Flashback - Aqueous Salts! PRECIPITATION REACTIONS Chapter 15. Analysis of Silver Group. Solubility of a Salt. Analysis of Silver Group
|
|
- Jasmine Shaw
- 6 years ago
- Views:
Transcription
1 Page III-15-1 / Chapter Fifteen Lecture Notes Flashback - Aqueous Salts! If one ion from the Soluble Compd. list is present in a compound, the compound is water soluble. PRECIPITATION REACTIONS Chapter 15 Ba(NO3)2? soluble BaCl2? soluble Chemistry 223 Professor Michael Russell Solubility of a Salt Ag Pb Hg2 Consider NaCl dissolving in water NaCl(s) qe Na BaSO4? insoluble Cl- Solubility of NaCl exceeded when solid precipitate does not dissolve All salts formed in this experiment are said to be INSOLUBLE They form when mixing moderately concentrated solutions of the metal ion with chloride ions. Ag Pb Hg2 Although all salts formed in this experiment are said to be insoluble, they do dissolve to some SLIGHT extent. AgCl(s) qe Ag Cl- When equilibrium has been established, no more AgCl dissolves and the solution is SATURATED. Ag Pb Hg2 AgCl(s) qe Ag Cl- When solution is SATURATED, expt. shows that [Ag = 1.67 x 10-5 M. This is equivalent to the SOLUBILITY of AgCl. What is [Cl-? This is also equivalent to the AgCl solubility. Page III-15-1 / Chapter Fifteen Lecture Notes
2 Page III-15-2 / Chapter Fifteen Lecture Notes Ag Pb Hg2 Ag Pb Hg2 AgCl(s) qe Ag Cl- AgCl(s) qe Ag Cl- Saturated solution has [Ag = [Cl- = 1.67 x 10-5 M Kc = [Ag [Cl- = 2.79 x Use this to calculate Kc Because this is the product of "solubilities", we call it Kc = [Ag [Cl- Ksp = solubility product constant = (1.67 x 10-5)(1.67 x 10-5) See: Solubility Guide = 2.79 x Lead(II) Chloride PbCl2(s) qe Pb 2 Cl- Ksp = 1.9 x 10-5 Soluble Compounds Solubility of Lead(II) Iodide Solubility of Lead(II) Iodide Consider PbI2 dissolving in water Consider PbI2 dissolving in water PbI2(s) qe Pb 2 I- PbI2(s) qe Pb 2 I- Calculate Ksp if solubility = M Calculate Ksp if solubility = M 1. Solubility refers to how many moles of solid dissolve per L 1. Solubility = [Pb = 1.30 x 10-3 M [I- = 2 x [Pb = 2.60 x 10-3 M Solubility = [Pb = 1.30 x 10-3 M [I- = 2 x [Pb = 2.60 x 10-3 M 2. Ksp = [Pb [I-2 = [Pb {2 [Pb}2 = 4 [Pb3 Page III-15-2 / Chapter Fifteen Lecture Notes
3 Page III-15-3 / Chapter Fifteen Lecture Notes Solubility of Lead(II) Iodide Consider PbI 2 dissolving in water PbI 2 (s) qe Pb 2 I - Calculate K sp if solubility = M 2. K sp = 4 [Pb 3 = 4 (solubility) 3 K sp = 4 (1.30 x 10-3 ) 3 = 8.79 x 10-9 Notice that solubility of PbI 2 (x) and K sp related here by: K sp = 4x 3 Solubility and K sp Relations # cations # anions K sp and solubility (x) Examples 1 1 K sp = x2 NaCl, SrO, KClO K sp = 4x 3 PbI 2, Mg(OH) K sp = 4x 3 Na 2O, (NH 4 ) 2 SO K sp = 27x 4 Li 3P, (NH 4 ) 3 PO K sp = 27x 4 AlBr 3, Cr(NO 3 ) K sp = 108x 5 Fe 2O 3, Al 2 (SO 4 ) K sp = 108x 5 Ti 3 As 2, Mg 3 (PO 4 ) 2 See: Solubility Guide Solubility and K sp Relations Example: What is the solubility of copper(ii) phosphate if K sp = 1.4*10-37? Answer: Formula = Cu 3 (PO 4 ) 2 3 cations & 2 anions, so K sp = 108x 5 x = (1.4*10-37 /108) (1/5) = 1.7*10-8 M Example: What is K sp for magnesium carbonate if the solubility at 25 C is 2.6*10-3 M? Answer: Formula = MgCO 3, 1 cation & 1 anion, so K sp = x 2 K sp = (2.6*10-3 ) 2 = 6.8*10-6 Precipitating an Insoluble Salt Hg 2 Cl 2 (s) qe Hg 2 2 Cl - K sp = 1.1 x = [Hg 2 [Cl - 2 If [Hg 2 = M, what [Cl - is req'd to just begin the precipitation of Hg 2 Cl 2? That is, what is the maximum [Cl - that can be in solution with M Hg 2 without forming Hg 2 Cl 2? Precipitating an Insoluble Salt Hg 2 Cl 2 (s) qe Hg 2 2 Cl - K sp = 1.1 x = [Hg 2 [Cl - 2 Recognize that K sp = product of maximum ion concs. Precip. begins when product of ion concs. EXCEEDS the K sp. Precipitating an Insoluble Salt Hg 2 Cl 2 (s) qe Hg 2 2 Cl - K sp = 1.1 x = [Hg 2 [Cl - 2 [Cl - that can exist when [Hg 2 = M: [Cl - = If this conc. of Cl - is just exceeded, Hg 2 Cl 2 begins to precipitate. K sp = 1.0 x 10-8 M Page III-15-3 / Chapter Fifteen Lecture Notes
4 Precipitating an Insoluble Salt Hg 2 Cl 2 (s) qe Hg 2 2 Cl - K sp = 1.1 x Now raise [Cl - to 1.0 M when [Hg 2 = M. What is the value of [Hg 2 at this point? [Hg 2 = K sp / [Cl - 2 = K sp / (1.0) 2 = 1.1 x M The concentration of Hg 2 has been reduced by 10 16! Page III-15-4 / Chapter Fifteen Lecture Notes Adding an ion "common" to an equilibrium causes the equilibrium to shift back to reactant. Common Ion Effect Adding an Ion "Common" to an Equilibrium K sp for BaSO 4 = 1.1 x = [Ba [SO 4 BaSO 4 (s) qe Ba SO 4 Solubility in pure water = [Ba = [SO 4 = x K sp = [Ba [SO 4 = x 2 x = (K sp ) 1/2 = 1.0 x 10-5 M Note 1:1 ratio of cation to anion: K sp = x 2 K sp for BaSO 4 = 1.1 x = [Ba [SO 4 BaSO 4 (s) qe Ba SO 4 So... Solubility in pure water = 1.0 x 10-5 mol/l. Now dissolve BaSO 4 in water already containing M Ba. Which way will the "common ion" shift the equilibrium? Will solubility of BaSO 4 be less than or greater than in pure water? K sp for BaSO 4 = 1.1 x = [Ba [SO 4 BaSO 4 (s) qe Ba SO 4 [Ba [SO 4 initial change y y equilib y y Page III-15-4 / Chapter Fifteen Lecture Notes
5 Page III-15-5 / Chapter Fifteen Lecture Notes K sp for BaSO 4 = 1.1 x = [Ba [SO 4 BaSO 4 (s) qe Ba SO 4 K sp = [Ba [SO 4 = (0.010 y) (y) Because y < 1.0 x 10-5 M (= x, the solubility in pure water), this means y is about equal to Therefore, K sp = 1.1 x = (0.010)(y) y = 1.1 x 10-8 M = solubility in presence of added Ba ion. K sp for BaSO 4 = 1.1 x = [Ba [SO 4 BaSO 4 (s) qe Ba SO 4 Solubility in pure water = x = 1.0 x 10-5 M Solubility in presence of added Ba = 1.1 x 10-8 M Le Chatelier's Principle is followed! See: Solubility Guide DISTRACTIONS!!! Separating Metal Ions Cu, Ag, Pb K sp Values AgCl 1.8 x PbCl x 10-5 PbCrO x Separating Salts by Differences in K sp A solution contains M Ag and M Pb. Add CrO 4 to precipitate red Ag 2 CrO 4 and yellow PbCrO 4. Which precipitates first? K sp for Ag 2 CrO 4 = 9.0 x = [Ag 2 [CrO 4 K sp for PbCrO 4 = 1.8 x = [Pb [CrO 4 The substance whose K sp is first exceeded precipitates first. The ion requiring the lesser amount of CrO 4 ppts. first. Separating Salts by Differences in K sp Page III-15-5 / Chapter Fifteen Lecture Notes A solution contains M Ag and M Pb. Add CrO 4 to precipitate red Ag 2 CrO 4 and yellow PbCrO 4. Which precipitates first? K sp for Ag 2 CrO 4 = 9.0 x = [Ag 2 [CrO 4 K sp for PbCrO 4 = 1.8 x = [Pb [CrO 4 - Calculate [CrO 4 required by each ion [CrO 4 to ppt. PbCrO 4 = K sp / [Pb = 1.8 x / = 9.0 x M [CrO 4 to ppt. Ag 2 CrO 4 = K sp / [Ag 2 = 9.0 x / (0.020) 2 = 2.3 x 10-8 M PbCrO 4 precipitates first.
6 Page III-15-6 / Chapter Fifteen Lecture Notes Separating Salts by Differences in Ksp Separating Salts by Differences in Ksp A solution contains M Ag and M Pb. Add CrO4 to precipitate red Ag2CrO4 and yellow PbCrO4. PbCrO4 ppts. first. Ksp (Ag2CrO4)= 9.0 x = [Ag2 [CrO4 A solution contains M Ag and M Pb. Add CrO4 to precipitate red Ag2CrO4 and yellow PbCrO4. Ksp (Ag2CrO4)= 9.0 x = [Ag2 [CrO4 Ksp (PbCrO4) = 1.8 x = [Pb [CrO4 How much Pb remains in solution when Ag begins to precipitate? Ksp (PbCrO4) = 1.8 x = [Pb [CrO4 How much Pb remains in solution when Ag begins to precipitate? We know that [CrO4 = 2.3 x 10-8 M to begin to precipitate Ag2CrO4. What is the Pb conc. at this point? [Pb = Ksp / [CrO4 = 1.8 x / 2.3 x 10-8 M = 7.8 x 10-7 M Lead ion has dropped from M to < 10-6 M Formation Constants Formation Constants (Kf) at 25 C Complex Ions are systems with Lewis bases connected around the (Lewis) acidic metal center. Examples: Zn(NH3)4, Ag(CN)1 Can write a Formation Constant, Kf Ag 2 CN-1 qe Ag(CN)2-1, Example: Ag 2 CN-1 qe Ag(CN)1 ions are reactants, complex ion is product, usually written as net ionic reactions and [Ag(CN) 1 2 Kf = = 5.6 * [Ag [CN Kf values usually quite large (product-favored) and product is always the complex ion End of Chapter 15 Formation Constants Complex Ions can be helpful when dissolving solids. Ex: AgCl(s) and Ag(NH3) AgCl(s) qe Ag Ag Cl- 2 NH3 qe Ag(NH3)2 Ksp Kf AgCl(s) 2 NH3 qe Ag(NH3) ClKnet = Ksp * Kf See: Chapter Fifteen Study Guide Chapter Fifteen Concept Guide Types of Equilibrium Constants Solubility Guide Page III-15-6 / Chapter Fifteen Lecture Notes
Flashback - Aqueous Salts! PRECIPITATION REACTIONS Chapter 15. Analysis of Silver Group. Solubility of a Salt. Analysis of Silver Group
Page III-15-1 / Chapter Fifteen Lecture Notes Flashback - Aqueous Salts! If one ion from the Soluble Compd. list is present in a compound, the compound is water soluble. PRECIPITATION REACTIONS Chapter
More informationChapter 18. Solubility and Complex- Ionic Equilibria
Chapter 18 Solubility and Complex- Ionic Equilibria 1 The common ion effect Le Chatelier Why is AgCl less soluble in sea water than in fresh water? AgCl(s) Ag + + Cl Seawater contains NaCl 2 Problem: The
More informationChapter 19. Solubility and Simultaneous Equilibria p
Chapter 19 Solubility and Simultaneous Equilibria p. 832 857 Solubility Product ) The product of molar concentrations of the constituent ions, each raised ot the power of its stoichiometric coefficients
More informationMore About Chemical Equilibria
1 More About Chemical Equilibria Acid-Base & Precipitation Reactions Chapter 15 & 16 1 Objectives Chapter 15 Define the Common Ion Effect (15.1) Define buffer and show how a buffer controls ph of a solution
More informationAP Chemistry Table of Contents: Ksp & Solubility Products Click on the topic to go to that section
Slide 1 / 91 Slide 2 / 91 AP Chemistry Aqueous Equilibria II: Ksp & Solubility Products Table of Contents: K sp & Solubility Products Slide 3 / 91 Click on the topic to go to that section Introduction
More informationModified Dr. Cheng-Yu Lai
Ch16 Aqueous Ionic Equilibrium Solubility and Complex Ion Equilibria Lead (II) iodide precipitates when potassium iodide is mixed with lead (II) nitrate Modified Dr. Cheng-Yu Lai Solubility-product constant
More informationSaturated vs. Unsaturated
Solubility Equilibria in Aqueous Systems K sp (Equilibria of Slightly Soluble Salts, Ionic Compounds) Factors that Affect Solubility (Common Ion Effect, AcidBase Chemistry) Applications of Ionic Equilibria
More informationSOLUBILITY REVIEW QUESTIONS
Solubility Problem Set 1 SOLUBILITY REVIEW QUESTIONS 1. What is the solubility of calcium sulphate in M, g/l, and g/100 ml? 2. What is the solubility of silver chromate? In a saturated solution of silver
More informationSolubility and Complex-ion Equilibria
Solubility and Complex-ion Equilibria Contents and Concepts Solubility Equilibria 1. The Solubility Product Constant 2. Solubility and the Common-Ion Effect 3. Precipitation Calculations 4. Effect of ph
More information116 PLTL Activity sheet / Solubility Equilibrium Set 11
Predicting Solubility Solubility problems are equilibrium problems. The reactant in a solubility equilibrium is a slightly soluble salt and the equilibrium constant for the reaction is the solubility product
More informationSolubility Equilibria. Dissolving a salt... Chem 30S Review Solubility Rules. Solubility Equilibrium: Dissociation = Crystalization
Chem 30S Review Solubility Rules Solubility Equilibria Salts are generally more soluble in HOT water(gases are more soluble in COLD water) Alkali Metal salts are very soluble in water. NaCl, KOH, Li 3
More informationUNIT III: SOLUBILITY EQUILIBRIUM YEAR END REVIEW (Chemistry 12)
I. Multiple Choice UNIT III: SOLUBILITY EQUILIBRIUM YEAR END REVIEW (Chemistry 12) 1) Which one of the following would form an ionic solution when dissolved in water? A. I 2 C. Ca(NO 3 ) 2 B. CH 3 OH D.
More information1. Forming a Precipitate 2. Solubility Product Constant (One Source of Ions)
Chemistry 12 Solubility Equilibrium II Name: Date: Block: 1. Forming a Precipitate 2. Solubility Product Constant (One Source of Ions) Forming a Precipitate Example: A solution may contain the ions Ca
More informationSolubility Multiple Choice. January Which of the following units could be used to describe solubility? A. g/s B. g/l C. M/L D.
Solubility Multiple Choice January 1999 14. Which of the following units could be used to describe solubility? A. g/s B. g/l C. M/L D. mol/s 15. Consider the following anions: When 10.0mL of 0.20M Pb(NO3)
More informationCHEM 12 Unit 3 Review package (solubility)
CHEM 12 Unit 3 Review package (solubility) 1. Which of the following combinations would form an ionic solid? A. Metalloid - metal B. Metal non-metal C. Metalloid metalloid D. Non-metal non-metal 2. Which
More informationAP Chemistry. Slide 1 / 39. Slide 2 / 39. Slide 3 / 39. Equilibrium Part C : Solubility Equilibrium. Table of Contents
Slide 1 / 39 AP Chemistry Slide 2 / 39 Equilibrium Part C : Solubility Equilibrium 2014-10-29 www.njctl.org Table of Contents click on the topic to go to that section Slide 3 / 39 Molar Solubility Calculating
More informationLecture #12 Complex Ions and Solubility
Lecture #12 Complex Ions and Solubility Stepwise exchange of NH 3 for H 2 O in M(H 2 O) 4 2+ M(H 2 O) 2 (NH 3 ) 2 2+ M(H 2 O) 4 2+ M(NH 3 ) 4 2+ M(H 2 O) 3 (NH 3 ) 2+ M(H 2 O)(NH 3 ) 3 2+ Formation Constants
More informationSolubility Equilibria
Chapter 17 SOLUBILITY EQUILIBRIA (Part II) Dr. Al Saadi 1 Solubility Equilibria The concept of chemical equilibrium helps to predict how much of a specific ionic compound (salt) will dissolve in water.
More informationLearning Objectives. Solubility and Complex-ion Equilibria. Contents and Concepts. 3. Precipitation Calculations. 4. Effect of ph on Solubility
Solubility and Comple-ion Equilibria. Solubility and the Common-Ion Effect a. Eplain how the solubility of a salt is affected by another salt that has the same cation or anion. (common ion) b. Calculate
More information22. What is the maximum concentration of carbonate ions that will precipitate BaCO 3 but not MgCO 3 from a solution that is 2.
PX312-1718 1. What is the solubility product expression for Th(IO 3 ) 4? A) K sp = [Th 4+ ][4IO 3 ] 4 B) K sp = [Th 4+ ][IO 3 ] C) K sp = [Th][IO 3 ] 4 D) K sp = [Th 4+ ][IO 3 ] 4 E) K sp = [Th 4+ ][IO
More informationSolubility Equilibrium. Solutions. Dissociation Equations. April/May Chemistry 30
Solubility Equilibrium Chemistry 30 Solutions Mixture containing two or more components, but looks like one homogeneous substance Solute: dissolved substance Solvent: dissolving substance In this course:
More informationPart One: Solubility Equilibria. Insoluble and slightly soluble compounds are important in nature and commercially.
CHAPTER 17: SOLUBILITY AND COMPLEX ION EQUILIBRIA Part One: Solubility Equilibria A. Ksp, the Solubility Product Constant. (Section 17.1) 1. Review the solubility rules. (Table 4.1) 2. Insoluble and slightly
More informationIII.1 SOLUBILITY CONCEPT REVIEW
III.1 SOLUBILITY CONCEPT REVIEW Read Hebden p. 73 76 and review basic solubility definitions. Soluble means Insoluble means The Dissolving Process IONIC Solutions MOLECULAR Solutions (Covalent compounds)
More informationSolubility Equilibrium
2016 Ksp note.notebook Solubility Equilibrium Learning Goals: to understand what happens when a compound dissolves in water to calculate the extent of dissolution...the molar solubility to calculate the
More informationSolubility Equilibria
Solubility Equilibria Heretofore, we have investigated gas pressure, solution, acidbase equilibriums. Another important equilibrium that is used in the chemistry lab is that of solubility equilibrium.
More informationSolubility Rules and Net Ionic Equations
Solubility Rules and Net Ionic Equations Why? Solubility of a salt depends upon the type of ions in the salt. Some salts are soluble in water and others are not. When two soluble salts are mixed together
More informationChapter 16. Solubility and Complex Ion Equilibria
Chapter 16 Solubility and Complex Ion Equilibria Section 16.1 Solubility Equilibria and the Solubility Product Solubility Equilibria Solubility product (K sp ) equilibrium constant; has only one value
More informationReview 7: Solubility Equilibria
Review 7: Solubility Equilibria Objectives: 1. Be able to write dissociation equations for ionic compounds dissolving in water. 2. Given Ksp, be able to determine the solubility of a substance in both
More informationChapter 17: Aqueous Ionic Equilibria III. Solubility equilibria Chem 102 Dr. Eloranta
Chapter 17: Aqueous Ionic Equilibria III Solubility equilibria Chem 102 Dr. Eloranta Solubility equilibria Solubility: amount of a solid (usually an ionic compound a salt) that dissolves in solution. Molar
More information1. Which one of the following would form an ionic solution when dissolved in water? A. I2 C. Ca(NO3)2 B. CH3OH D. C12H22O11
Chemistry 12 Solubility Equilibrium Review Package Name: Date: Block: I. Multiple Choice 1. Which one of the following would form an ionic solution when dissolved in water? A. I2 C. Ca(NO3)2 B. CH3OH D.
More informationSolubility and Complex-ion Equilibria
Solubility and Complex-ion Equilibria Solubility Equilibria Many natural processes depend on the precipitation or dissolving of a slightly soluble salt. In the next section, we look at the equilibria of
More informationWe CAN have molecular solutions (ex. sugar in water) but we will be only working with ionic solutions for this unit.
Solubility Equilibrium The Basics (should be mostly review) Solubility is defined as the maximum amount of a substance which can be dissolved in a given solute at a given temperature. The solubility of
More informationSOLUBILITY PRODUCT (K sp ) Slightly Soluble Salts & ph AND BUFFERS (Part Two)
SOLUBILITY PRODUCT (K sp ) Slightly Soluble Salts & ph AND BUFFERS (Part Two) ADEng. PRGORAMME Chemistry for Engineers Prepared by M. J. McNeil, MPhil. Department of Pure and Applied Sciences Portmore
More informationChapter 16. Solubility Equilibria 10/14/2010. Solubility Equilibria. Solubility Product (Constant), K sp. Solubility and the Solubility Product
Solubility Equilibria These are associated with ionic solids dissolving in water to form aqueous solutions Chapter 16 Solubility Equilibria It is assumed that when an ionic compound dissolves in water,
More informationSOLUBILITY EQUILIBRIA (THE SOLUBILITY PRODUCT)
SOLUBILITY EQUILIBRIA (THE SOLUBILITY PRODUCT) Saturated solutions of salts are another type of chemical equilibria. Slightly soluble salts establish a dynamic equilibrium with the hydrated cations and
More informationAqueous Equilibria, Part 2 AP Chemistry Lecture Outline
Aqueous Equilibria, Part 2 AP Chemistry Lecture Outline Name: The Common-Ion Effect Suppose we have a weak acid and a soluble salt of that acid. CH 3 COOH NaCH 3 COO CH 3 COOH CH 3 COO + H + Since NaCH
More information] [ SO 4 ] let sol y x x = x x be x = x 2 if sol y = 7.94 x 10 4 mol/l = 6.3 x 10 7
SCH 4U: UNIT 4 LESSONS Heterogeneous EQUILIBRIUM (Chap 17-pg 759) 1. Rationale: The principles of Chemical Equilibrium developed earlier (in Unit 3) also apply to weakly soluble salts. In this unit we
More informationChapter 19 Solubility and Complex Ion Equilibria
Chapter 19 Solubility and Complex Ion Equilibria "if you are not part of the solution, then you are part of the precipitate" - all solutions of salts exist as a balance between the dissolved cations and
More informationUnit 3: Solubility Equilibrium
Unit 3: Chem 11 Review Preparation for Chem 11 Review Preparation for It is expected that the student understands the concept of: 1. Strong electrolytes, 2. Weak electrolytes and 3. Nonelectrolytes. CHEM
More informationAqueous Equilibria: Part II- Solubility Product
Aqueous Equilibria: Part II- Solubility Product PSI AP Chemistry Name-------------------------- I Solubility Product, K sp MC #63-103 a) Writing K sp expression b) Solving for K sp c) Solving for (molar)
More informationSolubility Equilibrium When a substance dissolves an equilibrium results between the precipitate and the dissolved ions. The solution becomes
Solubility Equilibrium When a substance dissolves an equilibrium results between the precipitate and the dissolved ions. The solution becomes saturated. The particles dissolving equals the particles precipitating.
More informationPractice Worksheet - Answer Key. Solubility #1 (KEY)
Practice Worksheet - Answer Key Solubility #1 (KEY) 1 Indicate whether the following compounds are ionic or covalent a) NaCl ionic f) Sr(OH) 2 ionic b) CaBr 2 ionic g) MgCO 3 ionic c) SO 2 covalent h)
More informationThe solvent is the dissolving agent -- i.e., the most abundant component of the solution
SOLUTIONS Definitions A solution is a system in which one or more substances are homogeneously mixed or dissolved in another substance homogeneous mixture -- uniform appearance -- similar properties throughout
More informationApplications of Aqueous Equilibria Chapter 15. Solubility Equilbriua Sections 6-8
Applications of Aqueous Equilibria Chapter 15 Solubility Equilbriua Sections 6-8 Solubility Product CaF 2 (s) Ca 2+ (aq) + 2F - (aq) then Ca 2+ (aq) + 2F - (aq) CaF 2 (s) CaF 2 (s) Ca 2+ (aq) + 2F - (aq)
More informationUnit 3: Solubility Equilibrium
Unit 3: Chem 11 Review Preparation for Chem 11 Review Preparation for It is expected that the student understands the concept of: 1. Strong electrolytes, 2. Weak electrolytes and 3. Nonelectrolytes. CHEM
More informationChapter 16: Applications of Aqueous Equilibrium Part 3. Solubilities of Ionic Compounds and K sp
Chapter 16: Applications of Aqueous Equilibrium Part 3 Solubilities of Ionic Compounds and K sp You ve already learned that not all ionic compounds are water soluble. You memorized the solubility rules
More informationHW 16-10: Review from textbook (p.725 #84, 87, 88(mod), 89, 95, 98, 101, 102, 110, 113, 115, 118, 120, SG#23,A)
HW 6: Review from textbook (p.75 #84, 87, 88(mod), 89, 95, 98,,,, 3, 5, 8,, SG#3,A) 6.84 The pk a of the indicator methyl orange is 3.46. Over what ph range does this indicator change from 9 percent HIn
More informationA reaction in which a solid forms is called a precipitation reaction. Solid = precipitate
Chapter 7 Reactions in Aqueous Solutions 1 Section 7.1 Predicting Whether a Reaction Will Occur Four Driving Forces Favor Chemical Change 1. Formation of a solid 2. Formation of water 3. Transfer of electrons
More informationIII.2 Calculating Solubility and Ion Concentrations. ***This is a re-visitation to Chemistry 11: translating grams/l to moles/l (M) and back again.
III.2 Calculating Solubility and Ion Concentrations Solubility ***This is a re-visitation to Chemistry 11: translating grams/l to moles/l (M) and back again. Grams moles (M) L L Since Solubility is a measure
More information] after equilibrium has been established?
Chemistry 1 Solubility Equilibrium onster Review 1. A saturated solution forms when a 0. 10 mol of salt is added to 10. L of water. The salt is A. Li S B. CuBr C. Zn( OH) ( ) D. NH CO 4. Consider the following
More informationChapter 17. Additional Aspects of Equilibrium
Chapter 17. Additional Aspects of Equilibrium Sample Exercise 17.1 (p. 726) What is the ph of a 0.30 M solution of acetic acid? Be sure to use a RICE table, even though you may not need it. (2.63) What
More informationSolutions CHAPTER OUTLINE
Chapter 8A Solutions 1 CHAPTER OUTLINE Type of Solutions Electrolytes & Nonelectrolytes Equivalents of Electrolytes Solubility & Saturation Soluble & Insoluble Salts Formation of a Solid Precipitation
More informationChapter 15 Additional Aspects of
Chemistry, The Central Science Chapter 15 Additional Aspects of Buffers: Solution that resists change in ph when a small amount of acid or base is added or when the solution is diluted. A buffer solution
More informationCHEM Dr. Babb s Sections Exam #4 Review Sheet
CHEM 116 - Dr. Babb s Sections Exam #4 Review Sheet 158. Explain using the HC 2 H 3 O 2 /NaC 2 H 3 O 2 buffer system how a buffer maintains a relatively constant ph when small quantity of acid (HCl) or
More informationSolubility Equilibria. Even substances that are considered "insoluble" dissolve to a small extent.
Solubility Equilibria Even substances that are considered "insoluble" dissolve to a small extent. When a solution contains the maximum amount of dissolved material, it is saturated. 1 2 The undissolved
More informationSolubility and Complex Ion Equilibria
Solubility and Complex Ion Equilibria a mineral formed by marine organisms through biological precipitation CALCITE CaCO 3(s) Ca + (aq)+ CO 3 - (aq) K K sp [Ca + ][CO 3 - ].8 x 10-9 K sp solubility product
More informationAP* Chapter 16. Solubility and Complex Ion Equilibria
AP* Chapter 16 Solubility and Complex Ion Equilibria AP Learning Objectives LO 6.1 The student is able to, given a set of experimental observations regarding physical, chemical, biological, or environmental
More informationSolubility and Complex Ion Equilibria
CALCITE Solubility and Complex Ion Equilibria a mineral formed by marine organisms through biological precipitation CaCO (s) Ca + (aq)+ CO (aq) K K sp [Ca + ][CO ].8 x 10-9 K sp solubility product constant
More informationNet Ionic Reactions. The reaction between strong acids and strong bases is one example:
Net Ionic Reactions Model 1 Net Ionic Reactions. Net ionic reactions are frequently used when strong electrolytes react in solution to form nonelectrolytes or weak electrolytes. These equations let you
More informationSOLUBILITY EQUILIBRIUM
Introduction SOLUBILITY EQUILIBRIUM A. Ionic vs Molecular Solutions 1. Ionic Compounds form Ionic Solutions a) Ionic compounds ( + ) dissolved in water to form Ionic Solutions eg1: equation AlCl3(s) Al3+
More informationOperational Skills. Operational Skills. The Common Ion Effect. A Problem To Consider. A Problem To Consider APPLICATIONS OF AQUEOUS EQUILIBRIA
APPLICATIONS OF AQUEOUS EQUILIBRIA Operational Skills Calculating the common-ion effect on acid ionization Calculating the ph of a buffer from given volumes of solution Calculating the ph of a solution
More informationCHM 112 Dr. Kevin Moore
CHM 112 Dr. Kevin Moore Reaction of an acid with a known concentration of base to determine the exact amount of the acid Requires that the equilibrium of the reaction be significantly to the right Determination
More informationCh 17 Solubility Equilibria. Brown & LeMay
Ch 17 Solubility Equilibria Brown & LeMay When a typical ionic solid is dissolved in water that dissolved material can be assumed to be present as separate hydrated anions & cations. For example: CaF 2
More informationChemistry 12 Unit III Solubility Notes
Chemistry 12 Unit III Solubility Notes III.1 A Review Of Solubility There are only three classes of compounds that form ionic solutions: ACIDS, BASES and SALTS. This unit will deal only with SALTS. Acids
More informationReactions in aqueous solutions Precipitation Reactions
Reactions in aqueous solutions Precipitation Reactions Aqueous solutions Chemical reactions that occur in water are responsible for creation of cenotes. When carbon dioxide, CO2, dissolves in water, the
More informationChemical & Solubility Equilibrium (K eq, K c, K p, K sp )
Chemistry, The Central Science, 10th edition Theodore L. Brown; H. Eugene LeMay, Jr.; and Bruce E. Bursten Unit 8 (Chp 15,17): Chemical & Solubility (K eq, K c, K p, K sp ) John D. Bookstaver St. Charles
More informationReference: Chapter 4 in textbook. PART 6B Precipitate. textbook
PART 6A Solution Reference: Chapter 4 in textbook PART 6B Precipitate Reference: Chapter 16.5 16.8 in the textbook 1 Solution Solute, Solvent, and Solution Saturated solution and Solubility Saturated solution:
More informationIntroducing Driving Force #3 - Formation of a Solid
Introducing Driving Force #3 - Formation of a Solid A solid that forms in an aqueous reaction is called a precipitate Precipitation reactions are also known as double replacement reactions Cations trade
More informationSolution Stoichiometry
Chapter 8 Solution Stoichiometry Note to teacher: You will notice that there are two different formats for the Sample Problems in the student textbook. Where appropriate, the Sample Problem contains the
More informationHomework: 14, 16, 21, 23, 27, 29, 39, 43, 48, 49, 51, 53, 55, 57, 59, 67, 69, 71, 77, 81, 85, 91, 93, 97, 99, 104b, 105, 107
Homework: 14, 16, 21, 23, 27, 29, 39, 43, 48, 49, 51, 53, 55, 57, 59, 67, 69, 71, 77, 81, 85, 91, 93, 97, 99, 104b, 105, 107 Chapter 15 Applications of Aqueous Equilibria (mainly acid/base & solubility)
More informationIonic Equilibria. weak acids and bases. salts of weak acids and bases. buffer solutions. solubility of slightly soluble salts
Ionic Equilibria weak acids and bases salts of weak acids and bases buffer solutions solubility of slightly soluble salts Arrhenius Definitions produce H + ions in the solution strong acids ionize completely
More informationinsoluble partial very soluble (< 0.1 g/100ml) solubility (> 1 g/100ml) Factors Affecting Solubility in Water
Aqueous Solutions Solubility is a relative term since all solutes will have some solubility in water. Insoluble substances simply have extremely low solubility. The solubility rules are a general set of
More informationSOLUBILITY AND PRECIPITATION EQUILIBRIA
16 CHAPTER SOLUBILITY AND PRECIPITATION EQUILIBRIA 16.1 The Nature of Solubility Equilibria 16.2 Ionic Equilibria between Solids and Solutions 16.3 Precipitation and the Solubility Product 16.4 The Effects
More informationSOLUBILITY AND PRECIPITATION EQUILIBRIA
16 CHAPTER SOLUBILITY AND PRECIPITATION EQUILIBRIA 16.1 The Nature of Solubility Equilibria 16.2 Ionic Equilibria between Solids and Solutions 16.3 Precipitation and the Solubility Product 16.4 The Effects
More informationLast Lecture. K 2 SO 4 (aq) + Ba(NO 3 ) 2 (aq) AgNO 3 (aq) + KCl(aq) NaNO 3 (aq) + KCl(aq) What will happen when these are mixed together?
Announcements Precipitation lab write-up due tomorrow at the start of discussion Text HW due tomorrow in discussion Lon-capa HW #4 Type 1 due Monday, Oct 15 th at 7:00pm Lon-capa HW #4 Type 2 due Wednesday,
More informationAdvanced Chemistry Practice Problems
Aqueous Equilibria: olar Solubility and the Common Ion Effect 1. Question: Which of the following compounds will decrease the solubility of lead(ii) bromide in water? a. Lead(II) nitrate b. Sodium chloride
More informationUnit 10 Solution Chemistry 1. Solutions & Molarity 2. Dissolving 3. Dilution 4. Calculation Ion Concentrations in Solution 5. Precipitation 6.
Unit 10 Solution Chemistry 1. Solutions & Molarity 2. Dissolving 3. Dilution 4. Calculation Ion Concentrations in Solution 5. Precipitation 6. Formula, Complete, Net Ionic Equations 7. Qualitative Analysis
More informationCh. 14/15: Acid-Base Equilibria Sections 14.6, 14.7, 15.1, 15.2
Ch. 14/15: Acid-Base Equilibria Sections 14.6, 14.7, 15.1, 15.2 Creative Commons License Images and tables in this file have been used from the following sources: OpenStax: Creative Commons Attribution
More informationUnit 1 - Foundations of Chemistry
Unit 1 - Foundations of Chemistry Chapter 2 - Chemical Reactions Unit 1 - Foundations of Chemistry 1 / 42 2.1 - Chemical Equations Physical and Chemical Changes Physical change: A substance changes its
More informationHW 7 KEY!! Chap. 7, #'s 11, 12, odd, 31, 33, 35, 39, 40, 53, 59, 67, 70, all, 77, 82, 84, 88, 89 (plus a couple of unassigned ones)
HW 7 KEY!! Chap. 7, #'s 11, 12, 15-21 odd, 31, 33, 35, 39, 40, 53, 59, 67, 70, 72-75 all, 77, 82, 84, 88, 89 (plus a couple of unassigned ones) 11) NOTE: I used the solubility rules that I have provided
More informationChapter 17. Additional Aspects of Equilibrium
Chapter 17. Additional Aspects of Equilibrium 17.1 The Common Ion Effect The dissociation of a weak electrolyte is decreased by the addition of a strong electrolyte that has an ion in common with the weak
More information11.3 Reactions in Aqueous Essential Understanding Reactions that occur in aqueous solutions are double-replacement
13. Is the following sentence true or false? Hydrocarbons, compounds of hydrogen and carbon, are often the reactants in combustion reactions. 14. Circle the letter of each compound that can be produced
More informationSolubility & Equilibrium Unit Review
Solubility & Equilibrium Unit Review This review is worth 3 marks of your total test marks. It must be completed on test day. 3 marks will be given to students who have fully completed this review with
More informationOAC UNIT 4 - SOLUBILITY EQUILIBRIA - ANSWERS
OAC UNIT 4 - SOLUBILITY EQUILIBRIA - ANSWERS 1. a) NH 3 is most likely ( H = 201 ) **enthalpy (difference between the energy req d to break up the crystal lattice and the energy obtained in the hydration
More informationAP Chemistry. CHAPTER 17- Buffers and Ksp 17.1 The Common Ion Effect Buffered Solutions. Composition and Action of Buffered Solutions
AP Chemistry CHAPTER 17- Buffers and Ksp 17.1 The Common Ion Effect The dissociation of a weak electrolyte is decreased by the addition of a strong electrolyte that has an ion in common with the weak electrolyte.
More informationIONIC CHARGES. Chemistry 51 Review
IONIC CHARGES The ionic charge of an ion is dependent on the number of electrons lost or gained to attain a noble gas configuration. For most main group elements, the ionic charges can be determined from
More informationTYPES OF CHEMICAL REACTIONS
TYPES OF CHEMICAL REACTIONS Precipitation Reactions Compounds Soluble Ionic Compounds 1. Group 1A cations and NH 4 + 2. Nitrates (NO 3 ) Acetates (CH 3 COO ) Chlorates (ClO 3 ) Perchlorates (ClO 4 ) Solubility
More informationSession 8: LECTURE OUTLINE (SECTIONS I1 I4 pp F61 F67)
Session 8: LECTURE OUTLINE (SECTIONS I1 I4 pp F61 F67) I. Elecrolytes a. Soluble substances b. Insoluble substances c. Electrolytes d. Non-Electrolytes e. Ions and electrical conductivity f. Strong and
More informationChemistry 102 Chapter 17 COMMON ION EFFECT
COMMON ION EFFECT Common ion effect is the shift in equilibrium caused by the addition of an ion that takes part in the equilibrium. For example, consider the effect of adding HCl to a solution of acetic
More informationChem 12 Practice Solubility Test
Chem 12 Practice Solubility Test 1. Which combination of factors will affect the rate of the following reaction? Zn (s) + 2HCl ZnCl 2 + H 2(g) A. Temperature and surface area only B. Temperature and concentration
More informationName of Anion. (aq) NaCl NaNO 3 NaOH Na 2 SO 4 Na2CO3. MgSO4. AgNO 3. Ba(NO 3 ) 2. Pb(NO 3 ) 2. CuSO (1) AgNO 3 ( ) + NaCl( )
Name of Compound Prelab #1 Formula Cation (Metal) Name of Cation silver nitrate Ag Ag + silver magnesium sulfate barium nitrate lead nitrate copper sulfate Cation = (+)positive ion Anion = ()negative ion
More informationSolutions & Solubility: Net Ionic Equations (9.1 in MHR Chemistry 11)
Solutions & Solubility: Net Ionic Equations (9.1 in MHR Chemistry 11) 1 Solubility vs. Temperature 2 Solubility Table Anions SOLUBILITY Table 8.3 page 363 in MHR Cl Br I S OH SO CO 3 PO 3 SO 3 C 2 H 3
More informationPage III-4b-1 / Chapter Four Part II Lecture Notes. Chemistry 221 Professor Michael Russell MAR. Ba(NO3)2(aq)? soluble. BaCl2(aq)?
Page III-4b-1 / Chapter Four Part II Lecture Notes Solution Stoichiometry and Chemical Reactions Chapter 3 & Chapter 4, or Chapter 4 Part II Chemistry 221 Professor Michael Russell Terminology In solution
More informationAP 17.4, 17.5 Study Questions
Name: Class: Date: AP 17.4, 17.5 Study Questions True/False Indicate whether the statement is true or false. 1. The solubility product of a compound is numerically equal to the product of the concentration
More information9/24/09 Chem 111 Experiment #7 Solutions and Reactions Brown, LeMay, and Bursten Chapter
Chem 111 Experiment #7 Solutions and Reactions Brown, LeMay, and Bursten Chapter 4.1-4.4 KEY VOCABULARY: 1. Ionic compound a compound composed of cations (+) and anions (-). Many ionic compounds dissociate
More informationChapter 4 Suggested end-of-chapter problems with solutions
Chapter 4 Suggested end-of-chapter problems with solutions a. 5.6 g NaHCO 1 mol NaHCO 84.01 g NaHCO = 6.69 10 mol NaHCO M = 6.69 10 mol 50.0 m 1000 m = 0.677 M NaHCO b. 0.1846 g K Cr O 7 1 mol K 94.0 g
More informationChapter 8 Chemical Reactions
Chemistry/ PEP Name: Date: Chapter 8 Chemical Reactions Chapter 8: 1 7, 9 18, 20, 21, 24 26, 29 31, 46, 55, 69 Practice Problems 1. Write a skeleton equation for each chemical reaction. Include the appropriate
More information18.3 Solubility Equilibrium 18.3 FOCUS. Guide for Reading INSTRUCT. The Solubility Product. Section Resources
18.3 18.3 Solubility Equilibrium 1 FOCUS Objectives 18.3.1 Describe the relationship between the solubility product constant and the solubility of a compound. 18.3.2 Predict whether precipitation will
More informationEQUIVALENCE POINT. 8.8 millimoles is also the amount of acid left, and the added base gets converted to acetate ion!
184 Another interesting point: The halfway point phenolphthalein color change buffer region EQUIVALENCE POINT What's special about it? It's the point where we have added half the required base to reach
More informationCHAPTER 16 ACID-BASE EQUILIBRIA AND SOLUBILITY EQUILIBRIA
CHAPTER 16 ACID-BASE EQUILIBRIA AND SOLUBILITY EQUILIBRIA 16.3 (a) This is a weak acid problem. Setting up the standard equilibrium table: CH 3 COOH(aq) H + (aq) + CH 3 COO (aq) Initial (M): 0.40 0.00
More information