Ch. 20 Oxidation-Reduction Reactions. AKA Redox Reactions

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1 Ch. 20 Oxidation-Reduction Reactions AKA Redox Reactions

2 20.1 THE MEANING OF OXIDATION AND REDUCTION

3 Early Chemistry Oxidation: a substance gains oxygen Reduction: a substance loses oxygen Nothing can be oxidized without something being reduced (and vice versa) Called oxidation-reduction reactions or redox reactions

4 Modern Chemistry Oxidation: loss of electrons (complete or partial) or gain of oxygen Reduction: gain of electrons (complete or partial) or loss of oxygen

5 Mnemonic Devices LEO goes GER OIL RIG L- loss of O- oxidation E- electrons is I- is O- oxidation L- loss G- gain of R- reduction E- electrons is I- is R- reduction G- gain

6 The substance that loses electrons is the reducing agent Allows the other substance to be reduced while it itself is oxidized Substance that accepts electrons is the oxidizing agent Allows the other substance to be oxidized while it itself is reduced

7 HW Review A) (loses electrons) oxidation B) (loses electrons) oxidation C) (gains electrons) reduction D) (gains electrons) reduction

8 Redox with Covalent Compounds Complete transfer of electrons does not occur In a polar covalent bond electrons are not shared equally, which results in a partial gain or loss of electrons when such a bond is formed

9

10 Corrosion Occurs more rapidly in presence of salts and acids Salts and acids produce conductive solutions that make electron transfer easier and thus accelerate corrosion

11 Resistance to Corrosion Not all metals corrode easily Some resist losing electrons (ex. Gold, platinum) Some are protected from extensive corrosion by an oxide layer coating the surface (ex. Aluminum, chromium)

12 Controlling Corrosion To prevent corrosion, metal surfaces may be coated with oil, paint, plastic, or another metal Another method sacrifices one metal to prevent the oxidation of another Magnesium and zinc are often used to protect iron

13 Lesson Check

14

15 20.2 OXIDATION NUMBERS

16 Assigning Oxidation Numbers Oxidation number: positive or negative number assigned to an atom to indicate its degree of oxidation or reduction Generally, a bonded atom s oxidation number is the charge it would have if the electrons in the bond were assigned to the more electronegative atom In an ionic compound, each ion s oxidation number is the charge of that ion

17 Rules for Assigning Oxidation Numbers 1. For monatomic ions, the oxidation number is equal to the charge. 2. For H, oxidation number is +1, except in metal hydrides where it is For O, the oxidation number is -2, except in peroxides where it is -1 and compounds with more electronegative fluorine where it is For elemental form of an element, oxidation number is 0.

18 Rules for Assigning Oxidation Numbers 5. For neutral compounds, the sum of the oxidation numbers of the atoms must equal For a polyatomic ion, the sum of the oxidation numbers of the atoms must equal the charge of the ion.

19 Practice What is the oxidation number of each kind of atom in the following ions and compounds? SO 2 CO 3-2 Na 2 SO 4 (NH 4 ) 2 S S 2 O 3 Na 2 O 2 P 2 O 5

20 Oxidation-Number Changes in Chemical Reactions Use to determine whether oxidation or reduction is happening Oxidation: oxidation number increases (becomes more positive) Reduction: oxidation number decreases (becomes more negative)

21 Practice Assign oxidation numbers to each element Identify which element is oxidized and which is reduced Identify the oxidizing agent and reducing agent 2HgO O 2 + 2Hg NH 4 NO 2 (s) N 2 (g) + 2H 2 O(g) PbO 2 (aq) + 4HI(aq) I 2 (aq) + PbI 2 (s) + 2H 2 O(l)

22 20.3 DESCRIBING REDOX EQUATIONS

23 Identifying Redox Reactions Chemical reaction can be classified into two categories Redox reactions: electrons are transferred from one reacting species to another Ex. Many single replacement, combination, decomposition, and combustion reactions, many reactions in which color changes Non-redox reactions: no electron transfer occurs Ex. Double-replacement and acid-base reactions

24 Practice Identify which of the following are oxidation-reduction reactions. If a reaction is redox, name the element oxidized and the element reduced. CaCO 3 (s) + 2HCl(aq) CaCl 2 (aq) + H 2 O(l) + CO 2 (g) CuO(s) + H 2 (g) Cu(s) + H 2 O(l) 2KMnO 4 + 3KCN + H 2 O 2MnO 2 + 2KOH + 3K(OCN)

25 Practice: Assign Oxidation Numbers & Identify Which Elements are Oxidized and Reduced 4Na(s) + O 2 (g) 2Na 2 O(s) 2Sr + O 2 2SrO 2Li + H 2 2LiH 2Cs + Br 2 2CsBr

26 Practice: Assign Oxidation Numbers & Identify Which Elements are Oxidized and Reduced 3Mg + N 2 Mg 3 N 2 4Fe + 3O 2 2Fe 2 O 3 Cl 2 + 2NaBr 2NaCl + Br 2 Si + 2F 2 SiF 4 H 2 + Cl 2 2HCl 5Fe 2+ + MnO H + Mn Fe H 2 O

27 Balancing Redox Equations Redox reactions are often too complex to balance by trial and error Two methods for balancing, both based on the fact that the number of electrons gained in reduction must equal the number of electrons lost in oxidation Oxidation-number-change method Half-reaction method

28 Using Oxidation-Number Changes Step 1: assign oxidation numbers to all atoms in the equation Step 2: identify which atoms are oxidized and which reduced Step 3: use a bracketing line to connect the atoms that undergo oxidation and a second bracketing line to connect those that undergo reduction; write the change in oxidation number Step 4: make the total increase in oxidation number equal the total decrease in oxidation number by using appropriate coefficients Step 5: make sure the whole equation is balanced for both atoms and charge

29 Oxidation-Number Change Example

30 Using Half-Reactions Half-reactions show only the oxidation or reduction half of a redox reaction The two half reactions can be balanced separately before putting them back together for a complete balanced redox reaction

31 Using Half-Reactions Step 1: Write the unbalanced equation in ionic form, separating all ionic compounds into ions Step 2: Write separate half-reactions for the oxidation and reduction processes Step 3: Balance the atoms in the half-reactions Step 4: Add enough electrons to one side of each half-reaction to balance the charges (hint, if one reaction has e - on the reactant side, the other reaction will have e - on the product side)

32 Using Half-Reactions Step 5: Multiply each half-reaction by the appropriate numbers to make the numbers of electrons equal in both halves Step 6: Add the balanced half-reactions to show an overall equation Step 7: Add any spectator ions and balance the equation

33 Practice: Balance the following equations based on number of electrons in the half-reactions Zn(s) + Cu +2 (aq) Zn +2 (aq) + Cu(s) Zn +2 (aq) + Cr(s) Zn(s) + Cr +3 (aq) Ni(s) + Fe +3 (aq) Ni +2 (aq) + Fe +2 (aq) Zn(s) + H + (aq) Zn +2 (aq) + H 2 (g)

34 Practice: Balance the Following Equations Sn Cr 2 O 7 + H + Sn 4+ + Cr 3+ +H 2 O - Zn + NO 3 + H 2 O + OH - 2- NH 3 + Zn(OH) 4 - ClO 3 + I - +H + Cl - + I 2 + H 2 O 2- - C 2 O 4 + MnO 4 + H + Mn 2+ + CO 2 + H 2 O Br 2 + SO 2 + H 2 O Br SO 4 + H + Zn + As 2 O 3 + H 2 O Zn 2+ +AsH 3 + OH - 2- NiO 2 + S 2 O 3 + H 2 O + OH - 2- Ni(OH) 2 + SO 3

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