Degree theory and existence of positive solutions to coupled systems of multi-point boundary value problems
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1 Shah et al. Boundary Value Problems 16 16:43 DOI /s R E S E A R C H Open Access Degree theory and existence of positive solutions to coupled systems of multi-point boundary value problems Kamal Shah *, Amjad Ali and Rahmat Ali Khan * Correspondence: kamalshah48@gmail.com Department of Mathematics, University of Malakand, Chakadara DirL, Khyber Pakhtunkhwa, Pakistan Abstract In this article, we investigate existence and uniqueness of positive solutions to coupled systems of multi-point boundary value problems for fractional order differential equations of the form D α xt=φt, xt, yt, t I = [, 1], D β yt=ψt, xt, yt, t I = [, 1], x = gx, x1 = δxη, < η <1, y = hy, y1 = γ yξ, < ξ <1, where α, β 1, ], D denotes the Caputo fractional derivative, < δ, γ <1are parameters such that δη α <1,γξ β <1,h, g CI, R are boundary functions and φ, ψ : I R R R are continuous. We use the technique of topological degree theory to obtain sufficient conditions for existence and uniqueness of positive solutions to the system. Finally, we provide an example to illustrate our main results. MSC: 34A8; 35R11 Keywords: coupled system; boundary value problems; fractional differential equations; existence and uniqueness of solutions; topological degree theory 1 Introduction Recently much attention has been paid to investigate sufficient conditions for existence of positive solutions to boundary value problems for fractional order differential equations, we refer to [1 13] and the references therein. This is because of many applications of fractional differential equations in various field of science and technology as in [14 ]. Existence of solutions to boundary value problems for coupled systems of fractional order differential equations has also attracted some attentions, we refer to [13, 4]. In these papers, classical fixed point theorems such as Banach contraction principle and Schauder fixed point theorem are used for existence of solutions. The use of these results require stronger conditions on the nonlinear functions involved which restricts the applicability to limited classes of problems and very specialized systems of boundary value problems. In order to enlarge the class of boundary value problems and to impose less restricted conditions, one needs to search for other sophisticated tools of functional analysis. One 16 Shah et al. This article is distributed under the terms of the Creative Commons Attribution 4. International License which permits unrestricted use, distribution, and reproduction in any medium, provided you give appropriate credit to the original authors and the source, provide a link to the Creative Commons license, and indicate if changes were made.
2 Shah et al. Boundary Value Problems 16 16:43 Page of 1 such tool is topological degree theory. Few results can be found in the literature which use degree theory arguments for the existence of solutions to boundary value problems BVPs [5 3]. However, to the best of our knowledge, the existence and uniqueness of solutions to coupled systems of multi-point boundary value problems for fractional order differential equations with topological degree theory approach have not been studied previously. Wang et al. [8] studied the existence and uniqueness of solutions via topological degree method to a class of nonlocal Cauchy problems of the form { D q ut=f t, ut, u + gu=u, t I =[,T], where D q is the Caputo fractional derivative of order q, 1], u R,andf : I R R is continuous. The result was extended to the case of a boundary value problem by Chen et al. [6] who studied sufficient conditions for existence results for the following two point boundary value problem: { D α + φ pd β + ut = f t, ut, Dβ + ut, D β + u = Dβ + u1 =, where D α + and Dβ + are Caputo fractional derivatives, < α, β 1, 1 < α + β. Wang et al. [7] studied the following two point boundary value problem for fractional differential equations with different boundary conditions: { D α + φ pd β + ut = f t, ut, Dβ + ut, u =, D β + u = Dβ + u1, where D α + and Dβ + are Caputo fractional derivatives, < α, β 1, 1 < α + β. Motivated by the work cited above, in this paper, we use a coincidence degree theory approach for condensing maps to obtain sufficient conditions for the existence and uniqueness of solutions to more general coupled systems of nonlinear multi-point boundary value problems. The boundary conditions are also nonlinear. The system is of the form D α xt=φt, xt, yt, t I = [, 1], D β yt=ψt, xt, yt, t I = [, 1], x = gx, x1 = δxη, < η <1, y = hy, y1 = γ yξ, < ξ <1, 1 where α, β 1, ], D is used for standard Caputo fractional derivative and < δ, γ <1such that δη α <1,γξ β <1,h, g CI, R are boundary functions and φ, ψ : I R R R are continuous. Preliminaries In this section we give some fundamental definitions and results from fractional calculus and topological degree theory. For further detailed study, we refer to [19, 4, 6, 7, 33, 34].
3 Shah et al. Boundary Value Problems 16 16:43 Page 3 of 1 Definition.1 The fractional integral of order ρ R + of a function u L 1 [a, b], R is defined as I ρ + ut= 1 Ɣρ t a t s ρ 1 us ds. Definition. The Caputo fractional order derivative of a function u on the interval [a, b] is defined by D ρ + ut= 1 Ɣm ρ t a t s m ρ 1 u m s ds, where m =[ρ]+1and[ρ] represents the integer part of ρ. Lemma.1 The following result holds for fractional differential equations: I ρ D ρ ut=ut+d + d 1 t + d t + + d m 1 t m 1 for arbitrary d i R, i =,1,,...,m 1. The spaces X = C[, 1], R, Y = C[, 1], R of all continuous functions from [, 1] R are Banach spaces under the topological norms x = sup{ xt : t [, 1]} and y = sup{ yt : t [, 1]}, respectively. The product space X Y is a Banach space under the norm x, y = x + y. It is also a Banach space under the norm x, y = max{ x, y }. Let S be a family of all bounded sets of PX Y, where X Y is a Banach space. Then we recall the following notions [35]. Definition.3 The Kuratowski measure of non-compactness μ : S R + is defined as μs=inf{d >:S admitsafinitecoverbysetsofdiameter d}, where S S. Proposition.1 The Kuratowski measure μ satisfies the following properties: i μs=iff S is relatively compact. ii μ is a seminorm, i.e., μλs= λ μs, λ R and μs 1 + S μs 1 +μs. iii S 1 S implies μs 1 μs ; μs 1 S =max{μs 1, μs }. iv μconv S=μS. v μ S =μs. Definition.4 Let F : X be continuous bounded map, where X. ThenF is μ-lipschitz if there exists K suchthat μ FS KμS, S bounded. Further, F will be strict μ-contraction if K <1.
4 Shah et al. Boundary Value Problems 16 16:43 Page 4 of 1 Definition.5 A function F is μ-condensing if μ FS < μs, S bounded, with μs>. In other words, μfs μsimpliesμs=. Here,wedenotetheclassofallstrictμ-contractions F : X by ϑc μ and denote the class of all μ-condensing maps F : X by C μ. Remark 1 ϑc μ C μ andeveryf C μ isμ-lipschitz with constant K =1. Moreover, we recall that F : X is Lipschitz if there exists K >suchthat Fx Fy K x y, x, y, and that if K <1,thenF is a strict contraction. For the following results, we refer to [34]. Proposition. If F, G : Xareμ-Lipschitz with constants K and K, respectively, then F + G : Xisμ-Lipschitz with constant K + K. Proposition.3 If F : Xiscompact, then F is μ-lipschitz with constant K =. Proposition.4 If F : XisLipschitzwithconstantK, then F is μ-lipschitz with the same constant K. The following theorem due to Isaia [34] plays an important role for our main result. Theorem.1 Let F : X Xbeμ-condensing and = { x X : λ [, 1] such that x = λfx }. If is a bounded set in X, so there exists r >such that S r, then the degree D I λf, S r, =1, λ [, 1]. Consequently, F has at least one fixed point and the set of the fixed points of F lies in S r. Now, we list the following hypotheses. C 1 ThereexistconstantsK g, K h [, 1 such that gx gx 1 Kg x x 1, hy hy 1 K h y y 1 for x 1, x, y 1, y, R. C ThereexistconstantsC g, C h, M g, M h >such that, for x, y R, gx C g x + M g, hy C h y + M h.
5 Shah et al. Boundary Value Problems 16 16:43 Page 5 of 1 C 3 Thereexistconstantsc i, d i i =1,andM φ, M ψ such that, for x, y R, φt, x, y c1 x + c y + M φ, ψt, x, y d1 x + d y + M ψ. C 4 ThereexistconstantsL φ, L ψ such that, for x 1, x, y 1, y R, φt, x, y φt, x 1, y 1 Lφ x x 1 + y y 1, ψt, x, y ψt, x 1, y 1 Lψ x x 1 + y y 1. 3 Main results In this section, we discuss the existence and uniqueness of solutions to the BVP 1. Lemma 3.1 If h : I R is α times integrable function, then solutions of the BVP D α xt=ht, t I = [, 1], x = gx, x1 = δxη, < η <1, are a solution of the following Fredholm integral equation: xt= 1 t1 δ gx+ where G α t, s is defined by G α t, shs ds, t [, 1], 3 G α t, s= 1 Ɣα t s α 1 + tδη sα 1 t1 sα 1, s t η 1, t s α 1 t1 sα 1, η s t 1, tδη s α 1 t1 sα 1, t s η 1, t1 sα 1, η t s 1. 4 Proof Applying I α on D α xt=ht and using Lemma.1,wehave xt=i α ht+c + c 1 t 5 for some c, c 1 R. The conditions x = gx andx1 = δxη implyc = gx andc 1 = δ Iα hη 1 δ gx 1 Iα h1. Hence, we obtain [ xt=i α δ ht+gx+t Iα hη 1 δ ] gx 1 Iα h1, 6 which after rearranging can be written as xt= 1 t1 δ gx+ G α t, shs ds.
6 Shah et al. Boundary Value Problems 16 16:43 Page 6 of 1 In view of Lemma 3.1, solutions of the coupled systems of BVPs 1aresolutionsofthe following coupled systems of Fredholm integral equations: { xt=1 t1 δ gx+ G αt, sφt, xs, ys ds, t [, 1], yt=1 t1 γ 1 γξ hy+ G βt, sψt, xs, ys ds, t [, 1], 7 where G β t, sisdefinedby G β t, s= 1 Ɣβ t s β 1 tγ ξ sβ 1 + t1 sβ 1, s t ξ 1, 1 γξ 1 γξ t s β 1 t1 sβ 1, ξ s t 1, 1 γξ tγ ξ s β 1 1 γξ t1 sβ 1, 1 γξ t s ξ 1, t1 sβ 1, 1 γξ ξ t s 1. 8 Clearly max Gα t, s 1 s α 1 = t [,1] 1 δηɣα, max Gβ t, s 1 s β 1 =, s [, 1]. t [,1] 1 γξɣβ 9 Define the operators F 1 : X X, F : Y Y by F 1 xt= 1 t1 δ gx, F yt= 1 t1 γ 1 γξ hy and the operators G 1, G : X Y X Y by G 1 x, yt= G x, yt= G α t, sφ t, xs, ys ds, G β t, sψ t, xs, ys ds. Further, we define F =F 1, F, G =G 1, G andt = F + G. Then the system of integral equations 7 can be written as an operator equation of the form x, y=tx, y=fx, y+gx, y, 1 and solutions of the system 7arefixedpointsofT. Lemma 3. Under the assumptions C 1 and C, the operator F satisfies the Lipschitz condition and the following growth condition: Fx, y C x, y + M for every x, y X Y. 11
7 Shah et al. Boundary Value Problems 16 16:43 Page 7 of 1 Proof Using the assumption C 1, we obtain Fx, yt Fu, vt = t1 δ gx gu t1 γ hy hv 1 γξ K g x u + K h y v K x, y u, v, K = max{kg, K h }. 1 By Proposition.4, F is also μ-lipschitz with constant K. Now for the growth condition using C, we get Fx, y = F1 x, F y = F1 x + F y C x, y + M, where C = max{c g, C h }, M = max{m g, M h }. Lemma 3.3 The operator G is continuous and under the assumption C 3 satisfies the growth condition Gx, y x, y + for every x, y X Y, 13 where = θc + d, θ = max{ θm φ + M ψ. 1 Ɣα, 1 1 γξɣβ }, c = max{c 1, c }, d = max{d 1, d }, = Proof Let {x n, y n } be a sequence of a bounded set U r = { x, y r :x, y X Y } such that x n, y n x, yinu r. We need to prove that Gx n, y n Gx, y. Consider G1 x n, y n t G 1 x, yt 1 [ t t s α 1 φ s, xn s, y n s φ s, xs, ys ds Ɣα + + δ 1 η η s α 1 φ s, xn s, y n s φ s, xs, ys ds 1 s α 1 φ s, x n s, y n s φ s, xs, ys ] ds. From the continuity of φ and ψ, it follows that φs, x n s, y n s φs, xs, ys as n. For each t I,usingC 3, we obtain t s α 1 φs, x n, y n φs, x, y t s α 1 c 1 + c r + M φ, which implies the integrability for s, t I and by using the Lebesgue dominated convergence theorem, we obtain t t sα 1 φs, x n, y n φs, x, y ds asn. Similarly, the other terms approach as n. It followsthat G1 x n, y n t G 1 x, yt asn, and similarly we can show that G x n, y n t G x, yt asn.
8 Shah et al. Boundary Value Problems 16 16:43 Page 8 of 1 Now for growth condition on G,usingC 3 and9, we obtain G1 x, yt 1 = G α t, sφ s, xs, ys ds 1 c1 x + c y + M φ 1 δηɣα and G x, yt 1 = G β s, tψ s, xs, ys ds 1 d1 x + d y + M ψ. 1 γξɣβ Hence, it follows that Gx, y = G1 x, y + G x, y θ c 1 x + c y + M φ + θ d1 x + d y + M ψ θc + d x + y + θm φ + M ψ = x, y +. By this, we complete the proof. Lemma 3.4 The operator G : X Y X Yiscompact. Consequently, Gisμ-Lipschitz with zero constant. Proof Take a bounded set B U r X Y and a sequence {x n, y n } in B,thenusing13, we have Gx n, y n r + for every x, y X Y, which implies that GB is bounded. Now, for equi-continuity and for given ɛ >,take { δ = min δ 1 = 1 ɛɣα +1 6[c 1 + c ]r + M φ 1 α, δ = 1 ɛɣβ +1 6[d 1 + d ]r + M ψ For each x n, y n B, we claim that if t, τ [, 1] and < τ t < δ 1,then G1 x n, y n t G 1 x n, y n τ < ɛ. Now consider G 1 x n, y n t G 1 x n, y n τ = 1 t [ t s α 1 τ s α 1] φ s, x n s, y n s ds Ɣα + 1 Ɣα + + τ δt τ 1 δηɣα τ t 1 δηɣα t τ s α 1 φ s, x n s, y n s ds η η s α 1 φ s, x n s, y n s ds 1 s α 1 φ s, x n s, y n s ds 1 β }.
9 Shah et al. Boundary Value Problems 16 16:43 Page 9 of 1 c 1 x n + c y n + M φ [ t α τ α +τ t α] Ɣα +1 c 1 + c r + M φ [ τ α t α +τ t α]. Ɣα +1 We continue the proof with several cases. Case 1. δ 1 t < τ <1: G1 x n, y n t G 1 x n, y n τ c 1 + c r + M φ < Ɣα +1 Case. t < δ 1, τ <δ 1 : + αδ α 1 1 τ t < c 1 + c r + M φ + αδ1 α Ɣα +1 < ɛ. G1 x n, y n t G 1 x n, y n τ c 1 + c r + M φ [ < 3τ α ] Ɣα +1 < c 1 + c r + M φ 3δ 1 α = ɛ Ɣα +1. Similarly for the second part, for each x n, y n B, we claim that if t, τ [, 1] and < τ t < δ,then G x n, y n t G x n, y n τ < ɛ.then: Case 1. δ t < τ <1: G x n, y n t G x n, y n τ d 1 + d r + M ψ < Ɣβ +1 Case. t < δ, τ <δ : + βδ β 1 τ t < d 1 + d r + M ψ + βδ β Ɣβ +1 < ɛ. G x n, y n t G x n, y n τ d 1 + d r + M ψ [ < 3τ β ] Ɣβ +1 Hence, we have < d 1 + d r + M ψ 3δ β = ɛ Ɣβ +1. Gx n, y n Gx n, y n < ɛ. 14 Thus GB is equi-continuous. In view of the Arzelà-Ascoli theorem GB iscompact. Furthermore, by Proposition.3, G is μ-lipschitz with constant zero. Theorem 3.1 Under the assumptions C 1 -C 3, the system 1 has at least one solution x, y X YprovidedC+ <1.Moreover, the set of solutions of 1 is bounded in X Y. Proof By Lemma 3., F is μ-lipschitz with constant K [, 1 and by Lemma 3.4 G is μ-lipschitz with constant. It follows by Proposition. that T is a strict μ-contraction with constant K.Define B = { x, y X Y :thereexistλ [, 1] such that x, y=λtx, y }.
10 Shah et al. Boundary Value Problems 16 16:43 Page 1 of 1 We have to prove that B is bounded in X Y.Forthis,choosex, y B, theninviewof the growth conditions as in Lemmas 3. and 3.3,wehave x, y = λtx, y = λtx, y λ Fx, y + Gx, y λ [ C ] x, y + M + x, y + = λc + x, y + λm +, which implies that B is bounded in X Y. Therefore, by Theorem.1, T has at least one fixed point and the set of fixed points is bounded in X Y. Theorem 3. In addition to the assumption C 1 -C 4, assume that K + θl φ + L ψ <1, then the system 1 has a unique solution. Proof We use the Banach contraction theorem, for x, y, u, v R R,wehavefrom1 Fx, y Fu, v K x, y u, v. 15 Using C 4 and9, we obtain G1 x, y G 1 u, v Gα t, s φ s, xs, ys φ s, us, vs ds which implies that θl φ x u + y v, G1 x, y G 1 u, v θlφ x u + y v = θl φ x u, y v = θl φ x, y u, v. 16 Similarly, we have G x, y G u, v θl ψ x, y u, v. 17 From 16and17, it followsthat Gx, y Gu, v = G1 x, y G 1 u, v + G x, y G u, v θl ψ + L ψ x, y u, v. 18 Hence, in view of 15and18, we obtain Tx, y Tu, v Fx, y Fu, v + Gx, y Gu, v K + θl ψ + L ψ x, y u, v, which implies that T is a contraction. By the Banach contraction principle, the system 1 has a unique solution.
11 Shah et al. Boundary Value Problems 16 16:43 Page 11 of 1 4 Example Example 4.1 Consider the following multi-point BVP: D 3 xt= xt + yt, t [, 1], 5+t D 3 yt=, t [, 1], 1+ xt + yt 5+ cos xt + sin yt x = gx, x1 = 1 x 1, y = hy, y1 = 1 3 y The solution of the BVP 19is given by xt= gx 1 t 3 yt= hy 1 3t G α t, sφ s, xs, ys ds, G β t, sψ s, xs, ys ds, where G α, G β are the Green s functions and can be obtained easily as obtained generally in 4and8, respectively. From the system 19wetakeα = β = 3, δ = η = 1, γ = ξ = 1 3,and r = 1, 3, and let us take λ = 1 [, 1]. Then by the use of Theorem 3., wehavel φ = L ψ = 1 5, M φ = M ψ = 1 5 = c i = d i,fori = 1,, and taking K g = 1, K h = 1,thenassumptions C 1 -C 4 aresatisfied.wehave F 1 xt= gx 1 t 3 F yt= hy 1 3t 4, G 1 xt=, G yt= G α t, sφ s, xs, ys ds, G β t, sψ s, xs, ys ds. Since F 1, F, G 1, G are continuous and bounded, also F =F 1, F, G =G 1, G, which further implies that T = F + G is continuous and bounded. Further Fx, y Fu, v 1 x, y u, v, that is, if F is μ-lipschitz with Lipschitz constant 1 and G is μ-lipschitz with zero constant, this implies that T is a strict-μ-contraction with constant 1. Further it is easy to calculate θ =1.545.As B = {x, y CI R R, R, λ [, 1] : x, y= 1 } Tx, y. Then the solution x, y 1 Tx, y 1, implies that B is bounded and by Theorem 3.1 the BVP 19 has at least a solution x, yin CI R R, R. Furthermore K + θl φ + L ψ =.5618 < 1. Hence by Theorem 3. the boundary value problem 19 has a unique solution. Competing interests The authors declare that they have no competing interests.
12 Shah et al. Boundary Value Problems 16 16:43 Page 1 of 1 Authors contributions The authors have equally made contributions. All authors read and approved the final version of this manuscript. Acknowledgements We are thankful to the reviewver for his/her valuable suggestions, which improved the manuscript. Received: 6 November 15 Accepted: 4 February 16 References 1. Agarwal, RP, Benchohra, M, Hamani, S: A survey on existence results for boundary value problems of nonlinear fractional differential equations and inclusions. Acta Appl. Math. 19, Agarwal, RP, Belmekki, M, Benchohra, M: A survey on semilinear differential equations and inclusions involving Riemann-Liouville fractional derivative. Adv. Differ. Equ. 9, Article ID Balachandran, K, Kiruthika, S, Trujillo, JJ: Existence results for fractional impulsive integrodifferential equations in Banach spaces. Commun. Nonlinear Sci. Numer. 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