On finite semifelds of prime degree. equivalence classifcation of subspaces of invertible matrices
|
|
- Lynn Simon
- 5 years ago
- Views:
Transcription
1 On finite semifields of prime degree and the equivalence classifcation of subspaces of invertible matrices John Sheekey Rod Gow Claude Shannon Institute School of Mathematical Science University College Dublin 15 July 2009 / 9th International Conference on Finite Fields and their Applications
2 Outline 1 Semifields and presemifields Primitive elements 2 3
3 Outline Semifields and presemifields Primitive elements 1 Semifields and presemifields Primitive elements 2 3
4 Semifields and presemifields Primitive elements Definition A finite presemifield S = (V, +, ) is a (not necessarily associative) division algebra over a finite field F q. Definition A presemifield is called a semifield if it contains a multiplicative identity. Multiplication is F q bilinear. S has no zero divisors. F q is called the associative centre of S
5 Semifields and presemifields Primitive elements Definition Two presemifields (V, +, ) and (V, +, ) are said to be isotopic if there exist invertible linear transformations A, B, C : V V such that A(x y) = B(x) C(y) for all x, y V Every presemifield is isotopic to a semifield There are many constructions, but classification is difficult, and only known up to size 125
6 Semifields and presemifields Primitive elements Example (Albert s twisted fields) Define a new multiplication on F q n by x y := xy cx α y β where α, β are F q -automorphisms of F q n, and c a α 1 b β 1 for any a, b F q n. Then S := (F q n, +, ) is a presemifield. Menichetti (1996) showed that all semifields of prime dimension over their associative centre F q, for q large enough, are twisted fields.
7 Outline Semifields and presemifields Primitive elements 1 Semifields and presemifields Primitive elements 2 3
8 Semifields and presemifields Primitive elements Definition An element a of S is said to be left primitive if the elements a (i := aa (i 1 exhaust the non-zero elements of S. Most known semifields contain a primitive element. However, there exist semifields of size 32 and 64 containing no left or right primitive elements (Hentzel & Rua 2007). We aim to prove that all semifields of prime dimension over their associative centre F q, for q large enough, contain both left and right primitive elements.
9 Outline 1 Semifields and presemifields Primitive elements 2 3
10 For any field, the maximum dimension of a subspace of n n invertibles is n. Definition We say that two subspaces S and T are equivalent if there exist invertible matrices X and Y such that T = {XAY A S} We will see that this is related to the classification of presemifields up to isotopy.
11 Lemma The matrices of left-multiplication of the elements of a semifield S form a n-dimensional subspace of invertible matrices over F q. Proof. For each non-zero element a S define an element of M n (F q ) by L a (x) := ax x S Then L a is clearly invertible, for L a (x) = 0 ax = 0 x = 0. Then the set L S := {L a a S} is a n-dimensional subspace of n n invertibles.
12 Lemma Every basis for a n-dimensional subspace of n n invertible matrices defines a unique presemifield Proof. Let B = {E 1, E 2,..., E n } be such a basis. Define a presemifield S B := (F n, +, ) by Then S is a presemifield x y := (x 1 E 1 + x 2 E x n E n )y Note that if S is a semifield, we take E 1 = I.
13 Lemma Two presemifields are isotopic if and only if their associated subspaces are equivalent, i.e. S T L S L T
14 Outline 1 Semifields and presemifields Primitive elements 2 3
15 Lemma An element a is left primitive if and only if its matrix of left multiplication A has primitive characteristic polynomial. Proof. Note that a (i = A i e Suppose a is primitive. Then A i e e 0 < i < q n 1 Hence A i I, so A must have primitive characteristic polynomial.
16 Proof. Suppose now that A has primitive characteristic polynomial. Then F(A) = F q n Hence if 0 < i < q n 1, A i I is a non-zero element of F(A), and is hence invertible. Therefore, A i e e, and so a is a left primitive element. Hence it suffices to show that every subspace of n n invertibles contains a matrix with primitive characteristic polynomial.
17 Outline 1 Semifields and presemifields Primitive elements 2 3
18 Let {E 1 = I, E 2,..., E n } be a basis for a subspace of invertible matrices, obtained from a semifield S. Define a polynomial f S F q [x 1, x 2,..., x n ] by f S (x 1, x 2,..., x n ) := det(x 1 I + x 2 E x n E n ) Then f S is a degree n homogeneous polynomial in n variables, which has no non-trivial zeros in F n q.
19 Theorem (Chevalley-Warning) Let f be a homogeneous polynomial over F in m variables of degree d. Then if d < m, f has a non-trivial zero. Lemma The product of two polynomials g and h is homogeneous if and only if g and h are both homogeneous. Corollary Let f be a homogeneous polynomial over F in m variables of degree m with no non-trivial zeroes. Then f is irreducible over F.
20 Definition A polynomial in F[x 1,..., x m ] is said to be absolutely irreducible if it is irreducible in every finite algebraic extension of F (or, equivalently, is irreducible over F, the algebraic closure of F). Theorem (Lang-Weil) Let f be an absolutely irreducible homogeneous polynomial over F q in m variables of degree d. Then N, the number of zeros of f in F n q, satisfies N q m 1 (d 1)(d 2)q m Cq m 2 for some C which does not depend on q.
21 Cafure-Matera gave an explicit bound: Theorem (Cafure, Matera (2006)) Let f be as above. Then N q m 1 (d 1)(d 2)q m d 13 3 q m 2 Hence the polynomial arising from a subspace of invertibles is irreducible, but, for q large enough, cannot be absolutely irreducible.
22 We will show that, for n prime, this means that it must be a norm form : Definition A homogeneous polynomial f in n variables is said to be a norm form if f = gg σ... g σn 1 = n 1 i=0 g σi where g is a linear form in F q n[x 1,..., x n ], and σ is the Frobenuis automorphism.
23 Lemma Let f be an irreducible homogeneous polynomial over F q in n variables of degree n. Suppose f has a non-trivial factor g of degree r, irreducible over F q m, for some m. Then n = mr, and f = λgg σ... g σm 1 for some λ F q.
24 Proof. Let f = gh in F q m[x 1,..., x n ]. Then f σi = f = g σi h σi for all i. Since g is irreducible, g σi is irreducible for all i. Hence G := gg σ... g σm 1 divides f. (UFD) But G σ = G, and so G F q [x 1,..., x n ]. But f is irreducible in F q [x 1,..., x n ], therefore f = λg for some λ F q as claimed.
25 Outline 1 Semifields and presemifields Primitive elements 2 3
26 Hence we have the following: Lemma Let S be a presemifield of prime dimension n over it s associative centre F q. Then for q large enough, f S is a norm form over F q n Proof. We saw that f S is irreducible, but not absolutely irreducible. Hence f S has a divisor g of degree r over F q m, where mr = n and r n. But n is prime, and hence m = n and r = 1, i.e. f S is a norm form over F q n
27 Hence we can prove our main result... Theorem Let S be a semifield of prime degree n over it s associative centre F = F q. Then if q is large enough, S contains a primitive element. Proof. We have seen that f S must be a norm form in F q n, i.e. n 1 f S (x 1, x 2,..., x n ) = (x 1 + a 2 x a n x n ) σi i=0 for some a 2,..., a n F q n. Let α = a 1 λ 1 + a 2 λ a n λ n be a primitive element of F q n. Let A = λ 1 I λ n E n.
28 Proof. Then char(a) = det(xi A) = f S (x λ 1, λ 2,..., λ n ) n 1 = (x α) σi i=0 which is a primitive polynomial by definition. Example If n = 5 and q > 6296, then S contains a left- and right-primitive element. (for n = 3, every semifield contains primitive elements by a result of Rúa.)
29 We have shown that if q is large enough and n is prime, then any semifield of size q n with associative centre F q contains a right and left primitive element
30 References D.E. Knuth, Finite Semifields and Projective Planes, J. Algebra 2 (1965) Kantor, Finite Semifields, Finite Geometries, Groups, and Computation (2006) Rua, Primitive and non-primitive Finite Semifields, Communications in Algebra (2004) Menichetti, n-dimensional algebras over a field with a cyclic extension of degree n, Geom. Ded. (1996) Cafure Matera, Improved explicit estimates on the number of solutions of equations over a finite field, Finite Fields Appl. (2006)
COMMUTATIVE PRESEMIFIELDS AND SEMIFIELDS
COMMUTATIVE PRESEMIFIELDS AND SEMIFIELDS ROBERT S. COULTER AND MARIE HENDERSON Abstract. Strong conditions are derived for when two commutative presemifields are isotopic. It is then shown that any commutative
More informationCOMMUTATIVE SEMIFIELDS OF ORDER 243 AND 3125
COMMUTATIVE SEMIFIELDS OF ORDER 243 AND 3125 ROBERT S. COULTER AND PAMELA KOSICK Abstract. This note summarises a recent search for commutative semifields of order 243 and 3125. For each of these two orders,
More informationSEMIFIELDS ARISING FROM IRREDUCIBLE SEMILINEAR TRANSFORMATIONS
J. Aust. Math. Soc. 85 (28), 333 339 doi:.7/s44678878888 SEMIFIELDS ARISING FROM IRREDUCIBLE SEMILINEAR TRANSFORMATIONS WILLIAM M. KANTOR and ROBERT A. LIEBLER (Received 4 February 28; accepted 7 September
More informationSolutions of exercise sheet 8
D-MATH Algebra I HS 14 Prof. Emmanuel Kowalski Solutions of exercise sheet 8 1. In this exercise, we will give a characterization for solvable groups using commutator subgroups. See last semester s (Algebra
More information55 Separable Extensions
55 Separable Extensions In 54, we established the foundations of Galois theory, but we have no handy criterion for determining whether a given field extension is Galois or not. Even in the quite simple
More informationg(x) = 1 1 x = 1 + x + x2 + x 3 + is not a polynomial, since it doesn t have finite degree. g(x) is an example of a power series.
6 Polynomial Rings We introduce a class of rings called the polynomial rings, describing computation, factorization and divisibility in such rings For the case where the coefficients come from an integral
More informationSection VI.33. Finite Fields
VI.33 Finite Fields 1 Section VI.33. Finite Fields Note. In this section, finite fields are completely classified. For every prime p and n N, there is exactly one (up to isomorphism) field of order p n,
More informationJanuary 2016 Qualifying Examination
January 2016 Qualifying Examination If you have any difficulty with the wording of the following problems please contact the supervisor immediately. All persons responsible for these problems, in principle,
More informationSection III.6. Factorization in Polynomial Rings
III.6. Factorization in Polynomial Rings 1 Section III.6. Factorization in Polynomial Rings Note. We push several of the results in Section III.3 (such as divisibility, irreducibility, and unique factorization)
More informationUNIVERSITÀ DEGLI STUDI DI ROMA LA SAPIENZA. Semifield spreads
UNIVERSITÀ DEGLI STUDI DI ROMA LA SAPIENZA Semifield spreads Giuseppe Marino and Olga Polverino Quaderni Elettronici del Seminario di Geometria Combinatoria 24E (Dicembre 2007) http://www.mat.uniroma1.it/~combinat/quaderni
More informationChapter 4 Finite Fields
Chapter 4 Finite Fields Introduction will now introduce finite fields of increasing importance in cryptography AES, Elliptic Curve, IDEA, Public Key concern operations on numbers what constitutes a number
More informationD-MATH Algebra I HS18 Prof. Rahul Pandharipande. Solution 6. Unique Factorization Domains
D-MATH Algebra I HS18 Prof. Rahul Pandharipande Solution 6 Unique Factorization Domains 1. Let R be a UFD. Let that a, b R be coprime elements (that is, gcd(a, b) R ) and c R. Suppose that a c and b c.
More informationAlgebra Qualifying Exam August 2001 Do all 5 problems. 1. Let G be afinite group of order 504 = 23 32 7. a. Show that G cannot be isomorphic to a subgroup of the alternating group Alt 7. (5 points) b.
More informationPolynomials over UFD s
Polynomials over UFD s Let R be a UFD and let K be the field of fractions of R. Our goal is to compare arithmetic in the rings R[x] and K[x]. We introduce the following notion. Definition 1. A non-constant
More informationMath 120 HW 9 Solutions
Math 120 HW 9 Solutions June 8, 2018 Question 1 Write down a ring homomorphism (no proof required) f from R = Z[ 11] = {a + b 11 a, b Z} to S = Z/35Z. The main difficulty is to find an element x Z/35Z
More informationFactorization in Polynomial Rings
Factorization in Polynomial Rings These notes are a summary of some of the important points on divisibility in polynomial rings from 17 and 18. PIDs Definition 1 A principal ideal domain (PID) is an integral
More informationMathematical Olympiad Training Polynomials
Mathematical Olympiad Training Polynomials Definition A polynomial over a ring R(Z, Q, R, C) in x is an expression of the form p(x) = a n x n + a n 1 x n 1 + + a 1 x + a 0, a i R, for 0 i n. If a n 0,
More informationSolutions for Math 225 Assignment #4 1
Solutions for Math 225 Assignment #4 () Let B {(3, 4), (4, 5)} and C {(, ), (0, )} be two ordered bases of R 2 (a) Find the change-of-basis matrices P C B and P B C (b) Find v] B if v] C ] (c) Find v]
More informationFinite Fields. Saravanan Vijayakumaran Department of Electrical Engineering Indian Institute of Technology Bombay
1 / 25 Finite Fields Saravanan Vijayakumaran sarva@ee.iitb.ac.in Department of Electrical Engineering Indian Institute of Technology Bombay September 25, 2014 2 / 25 Fields Definition A set F together
More informationModern Computer Algebra
Modern Computer Algebra Exercises to Chapter 25: Fundamental concepts 11 May 1999 JOACHIM VON ZUR GATHEN and JÜRGEN GERHARD Universität Paderborn 25.1 Show that any subgroup of a group G contains the neutral
More informationA Generalization of Wilson s Theorem
A Generalization of Wilson s Theorem R. Andrew Ohana June 3, 2009 Contents 1 Introduction 2 2 Background Algebra 2 2.1 Groups................................. 2 2.2 Rings.................................
More informationAutomorphisms and bases
Chapter 5 Automorphisms and bases 10 Automorphisms In this chapter, we will once again adopt the viewpoint that a finite extension F = F q m of a finite field K = F q is a vector space of dimension m over
More informationPractice Algebra Qualifying Exam Solutions
Practice Algebra Qualifying Exam Solutions 1. Let A be an n n matrix with complex coefficients. Define tr A to be the sum of the diagonal elements. Show that tr A is invariant under conjugation, i.e.,
More informationSection X.55. Cyclotomic Extensions
X.55 Cyclotomic Extensions 1 Section X.55. Cyclotomic Extensions Note. In this section we return to a consideration of roots of unity and consider again the cyclic group of roots of unity as encountered
More informationFIELD THEORY. Contents
FIELD THEORY MATH 552 Contents 1. Algebraic Extensions 1 1.1. Finite and Algebraic Extensions 1 1.2. Algebraic Closure 5 1.3. Splitting Fields 7 1.4. Separable Extensions 8 1.5. Inseparable Extensions
More informationTROPICAL SCHEME THEORY
TROPICAL SCHEME THEORY 5. Commutative algebra over idempotent semirings II Quotients of semirings When we work with rings, a quotient object is specified by an ideal. When dealing with semirings (and lattices),
More informationMATH 101A: ALGEBRA I, PART D: GALOIS THEORY 11
MATH 101A: ALGEBRA I, PART D: GALOIS THEORY 11 3. Examples I did some examples and explained the theory at the same time. 3.1. roots of unity. Let L = Q(ζ) where ζ = e 2πi/5 is a primitive 5th root of
More informationHASSE-MINKOWSKI THEOREM
HASSE-MINKOWSKI THEOREM KIM, SUNGJIN 1. Introduction In rough terms, a local-global principle is a statement that asserts that a certain property is true globally if and only if it is true everywhere locally.
More informationCore Mathematics 2 Algebra
Core Mathematics 2 Algebra Edited by: K V Kumaran Email: kvkumaran@gmail.com Core Mathematics 2 Algebra 1 Algebra and functions Simple algebraic division; use of the Factor Theorem and the Remainder Theorem.
More informationx 9 or x > 10 Name: Class: Date: 1 How many natural numbers are between 1.5 and 4.5 on the number line?
1 How many natural numbers are between 1.5 and 4.5 on the number line? 2 How many composite numbers are between 7 and 13 on the number line? 3 How many prime numbers are between 7 and 20 on the number
More informationarxiv: v1 [math.gr] 8 Nov 2008
SUBSPACES OF 7 7 SKEW-SYMMETRIC MATRICES RELATED TO THE GROUP G 2 arxiv:0811.1298v1 [math.gr] 8 Nov 2008 ROD GOW Abstract. Let K be a field of characteristic different from 2 and let C be an octonion algebra
More informationAlgebra Review 2. 1 Fields. A field is an extension of the concept of a group.
Algebra Review 2 1 Fields A field is an extension of the concept of a group. Definition 1. A field (F, +,, 0 F, 1 F ) is a set F together with two binary operations (+, ) on F such that the following conditions
More informationNOTES ON FINITE FIELDS
NOTES ON FINITE FIELDS AARON LANDESMAN CONTENTS 1. Introduction to finite fields 2 2. Definition and constructions of fields 3 2.1. The definition of a field 3 2.2. Constructing field extensions by adjoining
More informationExplicit classes of permutation polynomials of F 3
Science in China Series A: Mathematics Apr., 2009, Vol. 53, No. 4, 639 647 www.scichina.com math.scichina.com www.springerlink.com Explicit classes of permutation polynomials of F 3 3m DING CunSheng 1,XIANGQing
More informationSection IV.23. Factorizations of Polynomials over a Field
IV.23 Factorizations of Polynomials 1 Section IV.23. Factorizations of Polynomials over a Field Note. Our experience with classical algebra tells us that finding the zeros of a polynomial is equivalent
More informationThe primitive root theorem
The primitive root theorem Mar Steinberger First recall that if R is a ring, then a R is a unit if there exists b R with ab = ba = 1. The collection of all units in R is denoted R and forms a group under
More informationMath 547, Exam 2 Information.
Math 547, Exam 2 Information. 3/19/10, LC 303B, 10:10-11:00. Exam 2 will be based on: Homework and textbook sections covered by lectures 2/3-3/5. (see http://www.math.sc.edu/ boylan/sccourses/547sp10/547.html)
More informationDiscrete Math, Second Problem Set (June 24)
Discrete Math, Second Problem Set (June 24) REU 2003 Instructor: Laszlo Babai Scribe: D Jeremy Copeland 1 Number Theory Remark 11 For an arithmetic progression, a 0, a 1 = a 0 +d, a 2 = a 0 +2d, to have
More informationABSTRACT ALGEBRA 2 SOLUTIONS TO THE PRACTICE EXAM AND HOMEWORK
ABSTRACT ALGEBRA 2 SOLUTIONS TO THE PRACTICE EXAM AND HOMEWORK 1. Practice exam problems Problem A. Find α C such that Q(i, 3 2) = Q(α). Solution to A. Either one can use the proof of the primitive element
More informationARCS IN FINITE PROJECTIVE SPACES. Basic objects and definitions
ARCS IN FINITE PROJECTIVE SPACES SIMEON BALL Abstract. These notes are an outline of a course on arcs given at the Finite Geometry Summer School, University of Sussex, June 26-30, 2017. Let K denote an
More informationFinite Fields. Mike Reiter
1 Finite Fields Mike Reiter reiter@cs.unc.edu Based on Chapter 4 of: W. Stallings. Cryptography and Network Security, Principles and Practices. 3 rd Edition, 2003. Groups 2 A group G, is a set G of elements
More informationbe any ring homomorphism and let s S be any element of S. Then there is a unique ring homomorphism
21. Polynomial rings Let us now turn out attention to determining the prime elements of a polynomial ring, where the coefficient ring is a field. We already know that such a polynomial ring is a UFD. Therefore
More informationList of topics for the preliminary exam in algebra
List of topics for the preliminary exam in algebra 1 Basic concepts 1. Binary relations. Reflexive, symmetric/antisymmetryc, and transitive relations. Order and equivalence relations. Equivalence classes.
More informationTHE MULTIPLICATIVE LOOPS OF JHA-JOHNSON SEMIFIELDS
THE MULTIPLICATIVE LOOPS OF JHA-JOHNSON SEMIFIELDS S. PUMPLÜN Abstract. The multiplicative loops of Jha-Johnson semifields are non-automorphic finite loops whose left and right nuclei are the multiplicative
More informationMath Introduction to Modern Algebra
Math 343 - Introduction to Modern Algebra Notes Field Theory Basics Let R be a ring. M is called a maximal ideal of R if M is a proper ideal of R and there is no proper ideal of R that properly contains
More informationSection V.7. Cyclic Extensions
V.7. Cyclic Extensions 1 Section V.7. Cyclic Extensions Note. In the last three sections of this chapter we consider specific types of Galois groups of Galois extensions and then study the properties of
More informationφ(xy) = (xy) n = x n y n = φ(x)φ(y)
Groups 1. (Algebra Comp S03) Let A, B and C be normal subgroups of a group G with A B. If A C = B C and AC = BC then prove that A = B. Let b B. Since b = b1 BC = AC, there are a A and c C such that b =
More information2 (17) Find non-trivial left and right ideals of the ring of 22 matrices over R. Show that there are no nontrivial two sided ideals. (18) State and pr
MATHEMATICS Introduction to Modern Algebra II Review. (1) Give an example of a non-commutative ring; a ring without unit; a division ring which is not a eld and a ring which is not a domain. (2) Show that
More informationAlgebra Homework, Edition 2 9 September 2010
Algebra Homework, Edition 2 9 September 2010 Problem 6. (1) Let I and J be ideals of a commutative ring R with I + J = R. Prove that IJ = I J. (2) Let I, J, and K be ideals of a principal ideal domain.
More informationMath 2070BC Term 2 Weeks 1 13 Lecture Notes
Math 2070BC 2017 18 Term 2 Weeks 1 13 Lecture Notes Keywords: group operation multiplication associative identity element inverse commutative abelian group Special Linear Group order infinite order cyclic
More informationChapter 8. P-adic numbers. 8.1 Absolute values
Chapter 8 P-adic numbers Literature: N. Koblitz, p-adic Numbers, p-adic Analysis, and Zeta-Functions, 2nd edition, Graduate Texts in Mathematics 58, Springer Verlag 1984, corrected 2nd printing 1996, Chap.
More informationDivision Algebras. Konrad Voelkel
Division Algebras Konrad Voelkel 2015-01-27 Contents 1 Big Picture 1 2 Algebras 2 2.1 Finite fields................................... 2 2.2 Algebraically closed fields........................... 2 2.3
More informationDetecting Rational Points on Hypersurfaces over Finite Fields
Detecting Rational Points on Hypersurfaces over Finite Fields Swastik Kopparty CSAIL, MIT swastik@mit.edu Sergey Yekhanin IAS yekhanin@ias.edu Abstract We study the complexity of deciding whether a given
More informationALGEBRA QUALIFYING EXAM SPRING 2012
ALGEBRA QUALIFYING EXAM SPRING 2012 Work all of the problems. Justify the statements in your solutions by reference to specific results, as appropriate. Partial credit is awarded for partial solutions.
More informationGroup Theory. 1. Show that Φ maps a conjugacy class of G into a conjugacy class of G.
Group Theory Jan 2012 #6 Prove that if G is a nonabelian group, then G/Z(G) is not cyclic. Aug 2011 #9 (Jan 2010 #5) Prove that any group of order p 2 is an abelian group. Jan 2012 #7 G is nonabelian nite
More informationHow might we evaluate this? Suppose that, by some good luck, we knew that. x 2 5. x 2 dx 5
8.4 1 8.4 Partial Fractions Consider the following integral. 13 2x (1) x 2 x 2 dx How might we evaluate this? Suppose that, by some good luck, we knew that 13 2x (2) x 2 x 2 = 3 x 2 5 x + 1 We could then
More informationFinite Fields. [Parts from Chapter 16. Also applications of FTGT]
Finite Fields [Parts from Chapter 16. Also applications of FTGT] Lemma [Ch 16, 4.6] Assume F is a finite field. Then the multiplicative group F := F \ {0} is cyclic. Proof Recall from basic group theory
More informationClassification of Finite Fields
Classification of Finite Fields In these notes we use the properties of the polynomial x pd x to classify finite fields. The importance of this polynomial is explained by the following basic proposition.
More informationSemifields, Relative Difference Sets, and Bent Functions
Semifields, Relative Difference Sets, and Bent Functions Alexander Pott Otto-von-Guericke-University Magdeburg December 09, 2013 1 / 34 Outline, or: 2 / 34 Outline, or: Why I am nervous 2 / 34 Outline,
More information9. Finite fields. 1. Uniqueness
9. Finite fields 9.1 Uniqueness 9.2 Frobenius automorphisms 9.3 Counting irreducibles 1. Uniqueness Among other things, the following result justifies speaking of the field with p n elements (for prime
More informationMTH310 EXAM 2 REVIEW
MTH310 EXAM 2 REVIEW SA LI 4.1 Polynomial Arithmetic and the Division Algorithm A. Polynomial Arithmetic *Polynomial Rings If R is a ring, then there exists a ring T containing an element x that is not
More informationMath 554 Qualifying Exam. You may use any theorems from the textbook. Any other claims must be proved in details.
Math 554 Qualifying Exam January, 2019 You may use any theorems from the textbook. Any other claims must be proved in details. 1. Let F be a field and m and n be positive integers. Prove the following.
More informationSection 33 Finite fields
Section 33 Finite fields Instructor: Yifan Yang Spring 2007 Review Corollary (23.6) Let G be a finite subgroup of the multiplicative group of nonzero elements in a field F, then G is cyclic. Theorem (27.19)
More information1. Algebra 1.5. Polynomial Rings
1. ALGEBRA 19 1. Algebra 1.5. Polynomial Rings Lemma 1.5.1 Let R and S be rings with identity element. If R > 1 and S > 1, then R S contains zero divisors. Proof. The two elements (1, 0) and (0, 1) are
More informationTC10 / 3. Finite fields S. Xambó
TC10 / 3. Finite fields S. Xambó The ring Construction of finite fields The Frobenius automorphism Splitting field of a polynomial Structure of the multiplicative group of a finite field Structure of the
More information(Can) Canonical Forms Math 683L (Summer 2003) M n (F) C((x λ) ) =
(Can) Canonical Forms Math 683L (Summer 2003) Following the brief interlude to study diagonalisable transformations and matrices, we must now get back to the serious business of the general case. In this
More informationOn Permutation Polynomials over Local Finite Commutative Rings
International Journal of Algebra, Vol. 12, 2018, no. 7, 285-295 HIKARI Ltd, www.m-hikari.com https://doi.org/10.12988/ija.2018.8935 On Permutation Polynomials over Local Finite Commutative Rings Javier
More informationMath Circles: Number Theory III
Math Circles: Number Theory III Centre for Education in Mathematics and Computing University of Waterloo March 9, 2011 A prime-generating polynomial The polynomial f (n) = n 2 n + 41 generates a lot of
More information3 Galois Theory. 3.1 Definitions and Examples
3 Galois Theory 3.1 Definitions and Examples This section of notes roughly follows Section 14.1 in Dummit and Foote. Let F be a field and let f (x) 2 F[x]. In the previous chapter, we proved that there
More informationSample algebra qualifying exam
Sample algebra qualifying exam University of Hawai i at Mānoa Spring 2016 2 Part I 1. Group theory In this section, D n and C n denote, respectively, the symmetry group of the regular n-gon (of order 2n)
More informationThe Hilbert-Mumford Criterion
The Hilbert-Mumford Criterion Klaus Pommerening Johannes-Gutenberg-Universität Mainz, Germany January 1987 Last change: April 4, 2017 The notions of stability and related notions apply for actions of algebraic
More informationUNDERSTANDING RULER AND COMPASS CONSTRUCTIONS WITH FIELD THEORY
UNDERSTANDING RULER AND COMPASS CONSTRUCTIONS WITH FIELD THEORY ISAAC M. DAVIS Abstract. By associating a subfield of R to a set of points P 0 R 2, geometric properties of ruler and compass constructions
More informationComputing Error Distance of Reed-Solomon Codes
Computing Error Distance of Reed-Solomon Codes Guizhen Zhu Institute For Advanced Study Tsinghua University, Beijing, 100084, PR China Email:zhugz08@mailstsinghuaeducn Daqing Wan Department of Mathematics
More informationSolutions for Field Theory Problem Set 1
Solutions for Field Theory Problem Set 1 FROM THE TEXT: Page 355, 2a. ThefieldisK = Q( 3, 6). NotethatK containsqand 3and 6 3 1 = 2. Thus, K contains the field Q( 2, 3). In fact, those two fields are the
More informationPolynomials. Chapter 4
Chapter 4 Polynomials In this Chapter we shall see that everything we did with integers in the last Chapter we can also do with polynomials. Fix a field F (e.g. F = Q, R, C or Z/(p) for a prime p). Notation
More informationIUPUI Qualifying Exam Abstract Algebra
IUPUI Qualifying Exam Abstract Algebra January 2017 Daniel Ramras (1) a) Prove that if G is a group of order 2 2 5 2 11, then G contains either a normal subgroup of order 11, or a normal subgroup of order
More informationDETAILED ANSWERS TO STARRED EXERCISES
DETAILED ANSWERS TO STARRED EXERCISES 1. Series 1 We fix an integer n > 1 and consider the symmetric group S n := Sym({1,..., n}). For a polynomial p(x 1,..., X n ) C[X 1,..., X n ] in n variables and
More informationThe Proj Construction
The Proj Construction Daniel Murfet May 16, 2006 Contents 1 Basic Properties 1 2 Functorial Properties 2 3 Products 6 4 Linear Morphisms 9 5 Projective Morphisms 9 6 Dimensions of Schemes 11 7 Points of
More information6]. (10) (i) Determine the units in the rings Z[i] and Z[ 10]. If n is a squarefree
Quadratic extensions Definition: Let R, S be commutative rings, R S. An extension of rings R S is said to be quadratic there is α S \R and monic polynomial f(x) R[x] of degree such that f(α) = 0 and S
More informationExample: This theorem is the easiest way to test an ideal (or an element) is prime. Z[x] (x)
Math 4010/5530 Factorization Theory January 2016 Let R be an integral domain. Recall that s, t R are called associates if they differ by a unit (i.e. there is some c R such that s = ct). Let R be a commutative
More informationAugust 2015 Qualifying Examination Solutions
August 2015 Qualifying Examination Solutions If you have any difficulty with the wording of the following problems please contact the supervisor immediately. All persons responsible for these problems,
More informationTheorem 5.3. Let E/F, E = F (u), be a simple field extension. Then u is algebraic if and only if E/F is finite. In this case, [E : F ] = deg f u.
5. Fields 5.1. Field extensions. Let F E be a subfield of the field E. We also describe this situation by saying that E is an extension field of F, and we write E/F to express this fact. If E/F is a field
More informationNoncommutative invariant theory and Auslander s Theorem
Noncommutative invariant theory and Auslander s Theorem Miami University Algebra Seminar Robert Won Wake Forest University Joint with Jason Gaddis, Ellen Kirkman, and Frank Moore arxiv:1707.02822 November
More informationElementary operation matrices: row addition
Elementary operation matrices: row addition For t a, let A (n,t,a) be the n n matrix such that { A (n,t,a) 1 if r = c, or if r = t and c = a r,c = 0 otherwise A (n,t,a) = I + e t e T a Example: A (5,2,4)
More informationFactorization in Polynomial Rings
Factorization in Polynomial Rings Throughout these notes, F denotes a field. 1 Long division with remainder We begin with some basic definitions. Definition 1.1. Let f, g F [x]. We say that f divides g,
More information1 Rings 1 RINGS 1. Theorem 1.1 (Substitution Principle). Let ϕ : R R be a ring homomorphism
1 RINGS 1 1 Rings Theorem 1.1 (Substitution Principle). Let ϕ : R R be a ring homomorphism (a) Given an element α R there is a unique homomorphism Φ : R[x] R which agrees with the map ϕ on constant polynomials
More informationbut no smaller power is equal to one. polynomial is defined to be
13. Radical and Cyclic Extensions The main purpose of this section is to look at the Galois groups of x n a. The first case to consider is a = 1. Definition 13.1. Let K be a field. An element ω K is said
More informationStructure of elliptic curves and addition laws
Structure of elliptic curves and addition laws David R. Kohel Institut de Mathématiques de Luminy Barcelona 9 September 2010 Elliptic curve models We are interested in explicit projective models of elliptic
More informationCYCLOTOMIC POLYNOMIALS
CYCLOTOMIC POLYNOMIALS 1. The Derivative and Repeated Factors The usual definition of derivative in calculus involves the nonalgebraic notion of limit that requires a field such as R or C (or others) where
More informationMath 123 Homework Assignment #2 Due Monday, April 21, 2008
Math 123 Homework Assignment #2 Due Monday, April 21, 2008 Part I: 1. Suppose that A is a C -algebra. (a) Suppose that e A satisfies xe = x for all x A. Show that e = e and that e = 1. Conclude that e
More informationIRREDUCIBILITY TESTS IN Q[T ]
IRREDUCIBILITY TESTS IN Q[T ] KEITH CONRAD 1. Introduction For a general field F there is no simple way to determine if an arbitrary polynomial in F [T ] is irreducible. Here we will focus on the case
More informationA connection between number theory and linear algebra
A connection between number theory and linear algebra Mark Steinberger Contents 1. Some basics 1 2. Rational canonical form 2 3. Prime factorization in F[x] 4 4. Units and order 5 5. Finite fields 7 6.
More informationModern Algebra Lecture Notes: Rings and fields set 6, revision 2
Modern Algebra Lecture Notes: Rings and fields set 6, revision 2 Kevin Broughan University of Waikato, Hamilton, New Zealand May 20, 2010 Solving quadratic equations: traditional The procedure Work in
More informationGALOIS THEORY I (Supplement to Chapter 4)
GALOIS THEORY I (Supplement to Chapter 4) 1 Automorphisms of Fields Lemma 1 Let F be a eld. The set of automorphisms of F; Aut (F ) ; forms a group (under composition of functions). De nition 2 Let F be
More informationFURTHER EVALUATIONS OF WEIL SUMS
FURTHER EVALUATIONS OF WEIL SUMS ROBERT S. COULTER 1. Introduction Weil sums are exponential sums whose summation runs over the evaluation mapping of a particular function. Explicitly they have the form
More informationPolynomial Rings : Linear Algebra Notes
Polynomial Rings : Linear Algebra Notes Satya Mandal September 27, 2005 1 Section 1: Basics Definition 1.1 A nonempty set R is said to be a ring if the following are satisfied: 1. R has two binary operations,
More informationLEGENDRE S THEOREM, LEGRANGE S DESCENT
LEGENDRE S THEOREM, LEGRANGE S DESCENT SUPPLEMENT FOR MATH 370: NUMBER THEORY Abstract. Legendre gave simple necessary and sufficient conditions for the solvablility of the diophantine equation ax 2 +
More informationMath 429/581 (Advanced) Group Theory. Summary of Definitions, Examples, and Theorems by Stefan Gille
Math 429/581 (Advanced) Group Theory Summary of Definitions, Examples, and Theorems by Stefan Gille 1 2 0. Group Operations 0.1. Definition. Let G be a group and X a set. A (left) operation of G on X is
More informationGalois Theory, summary
Galois Theory, summary Chapter 11 11.1. UFD, definition. Any two elements have gcd 11.2 PID. Every PID is a UFD. There are UFD s which are not PID s (example F [x, y]). 11.3 ED. Every ED is a PID (and
More informationx 3 2x = (x 2) (x 2 2x + 1) + (x 2) x 2 2x + 1 = (x 4) (x + 2) + 9 (x + 2) = ( 1 9 x ) (9) + 0
1. (a) i. State and prove Wilson's Theorem. ii. Show that, if p is a prime number congruent to 1 modulo 4, then there exists a solution to the congruence x 2 1 mod p. (b) i. Let p(x), q(x) be polynomials
More information