A product convergence theorem for Henstock Kurzweil integrals


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1 A product convergence theorem for Henstock Kurzweil integrls Prsr Mohnty Erik Tlvil 1 Deprtment of Mthemticl nd Sttisticl Sciences University of Albert Edmonton AB Cnd T6G 2G1 Abstrct. Necessry nd sufficient for b fgn b fg for ll Henstock Kurzweil integrble functions f is tht g be of bounded vrition, g n be uniformly bounded nd of uniform bounded vrition nd, on ech compct intervl in (, b), g n g in mesure or in the L 1 norm. The sme conditions re necessry nd sufficient for f(g n g) 0 for ll Henstock Kurzweil integrble functions f. If g n g.e. then convergence fg n fg for ll Henstock Kurzweil integrble functions f is equivlent to f(g n g) 0. This extends theorem due to Lee PengYee Mthemtics Subject Clssifiction: 26A39, 46E30 Key words: Henstock Kurzweil integrl, convergence theorem, Alexiewicz norm Let < b nd denote the Henstock Kurzweil integrble functions on (, b) by HK. The Alexiewicz norm of f HK is f = sup I f where I the supremum is tken over ll intervls I (, b). If g is relvlued function on [, b] we write V [,b] g for the vrition of g over [, b], dropping the subscript when the identity of [, b] is cler. The set of functions of normlised bounded vrition, N BV, consists of the functions on [, b] tht re of bounded vrition, re left continuous nd vnish t. It is known tht the multipliers for HK re N BV, i.e., fg HK for ll f HK if nd only if g is equivlent to function in N BV. This pper is concerned with necessry nd sufficient conditions under which b fg for ll f HK. One such set of conditions ws given by Lee PengYee in [2, Theorem 12.11]. If g is of bounded vrition, chnging g on countble set will mke it n element of N BV. With this observtion, minor modifiction of Lee s theorem produces the following result. 1 Reserch prtilly supported by the Nturl Sciences nd Engineering Reserch Council of Cnd.
2 2 Prsr Mohnty nd Erik Tlvil Theorem 1 [2, Theorem 12.11] Let < < b <, let g n nd g be relvlued functions on [, b] with g of bounded vrition. In order for b fg n fg for ll f HK it is necessry nd sufficient tht b for ech intervl (c, d) (, b), d c g n d g s n, c for ech n 1, g n is equivlent to function h n N BV, nd there is M [0, ) such tht V h n M for ll n 1. We extend this theorem to unbounded intervls, show tht the condition d c g n d c g in (1) cn be replced by g n g on ech compct intervl in (, b) either in mesure or in the L 1 norm, nd tht this lso lets us conclude f(g n g) 0. We lso show tht if g n g in mesure or lmost everywhere then fg n fg for ll f HK if nd only if fg n fg 0 for ll f HK. One might think the conditions (1) imply g n g lmost everywhere. This is not the cse, s is illustrted by the following exmple [1, p. 61]. Exmple 2 Let g n = χ (j2 k,(j+1)2 k ] where 0 j < 2 k nd n = j + 2 k. Note tht g n = 1, g n N BV, V g n 2, nd d c g n g n = 2 k < 2/n 0, so tht (1) is stisfied with g = 0. For ech x (0, 1] we hve inf n g n (x) = 0, sup n g n (x) = 1, nd for no x (0, 1] does g n (x) hve limit. However, g n 0 in mesure since if T n = {x [0, 1] : g n (x) > ɛ} then for ech 0 < ɛ 1, we hve λ(t n ) < 2/n 0 s n (λ is Lebesgue mesure). We hve the following extension of Theorem 1. Theorem 3 Let [, b] be compct intervl in R, let g n nd g be relvlued functions on [, b] with g of bounded vrition. In order for b fg for ll f HK it is necessry nd sufficient tht g n g in mesure s n, for ech n 1, g n is equivlent to function h n N BV, (2) nd there is M [0, ) such tht V h n M for ll n 1. If (, b) R is unbounded, then chnge the first line of (2) by requiring g n χ I gχ I in mesure for ech compct intervl I (, b). (1) Proof: By working with g n g we cn ssume g = 0. First consider the cse when (, b) is bounded intervl. If b fg n 0 for ll f HK, then using Theorem 1 nd chnging g n on countble set, we cn ssume g n N BV, V g n M, g n M nd
3 Product convergence for Henstock Kurzweil integrls 3 d c g n 0 for ech intervl (c, d) (, b). Suppose g n does not converge to 0 in mesure. Then there re δ, ɛ > 0 nd n infinite index set J N such tht λ(s n ) > δ for ech n J, where S n = {x (, b) : g n (x) > ɛ}. (Or else there is corresponding set on which g n (x) < ɛ for ll n J.) Now let n J. Since g n is left continuous, if x S n there is number c n,x > 0 such tht [x c n,x, x] S n. Hence, V n := {[c, x] : x S n nd [c, x] S n } is Vitli cover of S n. So there is finite set of disjoint closed intervls, σ n V n, with λ(s n \ I σn I) < δ/2. Write (, b) \ I σn I = I τn I where τ n is set of disjoint open intervls with crd(τ n ) = crd(σ n ) + 1. Let P n = crd({i τ n : g n (x) ɛ/2 for some x I}). Ech intervl I τ n tht does not hve or b s n endpoint hs contiguous intervls on its left nd right tht re in σ n (for ech of which g n (x) > ɛ/2 for some x). The intervl I then contributes more thn (ɛ ɛ/2) + (ɛ ɛ/2) = ɛ to the vrition of g n. If I hs s n endpoint then, since g n () = 0, I contributes more thn ɛ to the vrition of g n. If I hs b s n endpoint then I contributes more thn ɛ/2 to the vrition of g n. Hence, V g n (P n 1)ɛ + ɛ/2 = (P n 1/2)ɛ. (This inequlity is still vlid if P n = 1.) But, V g n M so P n P for ll n J nd some P N. Then we hve set of intervls, U n, formed by tking unions of intervls from σ n nd those intervls in τ n on which g n > ɛ/2. Now, λ( I Un I) > δ/2, crd(u n ) P + 1 nd g n > ɛ/2 on ech intervl I U n. Therefore, there is n intervl I n U n such tht λ(i n ) > δ/[2(p + 1)]. The sequence of centres of intervls I n hs convergent subsequence. There is then n infinite index set J J with the property tht for ll n J we hve g n > ɛ/2 on n intervl I (, b) with λ(i) > δ/[3(p + 1)]. Hence, lim sup n 1 I g n > δɛ/[6(p + 1)]. This contrdicts the fct tht I g n 0, showing tht indeed g n 0 in mesure. Suppose (2) holds. As bove, we cn ssume g n N BV, V g n M, g n M nd g n 0 in mesure. Let ɛ > 0. Define T n = {x (, b) : g n (x) > ɛ}. Then b g n g n + T n g n (,b)\t n (3) Mλ(T n ) + ɛ(b ). (4) Since lim λ(t n ) = 0, it now follows tht d c g n 0 for ech (c, d) (, b). Theorem 1 now shows b fg n 0 for ll f HK. Now consider integrls on R. If fg n 0 for ll f HK then it is necessry tht b fg n 0 for ech compct intervl [, b]. By the current theorem, g n g in mesure on ech [, b]. And, it is necessry tht fg 1 n 0. The chnge of vribles x 1/x now shows it is necessry tht g n be
4 4 Prsr Mohnty nd Erik Tlvil equivlent to function tht is uniformly bounded nd of uniform bounded vrition on [1, ]. Similrly with 1 fg n 0. Hence, it is necessry tht g n be uniformly bounded nd of uniform bounded vrition on R. Suppose (2) holds with g n g in mesure on ech compct intervl in R. Write fg n = fg n + b fg n + fg b n. Use Lemm 24 in [4] to write fg n fχ (,) V [,] g n fχ (,) M 0 s. We cn then tke lrge enough intervl [, b] R nd pply the current theorem on [, b]. Other unbounded intervls re hndled in similr mnner. Remrk 4 If (2) holds then dominted convergence shows g n g 1 0. And, convergence in 1 implies convergence in mesure. Therefore, in the first sttement of (2) nd in the lst sttement of Theorem 3, convergence in mesure cn be replced with convergence in 1. Similr remrks pply to Theorem 6. Remrk 5 The chnge of vribles rgument in the second lst prgrph of Theorem 3 cn be replced with n ppel to the Bnch Steinhus Theorem on unbounded intervls. See [3, Lemm 7]. Similrly in the proof of Theorem 8. The sequence of Heviside step functions g n = χ (n, ] shows (2) is not necessry to hve fg n 0 for ll f HK. For then, fg n = n f 0. In this cse, g n N BV nd V g n = 1. However, λ(t n ) = for ll 0 < ɛ < 1. Note tht for ech compct intervl [, b] we hve b g n 0 nd g n 0 in mesure on [, b]. It is somewht surprising tht the conditions (2) re lso necessry nd sufficient to hve f(g n g) 0 for ll f HK. Theorem 6 Let [, b] be compct intervl in R, let g n nd g be relvlued functions on [, b] with g of bounded vrition. In order for f(g n g) 0 for ll f HK it is necessry nd sufficient tht g n g in mesure s n, for ech n 1, g n is equivlent to function h n N BV, nd there is M [0, ) such tht V h n M for ll n 1. If (, b) R is unbounded, then chnge the first line of (5) by requiring g n χ I gχ I in mesure for ech compct intervl I (, b). (5) Proof: Certinly (5) is necessry in order for f(g n g) 0 for ll f HK. If we hve (5), let I n be ny sequence of intervls in (, b). We cn gin ssume g = 0. Write g n = g n χ In. Then g n g n, V g n V g n +
5 Product convergence for Henstock Kurzweil integrls 5 2 g n nd g n 0 in mesure. The result now follows by pplying Theorem 3 to f g n. Unbounded intervls re hndled s in Theorem 3. By combining Theorem 3 nd Theorem 6 we hve the following. Theorem 7 Let (, b) R then b fg for ll f HK if nd only if fg n fg 0 for ll f HK. Note tht f(g n g) fg n fg so if f(g n g) 0 then fg n fg. Thus, (5) is sufficient to hve fg n fg for ll f HK. However, this condition is not necessry. For exmple, let [, b] = [0, 1]. Define g n (x) = ( 1) n. Then g n = 1 nd V g n = 0. Let g = g 1. For no x [ 1, 1] does the sequence g n (x) converge to g(x). For no open intervl I [0, 1] do we hve I (g n g) 0. And, g n does not converge to g in mesure. However, let f HK with f > 0. Then f(g n g) = 0 when n is odd nd when n is even, f(g n g) = 2 f. And yet, for ll n, fg n = f = fg. It is nturl to sk wht extr condition should be given so tht fg n fg will imply fg n fg 0. We hve the following. Theorem 8 Let g n g in mesure or lmost everywhere. Then fg n fg for ll f HK if nd only if fg n fg 0 for ll f HK. Proof: Let [, b] be compct intervl. If fg n fg then g is equivlent to h N BV [2, Theorem 12.9] nd for ech f HK there is constnt C f such tht fg n C f. By the Bnch Steinhus Theorem [2, Theorem 12.10], ech g n is equivlent to function h n N BV with V h n M nd h n M. Let (c, d) (, b). By dominted convergence, d c g n d g. It now follows c from Theorem 1 tht b fg for ll f HK. Hence, by Theorem 7, fg n fg 0 for ll f HK. Now suppose (, b) = R nd fg n fg for ll f HK. The chnge of vribles x 1/x shows the Bnch Steinhus Theorem still holds on R. We then hve ech g n equivlent to h n N BV with V h n M nd h n M. As with the end of the proof of Theorem 3, given ɛ > 0 we cn find c R such tht c fg n < ɛ for ll n 1. The other cses re similr. Acknowledgment. An nonymous referee provided reference [3] nd pointed out tht in plce of convergence in mesure we cn use convergence in 1 (cf. Remrk 4). References [1] G.B. Follnd, Rel nlysis, New York, Wiley, 1999.
6 6 Prsr Mohnty nd Erik Tlvil [2] P.Y. Lee, Lnzhou lectures on integrtion, Singpore, World Scientific, [3] W.L.C. Srgent, On some theorems of Hhn, Bnch nd Steinhus, J. London Mth. Soc. 28 (1953) [4] E. Tlvil, Henstock Kurzweil Fourier trnsforms, Illinois J. Mth. (to pper).
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