CEE 320 Midterm Examination (1 hour)
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1 Examination (1 hour) Pleae write your name on thi cover. Pleae write you lat name on all other exam page Thi examination i open-book, open-note. There are 5 quetion worth a total of 100 point. Each quetion lit the point value for that quetion. Pleae work quietly and repect other people pace. Carefully read each quetion and enure that you anwer what i aked. If you need additional workpace, ue the back of the page or the blank page included at the end of the examination. If you need to untaple page, I have a tapler to retaple them at the end of the examination. ANSWER KEY Name (firt, lat): 1
2 Quetion 1: Short Anwer (5 point each) Regarding a vehicle braking ytem, to what doe the term brake force ratio (BFR) refer? BRF i the ratio of the ditribution of braking force by the vehicle braking ytem between front and rear brake. It i expreed a: front brake force rear brake force You need to know what it i and how it typically expreed for full credit. Baed on the hort reading, Reconidering the Ga Tax: Paying for What You Get, i the author in favor of or oppoed to the ga tax? In favor of the ga tax. He generally argue that it i a omewhat equitable uer tax. A vertical curve i 500 ft long and connect an entering grade (G 1 ) of +3.0% to an exiting grade (G ) of -.0%. What i the offet from the PI to the road urface directly below the PI? Thi i olved uing the offet equation. You can ue the full equation or the horthand one for the middle offet. Firt you need to know A = G 1 G = = 5 ()( 5 500) AL Y m = = = ft
3 Quetion (15 point) A garbage truck ha axle weight hown in the table below. Uing the th power thumbrule, etimate how much more damage a full garbage truck doe to the pavement than an empty one. Expre thi quantity a a multiple of the empty truck damage. For intance, the full truck caue XX time more damage than the empty one. Condition Front Axle Weight Rear Axle Weight Empty (no garbage) 6,000 lb 10,050 lb Full of garbage 8,50 lb 3,000 lb Picture from Heil Environmental Indutrie, Ltd. ( Empty 6,000 18,000 Full 8,50 18,000 Multiple.71 = , ,000 3, ,000 = = 0.11 = =.71 ESAL ESAL The full truck caue.6 time more damage than the empty truck 3
4 Quetion 3 (0 point) A truck i climbing up a 6% grade toward Manatah Summit on Intertate 8 jut outide of Ellenburg. It i jut able to maintain a contant peed of 5 mph a it acend the 6% grade. Given the following, what i the engine generated tractive effort? Truck weight = 105,500 lb Coefficient of drag = 1.00 Frontal area = 70 ft Air denity = lug/ft 3 Intertate 8 grade = 6% Remember, at a contant velocity, acceleration = 0. Thi problem eentially ak you to calculate the three baic reitance (aerodynamic, rolling and grade) and then, knowing acceleration = 0, add them up to find the force. If you look at Figure.6 in your text you will ee that the engine generated tractive effort i the controlling force once you get out of the firt couple of gear. Aerodynamic reitance R = ρ C D A f = ( 1.00)( 70)( 5 1.7) = 306. lb a 3 Rolling reitance f rl = = = R = f W = ,500 = 1,59.8 rl rl ( ) lb Grade reitance R g = WG = 105, = 6, ( ) lb Find the engine generated tractive effort Fe R = γ mma However, a = 0 ince velocity i contant. Therefore, F e = R = , ,330.0 = 8, lb
5 Quetion (0 point) The Pocono Raceway in Pennylvania conit of three turn a diagramed below. Turn data are given in the table below. Uing tandard deign aumption, what i the deign peed (to the nearet mph) for the Pocono Raceway baed on horizontal curve geometry only (you mut perform calculation for all 3 curve to get full credit). Note that thi i the deign peed for a typical automobile and not for a race car. Aume R v = R and the coefficient of ide friction = in all cae and for all peed. A Turn North A 1 Turn 1 Turn 3 A 3 Turn Number Curve Length Superelevation 1 Angle ft 6 degree A 1 = 60 degree 750 ft 8 degree A = 90 degree ft 1 degree A 3 = 30 degree Note 1: Superelevation i lited in DEGREES, not percent. Note : Angle meaured are a indicated in the picture and are NOT Δ (delta). One bonu point for the whole cla if anyone can name the NASCAR Nextel Cup champion for 006. You need to firt calculate the radiu for each turn and then ue the baic uperelevation equation to determine the velocity. Do thi for all three turn. The lowet of the three calculated velocitie would be the controlling deign peed and would, therefore, be the deign peed of the entire race track. Recognize that the central angle of the curve (Δ) i equal to 180 minu the angle given in the table. Alo, you need to convert the velocity you obtain from ft/econd to mph, which involved dividing by
6 Turn 1 Find curve radiu ( 800) = 381. ft Rv ( ) π 180L 180 L = RΔ R = = 180 πδ π 97 = Find uperelevation e o tan α = e = ( tanα )( 100) = ( tan 6 )( 100) = 10.5% 100 Find deign peed Rv g( f + e) ( )( 3.)( ) R = = = = 38. g Turn Find curve radiu ( f + e) ( 750) = 77. ft Rv ( ) π 180L 180 L = RΔ R = = 180 πδ π 6 = Find uperelevation e o tan α = e = ( tanα )( 100) = ( tan8 )( 100) = 1.1% 100 Find deign peed Rv g( f + e) ( 77.6)( 3.)( ) R = = = = 5. g Turn 3 Find curve radiu ( f + e) ( 675) = 57. ft Rv ( ) π 180L 180 L = RΔ R = = 180 πδ π 83 = Find uperelevation e o tan α = e = tanα 100 = tan =.9 ( f + e) ( )( ) ( )( ) % Find deign peed Rv g( f + e) ( 57.83)( 3.)( ) R = = = = 39. g mph mph mph Deign Speed = the lowet of the three rounded down to the nearet mph = 38 mph If you rounded up to 39 mph, you alo got full credit. 6
7 Quetion 5 (30 point) Deign a 0 mph equal tangent ag vertical curve to connect the two grade a hown in the drawing. A pedetrian walk-bridge mut be built over tation The bottom of the bridge mut be 0 ft above the centerline urface of the roadway to allow for proper vehicle clearance under the bridge. Report the curve length and the elevation of the pedetrian bridge bottom. PC Pedetrian Bridge Elevation =? 0 ft at STA 9+00 G 1 ertical Curve Data PI tation = PI elevation = 13 ft G 1 = -6.5% G = % PI G PT Strategy Deign a tandard 0 mph ag vertical curve uing K value. Find the length of the curve and calculate PC tation. PC elevation come from knowing G 1, curve length and PI elevation. Once the curve i deigned, you need to find the elevation at tation To do thi you will need to expre the curve a a parabola and then olve for a pecific location (bridge). Then add 0 ft and you have the bridge height. Calculation K ag from Table 3.3 for 0 mph i 6. ( 6.5 ) ft L = KA = 6 = 5 L 5 PC = PI = 5000 = STA L 5 elev = elevpi G1 = = 10. ( ) ( ) ft PC 68 Now, determine the equation for the parabola. y = ax + bx + c 7
8 At the PC : x = 0 and Y = c = ft dy At the PC : x = 0 and = b = G1 = 6.5 dx d Y G G1 G G Anywhere: = a = a = dx L L Therefore, y = x 6.5x with x in tation and y in feet 1 = 6.5 = ( 5.) Find the pedetrian bridge bottom elevation at STA 9+00 (thi i = 1.7 tation along the curve). Firt find the elevation of the roadway at thi point and then add 0 ft to get the bridge elevation. elev road = ( 1.7) 6.5( 1.7) = ft elev = elev + 0 = = 151. ft bridge road 81 8
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