ( 6 )( d) 5= 0+( 5)( d) d = 5 5 d = 5 5 d = 3 Now, fid the vlues of, 3, 4, d ( )() = = +( )()= ( )() = = +( )()= ( )() = = +( )()= ( )() = = +( )()= Thus, the four rithmetic mes re -7, -4, -, d. The fiite rithmetic sequece is {-0, -7, -4, -,, 5}.

PREFACE. Synergy for Success in Mathematics 10 is designed for Grade 10 students based on the new K to

PREFACE. Synergy for Success in Mathematics 10 is designed for Grade 10 students based on the new K to Syergy for Success i Mthemtics 0 is desiged for Grde 0 studets bsed o the ew K to Curriculum relesed by the Deprtmet of Eductio. The textbook cotis ll the required lerig competecies d is supplemeted with

More information

PROGRESSIONS AND SERIES

PROGRESSIONS AND SERIES PROGRESSIONS AND SERIES A sequece is lso clled progressio. We ow study three importt types of sequeces: () The Arithmetic Progressio, () The Geometric Progressio, () The Hrmoic Progressio. Arithmetic Progressio.

More information

Section 6.3: Geometric Sequences

Section 6.3: Geometric Sequences 40 Chpter 6 Sectio 6.: Geometric Sequeces My jobs offer ul cost-of-livig icrese to keep slries cosistet with ifltio. Suppose, for exmple, recet college grdute fids positio s sles mger erig ul slry of $6,000.

More information

INFINITE SERIES. ,... having infinite number of terms is called infinite sequence and its indicated sum, i.e., a 1

INFINITE SERIES. ,... having infinite number of terms is called infinite sequence and its indicated sum, i.e., a 1 Appedix A.. Itroductio As discussed i the Chpter 9 o Sequeces d Series, sequece,,...,,... hvig ifiite umber of terms is clled ifiite sequece d its idicted sum, i.e., + + +... + +... is clled ifite series

More information

is an ordered list of numbers. Each number in a sequence is a term of a sequence. n-1 term

is an ordered list of numbers. Each number in a sequence is a term of a sequence. n-1 term Mthemticl Ptters. Arithmetic Sequeces. Arithmetic Series. To idetify mthemticl ptters foud sequece. To use formul to fid the th term of sequece. To defie, idetify, d pply rithmetic sequeces. To defie rithmetic

More information

Student Success Center Elementary Algebra Study Guide for the ACCUPLACER (CPT)

Student Success Center Elementary Algebra Study Guide for the ACCUPLACER (CPT) Studet Success Ceter Elemetry Algebr Study Guide for the ACCUPLACER (CPT) The followig smple questios re similr to the formt d cotet of questios o the Accuplcer Elemetry Algebr test. Reviewig these smples

More information

Taylor Polynomials. The Tangent Line. (a, f (a)) and has the same slope as the curve y = f (x) at that point. It is the best

Taylor Polynomials. The Tangent Line. (a, f (a)) and has the same slope as the curve y = f (x) at that point. It is the best Tylor Polyomils Let f () = e d let p() = 1 + + 1 + 1 6 3 Without usig clcultor, evlute f (1) d p(1) Ok, I m still witig With little effort it is possible to evlute p(1) = 1 + 1 + 1 (144) + 6 1 (178) =

More information

Chapter 7 Infinite Series

Chapter 7 Infinite Series MA Ifiite Series Asst.Prof.Dr.Supree Liswdi Chpter 7 Ifiite Series Sectio 7. Sequece A sequece c be thought of s list of umbers writte i defiite order:,,...,,... 2 The umber is clled the first term, 2

More information

Lincoln Land Community College Placement and Testing Office

Lincoln Land Community College Placement and Testing Office Licol Ld Commuity College Plcemet d Testig Office Elemetry Algebr Study Guide for the ACCUPLACER (CPT) A totl of questios re dmiistered i this test. The first type ivolves opertios with itegers d rtiol

More information

,... are the terms of the sequence. If the domain consists of the first n positive integers only, the sequence is a finite sequence.

,... are the terms of the sequence. If the domain consists of the first n positive integers only, the sequence is a finite sequence. Chpter 9 & 0 FITZGERALD MAT 50/5 SECTION 9. Sequece Defiitio A ifiite sequece is fuctio whose domi is the set of positive itegers. The fuctio vlues,,, 4,...,,... re the terms of the sequece. If the domi

More information

Chapter Real Numbers

Chapter Real Numbers Chpter. - Rel Numbers Itegers: coutig umbers, zero, d the egtive of the coutig umbers. ex: {,-3, -, -,,,, 3, } Rtiol Numbers: quotiets of two itegers with ozero deomitor; termitig or repetig decimls. ex:

More information

Chapter 2 Infinite Series Page 1 of 9

Chapter 2 Infinite Series Page 1 of 9 Chpter Ifiite eries Pge of 9 Chpter : Ifiite eries ectio A Itroductio to Ifiite eries By the ed of this sectio you will be ble to uderstd wht is met by covergece d divergece of ifiite series recogise geometric

More information

Unit 1. Extending the Number System. 2 Jordan School District

Unit 1. Extending the Number System. 2 Jordan School District Uit Etedig the Number System Jord School District Uit Cluster (N.RN. & N.RN.): Etedig Properties of Epoets Cluster : Etedig properties of epoets.. Defie rtiol epoets d eted the properties of iteger epoets

More information

EVALUATING DEFINITE INTEGRALS

EVALUATING DEFINITE INTEGRALS Chpter 4 EVALUATING DEFINITE INTEGRALS If the defiite itegrl represets re betwee curve d the x-xis, d if you c fid the re by recogizig the shpe of the regio, the you c evlute the defiite itegrl. Those

More information

Indices and Logarithms

Indices and Logarithms the Further Mthemtics etwork www.fmetwork.org.uk V 7 SUMMARY SHEET AS Core Idices d Logrithms The mi ides re AQA Ed MEI OCR Surds C C C C Lws of idices C C C C Zero, egtive d frctiol idices C C C C Bsic

More information

Geometric Sequences. Geometric Sequence. Geometric sequences have a common ratio.

Geometric Sequences. Geometric Sequence. Geometric sequences have a common ratio. s A geometric sequece is sequece such tht ech successive term is obtied from the previous term by multiplyig by fixed umber clled commo rtio. Exmples, 6, 8,, 6,..., 0, 0, 0, 80,... Geometric sequeces hve

More information

A GENERAL METHOD FOR SOLVING ORDINARY DIFFERENTIAL EQUATIONS: THE FROBENIUS (OR SERIES) METHOD

A GENERAL METHOD FOR SOLVING ORDINARY DIFFERENTIAL EQUATIONS: THE FROBENIUS (OR SERIES) METHOD Diol Bgoo () A GENERAL METHOD FOR SOLVING ORDINARY DIFFERENTIAL EQUATIONS: THE FROBENIUS (OR SERIES) METHOD I. Itroductio The first seprtio of vribles (see pplictios to Newto s equtios) is ver useful method

More information

Graphing Review Part 3: Polynomials

Graphing Review Part 3: Polynomials Grphig Review Prt : Polomils Prbols Recll, tht the grph of f ( ) is prbol. It is eve fuctio, hece it is smmetric bout the bout the -is. This mes tht f ( ) f ( ). Its grph is show below. The poit ( 0,0)

More information

YOUR FINAL IS THURSDAY, MAY 24 th from 10:30 to 12:15

YOUR FINAL IS THURSDAY, MAY 24 th from 10:30 to 12:15 Algebr /Trig Fil Em Study Guide (Sprig Semester) Mrs. Duphy YOUR FINAL IS THURSDAY, MAY 4 th from 10:30 to 1:15 Iformtio About the Fil Em The fil em is cumultive for secod semester, coverig Chpters, 3,

More information

INTEGRATION TECHNIQUES (TRIG, LOG, EXP FUNCTIONS)

INTEGRATION TECHNIQUES (TRIG, LOG, EXP FUNCTIONS) Mthemtics Revisio Guides Itegrtig Trig, Log d Ep Fuctios Pge of MK HOME TUITION Mthemtics Revisio Guides Level: AS / A Level AQA : C Edecel: C OCR: C OCR MEI: C INTEGRATION TECHNIQUES (TRIG, LOG, EXP FUNCTIONS)

More information

MTH 146 Class 16 Notes

MTH 146 Class 16 Notes MTH 46 Clss 6 Notes 0.4- Cotiued Motivtio: We ow cosider the rc legth of polr curve. Suppose we wish to fid the legth of polr curve curve i terms of prmetric equtios s: r f where b. We c view the cos si

More information

LEVEL I. ,... if it is known that a 1

LEVEL I. ,... if it is known that a 1 LEVEL I Fid the sum of first terms of the AP, if it is kow tht + 5 + 0 + 5 + 0 + = 5 The iterior gles of polygo re i rithmetic progressio The smllest gle is 0 d the commo differece is 5 Fid the umber of

More information

0 x < 5 PIECEWISE FUNCTIONS DAY1 4.7

0 x < 5 PIECEWISE FUNCTIONS DAY1 4.7 PIECEWISE FUNCTIONS DAY 7 GOAL Red fuctios of grphs represeted by more th oe equtio fuctios of grphs represeted by more th oe equtio Grph piecewise fuctios PIECEWISE FUNCTION A fuctio defied by two or

More information

Approximations of Definite Integrals

Approximations of Definite Integrals Approximtios of Defiite Itegrls So fr we hve relied o tiderivtives to evlute res uder curves, work doe by vrible force, volumes of revolutio, etc. More precisely, wheever we hve hd to evlute defiite itegrl

More information

SM2H. Unit 2 Polynomials, Exponents, Radicals & Complex Numbers Notes. 3.1 Number Theory

SM2H. Unit 2 Polynomials, Exponents, Radicals & Complex Numbers Notes. 3.1 Number Theory SMH Uit Polyomils, Epoets, Rdicls & Comple Numbers Notes.1 Number Theory .1 Addig, Subtrctig, d Multiplyig Polyomils Notes Moomil: A epressio tht is umber, vrible, or umbers d vribles multiplied together.

More information

( a n ) converges or diverges.

( a n ) converges or diverges. Chpter Ifiite Series Pge of Sectio E Rtio Test Chpter : Ifiite Series By the ed of this sectio you will be ble to uderstd the proof of the rtio test test series for covergece by pplyig the rtio test pprecite

More information

EXERCISE a a a 5. + a 15 NEETIIT.COM

EXERCISE a a a 5. + a 15 NEETIIT.COM - Dowlod our droid App. Sigle choice Type Questios EXERCISE -. The first term of A.P. of cosecutive iteger is p +. The sum of (p + ) terms of this series c be expressed s () (p + ) () (p + ) (p + ) ()

More information

1. (25 points) Use the limit definition of the definite integral and the sum formulas to compute. [1 x + x2

1. (25 points) Use the limit definition of the definite integral and the sum formulas to compute. [1 x + x2 Mth 3, Clculus II Fil Exm Solutios. (5 poits) Use the limit defiitio of the defiite itegrl d the sum formuls to compute 3 x + x. Check your swer by usig the Fudmetl Theorem of Clculus. Solutio: The limit

More information

GRAPHING LINEAR EQUATIONS. Linear Equations. x l ( 3,1 ) _x-axis. Origin ( 0, 0 ) Slope = change in y change in x. Equation for l 1.

GRAPHING LINEAR EQUATIONS. Linear Equations. x l ( 3,1 ) _x-axis. Origin ( 0, 0 ) Slope = change in y change in x. Equation for l 1. GRAPHING LINEAR EQUATIONS Qudrt II Qudrt I ORDERED PAIR: The first umer i the ordered pir is the -coordite d the secod umer i the ordered pir is the y-coordite. (, ) Origi ( 0, 0 ) _-is Lier Equtios Qudrt

More information

Westchester Community College Elementary Algebra Study Guide for the ACCUPLACER

Westchester Community College Elementary Algebra Study Guide for the ACCUPLACER Westchester Commuity College Elemetry Alger Study Guide for the ACCUPLACER Courtesy of Aims Commuity College The followig smple questios re similr to the formt d cotet of questios o the Accuplcer Elemetry

More information

Chapter Real Numbers

Chapter Real Numbers Chpter. - Rel Numbers Itegers: coutig umbers, zero, d the egtive of the coutig umbers. ex: {,-3, -, -, 0,,, 3, } Rtiol Numbers: quotiets of two itegers with ozero deomitor; termitig or repetig decimls.

More information

Numbers (Part I) -- Solutions

Numbers (Part I) -- Solutions Ley College -- For AMATYC SML Mth Competitio Cochig Sessios v.., [/7/00] sme s /6/009 versio, with presettio improvemets Numbers Prt I) -- Solutios. The equtio b c 008 hs solutio i which, b, c re distict

More information

Lesson-2 PROGRESSIONS AND SERIES

Lesson-2 PROGRESSIONS AND SERIES Lesso- PROGRESSIONS AND SERIES Arithmetic Progressio: A sequece of terms is sid to be i rithmetic progressio (A.P) whe the differece betwee y term d its preceedig term is fixed costt. This costt is clled

More information

Infinite Series Sequences: terms nth term Listing Terms of a Sequence 2 n recursively defined n+1 Pattern Recognition for Sequences Ex:

Infinite Series Sequences: terms nth term Listing Terms of a Sequence 2 n recursively defined n+1 Pattern Recognition for Sequences Ex: Ifiite Series Sequeces: A sequece i defied s fuctio whose domi is the set of positive itegers. Usully it s esier to deote sequece i subscript form rther th fuctio ottio.,, 3, re the terms of the sequece

More information

Chapter System of Equations

Chapter System of Equations hpter 4.5 System of Equtios After redig th chpter, you should be ble to:. setup simulteous lier equtios i mtrix form d vice-vers,. uderstd the cocept of the iverse of mtrix, 3. kow the differece betwee

More information

Name: A2RCC Midterm Review Unit 1: Functions and Relations Know your parent functions!

Name: A2RCC Midterm Review Unit 1: Functions and Relations Know your parent functions! Nme: ARCC Midterm Review Uit 1: Fuctios d Reltios Kow your pret fuctios! 1. The ccompyig grph shows the mout of rdio-ctivity over time. Defiitio of fuctio. Defiitio of 1-1. Which digrm represets oe-to-oe

More information

( ) k ( ) 1 T n 1 x = xk. Geometric series obtained directly from the definition. = 1 1 x. See also Scalars 9.1 ADV-1: lim n.

( ) k ( ) 1 T n 1 x = xk. Geometric series obtained directly from the definition. = 1 1 x. See also Scalars 9.1 ADV-1: lim n. Sclrs-9.0-ADV- Algebric Tricks d Where Tylor Polyomils Come From 207.04.07 A.docx Pge of Algebric tricks ivolvig x. You c use lgebric tricks to simplify workig with the Tylor polyomils of certi fuctios..

More information

8.3 Sequences & Series: Convergence & Divergence

8.3 Sequences & Series: Convergence & Divergence 8.3 Sequeces & Series: Covergece & Divergece A sequece is simply list of thigs geerted by rule More formlly, sequece is fuctio whose domi is the set of positive itegers, or turl umbers,,,3,. The rge of

More information

In an algebraic expression of the form (1), like terms are terms with the same power of the variables (in this case

In an algebraic expression of the form (1), like terms are terms with the same power of the variables (in this case Chpter : Algebr: A. Bckgroud lgebr: A. Like ters: I lgebric expressio of the for: () x b y c z x y o z d x... p x.. we cosider x, y, z to be vribles d, b, c, d,,, o,.. to be costts. I lgebric expressio

More information

334 MATHS SERIES DSE MATHS PREVIEW VERSION B SAMPLE TEST & FULL SOLUTION

334 MATHS SERIES DSE MATHS PREVIEW VERSION B SAMPLE TEST & FULL SOLUTION MATHS SERIES DSE MATHS PREVIEW VERSION B SAMPLE TEST & FULL SOLUTION TEST SAMPLE TEST III - P APER Questio Distributio INSTRUCTIONS:. Attempt ALL questios.. Uless otherwise specified, ll worig must be

More information

0 otherwise. sin( nx)sin( kx) 0 otherwise. cos( nx) sin( kx) dx 0 for all integers n, k.

0 otherwise. sin( nx)sin( kx) 0 otherwise. cos( nx) sin( kx) dx 0 for all integers n, k. . Computtio of Fourier Series I this sectio, we compute the Fourier coefficiets, f ( x) cos( x) b si( x) d b, i the Fourier series To do this, we eed the followig result o the orthogolity of the trigoometric

More information

Limit of a function:

Limit of a function: - Limit of fuctio: We sy tht f ( ) eists d is equl with (rel) umer L if f( ) gets s close s we wt to L if is close eough to (This defiitio c e geerlized for L y syig tht f( ) ecomes s lrge (or s lrge egtive

More information

1.3 Continuous Functions and Riemann Sums

1.3 Continuous Functions and Riemann Sums mth riem sums, prt 0 Cotiuous Fuctios d Riem Sums I Exmple we sw tht lim Lower() = lim Upper() for the fuctio!! f (x) = + x o [0, ] This is o ccidet It is exmple of the followig theorem THEOREM Let f be

More information

Students must always use correct mathematical notation, not calculator notation. the set of positive integers and zero, {0,1, 2, 3,...

Students must always use correct mathematical notation, not calculator notation. the set of positive integers and zero, {0,1, 2, 3,... Appedices Of the vrious ottios i use, the IB hs chose to dopt system of ottio bsed o the recommedtios of the Itertiol Orgiztio for Stdrdiztio (ISO). This ottio is used i the emitio ppers for this course

More information

[ 20 ] 1. Inequality exists only between two real numbers (not complex numbers). 2. If a be any real number then one and only one of there hold.

[ 20 ] 1. Inequality exists only between two real numbers (not complex numbers). 2. If a be any real number then one and only one of there hold. [ 0 ]. Iequlity eists oly betwee two rel umbers (ot comple umbers).. If be y rel umber the oe d oly oe of there hold.. If, b 0 the b 0, b 0.. (i) b if b 0 (ii) (iii) (iv) b if b b if either b or b b if

More information

Algebra II, Chapter 7. Homework 12/5/2016. Harding Charter Prep Dr. Michael T. Lewchuk. Section 7.1 nth roots and Rational Exponents

Algebra II, Chapter 7. Homework 12/5/2016. Harding Charter Prep Dr. Michael T. Lewchuk. Section 7.1 nth roots and Rational Exponents Algebr II, Chpter 7 Hrdig Chrter Prep 06-07 Dr. Michel T. Lewchuk Test scores re vilble olie. I will ot discuss the test. st retke opportuit Sturd Dec. If ou hve ot tke the test, it is our resposibilit

More information

Riemann Integration. Chapter 1

Riemann Integration. Chapter 1 Mesure, Itegrtio & Rel Alysis. Prelimiry editio. 8 July 2018. 2018 Sheldo Axler 1 Chpter 1 Riem Itegrtio This chpter reviews Riem itegrtio. Riem itegrtio uses rectgles to pproximte res uder grphs. This

More information

Definite Integral. The Left and Right Sums

Definite Integral. The Left and Right Sums Clculus Li Vs Defiite Itegrl. The Left d Right Sums The defiite itegrl rises from the questio of fidig the re betwee give curve d x-xis o itervl. The re uder curve c be esily clculted if the curve is give

More information

Lecture 2. Rational Exponents and Radicals. 36 y. b can be expressed using the. Rational Exponent, thus b. b can be expressed using the

Lecture 2. Rational Exponents and Radicals. 36 y. b can be expressed using the. Rational Exponent, thus b. b can be expressed using the Lecture. Rtiol Epoets d Rdicls Rtiol Epoets d Rdicls Lier Equtios d Iequlities i Oe Vrile Qudrtic Equtios Appedi A6 Nth Root - Defiitio Rtiol Epoets d Rdicls For turl umer, c e epressed usig the r is th

More information

MA123, Chapter 9: Computing some integrals (pp )

MA123, Chapter 9: Computing some integrals (pp ) MA13, Chpter 9: Computig some itegrls (pp. 189-05) Dte: Chpter Gols: Uderstd how to use bsic summtio formuls to evlute more complex sums. Uderstd how to compute its of rtiol fuctios t ifiity. Uderstd how

More information

Vectors. Vectors in Plane ( 2

Vectors. Vectors in Plane ( 2 Vectors Vectors i Ple ( ) The ide bout vector is to represet directiol force Tht mes tht every vector should hve two compoets directio (directiol slope) d mgitude (the legth) I the ple we preset vector

More information

Algebra 2 Readiness Summer Packet El Segundo High School

Algebra 2 Readiness Summer Packet El Segundo High School Algebr Rediess Suer Pcket El Segudo High School This pcket is desiged for those who hve copleted Geoetry d will be erolled i Algebr (CP or H) i the upcoig fll seester. Suer Pcket Algebr II Welcoe to Algebr

More information

Week 13 Notes: 1) Riemann Sum. Aim: Compute Area Under a Graph. Suppose we want to find out the area of a graph, like the one on the right:

Week 13 Notes: 1) Riemann Sum. Aim: Compute Area Under a Graph. Suppose we want to find out the area of a graph, like the one on the right: Week 1 Notes: 1) Riem Sum Aim: Compute Are Uder Grph Suppose we wt to fid out the re of grph, like the oe o the right: We wt to kow the re of the red re. Here re some wys to pproximte the re: We cut the

More information

Important Facts You Need To Know/Review:

Important Facts You Need To Know/Review: Importt Fcts You Need To Kow/Review: Clculus: If fuctio is cotiuous o itervl I, the its grph is coected o I If f is cotiuous, d lim g Emple: lim eists, the lim lim f g f g d lim cos cos lim 3 si lim, t

More information

BC Calculus Review Sheet

BC Calculus Review Sheet BC Clculus Review Sheet Whe you see the words. 1. Fid the re of the ubouded regio represeted by the itegrl (sometimes 1 f ( ) clled horizotl improper itegrl). This is wht you thik of doig.... Fid the re

More information

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11 UTCLIFFE NOTE: CALCULU WOKOWKI CHAPTER Ifiite eries Coverget or Diverget eries Cosider the sequece If we form the ifiite sum 0, 00, 000, 0 00 000, we hve wht is clled ifiite series We wt to fid the sum

More information

POWER SERIES R. E. SHOWALTER

POWER SERIES R. E. SHOWALTER POWER SERIES R. E. SHOWALTER. sequeces We deote by lim = tht the limit of the sequece { } is the umber. By this we me tht for y ε > 0 there is iteger N such tht < ε for ll itegers N. This mkes precise

More information

The Exponential Function

The Exponential Function The Epoetil Fuctio Defiitio: A epoetil fuctio with bse is defied s P for some costt P where 0 d. The most frequetly used bse for epoetil fuctio is the fmous umber e.788... E.: It hs bee foud tht oyge cosumptio

More information

Review of the Riemann Integral

Review of the Riemann Integral Chpter 1 Review of the Riem Itegrl This chpter provides quick review of the bsic properties of the Riem itegrl. 1.0 Itegrls d Riem Sums Defiitio 1.0.1. Let [, b] be fiite, closed itervl. A prtitio P of

More information

HIGHER SCHOOL CERTIFICATE EXAMINATION MATHEMATICS 3 UNIT (ADDITIONAL) AND 3/4 UNIT (COMMON) Time allowed Two hours (Plus 5 minutes reading time)

HIGHER SCHOOL CERTIFICATE EXAMINATION MATHEMATICS 3 UNIT (ADDITIONAL) AND 3/4 UNIT (COMMON) Time allowed Two hours (Plus 5 minutes reading time) HIGHER SCHOOL CERTIFICATE EXAMINATION 999 MATHEMATICS 3 UNIT (ADDITIONAL) AND 3/ UNIT (COMMON) Time llowed Two hours (Plus 5 miutes redig time) DIRECTIONS TO CANDIDATES Attempt ALL questios. ALL questios

More information

PEPERIKSAAN PERCUBAAN SPM TAHUN 2007 ADDITIONAL MATHEMATICS. Form Five. Paper 2. Two hours and thirty minutes

PEPERIKSAAN PERCUBAAN SPM TAHUN 2007 ADDITIONAL MATHEMATICS. Form Five. Paper 2. Two hours and thirty minutes SULIT 347/ 347/ Form Five Additiol Mthemtics Pper September 007 ½ hours PEPERIKSAAN PERCUBAAN SPM TAHUN 007 ADDITIONAL MATHEMATICS Form Five Pper Two hours d thirty miutes DO NOT OPEN THIS QUESTION PAPER

More information

We will begin by supplying the proof to (a).

We will begin by supplying the proof to (a). (The solutios of problem re mostly from Jeffrey Mudrock s HWs) Problem 1. There re three sttemet from Exmple 5.4 i the textbook for which we will supply proofs. The sttemets re the followig: () The spce

More information

INTEGRATION IN THEORY

INTEGRATION IN THEORY CHATER 5 INTEGRATION IN THEORY 5.1 AREA AROXIMATION 5.1.1 SUMMATION NOTATION Fibocci Sequece First, exmple of fmous sequece of umbers. This is commoly ttributed to the mthemtici Fibocci of is, lthough

More information

Assessment Center Elementary Algebra Study Guide for the ACCUPLACER (CPT)

Assessment Center Elementary Algebra Study Guide for the ACCUPLACER (CPT) Assessmet Ceter Elemetr Alger Stud Guide for the ACCUPLACER (CPT) The followig smple questios re similr to the formt d cotet of questios o the Accuplcer Elemetr Alger test. Reviewig these smples will give

More information

1 Tangent Line Problem

1 Tangent Line Problem October 9, 018 MAT18 Week Justi Ko 1 Tget Lie Problem Questio: Give the grph of fuctio f, wht is the slope of the curve t the poit, f? Our strteg is to pproimte the slope b limit of sect lies betwee poits,

More information

 n. A Very Interesting Example + + = d. + x3. + 5x4. math 131 power series, part ii 7. One of the first power series we examined was. 2!

 n. A Very Interesting Example + + = d. + x3. + 5x4. math 131 power series, part ii 7. One of the first power series we examined was. 2! mth power series, prt ii 7 A Very Iterestig Emple Oe of the first power series we emied ws! + +! + + +!! + I Emple 58 we used the rtio test to show tht the itervl of covergece ws (, ) Sice the series coverges

More information

Content: Essential Calculus, Early Transcendentals, James Stewart, 2007 Chapter 1: Functions and Limits., in a set B.

Content: Essential Calculus, Early Transcendentals, James Stewart, 2007 Chapter 1: Functions and Limits., in a set B. Review Sheet: Chpter Cotet: Essetil Clculus, Erly Trscedetls, Jmes Stewrt, 007 Chpter : Fuctios d Limits Cocepts, Defiitios, Lws, Theorems: A fuctio, f, is rule tht ssigs to ech elemet i set A ectly oe

More information

Laws of Integral Indices

Laws of Integral Indices A Lws of Itegrl Idices A. Positive Itegrl Idices I, is clled the se, is clled the idex lso clled the expoet. mes times.... Exmple Simplify 5 6 c Solutio 8 5 6 c 6 Exmple Simplify Solutio The results i

More information

10.5 Power Series. In this section, we are going to start talking about power series. A power series is a series of the form

10.5 Power Series. In this section, we are going to start talking about power series. A power series is a series of the form 0.5 Power Series I the lst three sectios, we ve spet most of tht time tlkig bout how to determie if series is coverget or ot. Now it is time to strt lookig t some specific kids of series d we will evetully

More information

Mathacle. PSet Stats, Concepts In Statistics Level Number Name: Date:

Mathacle. PSet Stats, Concepts In Statistics Level Number Name: Date: APPENDEX I. THE RAW ALGEBRA IN STATISTICS A I-1. THE INEQUALITY Exmple A I-1.1. Solve ech iequlity. Write the solutio i the itervl ottio..) 2 p - 6 p -8.) 2x- 3 < 5 Solutio:.). - 4 p -8 p³ 2 or pî[2, +

More information

y udv uv y v du 7.1 INTEGRATION BY PARTS

y udv uv y v du 7.1 INTEGRATION BY PARTS 7. INTEGRATION BY PARTS Ever differetitio rule hs correspodig itegrtio rule. For istce, the Substitutio Rule for itegrtio correspods to the Chi Rule for differetitio. The rule tht correspods to the Product

More information

Mu Alpha Theta National Convention: Denver, 2001 Sequences & Series Topic Test Alpha Division

Mu Alpha Theta National Convention: Denver, 2001 Sequences & Series Topic Test Alpha Division Mu Alph Thet Ntiol Covetio: Dever, 00 Sequeces & Series Topic Test Alph Divisio. Wht is the commo rtio of the geometric sequece, 7, 9,? 7 (C) 5. The commo differece of the rithmetic sequece,, 0, is 5 (C)

More information

2.1.1 Definition The Z-transform of a sequence x [n] is simply defined as (2.1) X re x k re x k r

2.1.1 Definition The Z-transform of a sequence x [n] is simply defined as (2.1) X re x k re x k r Z-Trsforms. INTRODUCTION TO Z-TRANSFORM The Z-trsform is coveiet d vluble tool for represetig, lyig d desigig discrete-time sigls d systems. It plys similr role i discrete-time systems to tht which Lplce

More information

National Quali cations AHEXEMPLAR PAPER ONLY

National Quali cations AHEXEMPLAR PAPER ONLY Ntiol Quli ctios AHEXEMPLAR PAPER ONLY EP/AH/0 Mthemtics Dte Not pplicble Durtio hours Totl mrks 00 Attempt ALL questios. You my use clcultor. Full credit will be give oly to solutios which coti pproprite

More information

Chapter 5. The Riemann Integral. 5.1 The Riemann integral Partitions and lower and upper integrals. Note: 1.5 lectures

Chapter 5. The Riemann Integral. 5.1 The Riemann integral Partitions and lower and upper integrals. Note: 1.5 lectures Chpter 5 The Riem Itegrl 5.1 The Riem itegrl Note: 1.5 lectures We ow get to the fudmetl cocept of itegrtio. There is ofte cofusio mog studets of clculus betwee itegrl d tiderivtive. The itegrl is (iformlly)

More information

Statistics for Financial Engineering Session 1: Linear Algebra Review March 18 th, 2006

Statistics for Financial Engineering Session 1: Linear Algebra Review March 18 th, 2006 Sttistics for Ficil Egieerig Sessio : Lier Algebr Review rch 8 th, 6 Topics Itroductio to trices trix opertios Determits d Crmer s rule Eigevlues d Eigevectors Quiz The cotet of Sessio my be fmilir to

More information

2. Infinite Series 3. Power Series 4. Taylor Series 5. Review Questions and Exercises 6. Sequences and Series with Maple

2. Infinite Series 3. Power Series 4. Taylor Series 5. Review Questions and Exercises 6. Sequences and Series with Maple Chpter II CALCULUS II.4 Sequeces d Series II.4 SEQUENCES AND SERIES Objectives: After the completio of this sectio the studet - should recll the defiitios of the covergece of sequece, d some limits; -

More information

SEQUENCES AND SERIES

SEQUENCES AND SERIES Sequeces ad 6 Sequeces Ad SEQUENCES AND SERIES Successio of umbers of which oe umber is desigated as the first, other as the secod, aother as the third ad so o gives rise to what is called a sequece. Sequeces

More information

FACULTY OF MATHEMATICAL STUDIES MATHEMATICS FOR PART I ENGINEERING. Lectures

FACULTY OF MATHEMATICAL STUDIES MATHEMATICS FOR PART I ENGINEERING. Lectures FACULTY OF MATHEMATICAL STUDIES MATHEMATICS FOR PART I ENGINEERING Lectures MODULE 0 FURTHER CALCULUS II. Sequeces d series. Rolle s theorem d me vlue theorems 3. Tlor s d Mcluri s theorems 4. L Hopitl

More information

B. Examples 1. Finite Sums finite sums are an example of Riemann Sums in which each subinterval has the same length and the same x i

B. Examples 1. Finite Sums finite sums are an example of Riemann Sums in which each subinterval has the same length and the same x i Mth 06 Clculus Sec. 5.: The Defiite Itegrl I. Riem Sums A. Def : Give y=f(x):. Let f e defied o closed itervl[,].. Prtitio [,] ito suitervls[x (i-),x i ] of legth Δx i = x i -x (i-). Let P deote the prtitio

More information

FOURIER SERIES PART I: DEFINITIONS AND EXAMPLES. To a 2π-periodic function f(x) we will associate a trigonometric series. a n cos(nx) + b n sin(nx),

FOURIER SERIES PART I: DEFINITIONS AND EXAMPLES. To a 2π-periodic function f(x) we will associate a trigonometric series. a n cos(nx) + b n sin(nx), FOURIER SERIES PART I: DEFINITIONS AND EXAMPLES To -periodic fuctio f() we will ssocite trigoometric series + cos() + b si(), or i terms of the epoetil e i, series of the form c e i. Z For most of the

More information

MATRIX ALGEBRA, Systems Linear Equations

MATRIX ALGEBRA, Systems Linear Equations MATRIX ALGEBRA, Systes Lier Equtios Now we chge to the LINEAR ALGEBRA perspective o vectors d trices to reforulte systes of lier equtios. If you fid the discussio i ters of geerl d gets lost i geerlity,

More information

Discrete Mathematics I Tutorial 12

Discrete Mathematics I Tutorial 12 Discrete Mthemtics I Tutoril Refer to Chpter 4., 4., 4.4. For ech of these sequeces fid recurrece reltio stisfied by this sequece. (The swers re ot uique becuse there re ifiitely my differet recurrece

More information

Limits and an Introduction to Calculus

Limits and an Introduction to Calculus Nme Chpter Limits d Itroductio to Clculus Sectio. Itroductio to Limits Objective: I this lesso ou lered how to estimte limits d use properties d opertios of limits. I. The Limit Cocept d Defiitio of Limit

More information

RADICALS. Upon completion, you should be able to. define the principal root of numbers. simplify radicals

RADICALS. Upon completion, you should be able to. define the principal root of numbers. simplify radicals RADICALS m 1 RADICALS Upo completio, you should be ble to defie the pricipl root of umbers simplify rdicls perform dditio, subtrctio, multiplictio, d divisio of rdicls Mthemtics Divisio, IMSP, UPLB Defiitio:

More information

Frequency-domain Characteristics of Discrete-time LTI Systems

Frequency-domain Characteristics of Discrete-time LTI Systems requecy-domi Chrcteristics of Discrete-time LTI Systems Prof. Siripog Potisuk LTI System descriptio Previous bsis fuctio: uit smple or DT impulse The iput sequece is represeted s lier combitio of shifted

More information

Surds, Indices, and Logarithms Radical

Surds, Indices, and Logarithms Radical MAT 6 Surds, Idices, d Logrithms Rdicl Defiitio of the Rdicl For ll rel, y > 0, d ll itegers > 0, y if d oly if y where is the ide is the rdicl is the rdicd. Surds A umber which c be epressed s frctio

More information

The Elementary Arithmetic Operators of Continued Fraction

The Elementary Arithmetic Operators of Continued Fraction Americ-Eursi Jourl of Scietific Reserch 0 (5: 5-63, 05 ISSN 88-6785 IDOSI Pulictios, 05 DOI: 0.589/idosi.ejsr.05.0.5.697 The Elemetry Arithmetic Opertors of Cotiued Frctio S. Mugssi d F. Mistiri Deprtmet

More information

Linear Programming. Preliminaries

Linear Programming. Preliminaries Lier Progrmmig Prelimiries Optimiztio ethods: 3L Objectives To itroduce lier progrmmig problems (LPP To discuss the stdrd d coicl form of LPP To discuss elemetry opertio for lier set of equtios Optimiztio

More information

Prior distributions. July 29, 2002

Prior distributions. July 29, 2002 Prior distributios Aledre Tchourbov PKI 357, UNOmh, South 67th St. Omh, NE 688-694, USA Phoe: 4554-64 E-mil: tchourb@cse.ul.edu July 9, Abstrct This documet itroduces prior distributios for the purposes

More information

Approximate Integration

Approximate Integration Study Sheet (7.7) Approimte Itegrtio I this sectio, we will ler: How to fid pproimte vlues of defiite itegrls. There re two situtios i which it is impossile to fid the ect vlue of defiite itegrl. Situtio:

More information

Linford 1. Kyle Linford. Math 211. Honors Project. Theorems to Analyze: Theorem 2.4 The Limit of a Function Involving a Radical (A4)

Linford 1. Kyle Linford. Math 211. Honors Project. Theorems to Analyze: Theorem 2.4 The Limit of a Function Involving a Radical (A4) Liford 1 Kyle Liford Mth 211 Hoors Project Theorems to Alyze: Theorem 2.4 The Limit of Fuctio Ivolvig Rdicl (A4) Theorem 2.8 The Squeeze Theorem (A5) Theorem 2.9 The Limit of Si(x)/x = 1 (p. 85) Theorem

More information

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11 SUTCLIFFE S NOTES: CALCULUS SWOKOWSKI S CHAPTER Ifiite Series.5 Altertig Series d Absolute Covergece Next, let us cosider series with both positive d egtive terms. The simplest d most useful is ltertig

More information

Northwest High School s Algebra 2

Northwest High School s Algebra 2 Northwest High School s Algebr Summer Review Pcket 0 DUE August 8, 0 Studet Nme This pcket hs bee desiged to help ou review vrious mthemticl topics tht will be ecessr for our success i Algebr. Istructios:

More information

Review of Sections

Review of Sections Review of Sectios.-.6 Mrch 24, 204 Abstrct This is the set of otes tht reviews the mi ides from Chpter coverig sequeces d series. The specific sectios tht we covered re s follows:.: Sequces..2: Series,

More information

The Definite Integral

The Definite Integral The Defiite Itegrl A Riem sum R S (f) is pproximtio to the re uder fuctio f. The true re uder the fuctio is obtied by tkig the it of better d better pproximtios to the re uder f. Here is the forml defiitio,

More information

UNIT 4 EXTENDING THE NUMBER SYSTEM Lesson 1: Working with the Number System Instruction

UNIT 4 EXTENDING THE NUMBER SYSTEM Lesson 1: Working with the Number System Instruction Lesso : Workig with the Nuber Syste Istructio Prerequisite Skills This lesso requires the use of the followig skills: evlutig expressios usig the order of opertios evlutig expoetil expressios ivolvig iteger

More information

ALGEBRA II CHAPTER 7 NOTES. Name

ALGEBRA II CHAPTER 7 NOTES. Name ALGEBRA II CHAPTER 7 NOTES Ne Algebr II 7. th Roots d Rtiol Expoets Tody I evlutig th roots of rel ubers usig both rdicl d rtiol expoet ottio. I successful tody whe I c evlute th roots. It is iportt for

More information

Some New Iterative Methods Based on Composite Trapezoidal Rule for Solving Nonlinear Equations

Some New Iterative Methods Based on Composite Trapezoidal Rule for Solving Nonlinear Equations Itertiol Jourl of Mthemtics d Sttistics Ivetio (IJMSI) E-ISSN: 31 767 P-ISSN: 31-759 Volume Issue 8 August. 01 PP-01-06 Some New Itertive Methods Bsed o Composite Trpezoidl Rule for Solvig Nolier Equtios

More information

The Reimann Integral is a formal limit definition of a definite integral

The Reimann Integral is a formal limit definition of a definite integral MATH 136 The Reim Itegrl The Reim Itegrl is forml limit defiitio of defiite itegrl cotiuous fuctio f. The costructio is s follows: f ( x) dx for Reim Itegrl: Prtitio [, ] ito suitervls ech hvig the equl

More information