# Mechanics of Materials

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1 Mechanics of Materials Notation: a = acceleration = area (net = with holes, bearing = in contact, etc...) SD = allowable stress design d = diameter of a hole = calculus symbol for differentiation e = change in length E = modulus of elasticity or Young s modulus f = symbol for stress = physics symbol for force fallowable = allowable stress fv = shear stress fp = bearing stress (see ) Fallowed. = allowable stress F.S. = factor of safety g = acceleration due to gravity Ga = giga ascals (10 9 a) ka = kilopascals or 1 kn/m 2 ksi = kips per square inch = length RFD = load and resistance factor design m = mass Ma = megapascals or 10 6 N/m 2 or 1 N/mm 2 psi = pounds per square inch psf = pounds per square foot = name for axial force vector = name for internal axial force vector a = ascal (N/m 2 ) R = name for reaction force vector = name for design quantity (force or moment) for RFD, ex. R, RD, or Rn s t v W x y t restr T T = normal strain = length traveled of a particle = thickness = velocity = oisson's ratio = force due to a weight = horizontal dimension = vertical dimension = coefficient of thermal expansion for a material = strain = thermal strain (no units) = elongation or length change = elongation due to axial load = restrained length change = elongation due or length change due to temperature = change in temperature = angle of twist = resistance factor for RFD = diameter symbol = lateral strain ratio or oisson s ratio = symbol for micron = shear strain = dead load factor for RFD D = live load factor for RFD = angle of principle stress = radial distance = engineering symbol for normal stress = engineering symbol for shearing stress Mechanics of Materials is a basic engineering science that deals with the relation between externally applied load and its effect on deformable bodies. The main purpose of Mechanics of Materials is to answer the question of which requirements have to be met to assure STRENGTH, RIGIDITY, ND STBIITY of engineering structures. 79

2 To solve a problem in Mechanics of Materials, one has to consider THREE SECTS OF THE ROBEM: 1. STTICS: equilibrium of external forces, internal forces, stresses 2. GEOMETRY: deformations and conditions of geometric fit, strains 3. MTERI ROERTIES: stress-strain relationship for each material, obtained from material testing. STRESS The intensity of a force acting over an area Normal Stress (or Direct Stress) Stress that acts along an axis of a member; can be internal or external; can be compressive or tensile. B B f Strength condition: f f allowable or Fallowed net net Shear Stress (or Direct Shear Stress) Stress that acts perpendicular to an axis or length of a member, or that is parallel to the cross section is called shear stress. Shear stress cannot be assumed to be uniform, so we refer to average shearing stress. f v Strength condition: fv allowable or Fallowed net net 80

3 Shear Stress in Beams stress that acts transversely to the cross section, or along the beam length. It happens when there are vertical loads on a horizontal beam. and is larger than direct shear stress from the internal vertical force over the cross section. Bearing Stress compressive normal stress acting between two bodies. f p bearing Bending Stress in Beams normal stress caused by bending; can be compressive or tensile. Torsional Stress shear stress caused by torsion (moment around the axis). 81

4 Bolts in Shear and Bearing Single shear - forces cause only one shear drop across the bolt. Double shear - forces cause two shear changes across the bolt. 82

5 Bearing of a bolt on a bolt hole The bearing surface can be represented by projecting the cross section of the bolt hole on a plane (into a rectangle). f p td STRIN The relative change in geometry (length, angle, etc.) with respect to the original geometry. Deformation is the change in the size or shape of a structural member under loading. It can also occur due to heating or cooling of a material. Normal Strain In an axially loaded member, normal strain, s (or ) is the change in the length, e (or ) with respect to the original length,. s e or It is UNITESS, but may be called strain or microstrain (). 83

6 Shearing Strain In a member loaded with shear forces, shear strain, is the change in the sheared side, s with respect to the original height,. For small angles:. s tan tan s In a member subjected to twisting, the shearing strain is a measure of the angle of twist with respect to the length and distance from the center, : Testing of oad vs. Strain Behavior of materials can be measured by recording deformation with respect to the size of the load. For members with constant cross section area, we can plot stress vs. strain. BRITTE MTERIS - ceramics, glass, stone, cast iron; show abrupt fracture at small strains. DUCTIE MTERIS plastics, steel; show a yield point and large strains (considered plastic) and necking (give warning of failure) SEMI-BRITTE MTERIS concrete; show no real yield point, small strains, but have some strain-hardening. f inear-elastic Behavior E In the straight portion of the stress-strain diagram, the materials are elastic, which means if they are loaded and unloaded no permanent deformation occurs. 1 84

7 True Stress & Engineering Stress True stress takes into account that the area of the cross section changes with loading. Engineering stress uses the original area of the cross section. Hooke s aw Modulus of Elasticity In the linear-elastic range, the slope of the stress-strain diagram is constant, and has a value of E, called Modulus of Elasticity or Young s Modulus. or f E f E s Isotropic Materials have the same E with any direction of loading. nisotropic Materials have different E s with the direction of loading. Orthotropic Materials have directionally based E s 85

8 lastic Behavior & Fatigue ermanent deformations happen outside the linear-elastic range and are called plastic deformations. Fatigue is damage caused by reversal of loading. The proportional limit (at the end of the elastic range) is the greatest stress valid using Hooke s law. The elastic limit is the maximum stress that can be applied before permanent deformation would appear upon unloading. The yield point (at the yield stress) is where a ductile material continues to elongate without an increase of load. (May not be well defined on the stress-strain plot.) The ultimate strength is the largest stress a material will see before rupturing, also called the tensile strength. The rupture strength is the stress at the point of rupture or failure. It may not coincide with the ultimate strength in ductile materials. In brittle materials, it will be the same as the ultimate strength. The fatigue strength is the stress at failure when a member is subjected to reverse cycles of stress (up & down or compression & tension). This can happen at much lower values than the ultimate strength of a material. Toughness of a material is how much work (a combination of stress and strain) us used for fracture. It is the area under the stress-strain curve. Concrete does not respond well to tension and is tested in compression. The strength at crushing is called the compression strength. Materials that have time dependent elongations when loaded are said to have creep. Concrete and wood experience creep. Concrete also has the property of shrinking over time. permanent deformation on unloading fatigue cyclic loading 86

9 oisson s Ratio For an isometric material that is homogeneous, the properties are the same for the cross section: y z z There exists a linear relationship while in the linear-elastic range of the material between longitudinal strain and lateral strain: lateral strain y axial strain x z x f x y z E x ositive strain results from an increase in length with respect to overall length. Negative strain results from a decrease in length with respect to overall length. is the oisson s ratio and has a value between 0 and ½, depending on the material. Relation of Stress to Strain f ; and E f so E which rearranges to: or E e E Orthotropic Materials One class of non-isotropic materials is orthotropic materials that have directionally based values of modulus of elasticity and oisson s ratio (E, ). Ex: plywood, laminates, fiber reinforced polymers with direction fibers 87

10 Stress Concentrations In some sudden changes of cross section, the stress concentration changes (and is why we used average normal stress). Examples are sharp notches, or holes or corners. (Think about airplane window shapes...) Maximum Stress When both normal stress and shear stress occur in a structural member, the maximum stresses can occur at some other planes (angle of ). Maximum Normal Stress happens when Maximum Shearing Stress happens when 0 ND 45 with only normal stress in the x direction. Thermal Strains hysical restraints limit deformations to be the same, or sum to zero, or to be proportional with respect to the rotation of a rigid body. We know axial stress relates to axial strain: e which relates e or to. E Deformations can be caused by the material reacting to a change in energy with temperature. In general (there are some exceptions): Solid materials can contract with a decrease in temperature. Solid materials can expand with an increase in temperature. The change in length per unit temperature change is the coefficient of thermal expansion,. It has units of F or C and the deformation is related by: T T Thermal Strain: T T 88

11 Coefficient of Thermal Expansion Material Coefficients () [in./in./ F] Coefficients () [mm/mm/ C] Wood 3.0 x x 10-6 Glass 4.4 x x 10-6 Concrete 5.5 x x 10-6 Cast Iron 5.9 x x 10-6 Steel 6.5 x x 10-6 Wrought Iron 6.7 x x 10-6 Copper 9.3 x x 10-6 Bronze 10.1 x x 10-6 Brass 10.4 x x 10-6 luminum 12.8 x x 10-6 There is no stress associated with the length change with free movement, BUT if there are restraints, thermal deformations or strains can cause internal forces and stresses. How Restrained Bar Feels with Thermal Strain 1. Bar pushes on supports because the material needs to expand with an increase in temperature. 2. Supports push back. Bar is restrained, can t move and the reaction causes internal stress. Superposition Method If we want to solve a statically indeterminate problem that has extra support forces, we can: Remove a support or supports that makes the problem look statically determinate Replace it with a reaction and treat it like it is an applied force Impose the geometry restrictions that the support imposes For Example: T T T 0 E E T T E p E T 0 f T E 89

13 Example 1 (pg 50) Example 3*. running track in a gymnasium is hung from the roof trusses by 9.84 ft long steel rods, each of which supports a tensile load of 11,200 lb. The round rods have a diameter of 7/8 in. with the ends upset, that is, made larger by forging. This upset allows the full cross-sectional area of the rod (0.601 in. 2 ) to be utilized; otherwise the cutting of the threads will reduce the cross section of the rod. Investigate this design to determine whether it is safe. lso, determine the elongation of the steel rods when the load at capacity is applied. 91

14 Example 2 SO: If the beam is anchored to a concrete slab, and the steel sees a temperature change of 50 F while the concrete only sees a change of 30 F, determine the compressive stress in the beam. c = 5.5 x 10-6 / F s = 6.5 x 10-6 / F E c = 3 x 10 6 psi E s = 29 x 10 6 psi 92

15 Example 3 93

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