SBI PO 2015 PRELIM (TIER I) EXAM MODEL PAPER SOLUTIONS

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1 SBI PO 2015 PRELIM (TIER I) EXAM MODEL PAPER SOLUTIONS Part 1 SOLUTIONS ENGLISH LANGUAGE Answers (1-10) 1. (5) 2. (1) 3. (2) 4. (3) 5. (4) 6. (4) nurturing 7. (1) drive 8. (4) hurdle 9. (2) manageable 10. (4) differ from Explanations (11-15) 11. (2) Use on in place of by. (lack of interest on the part of the public) 12. (2) Use booming in place of boom. (a booming business fuelled) 13. (5) No error. 14. (4) Use among in place of between. (among the public) 15. (5) No error Answer (16-20) 16. (4) 17. (4) 18. (5) 19. (5) 20. (1) Answers (21-30) 21. (2) 22. (3) 23. (5) 24. (3) 25. (4) 26. (5) 27. (4) 28. (2) 29. (1) 30. (1) Part 2 SOLUTIONS QUANTITATIVE APTITUDE Solutions (31-35) 31. (2) 32. (2) 33. (3) 34. (4) 35. (1) Solutions (36-40) 36. (2) I. 12x x + 12 = 10x x 2x 2-11x + 12 = 0 2x 2-8x 3x + 12 = 0 2x (x 4) 3 (x 4) = 0 (x 4) (2x 3) x = 4, x = 1.5 II. 13y 2 18y + 3 = 9y 2 10y 4y 2 8y + 3 = 0 4y 2 6y 2y + 3 = 0 4y 2 2y 6y + 3 = 0 2y (2y 1) 3 (2y -1) = 0 (2y 1) (2y 3) = 0 y = 1/2, y = 3/2 y = 1.5, y = 3/2 So x > y

2 37. (3) I. 18/x 2 + 6/x 12/x 2 = 8/x x - 12/ x 2 =8/x x = 8 6x = 2 X = 2/6 = 0.33 II. y = y 3 = y 3 = 1.63 y = 1.63 y ~ 1.18 x < y 38. (1) I x = 0 35x + 70 = 0 x = - 70/35 x = - 2 II. (81) 1/4 y + (343) 1/3 = 0 3y + 7 = 0 y = - 7/3 y = x > y 39. (1) I. (2) 5 + (11) 3 / 6 = x / 6 = x 3 x 3 = 1363/6 = II. 4y 3 = - (589 4) + 5y 3 y 3 = (589 4) y 3 = x > y 40. (4) I. (x 7/5 9) = 169 x 3/5 X 10/5 = 9 x 169 X 2 = 9 x 169 X = ± 3 x 13 X = ± 39 II. y 1/4 X y 1/4 X 7 = 273 y 1/2 y = 273/7 = 39 x < y Solutions (41-45) 41. (5) 29, 37, 21, 43, 13, 53, = 21, 21 8 = 13, 13 8 = = 45, = 53 So wrong number in the series is (3) 600, 125, 30, 13, 7.2, 6.44, x 5 (5x5) = x 5 (5x5) = x 5 (5x5) = x 5 (5x5) = x 5 (5x5) = x 5 (5x5) = 600 So wrong number in the series is (3) 80, 42, 24, 13.5, 8.75, 6.375, x 2 (2x2) = x 2 (2x2) = x 2 (2x2) = x 2 (2x2) = x 2 (2x2) = x2 (2x2) = 80 So wrong number in the series is (2) 10, 8, 13, 15, 35, 135, 671, x1 2 = 8 8 x2 3 = x3 4 = x4 5 = x 5 6 = x 6 7 = 4007 So wrong number in the series is (5)150, 290, 560, 1120, 2140, 4230, x2 10 = x 2 20 = x 2 30 = x2 40 = 2140 So wrong number in the series is Solutions (46 55) 46. (1) Let the amount be Rs. x According to the question: (3/9) x (2/14) x = 40 x (1/3 1/7) = 40 x = (21 X 40)/4 x = 210 Rs. 47. (3) According to the question, Rachita buys highest number of pastries than cookies and then ice cream She has to buy 9 units of each. But she has to buy total 32 units and each item of one is must. Pastries > Cookies > Ice cream 13 or or 11 9 Hence, she can buy either 10 or 11 units of cookies. 48. (3) Bus fare of first 5 km is = Rs. x So bus fare of 1 km is = Rs. x/5 According to the question:

3 5 X (x/5) X 13 = 2402 x = 2402 x = 36 x = Rs (1) Let three even numbers are x, (x + 2), (x + 4) According to the question: x (x + 2) (x + 4) = 4032 x (x + 4) = 252 Eq (I) (x + 2) 252 = 4032 Eq (II) (x + 2) = (4032/252) = 16 x = 16-2 = 14 x = 14 So numbers are 14, 16 and 18. Now five times of the second number will be = 16 x 5 = (1) Sum of ages of 4 members of a family 5 yr ago = 94 yr Their present age with daughter = x 5 = 114 yr Now, their present age with daughter in law = 92 yr Difference between daughter and daughter in law = = 22 yr 51. (4) Total ball in the bag = = 20 n(s) = 20 C 2 = (20!/2! 8!) = (20 x 19 x 18!!)/ 2 x 18! = 190 and for same colour of ball n(e 1) = 13 C 2 = (13!/2! 11!) = (13 x 12 x 11!)/ 2 x 11! = (13 x 12)/2 = 78 and n(e 2) = 7 C 2 = (7!/2! 5!) = (7x 6 x 5!)/ 2 x 5! = (7x6)/ 2 = 21 Required probability for same colour ball = P(E) = [n(e 1) + n(e 2) ]/ n(s) = ( )/190 = 99/ (2) Akash scored in subject A = 73 marks Akash scored in subject B = 56% of 150 = 84 Akash scored in subject C = x marks Maximum marks in all the three subject is = 150 Total marks = 150 x 3 = 450 Now according to the question: Marks obtained in subject (A + B + C) = 54% of total marks x = 54% of 450 x = 86, hence Akash scored 86 marks in subject C. 53. (4) Area of Square = 1444m 2 Side of the square = 1444 = 38m Now, according to the question, Breadth of the rectangle = 38 x 1/4 Length of the rectangle = 38 x 3/4 Area of rectangle = Length x Breadth = 38 x 1/4 X 38 x 3/4 = 1444 x (3/16) m 2 Now, difference between the Area of Square and rectangle = x (3/16) = 1444 (1 3/16) = m (5) Share of A = 4/11 x = Rs Share of B = 7/11 x = Rs Required difference = 2 x share of B 3 x share of A = 2 x x = Rs (4) In one day, work done by: A + B = 1/20 (i) B + C = 1/30 (ii) A + C = 1/40 (iii) Adding (i) and (ii) above, work done by A + 2B + C = 1/20 + 1/ /30 2B = 1/20 + 1/30 1/ /40 B = 7/240 putting (B = 7/240) in (i) A does 5/240 work in one day, similarly putting the same value in (ii) C does 1/240 work in one day. Required ratio = (1/240) : (5/240) = 1:5 Solutions (56-60) 56. (3) Number of mobiles phones sold in the month of July = x 17/1000 = 7650 company A = (8/15) x 7650 = 4080 company B = = 3570 Now number of mobiles phones sold in the month of December = x (16/100) = 7200 Company A = (7/16) x 7200 = 3150 Mobile phone sold by company B = = 4050 So required ratio = 3570 : 4050 = 357 : 405 = 119 : (3) Number of mobile phones sold in the month of November = x (12/100) = 5400 Mobile phone sold by company A = (7/15) x 5400 = 2520 company A at a discount = 35% of 2520 = 882 company A without a discount = = (4) Number of mobile phones sold in the month of October = x (8/100) = 3600 Mobile phone sold by company B = (5/12) x 3600 = 1500 Total profit earned by company B = 1500 x 433 = Rs

4 59. (5) From sol. No. 56 Number of mobiles phones sold by company A in the month of July = 4080 Number of mobiles phones sold by company A in the month of December = 3150 : Required % = (4080/3150) x 100 = % ~ = 130% 60. (1) Number of mobiles phones sold in the month of August = x (22/100) = 9900 Number of mobiles phones sold by company B in August = (5/9) x 9900 = 5500 Total number of mobiles phones sold in the month of September = x (25/100) = Number of mobiles phones sold by company B in September = (2/5) x = 4500 So total number of phones sold by company B in August and September = = 1000 Solutions (61-65) 61. (1) Required average earning = Rs ( )3 = Rs lakhs 62. (2) Required respective ratio = 2.79 : 9.45 = 31 : (5) Required increasee percentage = ( /8.42) x 100 = ~ 12% 64. (4) D s earning increased consistently from the year 2005 to the year (3) Required percentage = ( )/5.53 x 100 = ~ 168% Part 3 SOLUTIONS REASONING Solutions (66-69) After carefully study the given input and various steps of arrangement, we may conclude that in each step numbers are arranged in descending order from left to right while words are arranged in opposite English alphabetical order from right to left and the same process is continued till the rearrangement ends. Input: 84 why shit not best ink feet vain Step I: why shit 32 not ink feet vain best Step II: why shit 32 not ink 51 vain best feet Step III: why shit not 51 vain best feet ink Step IV: why shit vain best feet ink not Step V: why vain 92 best feet ink not shit Step VI: vain 92 best feet ink not shit why Step VII: best feet ink not shit why vain 66. (5) There is no such step 67. (4) Step V: why vain 92 best feet ink not shit Hence best would be at 5 th position from right in Step V. 68. (2) Step VII (last step) best feet ink not shit why vain Hence three element (best, 14, 27) are between feet and (3) Step IV: why shit vain best feet ink not Hence why is sixth from the left in Step IV> Solutions (70 75) 70. (2) 71. (3) 72. (4) 73. (1) 74. (5) 75. (2) Solutions (76-78) 76. (5): From statement I, Deep is sister of Shilpa who has two siblings. From statement II, Kaushal is the only son of Deepa s parents. So by analyzing both the statement we can conclude Shilpa has one brother. 77. (3): From statement I, Hence D is immediatee right of B. From Statement II,

5 Hence D is immediate right of B. 78. (3): From statement I, 85. (1) Only I follow Hence Sudha is facing South direction. From Statement II, Hence Sudha is facing South direction Solutions (79 80) Answers: (86-90) 86. (4) 87. (4) 88. (4) 89. (2) 90. (5) Solutions (91 95) 79. (4): C 80. (1) ABE Solutions (81-85) 81. (2) Only II & III follow 82. (5) None of these 83. (4) Only I & III follow 91. (4) 92. (5) 93. (1) 94. (4) 95. (3) 96. (5) Either + or 97. (4) Only three pairs in the word AC, AE, CE SEARCHES Solutions (98 100) Codes are as follows: he pa is ro waiting ta there la the ji train zo at ma station fu this bi/vi a vi/bi 98. (2) pa 99. (3) fu ji zo 100.(2) ta ki ro 84. (2) Only III follows

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IBPS RRB Office Assistant Prelims A. 1 B. 2 C. 3. D. no one A. R B. S C.Q D. U

Memory Based Questions 18 th August 2018 IBPS RRB Office Assistant Prelims Logical Reasoning: Direction (1-5): Study the following information carefully and answer the questions given below: Six persons