Concentration of Solutions

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1 Concentration of Solutions 1 of 27 Boardworks Ltd 2016

2 Concentration of Solutions 2 of 27 Boardworks Ltd 2016

3 Measuring concentrations 3 of 27 Boardworks Ltd 2016 It is not enough to say that one concentration is higher or lower than another. Concentrations usually need to be measured accurately. There are two ways of measuring concentration: mass per unit volume, e.g. grams per decimetre cubed (g/dm 3 ) moles per unit volume, e.g. moles per decimetre cubed (mol/dm 3 ). A cubic decimetre (dm 3 ) is a unit of volume. 1dm 3 is equivalent to 1000cm 3. divide by cm 3 1dm 3 multiply by 1000

4 Volume unit conversions 4 of 27 Boardworks Ltd 2016

5 5 of 27 Boardworks Ltd 2016 Concentrations in g/dm 3 The following equation gives concentration in g/dm 3 : concentration = mass dissolved (g) volume of solution (dm 3 ) If 1.0g of solid sodium hydroxide is dissolved in 250 cm 3 of water, what is the concentration in g/dm 3? 1g concentration = 250cm 3 1 g = = 0.25dm g dm 3 convert the units = 4g/dm 3

6 Calculating concentrations in g/dm 3 6 of 27 Boardworks Ltd 2016

7 7 of 27 Boardworks Ltd 2016 Concentrations in mol/dm 3 To calculate concentration in mol/dm 3 : concentration = number of moles (mol) volume of solution (dm 3 ) This equation can be added to a formula triangle to rearrange the formula: c = n v n = c v = n c v

8 Concentrations in mol/dm 3 example 8 of 27 Boardworks Ltd 2016 If 1.0g of solid sodium hydroxide (NaOH) is dissolved in 250 cm 3 of water, what is the concentration in mol/dm 3? c = n v? = 0.25dm 3 The information in the question provides the volume but not the number of moles. The following formula is required: mass 1 number of moles = = = 0.025mol molar mass 40 Remember, molar mass = relative formula mass (RFM) Now substitute mol into the original formula: mol c = = 0.1mol/dm dm 3

9 Concentrations in mol/dm 3 : practise 9 of 27 Boardworks Ltd 2016

10 Rearranging formulae example 1 10 of 27 Boardworks Ltd 2016 What volume of 0.80mol/dm 3 potassium bromide solution contains 1.6moles of potassium bromide (KBr)? v = n / c This calculation is simply a matter of substituting the values into the rearranged formula: v = n / c = 1.6 / 0.8 = 2dm 3

11 Rearranging formulae example 2 11 of 27 Boardworks Ltd 2016 How many moles of copper sulfate are there in 250 cm 3 of 0.2mol/dm 3 copper sulfate solution (CuSO 4 )? n = c v Step 1: convert the units 250cm 3 = 0.25dm 3 Step 2: substitute into the formula n = c x v = = 0.05mol

12 Calculating mass of solute 12 of 27 Boardworks Ltd 2016 What mass of copper sulfate (CuSO 4 ) was used to make 250cm 3 of 0.2mol/dm 3 copper sulfate solution? Step 1: Calculate the number of moles of copper sulfate Step 2: Rearrange the moles formula to give the mass value This is simply an extension of the previous calculation, from which the moles of copper sulfate was found to be 0.05mol. mass of copper sulfate = number of moles molar mass = = 8.0g

13 Concentration of Solutions 13 of 27 Boardworks Ltd 2016

14 Titrations 14 of 27 Boardworks Ltd 2016 A titration is a technique used to accurately determine the concentration of a substance in solution. During a titration, a solution of known concentration, called a standard solution, is added to a solution of unknown concentration. The purpose of a titration is to determine the volume of solution required to reach an endpoint. An endpoint is an observable physical change, such as a colour change. Why is measuring the volume useful?

Finding an unknown concentration 15 of 27 Boardworks Ltd 2016 Volume can be used to determine the concentration by using the following relationship: concentration = number of moles (mol) volume

15 Finding an unknown concentration 15 of 27 Boardworks Ltd 2016 Volume can be used to determine the concentration by using the following relationship: concentration = number of moles (mol) volume of solution (dm 3 ) An unknown concentration value can be found if the following values are known: number of moles in solution volume of solution. These values can be found through a titration.

16 Titration equipment 16 of 27 Boardworks Ltd 2016 The following laboratory equipment is required to perform a titration: safety filler burette stand pipette conical flask beaker

Indicators are substances which change colour according to the ph of a solution.

17 Indicators 17 of 27 Boardworks Ltd 2016 The endpoint of a titration is often marked by a colour change. This is provided by an indicator solution. Indicators are substances which change colour according to the ph of a solution. A small amount of indicator solution is added to one of the solutions during a titration. When the indicator changes colour, the endpoint of the titration has been reached.

18 Performing a titration 18 of 27 Boardworks Ltd 2016

19 Titration apparatus 19 of 27 Boardworks Ltd 2016

20 Concentration of Solutions 20 of 27 Boardworks Ltd 2016

21 Using titration results 21 of 27 Boardworks Ltd 2016 How are the results of a titration used to calculate the unknown molar concentration of a solution? Step 1: Write a balanced equation for the reaction. Step 2: Calculate the number of moles of standard solution by rearranging the concentration formula: moles = concentration volume Step 3: Use the balanced equation to determine the number of moles for the solution under investigation. Step 4: Use the concentration formula to determine the unknown molar concentration: molar concentration = moles volume

22 Titration calculations: worked example (1) 22 of 27 Boardworks Ltd 2016 The endpoint of a titration was reached when 20 cm 3 of 0.1mol/dm 3 sodium hydroxide was added to 25 cm 3 of hydrochloric acid. What is the concentration of the acid? 1. Write a balanced equation for the reaction: 2. Calculate the number of moles of sodium hydroxide: moles = concentration (mol/dm 3 ) volume (dm 3 ) = 0.1 ( ) = mol NaOH

23 Titration calculations: worked example (2) 23 of 27 Boardworks Ltd The balanced equation from step 1 shows that one mole of HCl reacts with one mole of NaOH: Therefore moles of NaOH will react with: moles of HCl. 4. Use the number of moles to calculate the molar concentration of the hydrochloric acid: molar concentration = moles = volume (dm 3 ) ( ) = 0.08mol/dm 3

24 Titration calculations: questions 24 of 27 Boardworks Ltd 2016

25 Concentration of Solutions 25 of 27 Boardworks Ltd 2016

26 Glossary 26 of 27 Boardworks Ltd 2016

27 Multiple-choice quiz 27 of 27 Boardworks Ltd 2016

Concentration of Solutions

Concentration of Solutions 1 of 27 Boardworks Ltd 2016 Concentration of Solutions 2 of 27 Boardworks Ltd 2016 Measuring concentrations 3 of 27 Boardworks Ltd 2016 It is not enough to say that one concentration