Concepts. Materials. Objective
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1 . Activity 10 From a Distance... You Can See It! Teacher Notes Concepts Midpoint between two points Distance between two points Pythagorean Theorem Calculator Skills Entering fractions: N Setting decimal places: % Using the F key Materials TI-30X ÖS Student Activity pages (p ) 3 x 5 index cards Coordinate grid paper (centimeter paper) Objective In this activity, students will find distances between points using common fraction and decimal calculations with the concepts of midpoint and distance. They also will learn to solve problems using the Pythagorean Theorem and by finding the diagonal distance in a rectangular prism. Topics Covered Translating between synthetic and coordinate representations Deducing properties of figures using coordinates Using coordinates in problem solving Introduction Construct a triangle on rectangular grid paper with vertices at F(0,0), G(12,0), and H(8,6). Estimate the location of the midpoint of side FH and call it point M. Estimate the location of the midpoint of side GH and call it point N. Connect MN with a line segment. What is the length of segment MN?
2 92 Math Investigations with the TI-30X ÖS: Activities for Secondary Mathematics Investigation 1. Draw line segment ST. Locate and label three midpoints as follows: Let R be the midpoint of ST. Let Q be the midpoint of RT and P be the midpoint of QT. The length of ST = 38 ½ centimeters. 2. Use the overhead calculator to find the length of RT. Continue this procedure to find the lengths of QT (9 5/8) and PT (4 13/16). Press: - 38 N 1 N 2 < 38Â1Â2 W 2 < The calculator shows: Ans/2 38 1/2 19 1/4 3. On coordinate grid paper, locate and plot the points A(1,-2), B(1,7), C(5,7) and D(7,-2). Connect the points with line segments in order from A to B, B to C, C to D, and D to A. The geometric shape should be a trapezoid. 4. Find the midpoints for AB, BC, and DA. Label these points M, E, and T respectively. 5. Finding the midpoint R of CD is more difficult. To find the midpoint for any two points P 1 (x 1, y 1 ) and P 2 (x 2, y 2 ), use the midpoint formula: x + x, y y Use the overhead calculator to find the midpoint R of segment CD. Therefore, the coordinates of the midpoint R are (6, 2.5). Press: - D 5 T 7 E W 2 < D 7 T M 2 E W 2 < The calculator shows: (5 ¼7)/2 (7 ¼L2) 6 2.5
3 Activity 10: From a Distance...You Can See It! Find the length of CD above, using the distance formula: d= x x + y y Use C(5, 7) and D(7, -2). Display the result with two decimal places. Press: - % b D 7 U 5 E F T D M 2 U 7 E F E < The calculator shows: ( (7N5) 2 ¼( L2¹ % " " " F < ( (7N5) 2 ¼( L2¹ FIX 9.22 Wrap-Up Assign Student Activity Part 1 and Student Activity Part 2 as individual work and then have students discuss their answers in pairs. Use Student Activity Part 3 as a group activity to discover or reinforce the Pythagorean Theorem. Make sure students set the calculator to floating-decimal format at the end of this activity. Extensions The line segment MN in the Introduction is called the median. Ask students how they determined the estimates of the location of the midpoints. What is the length of the median? Why is this segment called the median? How many different trapezoids can you construct whose bases are odd numbers with height of 6 inches and whose area is 48 square inches?
4 94 Math Investigations with the TI-30X ÖS: Activities for Secondary Mathematics Solutions Part 1 Draw line segment LM with midpoint T. Point X is the midpoint of segment LT, and Y is the midpoint of segment TM. Point Z is the midpoint of segment LX. The distance from L to M is 42 1/4 centimeters. Express your answers as mixed fractions. 1. The distance TM is 21 1/8 centimeters. 2. The distance TX is 10 9/16 centimeters. 3. The distance YM is10 9/16 centimeters. 4. The distance LZ is 5 9/32 centimeters. 5. The distance TZ is 15 27/32 centimeters. 6. The distance ZY is 26 13/32 centimeters. Suppose that the distance from Z to Y is 18 3/4 centimeters. Express your answers as mixed fractions. 7. The distance ZT is 11 1/4 centimeters. 8. The distance LY is 22 1/2 centimeters. 9. The distance LM is 30 centimeters. 10. The distance YM is 7 1/2 centimeters. Name all other segments that are the same length as YM. TY, XT, LX Solutions Part 2 Use the trapezoid from before with the points A(1,-2), B(1,7), C(5,7), and D(7,-2). Label the midpoints for AB, BC, CD, and DA as points M, E, R, and T, respectively. Use the distance formula and your calculator to solve the problems below. Write your answers correct to three decimal places. 1. Find the distance AC Find the distance BD Find the distance MR Find the distance ET Find the distance MC Find the distance BT Find the perimeter of ABCD AB = 9 BC = 4 CD = DA = 6
5 Activity 10: From a Distance...You Can See It! Find the perimeter of MERT ME = Perimeter of ABCD 9. Find the ratio Perimeter of MERT How can you explain the answer for #9? ER = RT = TM = The perimeter of the trapezoid is 36.69% larger than the perimeter of the quadrilateral connecting the midpoints of the sides. Solutions Part 3 1. Cut a 3 x 5 card along one diagonal. How do the two right triangles compare? a. Draw an altitude from the right angle to the hypotenuse of one of the right triangles. Now cut along the altitude to create two triangles. Use the diagram below as a guide. You should now have three triangles. How do the three triangles compare? They are similar triangles b. Use a ruler to measure the lengths of the sides of the small triangle, the medium, triangle, and the large triangle. Record the measures in the table below, then use your calculator to find the squares of each of the measures. Record these calculated values in the table. (The answers will vary) Small Medium Large Short Leg Long Leg Hypotenuse (Short leg) 2 (Long Leg) 2 (Hypotenuse) 2 c. Describe the relationships that you observe between the legs and the hypotenuse in the table. The measures in the table should confirm the conclusion of the Pythagorean Theorem. That is, the sum of the squares of the short leg and the long leg should be equal to the square of the hypotenuse.
6 96 Math Investigations with the TI-30X ÖS: Activities for Secondary Mathematics 2. An antenna used to transmit television signals is 235 feet tall. Three support cables, each of which measure 205 feet, are attached to the antenna at a point that is 183 feet above the ground. How far away from the base of the antenna will the ends of the three support cables be when attached to the ground? The distance away from the antenna should be = feet. 3. The length d of the diagonal of any rectangular solid can be found by the formula d = length 2 + width 2 + height 2. Why does this formula work? The formula works because it is an extension of the Pythagorean Theorem in three dimensions. (Answers may vary) 4. Jacqueline wishes to pack a 3 ½ - foot umbrella in a rectangular suitcase that measures 3 ft x 2 ft x ¾ ft. Is this possible? Why or why not? Yes! The maximum distance is the diagonal distance = feet.
7 Student Activity 10 Name Date Geometry and Measurement From a Distance...You Can See It! Objective: In this activity, you will find the distance between points using common fraction and decimal calculations with the concepts of midpoint and distance. You also will solve problems using the Pythagorean Theorem and by finding the diagonal distance in a rectangular prism. Part 1: Finding Distances Between Points Draw line segment LM with midpoint T. Point X is the midpoint of segment LT, and Y is the midpoint of segment TM. Point Z is the midpoint of segment LX. The distance from L to M is 42 ¼ centimeters. Express your answers as mixed fractions. 1. The distance TM is centimeters. 2. The distance TX is centimeters. 3. The distance YM is centimeters. 4. The distance LZ is centimeters. 5. The distance TZ is centimeters. 6. The distance ZY is centimeters. Suppose that the distance from Z to Y is 18 ¾ centimeters. Express your answers as mixed fractions. 7. The distance ZT is centimeters. 8. The distance LY is centimeters. 9. The distance LM is centimeters.
8 98 Math Investigations with the TI-30X ÖS: Activities for Secondary Mathematics 10. The distance YM is centimeters. 11. Name all other segments that are the same length as YM. Part 2: Finding Measurements on a Trapezoid Use the trapezoid from before with the points A(1,-2), B(1,7), C(5,7), and D(7,-2). Label the midpoints for AB, BC, CD, and DA as points M, E, R, and T, respectively. Use the distance formula and your calculator to solve the problems below. Write your answers correct to three decimal places. 1. Find the distance AC. 2. Find the distance BD. 3. Find the distance MR. 4. Find the distance ET. 5. Find the distance MC. 6. Find the distance BT. 7. Find the perimeter of ABCD. 8. Find the perimeter of MERT. 9. Find the ratio Perimeter of ABCD Perimeter of MERT. 10. How can you explain the answer for #9?
9 Activity 10: From a Distance...You Can See It! 99 Part 3: Working with Triangles 1. Cut a 3 x 5 card along one diagonal. How do the two right triangles compare? a. Draw an altitude from the right angle to the hypotenuse of one of the right triangles. Now cut along the altitude to create two triangles. Use the diagram below as a guide. You should now have three triangles. How do the three triangles compare? b. Use a ruler to measure the lengths of the sides of the small triangle, the medium triangle, and the large triangle. Record the measures in the table below, and then use your calculator to find the squares of each of the measures. Record these calculated values in the table. Small Medium Large Short Leg Long Leg Hypotenuse (Short leg) 2 (Long Leg) 2 (Hypotenuse) 2 c. Describe the relationships that you observe between the legs and the hypotenuse in the table. 2. An antenna used to transmit television signals is 235 feet tall. Three support cables, each of which measure 205 feet, are attached to the antenna at a point that is 183 feet above the ground. How far away from the base of the antenna will the ends of the three support cables be when attached to the ground?
10 100 Math Investigations with the TI-30X ÖS: Activities for Secondary Mathematics 3. The length d of the diagonal of any rectangular solid can be found by the formula d = length 2 + width 2 + height 2. Why does this formula work? 4. Jacqueline wishes to pack a 3 ½ - foot umbrella in a rectangular suitcase that measures 3 ft x 2 ft x ¾ ft. Is this possible? Why or why not?
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