THIS IS A NEW SPECIFICATION

Size: px
Start display at page:

Download "THIS IS A NEW SPECIFICATION"

Transcription

1 TIS IS A NEW SPECIFICATION ADVANCED SUBSIDIARY GCE CEMISTRY A Chains, Energy and Resources F322 * OCE / * Candidates answer on the Question Paper OCR Supplied Materials: Data Sheet for Chemistry A (inserted) Other Materials Required: Scientific calculator Thursday 14 January 2010 Morning Duration: 1 hour 45 minutes * F * INSTRUCTIONS TO CANDIDATES Write your name clearly in capital letters, your Centre Number and Candidate Number in the boxes above. Use black ink. Pencil may be used for graphs and diagrams only. Read each question carefully and make sure that you know what you have to do before starting your answer. Answer all the questions. Do not write in the bar codes. Write your answer to each question in the space provided, however additional paper may be used if necessary. INFORMATION FOR CANDIDATES The number of marks is given in brackets [ ] at the end of each question or part question. Where you see this icon you will be awarded marks for the quality of written communication in your answer. This means for example you should: ensure that text is legible and that spelling, punctuation and grammar are accurate so that meaning is clear; organise information clearly and coherently, using specialist vocabulary when appropriate. You may use a scientific calculator. A copy of the Data Sheet for Chemistry A is provided as an insert with this question paper. You are advised to show all the steps in any calculations. The total number of marks for this paper is 100. This document consists of 20 pages. Any blank pages are indicated. OCR 2010 [/500/7834] DC (SJ/SW) 19234/3 OCR is an exempt Charity Turn over

2 2 Answer all the questions. 1 Kerosene is used as a fuel for aeroplane engines. (a) Kerosene is obtained from crude oil. Name the process used to obtain kerosene from crude oil and explain why the process works [2] (b) Some of the hydrocarbons in kerosene have the formula C (i) What is the name of the straight chain hydrocarbon with the formula C 10 22?... [1] (ii) Draw the skeletal formula of one branched chain isomer with the formula C [1] (iii) Explain why the straight chain isomer of C has a higher boiling point than any of its branched chain structural isomers.... [2] (iv) Explain why the straight chain isomer of C is converted by the petroleum industry into its branched chain isomers.... [1] OCR 2010

3 3 (c) When kerosene burns in an aeroplane engine very little carbon monoxide, CO, is formed but a significant amount of nitrogen monoxide, NO, is formed. (i) Construct the equation to show the complete combustion of C [2] (ii) Suggest, with the aid of an equation, how NO is formed within an aeroplane engine.... [1] (d) NO is a radical and contributes towards ozone depletion in the stratosphere. (i) What is a radical?... [1] (ii) One of the processes leading to the breakdown of ozone in the stratosphere can be represented by the following two equations. NO(g) + O 3 (g) NO 2 (g) + O(g) NO 2 (g) + O 2 (g) NO(g) + O 2 (g) What is the role of the NO in this process?... [1] (iii) Ozone in the stratosphere is broken down to make O 2 and O. Describe and explain how the concentration of ozone in the stratosphere is maintained.... [2] (iv) Why is it important to life on the Earth s surface that the concentration of ozone in the stratosphere is maintained?... [1] [Total: 15] OCR 2010 Turn over

4 2 Dilute aqueous hydrogen peroxide, 2 O 2 (aq), is used to sterilise contact lenses. 4 (a) Dilute 2 O 2 (aq) slowly decomposes at room temperature to produce oxygen and water. The decomposition of 2 O 2 (aq) can be made faster by: increasing the concentration of the 2 O 2 (aq), adding a small amount of manganese(iv) oxide catalyst, heating the solution to 60 C. (i) Construct the equation for the decomposition of 2 O [1] (ii) Explain why increasing the concentration of 2 O 2 (aq) increases the rate of decomposition.... [2] (iii) Explain how the catalyst can increase the rate of decomposition of 2 O 2 (aq).... [2] OCR 2010

5 (iv) 5 Explain why increasing the temperature of 2 O 2 (aq) increases the rate of decomposition. As part of your answer, you should add a second curve and any necessary labels to the Boltzmann distribution of molecular kinetic energies shown below. number of molecules with a given energy energy... [3] OCR 2010 Turn over

6 6 (b) (i) In the past, hydrogen peroxide was manufactured by reacting barium peroxide, BaO 2, with ice-cold dilute sulfuric acid. BaO 2 (s) + 2 SO 4 (aq) BaSO 4 (s) + 2 O 2 (aq) This method required the disposal of poisonous barium compounds. Calculate the atom economy for this manufacture of hydrogen peroxide from BaO 2. Use the table of relative formula masses given below. compound relative formula mass BaO SO BaSO O atom economy =... % [2] OCR 2010

7 (ii) 7 Nowadays, hydrogen peroxide is manufactured using hydrogen gas, oxygen from the air and a substance called anthraquinone. stage anthraquinone anthraquinol stage 2 O 2 + anthraquinol 2 O 2 + anthraquinone Compare the manufacture of 2 O 2 from hydrogen and oxygen with the manufacture from barium peroxide described in b(i). Explain the advantages of the manufacture of 2 O 2 from hydrogen and oxygen.... [3] (c) Some reactions of 2 O 2 are exothermic. Use ideas about the enthalpy changes that take place during bond breaking and bond making to explain why some reactions are exothermic [2] [Total: 15] OCR 2010 Turn over

8 3 Glucose, C 6 12 O 6, can be completely combusted to give carbon dioxide and water. 8 C 6 12 O 6 (s) + 6O 2 (g) 6CO 2 (g) O(l) (a) In the body, the conversion of glucose into carbon dioxide and water takes place in a number of stages catalysed by enzymes. What name is given to this oxidation process in the body?... [1] (b) A student carries out an experiment to determine the enthalpy change of combustion of glucose. In the experiment, g of glucose is burned. The energy released is used to heat 100 cm 3 of water from 23.7 C to 41.0 C. (i) Calculate the energy released, in kj, during combustion of g glucose. The specific heat capacity of water = 4.18 J g 1 K 1. Density of water = 1.00 g cm 3. energy =... kj [2] (ii) Calculate the amount, in moles, of glucose that is burned. amount =... mol [2] (iii) Calculate the enthalpy change of combustion of glucose. Give your answer to three significant figures. Δ c =... kj mol 1 [2] OCR 2010

9 9 (c) The standard enthalpy change of combustion of glucose can also be determined indirectly. Calculate the standard enthalpy change of combustion of glucose using the standard enthalpy changes of formation below. substance O Δ f / kj mol 1 C 6 12 O 6 (s) 1250 CO 2 (g) O(l) 286 C 6 12 O 6 (s) + 6O 2 (g) 6CO 2 (g) O(l) 1 answer =... kj mol 1 [3] (d) Suggest two reasons why standard enthalpy changes of combustion determined experimentally are less exothermic than the calculated theoretical values [2] [Total: 12] OCR 2010 Turn over

10 4 A reaction mechanism shows the individual steps that take place during a reaction. 10 (a) Methane reacts with bromine in the presence of ultraviolet radiation to form several products. Two of these products are bromomethane and hydrogen bromide. (i) Write an equation for the reaction between methane and bromine to make bromomethane and hydrogen bromide.... [1] (ii) Name one other bromine-containing organic product which is formed when methane reacts with bromine.... [1] (iii) The mechanism for this reaction is called radical substitution. Describe the mechanism for the radical substitution of methane by bromine to make bromomethane. Use the mechanism to suggest why a small amount of ethane is also formed. In your answer, you should organise your answer and use the correct technical terms.... [7] OCR 2010

11 11 (b) The curly arrows model is used in reaction mechanisms to show the movement of electron pairs during chemical reactions. Choose a reaction mechanism that you have studied involving the curly arrow model. Name and describe your chosen reaction mechanism. In your answer, include: an example of the reaction with the chosen mechanism, the type of bond fission that occurs, relevant dipoles [6] [Total: 15] OCR 2010 Turn over

12 12 5 Alkenes are a very useful series of hydrocarbons used widely in synthesis. Alkenes are more reactive than alkanes. (a) What is the name of the process used to convert long chain alkanes into more useful shorter chain alkenes?... [1] (b) Ethene and steam can be converted into ethanol. The equilibrium is shown below. C 2 4 (g) + 2 O(g) C 2 5 O(g) Δ = 46 kj mol 1 le Chatelier s principle can be used to predict the effect of changing conditions on the position of equilibrium. (i) Name the catalyst used in this reaction.... [1] (ii) State le Chatelier s principle.... [1] (iii) Using le Chatelier s principle, predict and explain the conditions that would give the maximum equilibrium yield of ethanol from ethene and steam.... [3] (iv) The actual conditions used are 60 atmospheres pressure at 300 C in the presence of a catalyst. Compare these conditions with your answer to (iii) and comment on why these conditions are used.... [3] OCR 2010

13 13 (c) Alkenes are used to make addition polymers. The repeat unit for an addition polymer is shown below. C C 3 C n What is the name of the monomer used to make this polymer?... [1] (d) Poly(chloroethene) has the repeat unit below. Cl C C n This repeat unit can be written as C 2 CCl. One way to dispose of poly(chloroethene) is to react it with oxygen at high temperature. This is called incineration. (i) Complete the following equation that shows the reaction taking place during incineration. C 2 CCl + O 2 CO O + Cl [1] (ii) Research chemists have reduced the environmental impact of incineration by removing the Cl formed from the waste gases. Suggest a type of reactant that could be used to remove the Cl.... [1] (e) The disposal of polymers causes environmental damage. Research chemists are developing polymers that will reduce this environmental damage and increase sustainability. Describe two ways in which chemists can reduce this environmental damage [2] OCR 2010 [Total: 14] Turn over

14 6 This question is about the six alcohols below. 14 butan-2-ol 2-methylpentan-3-ol propan-1-ol ethane-1,2-diol 2-methylpropan-2-ol propan-2-ol (a) Which alcohol is an example of a tertiary alcohol?... [1] (b) Draw the skeletal formula for 2-methylpentan-3-ol. [1] (c) Butan-2-ol and 2-methylpropan-2-ol are structural isomers. (i) What is meant by the term structural isomer?... [1] (ii) Draw another structural isomer of these two alcohols. [1] (d) Ethane-1,2-diol can be dissolved in water to act as an anti-freeze in car radiators. Explain why ethane-1,2-diol is very soluble in water [2] OCR 2010

15 15 (e) Ethane-1,2-diol is heated under reflux with ethanoic acid and a small amount of 2 SO 4 catalyst. Compound A is formed with molecular formula C 6 10 O 4. Draw the structure of compound A. [2] (f) Butan-2-ol is heated with 2 SO 4 catalyst. A mixture of three alkenes forms, B, C and D. The alkenes B and C are stereoisomers. (i) Draw the structures of the two stereoisomers B and C. [2] (ii) What type of stereoisomerism is shown by B and C?... [1] (iii) Draw the structure of the other alkene, D, that is formed in this reaction. [1] OCR 2010 Turn over

16 (g) Alcohol E is one of the following alcohols. 16 butan-2-ol 2-methylpentan-3-ol propan-1-ol ethane-1,2-diol 2-methylpropan-2-ol propan-2-ol A student oxidises alcohol E by heating under reflux with excess acidified potassium dichromate(vi). An organic product F is isolated. The mass spectrum of the alcohol E is shown below relative intensity m / z The infrared spectrum of the organic product F is shown below. 100 transmittance (%) wavenumber / cm OCR 2010

17 Name or draw the structures of the alcohol E and the organic product F. 17 Write an equation for the reaction of alcohol E with acidified potassium dichromate(vi). Use [O] to represent the oxidising agent, acidified potassium dichromate(vi). In your answer, you should make clear how each structure fits with the information given above [7] [Total: 19] OCR 2010 Turn over

18 18 7 There is much international concern that an increase in atmospheric concentrations of carbon dioxide and methane may lead to global warming and climate change. (a) Carbon dioxide and methane are both greenhouse gases. (i) What type of radiation is absorbed by methane molecules and what effect does this radiation have on these molecules?... [2] (ii) Some scientists are more concerned about carbon dioxide as a greenhouse gas than methane. Suggest why.... [1] (b) Describe ways that research chemists are trying to minimise climate change resulting from global warming caused by the release of greenhouse gases [5] OCR 2010

19 19 (c) Research scientists working in the Antarctic have measured the concentration of carbon dioxide in the ice. This study has allowed the scientists to estimate the atmospheric concentration of carbon dioxide over many thousands of years. The graphs below show these atmospheric concentrations and the corresponding average surface temperature CO 2 / ppm change in temperature / C age (thousands of years before present) present day temperature age (thousands of years before present) Do the graphs provide reliable evidence that an increase in atmospheric carbon dioxide concentration will result in global warming? Explain your answer [2] OCR 2010 END OF QUESTION PAPER [Total: 10]

20 20 PLEASE DO NOT WRITE ON TIS PAGE Copyright Information OCR is committed to seeking permission to reproduce all third-party content that it uses in its assessment materials. OCR has attempted to identify and contact all copyright holders whose work is used in this paper. To avoid the issue of disclosure of answer-related information to candidates, all copyright acknowledgements are reproduced in the OCR Copyright Acknowledgements Booklet. This is produced for each series of examinations, is given to all schools that receive assessment material and is freely available to download from our public website ( after the live examination series. If OCR has unwittingly failed to correctly acknowledge or clear any third-party content in this assessment material, OCR will be happy to correct its mistake at the earliest possible opportunity. For queries or further information please contact the Copyright Team, First Floor, 9 ills Road, Cambridge CB2 1GE. OCR is part of the Cambridge Assessment Group; Cambridge Assessment is the brand name of University of Cambridge Local Examinations Syndicate (UCLES), which is itself a department of the University of Cambridge. OCR 2010

21 F322 Mark Scheme January 2010 F322 Chains, Energy and Resources Question Expected Answers Marks Additional Guidance 1 (a) 2 Fractional distillation DO NOT ALLOW just distillation Because fractions have different boiling points For fractions, ALLOW components OR hydrocarbons OR compounds ALLOW condense at different temperatures ALLOW because van der Waals forces differ between molecules IGNORE reference to melting points IGNORE crude oil OR mixture has different boiling points but ALLOW separates crude oil by boiling points (b) (i) Decane 1 DO NOT ALLOW deceane (ii) Skeletal formula of branched C Formula must be skeletal AND must not include any symbol, e.g. C 3 Any possible skeletal formulae e.g. 13

22 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance (iii) (iv) Decane has more surface contact OR branched chains have less surface contact Decane has more van der Waals forces OR branched chains have fewer van der Waals forces Branched chains have more efficient combustion OR decane has less efficient combustion 2 Both answers need to be comparisons Assume it refers to decane IGNORE surface area ALLOW straight chains can get closer together OR branched chains cannot get as close to one another IGNORE branched chain are more compact ALLOW Decane has stronger van der Waals forces OR branched chains have weaker van der Waals forces More intermolecular forces is not sufficient 1 ALLOW branched chains are easier to burn OR easier to combust OR burn better OR more efficient fuel OR less likely to produce pre-ignition or knocking OR increases octane rating ALLOW ORA for decane 14

23 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance Better fuel is NOT sufficient Burns more cleanly is NOT sufficient (c) (i) C ½O 2 10CO O 2 ALLOW any correct multiple IGNORE state symbols All four species correct balancing of four correct species (ii) N 2 + O 2 2NO 1 ALLOW any correct multiple including fractions IGNORE state symbols The mark is for the equation IGNORE writing 15

24 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance (d) (i) Species with an unpaired electron 1 ALLOW atom, molecule or particle with an unpaired electron ALLOW has an unpaired electron ALLOW particle formed by homolytic fission (ii) catalyst 1 DO NOT ALLOW particle with a single electron OR particle with a free electron (iii) O + O 2 O 3 OR O reacts with O 2 to make ozone OR the reaction is reversible Rate of formation of ozone is the same as rate of decomposition 2 ALLOW O 2 + O O 3 OR O 3 O 2 + O ALLOW is in equilibrium OR in correct equation OR has steady state condition IGNORE other equations involving ozone (iv) absorbs (harmful) UV 1 ALLOW keeps out UV OR filters UV ALLOW increased UV could cause skin cancer OR increased UV could cause cataracts OR increased UV could cause mutation of crops Total 15 IGNORE gamma 16

25 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance 2 (a) (i) 2 2 O O + O 2 1 ALLOW any correct multiple including fractions IGNORE state symbols (ii) (iii) More crowded particles OR more particles per (unit) volume more collisions per second OR more frequent collisions Any two from the following: Reaction takes alternative route Activation energy is lowered More molecules have energy above activation energy OR more molecules have enough energy to react 2 ALLOW particles are closer together DO NOT ALLOW area instead of volume IGNORE more concentrated particles 2 ALLOW collisions more often OR increased rate of collision OR collisions are more likely OR there is a greater chance of collisions More collisions is not sufficient ALLOW catalyst changes reaction mechanism ALLOW an alternative approach using adsorption particles adsorbed onto surface so bonds weakened as a result of the adsorption 17

26 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance (iv) Correct curve for higher temperature 3 maximum of curve to right AND lower than maximum of original curve AND above dotted line at higher energy as shown in diagram below Activation energy does not change OR clearly labelled on diagram, e.g. E a OR E IGNORE minor point of inflexion of curve Note that the diagram above would score all 3 marks More molecules have energy above activation energy OR more molecules have enough energy to react (b) (i) % More successful collisions is not sufficient 2 First mark for OR ( ) OR ( ) at bottom of fraction with or without 100 ALLOW from 2 sig figs up to calculator value ALLOW full marks for 13 OR 12.7 OR OR up to calculator value with no working out scores one mark only NO ECF for this part from incorrect numbers in first expression 18

27 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance (ii) Any three from the following: 3 Oxygen comes from air No poisonous materials formed OR no poisonous materials involved No waste products formed OR atom economy is 100% IGNORE hydrogen comes from the air IGNORE harmful ALLOW higher atom economy Anthraquinone is regenerated OR recycled OR used again OR Anthraquinone acts as a catalyst (c) Bond breaking absorbs energy AND bond making releases energy More energy released than absorbed 2 ALLOW bond breaking is endothermic AND bond making is exothermic ALLOW exothermic change transfers more energy than endothermic change OR bond making transfers more energy than bond breaking OR (the sum of the) bond enthalpies in the products is greater than the (sum of the) bond enthalpies in the reactants OR (the sum of the) bond enthalpies of the bonds made is greater than (the sum of) the bond enthalpies of the bonds broken IGNORE reference to strong and weak bonds IGNORE enthalpy of products is less than enthalpy of reactants Total 15 19

28 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance 3 (a) Respiration 1 IGNORE anaerobic (b) (i) (kj) 2 ALLOW 7231 J ALLOW 7.23 with no working out ALLOW from 7.2 up to calculator value of ALLOW from up to calculator value for 1 mark (i.e. ECF from use of m = in first stage) IGNORE sign (ii) M r = (iii) amount = (mol) c = 1560 (kj) OR 1570 (kj) but answer must be to 3 sig fig minus sign ALLOW OR OR up to calculator value DO NOT ALLOW ALLOW ECF from wrong M r 2 ALLOW ECF from answer to (i) answer to (ii) but answer must be to 3 sig fig minus mark is an independent mark 20

29 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance (c) ALLOW full marks for 2830 with no working out +( 394 6) + ( 286 6) OR ALLOW for 2 marks: cycle wrong way around OR 1400 OR 860 one value not 6 OR 5330 OR wrong sign for 1250 or 4080 OR +570 correct cycle but not 6 ALLOW for 1 mark: 1400 OR 860 cycle wrong way around and one value not 6 OR 570 cycle wrong way around and not 6 OR 1930 OR wrong sign and not 6 Note: There may be other possibilities. (d) Any two from the following: 2 eat released to the surroundings Incomplete combustion OR incomplete reaction OR not everything burns ALLOW heat loss IGNORE reference to evaporation Non-standard conditions Total 12 21

30 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance 4 (a) (i) C 4 + Br 2 C 3 Br + Br 1 ALLOW any correct multiple IGNORE state symbols (ii) Dibromomethane OR tribromomethane OR tetrabromomethane 1 ALLOW 1,1-dibromomethane OR 1,1,1-tribromomethane etc ALLOW 1-dibromomethane DO NOT ALLOW 2,2-dibromomethane etc (iii) Br 2 2Br OR homolytic fission of bromine Br + C 4 Br + C 3 C 3 + Br 2 C 3 Br + Br Br + C 3 C 3 Br OR Br + Br Br 2 Ethane made when two methyl radicals react OR C 3 + C 3 C 2 6 Quality of Written Communication Consists of initiation step linked to correct equation propagation step linked to one equation in which there is a radical on the left and a radical on the right termination step linked to correct equation: 2 names of steps linked to correct equations BUT 3 names of steps linked to correct equations ALLOW correct formulae e.g. C 2 Br 2 7 All equations can be described in words Radicals do NOT need a single dot IGNORE any state symbols ALLOW any other suitable termination If no equations are given to link the names of the step then award one mark for mention of all three steps 22

31 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance (b) EITER Nucleophilic substitution Example of nucleophilic substitution eterolytic fission C I curly arrow Correct dipole on C I bond O curly arrow from one lone pair on O of O ion OR from minus sign on O ion 6 The example mark can be awarded as an example of the name of the mechanism given or if the name is wrong can be given as an example of a reasonably correct drawn mechanism If curly half arrows drawn do not give a mark the first time used and then apply ECF 3 C C I 3 C C O + I O OR Electrophilic addition Example of electrophilic addition eterolytic fission Curly arrow from C=C bond to Br Br bond and Dipole and curly arrow associated with Br 2 Correct carbocation ion Curly arrow from one lone pair on Br ion OR from minus sign on Br ion ALLOW Electrophilic substitution Example of electrophilic substitution eterolytic fission Curly arrow from benzene ring to the electrophile (i.e. NO 2 + OR Br + ) Correct intermediate Curly arrow to show loss of hydrogen ion ALLOW mechanisms for other halogenoalkaes C 3 C C Br Br C 3 C Br Br C C 3 C 3 ALLOW mechanisms for other halogens and hydrogen halides ALLOW Nucleophilic addition Example of nucleophilic addition eterolytic fission Correct dipole on carbonyl group Curly arrow from lone pair on ion OR from minus sign on to C=O carbon and breaking of C=O bond Curly arrow from carbonyl oxygen to either + or 2 O Total 15 23

32 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance 5 (a) Cracking 1 ALLOW catalytic or thermal cracking (b) (i) Acid 1 ALLOW correct formula if no name given: e.g. 3 PO 4 OR 2 SO 4 OR + ALLOW correct name of acid even if an incorrect formula is used (ii) (iii) (iv) The position of equilibrium will shift so as to minimise the effect of any change in conditions Low temperature AND high pressure Low temperature because the (forward) reaction is exothermic igh pressure because there are fewer moles (of gas) on the right hand side (60 atmosphere pressure is a) high pressure may be too expensive OR may cause safety problems (300 ºC is sufficiently high) to give a fast rate of reaction without shifting equilibrium to the left OR compromising equilibrium yield IGNORE heterogeneous OR homogeneous 1 DO NOT ALLOW reaction shifts The idea of a shift in equilibrium is essential 3 One mark for conditions. This mark is independent of the reasons for conditions 3 One mark for reason for the chosen temperature One mark for reason for the chosen pressure ALLOW fewer moles of products (c) Propene 1 ALLOW prop-1-ene DO NOT ALLOW prop-2-ene (d) (i) C 2 CCl + 2½O 2 2CO O + Cl 1 (ii) Alkali OR base OR carbonate 1 ALLOW correct formula of or named carbonate OR alkali OR base Correct name and wrong formula does not score 24

33 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance (e) Any two marks from the following: 2 Develop photodegradable polymers Develop biodegradable polymers OR develop compostable polymers Develop techniques for cracking polymers OR develop use as a chemical feedstock Develop ways of making polymers from plant-based substances OR reduce the need to use finite raw materials such as crude oil Designing processes with high atom economy OR reduce waste products during manufacture Develop ways of sorting AND recycling polymers Total 14 25

34 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance 6 (a) (i) 2-Methylpropan-2-ol 1 ALLOW methylpropan-2-ol (b) 1 Formula must be skeletal AND not include any symbol except for O O (c) (i) Same molecular formula but different structural formulae 1 ALLOW Same molecular formula but different arrangement of atoms OR Same molecular formula but different structures OR Same molecular formula but different displayed formulae DO NOT ALLOW Same molecular formula but different spatial arrangement of atoms (ii) C 3 C 2 C 2 C 2 O OR (C 3 ) 2 CC 2 O 1 ALLOW displayed formula ALLOW ALLOW sticks (i.e. no shown bonded to C) O OR O ALLOW DO NOT ALLOW O shown as below C C C C O C C C C O sticks OK and O is OK sticks OK but O is not OK ALLOW correct ethers 26

35 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance (d) as O (bonds) OR has hydroxyl (groups) OR has hydroxy (groups) 2 ALLOW marks from a diagram of hydrogen bonding IGNORE reference to alcohol functional group Forms hydrogen bonds with water (molecules) (e) C 3 COOC 2 C 2 OOCC 3 1 mark for each ester end of molecule DO NOT ALLOW forms hydrogen bonds 2 ALLOW displayed formula OR skeletal formula ALLOW sticks C 3 COOC 2 C 2 O shows one of the two ester groups and scores one mark (f) (i) C 3 C 3 C 3 2 DO NOT ALLOW C C C C 3 C C 3 3 C O C 3 C C C C i.e. no ECF O C 3 (ii) E/Z 1 ALLOW cis-trans IGNORE geometric (iii) C 3 C 2 C=C 2 OR but-1-ene 1 If but-1-ene given in part (i), ALLOW but-2-ene OR C 3 C=CC 3 i.e. ECF from f(i) DO NOT ALLOW methylpropene: 3 C C C 3 C 27

36 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance From the evidence, candidates may have identified compound F as propanone, propanal or propanoic acid The mark scheme for F = propanone and propanal is shown in the Expected Answers column. The mark scheme for F = propanoic acid is shown in the Additional Guidance column. If F is propanone or propanoic acid, then maximum score = 7; but if F is propanal then maximum score = 6 (g) Mark scheme for F = propanone and propanal 7 Mark scheme for F = propanoic acid mass spec of E Remember to check the spectrum Quality of Written Communication mass spec gives M + or molecular ion of 60 OR mass spec gives parent ion of 60 OR highest m/z (ALLOW m/e) value is 60 mass spec of E Remember to check the spectrum QWC mass spec gives M + or molecular ion of 60 OR mass spec gives parent ion of 60 OR highest m/z (OR m/e) value is 60 m/z = 45 indicates loss of C 3 OR m/z = 45 indicates presence of C 3 CO OR C 2 C 2 O OR C 2 5 O IR of F Remember to check the spectrum IR shows no broad absorption between 2500 to 3300 cm 1 so no O bond OR no broad absorption between 2500 to 3300 cm 1 so not a carboxylic acid IR shows absorption at 1700 cm 1 due to a C=O bond OR absorption at 1700 cm 1 indicates a ketone OR aldehyde present Identification and equation F is C 3 COC 3 OR propanone E is C 3 COC 3 OR propan-2-ol C 3 COC 3 + [O] C 3 COC O If F has been incorrectly identified as propanal, mark identification and equation as ECF, so max = 2 ALLOW E is C 3 C 2 C 2 O m/z = 45 indicates loss of C 3 OR m/z = 45 indicates presence of C 3 CO OR C 2 C 2 O OR C 2 5 O IR of F Remember to check the spectrum IR shows (broad) absorption somewhere between 3500 and 2500 cm 1 suggests carboxylic acid OR O bond IR shows absorption at 1700 cm 1 due to C=O OR absorption at 1700 cm 1 indicates a carboxylic acid Identification and equation F is C 3 C 2 COO OR propanoic acid E is C 3 C 2 C 2 O OR propan-1-ol C 3 C 2 C 2 O + 2[O] C 3 C 2 COO + 2 O ALLOW: C 3 C 2 C 2 O + [O] C 3 C 2 CO + 2 O Total 19 28

37 F322 Mark Scheme January 2010 Extra guidance for marking of Q6(g) If E has not been identified OR if F has been identified as a ketone or aldehyde, use the left-hand mark scheme If F has been identified as a carboxylic acid, use the right-hand mark scheme Mass spec These two marking points stand as independent marks whichever compounds have been identified. The positive sign for fragment ions is not required. IGNORE negative charge. The mass spec may well be on the actual spectrum. IR mark These stand as independent marks whichever compounds have been identified. The IR analysis may well be on the actual spectrum. Identification marks If both structure and name are given they must both be correct but allow propanol drawn with the correct structure because the position number of the O has been clearly identified ALLOW ECF for identification of F e.g. if E is pentan-2-ol then an answer of pentan-2-one for F will be given a mark as ECF ALLOW identification marks for E and F from equation Equation mark ALLOW ECF for any correct equation showing the oxidation of any alcohol to the appropriate product. ALLOW molecular formulae in equations, i.e. C 3 7 O + [O] C 2 5 CO + 2 O ; C 3 8 O + [O] C 3 6 O + 2 O ; C 3 7 O + [O] C 2 5 CO + 2 O 29

38 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance 7 (a) (i) 2 Infrared (radiation absorbed) ALLOW bond stretching OR bond bending (ii) by (C ) bond vibration Greater concentration of carbon dioxide OR more carbon dioxide is being made DO NOT ALLOW molecules vibrating 1 ALLOW carbon dioxide is the main contributor to global warming DO NOT ALLOW any response that states that CO 2 causes ozone depletion ALLOW C=O bonds absorb IR more readily than C bonds ALLOW carbon dioxide has a greater greenhouse effect 30

39 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance 7 (b) Any five from the following: Developing carbon capture AND storage 5 carbon, capture AND storage required ALLOW CCS One example of CCS Second example of CCS Examples of CCS deep in the oceans OR on the sea-bed DO NOT ALLOW dissolve CO 2 in the sea OR stored in ocean storage in geological formations OR piped into disused or partially filled oil wells or porous rocks OR under the sea-bed Provide evidence to governments OR international conferences (e.g. Kyoto) OR reports to United Nations etc Educating society OR writing in journals OR producing documentaries OR writing books OR making posters by reaction with metal oxides OR reaction to form (solid) carbonates OR stored as a carbonate OR equation to show formation of metal carbonate IGNORE mineral storage Monitoring atmospheric changes Develop alternative energy sources One example of an alternative energy source e.g. develop fuel cells OR developing solar power OR fuels that do not produce CO 2 (Develop) more efficient engines for transport OR lean burn engines OR hybrid engines OR electric cars Find uses for carbon dioxide OR named use: e.g. dry cleaning OR making decaffeinated coffee OR blowing agent OR fizzy drinks, etc ALLOW idea of biofuels only if linked to carbon-neutrality IGNORE reforestation IGNORE reference to CFCs DO NOT ALLOW use less carbon dioxide 31

40 F322 Mark Scheme January 2010 Question Expected Answers Marks Additional Guidance (c) Any two from the following: 2 There are times when CO 2 has a high concentration and the temperature is also high OR There are times when CO 2 has a low concentration and the temperature is low It is impossible to measure with certainty the average temperature years ago ALLOW a (positive) correlation between temperature and carbon dioxide concentration but DO NOT ALLOW just a correlation IGNORE graphs are the same shape IGNORE graphs are similar There are other gases that may cause a greenhouse effect OR There are other factors that may cause a greenhouse effect There are very few anomalous results Total 10 32

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 9 THIS IS A NEW SPECIFICATION

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 9 THIS IS A NEW SPECIFICATION THIS IS A NEW SPECIFICATION ADVANCED SUBSIDIARY GCE CHEMISTRY A Chains, Energy and Resources F322 * OCE / 1 9 2 3 4* Candidates answer on the Question Paper OCR Supplied Materials: Data Sheet for Chemistry

More information

THIS IS A NEW SPECIFICATION

THIS IS A NEW SPECIFICATION THIS IS A NEW SPECIFICATION ADVANCED SUBSIDIARY GCE CHEMISTRY A Chains, Energy and Resources F322 * OCE / 1 9 2 3 4* Candidates answer on the Question Paper OCR Supplied Materials: Data Sheet for Chemistry

More information

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CHEMISTRY A. Chains, Energy and Resources

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CHEMISTRY A. Chains, Energy and Resources Candidate Forename Centre Number Candidate Surname Candidate Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CHEMISTRY A Chains, Energy and Resources THURSDAY 14 JANUARY 2010:

More information

Wednesday 16 January 2013 Morning

Wednesday 16 January 2013 Morning Wednesday 16 January 2013 Morning AS GCE CEMISTRY A F322/01 Chains, Energy and Resources *F314440113* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry A (inserted)

More information

Wednesday 16 January 2013 Morning

Wednesday 16 January 2013 Morning Wednesday 16 January 2013 Morning AS GCE CEMISTRY A F322/01 Chains, Energy and Resources *F314440113* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry A (inserted)

More information

Tuesday 2 June 2015 Afternoon

Tuesday 2 June 2015 Afternoon Oxford Cambridge and RSA Tuesday 2 June 2015 Afternoon AS GCE CHEMISTRY A 322/01 Chains, Energy and Resources *4989278233* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for

More information

surname number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CHEMISTRY A Chains, Energy and Resources

surname number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CHEMISTRY A Chains, Energy and Resources Candidate forename Centre number Candidate surname Candidate number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CEMISTRY A Chains, Energy and Resources FRIDAY 27 MAY 2011: Afternoon

More information

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 12

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 12 herry ill Tuition A Level hemistry OR (A) Paper 12 ADVANED SUBSIDIARY GE EMISTRY A hains, Energy and Resources F322 *F318530611* andidates answer on the question paper. OR Supplied Materials: Data Sheet

More information

THIS IS A NEW SPECIFICATION

THIS IS A NEW SPECIFICATION TIS IS A NEW SPECIFICATION ADVANCED SUBSIDIARY GCE CEMISTRY A Chains, Energy and Resources F322 * OCE / 22979* Candidates answer on the Question Paper OCR Supplied Materials: Data Sheet for Chemistry A

More information

2. (i) Infrared (radiation absorbed) by (C H) bond vibration ALLOW bond stretching OR bond bending DO NOT ALLOW molecules vibrating 2

2. (i) Infrared (radiation absorbed) by (C H) bond vibration ALLOW bond stretching OR bond bending DO NOT ALLOW molecules vibrating 2 . (i) Species with an unpaired electron ALLOW atom, molecule or particle with an unpaired electron ALLOW has an unpaired electron ALLOW particle formed by homolytic fission DO NOT ALLOW particle with a

More information

Friday 10 June 2016 Afternoon

Friday 10 June 2016 Afternoon Oxford Cambridge and RSA Friday 10 June 2016 Afternoon AS GCE CHEMISTRY A F322/01 Chains, Energy and Resources *5878514104* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for

More information

Wednesday 23 May 2012 Afternoon

Wednesday 23 May 2012 Afternoon herry ill Tuition A Level hemistry OR (A) Paper 14 Wednesday 23 May 2012 Afternoon AS GE EMISTRY A F322 hains, Energy and Resources *F314620612* andidates answer on the Question Paper. OR supplied materials:

More information

Thursday 19 January 2012 Afternoon

Thursday 19 January 2012 Afternoon Thursday 19 January 2012 Afternoon AS GE EMISTRY A F322 hains, Energy and Resources *F314440112* andidates answer on the Question Paper. OR supplied materials: Data Sheet for hemistry A (inserted) Other

More information

Tuesday 4 June 2013 Afternoon

Tuesday 4 June 2013 Afternoon Tuesday 4 June 2013 Afternoon AS GCE CHEMISTRY A F322/01 Chains, Energy and Resources *F314620613* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry A (inserted)

More information

THIS IS A NEW SPECIFICATION

THIS IS A NEW SPECIFICATION THIS IS A NEW SPECIFICATION ADVANCED SUBSIDIARY GCE CHEMISTRY A Chains, Energy and Resources F322 *OCE/T73768* Candidates answer on the question paper OCR Supplied Materials: Data Sheet for Chemistry A

More information

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F332/TEST CHEMISTRY B (SALTERS) Chemistry of Natural Resources

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F332/TEST CHEMISTRY B (SALTERS) Chemistry of Natural Resources Candidate Forename Centre Number Candidate Surname Candidate Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F332/TEST CEMISTRY B (SALTERS) Chemistry of Natural Resources TURSDAY 14

More information

THIS IS A NEW SPECIFICATION

THIS IS A NEW SPECIFICATION THIS IS A NEW SPECIFICATION ADVANCED SUBSIDIARY GCE CHEMISTRY B (SALTERS) Chemistry for Life F331 * OCE / 1 091 6 * Candidates answer on the Question Paper A calculator may be used for this paper OCR Supplied

More information

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 11

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 11 ADVANCED SUBSIDIARY GCE CEMISTRY A Chains, Energy and Resources F322 *OCE/23212* Candidates answer on the question paper. OCR Supplied Materials: Data Sheet for Chemistry A (inserted) Other Materials Required:

More information

Thursday 10 January 2013 Morning

Thursday 10 January 2013 Morning Thursday 10 January 2013 Morning AS GCE CHEMISTRY B (SALTERS) F331/01 Chemistry for Life *F314500113* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry B (Salters)

More information

Friday 10 June 2016 Afternoon Time allowed: 1 hour 30 minutes

Friday 10 June 2016 Afternoon Time allowed: 1 hour 30 minutes Oxford Cambridge and RSA AS Level Chemistry A 032/02 Depth in chemistry Friday 10 June 2016 Afternoon Time allowed: 1 hour 30 minutes *6012828836* You must have: the Data Sheet for Chemistry A (sent with

More information

Thursday 23 May 2013 Morning

Thursday 23 May 2013 Morning Thursday 23 May 2013 Morning AS GCE CHEMISTRY B (SALTERS) F331/01 Chemistry for Life *F314860613* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry B (Salters) (inserted)

More information

F331. CHEMISTRY B (SALTERS) Chemistry for Life ADVANCED SUBSIDIARY GCE. Thursday 13 January 2011 Morning. Duration: 1 hour 15 minutes

F331. CHEMISTRY B (SALTERS) Chemistry for Life ADVANCED SUBSIDIARY GCE. Thursday 13 January 2011 Morning. Duration: 1 hour 15 minutes ADVANCED SUBSIDIARY GCE CHEMISTRY B (SALTERS) Chemistry for Life F331 *OCE/25640* Candidates answer on the question paper. OCR supplied materials: Data Sheet for Chemistry B (Salters) (inserted) Other

More information

Wednesday 16 January 2013 Morning

Wednesday 16 January 2013 Morning Wednesday 16 January 2013 Morning AS GCE CHEMISTRY B (SALTERS) F332/01/TEST Chemistry of Natural Resources *F314520113* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry

More information

Candidate number. Centre number

Candidate number. Centre number Oxford Cambridge and RSA AS Level Chemistry A H032/02 Depth in Chemistry Friday 9 June 2017 Afternoon Time allowed: 1 hour 30 minutes *6891085936* You must have: the Data Sheet for Chemistry A (sent with

More information

Tuesday 19 June 2012 Afternoon

Tuesday 19 June 2012 Afternoon Tuesday 19 June 2012 Afternoon A2 GCE CEMISTRY A F324 Rings, Polymers and Analysis *F314730612* Candidates answer on the Question Paper. CR supplied materials: Data Sheet for Chemistry A (inserted) ther

More information

GCE. Chemistry A. Mark Scheme for June Advanced Subsidiary GCE Unit F322: Chains, Energy and Resources

GCE. Chemistry A. Mark Scheme for June Advanced Subsidiary GCE Unit F322: Chains, Energy and Resources Cherry ill Tuition A Level Chemistry OCR (A) Paper 12. Mark Scheme ` GCE Chemistry A Advanced Subsidiary GCE Unit F322: Chains, Energy and Resources Mark Scheme for June 2011 Oxford Cambridge and RSA Examinations

More information

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 10 THIS IS A NEW SPECIFICATION

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 10 THIS IS A NEW SPECIFICATION herry ill Tuition A Level hemistry OR (A) Paper 10 TIS IS A NEW SPEIFIATION ADVANED SUBSIDIARY GE EMISTRY A hains, Energy and Resources F322 * OE / 22979* andidates answer on the Question Paper OR Supplied

More information

Thursday 19 January 2012 Afternoon

Thursday 19 January 2012 Afternoon Thursday 19 January 2012 Afternoon AS GCE CHEMISTRY B (SALTERS) F332/TEST Chemistry of Natural Resources *F314520112* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry

More information

F331. CHEMISTRY B (SALTERS) Chemistry for Life ADVANCED SUBSIDIARY GCE. Monday 23 May 2011 Afternoon. Duration: 1 hour 15 minutes

F331. CHEMISTRY B (SALTERS) Chemistry for Life ADVANCED SUBSIDIARY GCE. Monday 23 May 2011 Afternoon. Duration: 1 hour 15 minutes ADVANCED SUBSIDIARY GCE CHEMISTRY B (SALTERS) Chemistry for Life F331 *F318770611* Candidates answer on the question paper. OCR supplied materials: Data Sheet for Chemistry B (Salters) (inserted) Other

More information

Wednesday 19 June 2013 Morning

Wednesday 19 June 2013 Morning Wednesday 19 June 2013 Morning A2 GCE CHEMISTRY B (SALTERS) F334/01 Chemistry of Materials *F315280113* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry B (Salters)

More information

Tuesday 4 June 2013 Afternoon

Tuesday 4 June 2013 Afternoon Tuesday 4 June 2013 Afternoon AS GCE CHEMISTRY B (SALTERS) F332/01/TEST Chemistry of Natural Resources *F314880613* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry

More information

Thursday 10 January 2013 Morning

Thursday 10 January 2013 Morning Thursday 10 January 2013 Morning AS GCE CHEMISTRY A F321/01 Atoms, Bonds and Groups *F314420113* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry A (inserted) Other

More information

F322 Chains, Energy and Resources

F322 Chains, Energy and Resources F322 Chains, Energy and Resources 1 (a) C n 2n+2 1 ALLOW C n 2(n+1) IGNORE size of subscripts (b) (i) C 8 18 + 8½O 2 8CO + 9 2 O 1 ALLOW any correct multiples IGNORE state symbols (ii) limited supply of

More information

Friday 27 May 2016 Morning

Friday 27 May 2016 Morning Oxford Cambridge and RSA Friday 27 May 2016 Morning AS GCE CHEMISTRY A F321/01 Atoms, Bonds and Groups *5986785801* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry

More information

F332/TEST. CHEMISTRY B (SALTERS) Chemistry of Natural Resources ADVANCED SUBSIDIARY GCE. Friday 27 May 2011 Afternoon. Duration: 1 hour 45 minutes

F332/TEST. CHEMISTRY B (SALTERS) Chemistry of Natural Resources ADVANCED SUBSIDIARY GCE. Friday 27 May 2011 Afternoon. Duration: 1 hour 45 minutes ADVANCED SUBSIDIARY GCE CHEMISTRY B (SALTERS) Chemistry of Natural Resources F332/TEST *OCE/26193* Candidates answer on the question paper. OCR supplied materials: Data Sheet for Chemistry B (Salters)

More information

surname number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CHEMISTRY A Chains, Energy and Resources

surname number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CHEMISTRY A Chains, Energy and Resources Candidate forename Centre number Candidate surname Candidate number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CHEMISTRY A Chains, Energy and Resources THURSDAY 20 JANUARY 2011:

More information

THIS IS A NEW SPECIFICATION

THIS IS A NEW SPECIFICATION THIS IS A NEW SPECIFICATION ADVANCED SUBSIDIARY GCE CHEMISTRY A Atoms, Bonds and Groups F321 *CUP/T73723* Candidates answer on the question paper OCR Supplied Materials: Data Sheet for Chemistry A (Inserted)

More information

Friday 26 May 2017 Morning

Friday 26 May 2017 Morning Oxford Cambridge and RSA Friday 26 May 2017 Morning AS GCE CHEMISTRY A F321/01 Atoms, Bonds and Groups *6679472758* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry

More information

F324. CHEMISTRY A Rings, Polymers and Analysis ADVANCED GCE. Friday 24 June 2011 Morning PMT. Duration: 1 hour

F324. CHEMISTRY A Rings, Polymers and Analysis ADVANCED GCE. Friday 24 June 2011 Morning PMT. Duration: 1 hour ADVANCED GCE CHEMISTRY A Rings, Polymers and Analysis F324 *F318640611* Candidates answer on the question paper. OCR supplied materials: Data Sheet for Chemistry A (inserted) Other materials required:

More information

Monday 19 June 2017 Morning

Monday 19 June 2017 Morning Oxford Cambridge and RSA Monday 19 June 2017 Morning A2 GCE CHEMISTRY A F325/01 Equilibria, Energetics and Elements *6765485324* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet

More information

CHEMISTRY 2812/01 Chains and Rings

CHEMISTRY 2812/01 Chains and Rings TIS IS A LEGAY SPEIFIATION ADVANED SUBSIDIARY GE EMISTRY 2812/01 hains and Rings *UP/T57226* andidates answer on the question paper OR Supplied Materials: Data Sheet for hemistry (Inserted) Other Materials

More information

Monday 14 January 2013 Afternoon

Monday 14 January 2013 Afternoon Monday 14 January 2013 Afternoon A2 GCE CHEMISTRY B (SALTERS) F334/01 Chemistry of Materials *F314560113* Candidates answer on the Question Paper. CR supplied materials: Data Sheet for Chemistry B (Salters)

More information

THIS IS A NEW SPECIFICATION MODIFIED LANGUAGE

THIS IS A NEW SPECIFICATION MODIFIED LANGUAGE THIS IS A NEW SPECIFICATION ADVANCED SUBSIDIARY GCE CHEMISTRY B (SALTERS) Chemistry of Natural Resources F332/TEST * OCE / 14831* Candidates answer on the question paper OCR Supplied Materials: Data Sheet

More information

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 1 THIS IS A NEW SPECIFICATION

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 1 THIS IS A NEW SPECIFICATION OCR 2010 [D/500/7833] OCR is an exempt Charity THIS IS A NEW SPECIFICATION ADVANCED SUBSIDIARY GCE CHEMISTRY A Atoms, Bonds and Groups F321 * OCE / 1 9 2 3 2* Candidates answer on the Question Paper OCR

More information

F321. CHEMISTRY A Atoms, Bonds and Groups ADVANCED SUBSIDIARY GCE. Thursday 13 January 2011 Morning PMT. Duration: 1 hour

F321. CHEMISTRY A Atoms, Bonds and Groups ADVANCED SUBSIDIARY GCE. Thursday 13 January 2011 Morning PMT. Duration: 1 hour ADVANCED SUBSIDIARY GCE CHEMISTRY A Atoms, Bonds and Groups F321 * OCE / 2 5757* Candidates answer on the question paper. OCR supplied materials: Data Sheet for Chemistry A (inserted) Other materials required:

More information

THIS IS A NEW SPECIFICATION

THIS IS A NEW SPECIFICATION TIS IS A NEW SPECIFICATION ADVANCED SUBSIDIARY GCE CEMISTRY B (SALTERS) Chemistry for Life F331 *CUP/T69920* Candidates answer on the question paper A calculator may be used for this paper OCR Supplied

More information

Tuesday 2 June 2015 Afternoon

Tuesday 2 June 2015 Afternoon Oxford Cambridge and RSA Tuesday 2 June 2015 Afternoon AS GCE CHEMISTRY B (SALTERS) 332/01/TEST Chemistry of Natural Resources *5000749632* Candidates answer on the Question Paper. OCR supplied materials:

More information

CHEMISTRY 2815/01 Trends and Patterns

CHEMISTRY 2815/01 Trends and Patterns THIS IS A LEGACY SPECIFICATION ADVANCED GCE CHEMISTRY 2815/01 Trends and Patterns *OCE/13482* Candidates answer on the Question Paper A calculator may be used for this paper OCR Supplied Materials: Data

More information

F322: Chains, Energy and Resources Basic Concepts

F322: Chains, Energy and Resources Basic Concepts F322: hains, Energy and Resources Basic oncepts 1. Some of the hydrocarbons in kerosene have the formula 10 22. (i) What is the name of the straight chain hydrocarbon with the formula 10 22? (ii) Draw

More information

, can be completely combusted to give carbon dioxide and water. (s) + 6O 2

, can be completely combusted to give carbon dioxide and water. (s) + 6O 2 1 Glucose, C 6 H 12 O 6, can be completely combusted to give carbon dioxide and water. C 6 H 12 O 6 (s) + 6 (g) 6C (g) + 6 O(l) (a) In the body, the conversion of glucose into carbon dioxide and water

More information

Tuesday 22 January 2013 Afternoon

Tuesday 22 January 2013 Afternoon Tuesday 22 January 2013 Afternoon A2 GCE CHEMISTRY A F325/01 Equilibria, Energetics and Elements *F314480113* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry A

More information

THIS IS A NEW SPECIFICATION MODIFIED LANGUAGE

THIS IS A NEW SPECIFICATION MODIFIED LANGUAGE THIS IS A NEW SPECIFICATION ADVANCED GCE CHEMISTRY A Equilibria, Energetics and Elements F325 * OCE /30146 * Candidates answer on the Question Paper OCR Supplied Materials: Data Sheet for Chemistry A (inserted)

More information

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F332/TEST CHEMISTRY B (SALTERS) Chemistry of Natural Resources

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F332/TEST CHEMISTRY B (SALTERS) Chemistry of Natural Resources Candidate Forename Centre Number Candidate Surname Candidate Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F332/TEST CHEMISTRY B (SALTERS) Chemistry of Natural Resources WEDNESDAY

More information

G642. SCIENCE Science and Human Activity ADVANCED SUBSIDIARY GCE. Thursday 20 January 2011 Morning

G642. SCIENCE Science and Human Activity ADVANCED SUBSIDIARY GCE. Thursday 20 January 2011 Morning ADVANCED SUBSIDIARY GCE SCIENCE Science and Human Activity G642 *G616830611* Candidates answer on the question paper. OCR supplied materials: None Other materials required: Electronic calculator Ruler

More information

CHEMISTRY. How Far, How Fast? THURSDAY 11 JANUARY 2007 ADVANCED SUBSIDIARY GCE 2813/01. Morning. Time: 45 minutes

CHEMISTRY. How Far, How Fast? THURSDAY 11 JANUARY 2007 ADVANCED SUBSIDIARY GCE 2813/01. Morning. Time: 45 minutes ADVANCED SUBSIDIARY GCE 83/0 CHEMISTRY How Far, How Fast? THURSDAY JANUARY 007 Morning Additional materials: Scientific calculator Data Sheet for Chemistry (Inserted) Time: 45 minutes INSTRUCTIONS TO CANDIDATES

More information

CHEMISTRY 2814/01 Chains, Rings and Spectroscopy

CHEMISTRY 2814/01 Chains, Rings and Spectroscopy TIS IS A LEGAY SPEIFIATION ADVANED GE EMISTRY 2814/01 hains, Rings and Spectroscopy * OE / 1 9368* andidates answer on the Question Paper A calculator may be used for this paper OR Supplied Materials:

More information

surname number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A Rings, Polymers and Analysis

surname number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A Rings, Polymers and Analysis Candidate forename Centre number Candidate surname Candidate number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A Rings, Polymers and Analysis FRIDAY 24 JUNE 2011: Morning DURATION:

More information

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F321 CHEMISTRY A. Atoms, Bonds and Groups

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F321 CHEMISTRY A. Atoms, Bonds and Groups Candidate Forename Centre Number Candidate Surname Candidate Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F321 CHEMISTRY A Atoms, Bonds and Groups THURSDAY 14 JANUARY 2010: Morning

More information

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A. Rings, Polymers and Analysis

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A. Rings, Polymers and Analysis Candidate Forename Centre Number Candidate Surname Candidate Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A Rings, Polymers and Analysis WEDNESDAY 27 JANUARY 2010: Morning DURATION:

More information

CHEMISTRY Chains and Rings. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary GCE

CHEMISTRY Chains and Rings. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary GCE OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary GCE CHEMISTRY 2812 Chains and Rings Wednesday 8 JUNE 2005 Morning 1 hour Candidates answer on the question paper. Additional materials: Data Sheet

More information

DO NOT ALLOW any reference to spatial/space

DO NOT ALLOW any reference to spatial/space Question Answer Mark Guidance 1 (a) (i) (compounds or molecules having the) same molecular 1 ALLOW different structure OR different displayed formula but different structural formulae formula OR different

More information

4 ALLOW sugar from equation

4 ALLOW sugar from equation Question Expected Answers Marks Additional Guidance 1 (a) method 1: fermentation of sugars or carbohydrates R reaction with yeast with sugar or carbohydrates 6 12 6 2 2 5 + 2 2 4 ALLW sugar from equation

More information

Thursday 26 January 2012 Afternoon

Thursday 26 January 2012 Afternoon Thursday 26 January 2012 Afternoon A2 GE EMISTRY A F324 Rings, Polymers and Analysis *F314460112* andidates answer on the Question Paper. R supplied materials: Data Sheet for hemistry A (inserted) ther

More information

... [1] Draw another structural isomer of these two alcohols.

... [1] Draw another structural isomer of these two alcohols. 1 This question is about the six alcohols below. butan-2-ol 2-methylpentan-3-ol propan-1-ol ethane-1,2-diol 2-methylpropan-2-ol propan-2-ol (a) Which alcohol is an example of a tertiary alcohol?... [1]

More information

Monday 23 May 2016 Morning

Monday 23 May 2016 Morning Oxford Cambridge and RSA Monday 23 May 2016 Morning AS GCE SCIENCE G642/01 Science and Human Activity *5990094934* Candidates answer on the Question Paper. OCR supplied materials: None Other materials

More information

Morning. This document consists of 14 printed pages, 2 blank pages and a Data Sheet for Chemistry (Salters).

Morning. This document consists of 14 printed pages, 2 blank pages and a Data Sheet for Chemistry (Salters). ADVANCED SUBSIDIARY GCE 2848/01 EMISTRY (SALTERS) Chemistry of Natural Resources THURSDAY 11 JANUARY 2007 Morning Additional materials: Data Sheet for Chemistry (Salters) (Inserted) Scientific calculator

More information

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F325 CHEMISTRY A. Equilibria, Energetics and Elements

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F325 CHEMISTRY A. Equilibria, Energetics and Elements Candidate Forename Centre Number Candidate Surname Candidate Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F325 CHEMISTRY A Equilibria, Energetics and Elements THURSDAY 17 JUNE 2010: Afternoon

More information

Wednesday 13 June 2012 Morning

Wednesday 13 June 2012 Morning Wednesday 13 June 2012 Morning A2 GCE CHEMISTRY A F325 Equilibria, Energetics and Elements *F314750612* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry A (inserted)

More information

Wednesday 22 June 2016 Morning

Wednesday 22 June 2016 Morning Oxford Cambridge and RSA Wednesday 22 June 2016 Morning A2 GCE CHEMISTRY B (SALTERS) F335/01 Chemistry by Design *5881601420* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet

More information

(g) 2NH 3. (g) ΔH = 92 kj mol 1

(g) 2NH 3. (g) ΔH = 92 kj mol 1 1 The uses of catalysts have great economic and environmental importance For example, catalysts are used in ammonia production and in catalytic converters (a) Nitrogen and hydrogen react together in the

More information

CHEMISTRY 2813/01 How Far, How Fast?

CHEMISTRY 2813/01 How Far, How Fast? THIS IS A LEGACY SPECIFICATION ADVANCED SUBSIDIARY GCE CHEMISTRY 2813/01 How Far, How Fast? *CUP/T57245* Candidates answer on the question paper A calculator may be used for this paper OCR Supplied Materials:

More information

CHEMISTRY Chains and Rings. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary GCE

CHEMISTRY Chains and Rings. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary GCE OXFORD AMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary GE EMISTRY 2812 hains and Rings Tuesday 11 JANUARY 2005 Morning 1 hour andidates answer on the question paper. Additional materials: Data Sheet

More information

A Level Chemistry A H432/02 Synthesis and analytical techniques. Practice paper Set 1 Time allowed: 2 hours 15 minutes

A Level Chemistry A H432/02 Synthesis and analytical techniques. Practice paper Set 1 Time allowed: 2 hours 15 minutes A Level hemistry A 432/02 Synthesis and analytical techniques Practice paper Set 1 Time allowed: 2 hours 15 minutes You must have: the Data Sheet for hemistry A You may use: a scientific calculator a ruler

More information

Tuesday 14 June 2016 Afternoon

Tuesday 14 June 2016 Afternoon xford Cambridge and RSA Tuesday 14 June 2016 Afternoon A2 GCE CHEMISTRY B (SALTERS) F334/01 Chemistry of Materials *5881572259* Candidates answer on the Question Paper. CR supplied materials: Data Sheet

More information

CHEMISTRY 2816/01 Unifying Concepts in Chemistry

CHEMISTRY 2816/01 Unifying Concepts in Chemistry THIS IS A LEGACY SPECIFICATION ADVANCED GCE CHEMISTRY 2816/01 Unifying Concepts in Chemistry *OCE/14639* Candidates answer on the Question Paper A calculator may be used for this paper OCR Supplied Materials:

More information

Tuesday 13 June 2017 Afternoon

Tuesday 13 June 2017 Afternoon xford Cambridge and RSA Tuesday 13 June 2017 Afternoon A2 GCE CHEMISTRY B (SALTERS) F334/01 Chemistry of Materials *6766252685* Candidates answer on the Question Paper. CR supplied materials: Data Sheet

More information

Alkanes and Alkenes. The Alkanes

Alkanes and Alkenes. The Alkanes Alkanes and Alkenes The Alkanes Alkanes are hydrocarbons (i.e. compounds of carbon and hydrogen only). They are called saturated hydrocarbons because they contain no double bonds, and so cannot undergo

More information

SPECIMEN. Date Morning/Afternoon Time allowed: 1 hour 30 minutes. AS Level Chemistry B (Salters) H033/02 Chemistry in depth Sample Question Paper

SPECIMEN. Date Morning/Afternoon Time allowed: 1 hour 30 minutes. AS Level Chemistry B (Salters) H033/02 Chemistry in depth Sample Question Paper AS Level Chemistry B (Salters) H033/02 Chemistry in depth Sample Question Paper Date Morning/Afternoon Time allowed: 1 hour 30 minutes You must have: the Data Sheet for Chemistry B (Salters) You may use:

More information

G484. PHYSICS A The Newtonian World ADVANCED GCE. Thursday 27 January 2011 Afternoon. Duration: 1 hour

G484. PHYSICS A The Newtonian World ADVANCED GCE. Thursday 27 January 2011 Afternoon. Duration: 1 hour ADVANCED GCE PHYSICS A The Newtonian World G484 *OCE/17456* Candidates answer on the question paper. OCR supplied materials: Data, Formulae and Relationships Booklet Other materials required: Electronic

More information

F334. CHEMISTRY B (SALTERS) Chemistry of Materials ADVANCED GCE. Friday 24 June 2011 Morning. Duration: 1 hour 30 minutes

F334. CHEMISTRY B (SALTERS) Chemistry of Materials ADVANCED GCE. Friday 24 June 2011 Morning. Duration: 1 hour 30 minutes ADVANED GE HEMISTRY B (SALTERS) hemistry of Materials F334 *E/26423* andidates answer on the question paper. A calculator may be used for this paper. R supplied materials: Data Sheet for hemistry B (Salters)

More information

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F331 CHEMISTRY B (SALTERS) Chemistry for Life

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F331 CHEMISTRY B (SALTERS) Chemistry for Life Candidate Forename Centre Number Candidate Surname Candidate Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F331 CHEMISTRY B (SALTERS) Chemistry for Life THURSDAY 14 JANUARY 2010:

More information

THIS IS A NEW SPECIFICATION

THIS IS A NEW SPECIFICATION TIS IS A EW SPEIFIATI ADVAED GE EMISTRY A Rings, Polymers and Analysis F324 * E / 1 5371* andidates answer on the Question Paper R Supplied Materials: Data Sheet for hemistry A (inserted) ther Materials

More information

OXFORD CAMBRIDGE AND RSA EXAMINATIONS GCSE TWENTY FIRST CENTURY SCIENCE A173/02. CHEMISTRY A / FURTHER ADDITIONAL SCIENCE A Module C7 (Higher Tier)

OXFORD CAMBRIDGE AND RSA EXAMINATIONS GCSE TWENTY FIRST CENTURY SCIENCE A173/02. CHEMISTRY A / FURTHER ADDITIONAL SCIENCE A Module C7 (Higher Tier) OXFORD CAMBRIDGE AND RSA EXAMINATIONS GCSE TWENTY FIRST CENTURY SCIENCE A173/02 CHEMISTRY A / FURTHER ADDITIONAL SCIENCE A Module C7 (Higher Tier) THURSDAY 19 JUNE 2014: Afternoon DURATION: 1 hour plus

More information

THIS IS A NEW SPECIFICATION

THIS IS A NEW SPECIFICATION THIS IS A NEW SPECIFICATION ADVANCED GCE PHYSICS A The Newtonian World G484 * OCE / 2 301 6 * Candidates answer on the Question Paper OCR Supplied Materials: Data, Formulae and Relationships Booklet Other

More information

CHEMISTRY 2814/01 Chains, Rings and Spectroscopy

CHEMISTRY 2814/01 Chains, Rings and Spectroscopy THIS IS A LEGAY SPEIFIATION ADVANED GE HEMISTRY 2814/01 hains, Rings and Spectroscopy *OE/T69510* andidates answer on the question paper OR Supplied Materials: Data Sheet for hemistry (inserted) Other

More information

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A. Rings, Polymers and Analysis

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A. Rings, Polymers and Analysis Candidate Forename Centre Number Candidate Surname Candidate Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A Rings, Polymers and Analysis MONDAY 28 JUNE 2010: Morning DURATION:

More information

Wednesday 1 February 2012 Morning

Wednesday 1 February 2012 Morning Wednesday 1 February 2012 Morning A2 GCE CHEMISTRY B (SALTERS) F335 Chemistry by Design *F314580112* Candidates answer on the Question Paper. OCR supplied materials: Data Sheet for Chemistry B (Salters)

More information

F331. CHEMISTRY B (SALTERS) Chemistry for Life ADVANCED SUBSIDIARY GCE. Thursday 13 January 2011 Morning

F331. CHEMISTRY B (SALTERS) Chemistry for Life ADVANCED SUBSIDIARY GCE. Thursday 13 January 2011 Morning OCR 2011 [K/500/7964] OCR is an exempt Charity Cherry Hill Tuition A Level Chemistry OCR (B) Paper 3 Page 1 of 9 ADVANCED SUBSIDIARY GCE CHEMISTRY B (SALTERS) Chemistry for Life 331 *OCE/25640* Candidates

More information

OXFORD CAMBRIDGE AND RSA EXAMINATIONS GCSE TWENTY FIRST CENTURY SCIENCE A173/01

OXFORD CAMBRIDGE AND RSA EXAMINATIONS GCSE TWENTY FIRST CENTURY SCIENCE A173/01 OXFORD CAMBRIDGE AND RSA EXAMINATIONS GCSE TWENTY FIRST CENTURY SCIENCE A173/01 CHEMISTRY A / FURTHER ADDITIONAL SCIENCE A Module C7 (Foundation Tier) THURSDAY 19 JUNE 2014: Afternoon DURATION: 1 hour

More information

Alcohols. Ethanol Production. 182 minutes. 181 marks. Page 1 of 25

Alcohols. Ethanol Production. 182 minutes. 181 marks. Page 1 of 25 3..10 Alcohols Ethanol Production 18 minutes 181 marks Page 1 of 5 Q1. Ethanol is produced commercially by fermentation of aqueous glucose, C 6 H 1 O 6 State two conditions, other than temperature, which

More information

A mass spectrometer can be used to distinguish between samples of butane and propanal. The table shows some precise relative atomic mass values.

A mass spectrometer can be used to distinguish between samples of butane and propanal. The table shows some precise relative atomic mass values. Butane and propanal are compounds with M r = 58.0, calculated using data from your Periodic Table. (a) A mass spectrometer can be used to distinguish between samples of butane and propanal. The table shows

More information

3.2.8 Haloalkanes. Nucleophilic Substitution. 267 minutes. 264 marks. Page 1 of 36

3.2.8 Haloalkanes. Nucleophilic Substitution. 267 minutes. 264 marks. Page 1 of 36 3.2.8 Haloalkanes Nucleophilic Substitution 267 minutes 264 marks Page 1 of 36 Q1. (a) The equation below shows the reaction of 2-bromopropane with an excess of ammonia. CH 3 CHBrCH 3 + 2NH 3 CH 3 CH(NH

More information

This document consists of 12 printed pages and a Data Sheet for Chemistry.

This document consists of 12 printed pages and a Data Sheet for Chemistry. ADVANCED SUBSIDIARY GCE 2811/01 CHEMISTRY Foundation Chemistry WEDNESDAY 6 JUNE 2007 Morning Additional materials: Scientific calculator Data Sheet for Chemistry (Inserted) Time: 1 hour INSTRUCTIONS TO

More information

10.2 ALCOHOLS EXTRA QUESTIONS. Reaction excess conc, H SO 180 C

10.2 ALCOHOLS EXTRA QUESTIONS. Reaction excess conc, H SO 180 C 10.2 ALOOLS EXTRA QUESTIONS 1. onsider the reaction scheme below which starts from butanone. N Reaction 1 3 2 3 3 2 3 O Reaction 2 O A 3 O B 2 3 excess conc, SO 180 2 4 but 1 ene and but 2 ene (a) When

More information

THIS IS A NEW SPECIFICATION

THIS IS A NEW SPECIFICATION THIS IS A NEW SPECIFICATION ADVANCED SUBSIDIARY GCE CHEMISTRY A Atoms, Bonds and Groups F321 *CUP/T73721* Candidates answer on the question paper OCR Supplied Materials: Data Sheet for Chemistry A (Inserted)

More information

CHEMISTRY (SALTERS) 2849/01 Chemistry of Materials

CHEMISTRY (SALTERS) 2849/01 Chemistry of Materials TIS IS A LEGACY SPECIFICATION ADVANCED GCE CEMISTRY (SALTERS) 2849/01 Chemistry of Materials *OCE/13048* Candidates answer on the Question Paper OCR Supplied Materials: Data Sheet for Chemistry (Salters)

More information

Morning. This document consists of 8 printed pages and a Data Sheet for Chemistry.

Morning. This document consists of 8 printed pages and a Data Sheet for Chemistry. ADVANCED SUBSIDIARY GCE 2813/01 CHEMISTRY How Far, How Fast? THURSDAY 11 JANUARY 2007 Morning Additional materials: Scientific calculator Data Sheet for Chemistry (Inserted) Time: 45 minutes INSTRUCTIONS

More information

PhysicsAndMathsTutor.com. Advanced Subsidiary Paper 2: Core Organic and Physical Chemistry

PhysicsAndMathsTutor.com. Advanced Subsidiary Paper 2: Core Organic and Physical Chemistry Write your name here Surname Other names Pearson Edexcel GE entre Number andidate Number hemistry Advanced Subsidiary Paper 2: ore Organic and Physical hemistry Friday 10 June 2016 Afternoon Time: 1 hour

More information

Wednesday 21 May 2014 Afternoon

Wednesday 21 May 2014 Afternoon Wednesday 21 May 2014 Afternoon AS GCE SCIENCE G641/01 Remote Sensing and the Natural Environment *1319354529* Candidates answer on the Question Paper. OCR supplied materials: None Other materials required:

More information

CHEMISTRY 2811/01 Foundation Chemistry

CHEMISTRY 2811/01 Foundation Chemistry THIS IS A LEGACY SPECIFICATION ADVANCED SUBSIDIARY GCE CHEMISTRY 2811/01 Foundation Chemistry *CUP/T56917* Candidates answer on the question paper OCR Supplied Materials: Data Sheet for Chemistry (inserted)

More information